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PHXI13:KINETIC THEORY

360273 If at the same temperature and pressure, the densities of two diatomic gases are $d_{1}$ and $d_{2}$ respectively. The ratio of mean kinetic energy per molecules of gases will be

1

1 : 1

2

d_{1} : d_{2}

3

\sqrt{d_{1}} : \sqrt{d_{2}}

4

\sqrt{d_{2}} : \sqrt{d_{1}}

Explanation:

At a given temperature $(T)$ all the ideal gas molecules no matter what their masses, have the same average translational kinetic energy.
$E = \frac{3}{2} K T$
So $E$ does not depend upon density $\frac{E_{1}}{E_{2}} = \frac{1}{1}$ .

PHXI13:KINETIC THEORY

360274 The average thermal energy for a mono-atomic gas is : ( $K_{B}$ is Boltzmann constant and $T$ absolute temperature)

1

\frac{3}{2} k_{B} T

2

\frac{5}{2} k_{B} T

3

\frac{7}{2} k_{B} T

4

\frac{1}{2} k_{B} T

Explanation:

Average thermal energy $= \frac{3}{2} k_{B} T$
where 3 is translational degree of freedom. For monoatomic gas total degree of freedom $f = 3$ (translational degree of freedom)

NEET - 2020

PHXI13:KINETIC THEORY

360275 The gases carbon-monoxide $(C O)$ and oxgen $(O_{2})$ at the same temperature, have kinetic energies $E_{1}$ and $E_{2}$ , respectively. Then

1

E_{1} = E_{2}

2

E_{1} < E_{2}

3

E_{1} > E_{2}

4

E_{1}

and

E_{2}

cannot be compared

Explanation:

The gases carbon-monoxide ( $C O$ ) and nitrogen $(N_{2})$ are diatomic, so both have equal kinetic energy $(\frac{5}{2} k T)$ , $i . e .$ $E_{1} = E_{2}$ .

PHXI13:KINETIC THEORY

360276 Assertion :
Absolute zero is not the temperature corresponding to zero energy.
Reason :
The temperature at which molecular motion ceases is called absolute zero temperature.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXI13:KINETIC THEORY

360273 If at the same temperature and pressure, the densities of two diatomic gases are $d_{1}$ and $d_{2}$ respectively. The ratio of mean kinetic energy per molecules of gases will be

1

1 : 1

2

d_{1} : d_{2}

3

\sqrt{d_{1}} : \sqrt{d_{2}}

4

\sqrt{d_{2}} : \sqrt{d_{1}}

Explanation:

At a given temperature $(T)$ all the ideal gas molecules no matter what their masses, have the same average translational kinetic energy.
$E = \frac{3}{2} K T$
So $E$ does not depend upon density $\frac{E_{1}}{E_{2}} = \frac{1}{1}$ .

PHXI13:KINETIC THEORY

360274 The average thermal energy for a mono-atomic gas is : ( $K_{B}$ is Boltzmann constant and $T$ absolute temperature)

1

\frac{3}{2} k_{B} T

2

\frac{5}{2} k_{B} T

3

\frac{7}{2} k_{B} T

4

\frac{1}{2} k_{B} T

Explanation:

Average thermal energy $= \frac{3}{2} k_{B} T$
where 3 is translational degree of freedom. For monoatomic gas total degree of freedom $f = 3$ (translational degree of freedom)

NEET - 2020

PHXI13:KINETIC THEORY

360275 The gases carbon-monoxide $(C O)$ and oxgen $(O_{2})$ at the same temperature, have kinetic energies $E_{1}$ and $E_{2}$ , respectively. Then

1

E_{1} = E_{2}

2

E_{1} < E_{2}

3

E_{1} > E_{2}

4

E_{1}

and

E_{2}

cannot be compared

Explanation:

The gases carbon-monoxide ( $C O$ ) and nitrogen $(N_{2})$ are diatomic, so both have equal kinetic energy $(\frac{5}{2} k T)$ , $i . e .$ $E_{1} = E_{2}$ .

PHXI13:KINETIC THEORY

360276 Assertion :
Absolute zero is not the temperature corresponding to zero energy.
Reason :
The temperature at which molecular motion ceases is called absolute zero temperature.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXI13:KINETIC THEORY

360273 If at the same temperature and pressure, the densities of two diatomic gases are $d_{1}$ and $d_{2}$ respectively. The ratio of mean kinetic energy per molecules of gases will be

1

1 : 1

2

d_{1} : d_{2}

3

\sqrt{d_{1}} : \sqrt{d_{2}}

4

\sqrt{d_{2}} : \sqrt{d_{1}}

Explanation:

At a given temperature $(T)$ all the ideal gas molecules no matter what their masses, have the same average translational kinetic energy.
$E = \frac{3}{2} K T$
So $E$ does not depend upon density $\frac{E_{1}}{E_{2}} = \frac{1}{1}$ .

PHXI13:KINETIC THEORY

360274 The average thermal energy for a mono-atomic gas is : ( $K_{B}$ is Boltzmann constant and $T$ absolute temperature)

1

\frac{3}{2} k_{B} T

2

\frac{5}{2} k_{B} T

3

\frac{7}{2} k_{B} T

4

\frac{1}{2} k_{B} T

Explanation:

Average thermal energy $= \frac{3}{2} k_{B} T$
where 3 is translational degree of freedom. For monoatomic gas total degree of freedom $f = 3$ (translational degree of freedom)

NEET - 2020

PHXI13:KINETIC THEORY

360275 The gases carbon-monoxide $(C O)$ and oxgen $(O_{2})$ at the same temperature, have kinetic energies $E_{1}$ and $E_{2}$ , respectively. Then

1

E_{1} = E_{2}

2

E_{1} < E_{2}

3

E_{1} > E_{2}

4

E_{1}

and

E_{2}

cannot be compared

Explanation:

The gases carbon-monoxide ( $C O$ ) and nitrogen $(N_{2})$ are diatomic, so both have equal kinetic energy $(\frac{5}{2} k T)$ , $i . e .$ $E_{1} = E_{2}$ .

PHXI13:KINETIC THEORY

360276 Assertion :
Absolute zero is not the temperature corresponding to zero energy.
Reason :
The temperature at which molecular motion ceases is called absolute zero temperature.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXI13:KINETIC THEORY

360273 If at the same temperature and pressure, the densities of two diatomic gases are $d_{1}$ and $d_{2}$ respectively. The ratio of mean kinetic energy per molecules of gases will be

1

1 : 1

2

d_{1} : d_{2}

3

\sqrt{d_{1}} : \sqrt{d_{2}}

4

\sqrt{d_{2}} : \sqrt{d_{1}}

Explanation:

At a given temperature $(T)$ all the ideal gas molecules no matter what their masses, have the same average translational kinetic energy.
$E = \frac{3}{2} K T$
So $E$ does not depend upon density $\frac{E_{1}}{E_{2}} = \frac{1}{1}$ .

PHXI13:KINETIC THEORY

360274 The average thermal energy for a mono-atomic gas is : ( $K_{B}$ is Boltzmann constant and $T$ absolute temperature)

1

\frac{3}{2} k_{B} T

2

\frac{5}{2} k_{B} T

3

\frac{7}{2} k_{B} T

4

\frac{1}{2} k_{B} T

Explanation:

Average thermal energy $= \frac{3}{2} k_{B} T$
where 3 is translational degree of freedom. For monoatomic gas total degree of freedom $f = 3$ (translational degree of freedom)

NEET - 2020

PHXI13:KINETIC THEORY

360275 The gases carbon-monoxide $(C O)$ and oxgen $(O_{2})$ at the same temperature, have kinetic energies $E_{1}$ and $E_{2}$ , respectively. Then

1

E_{1} = E_{2}

2

E_{1} < E_{2}

3

E_{1} > E_{2}

4

E_{1}

and

E_{2}

cannot be compared

Explanation:

The gases carbon-monoxide ( $C O$ ) and nitrogen $(N_{2})$ are diatomic, so both have equal kinetic energy $(\frac{5}{2} k T)$ , $i . e .$ $E_{1} = E_{2}$ .

PHXI13:KINETIC THEORY

360276 Assertion :
Absolute zero is not the temperature corresponding to zero energy.
Reason :
The temperature at which molecular motion ceases is called absolute zero temperature.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

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