360217
Pressure of ideal gas at constant volume is proportional to
1 total energy of the gas
2 average kinetic energy of the molecules
3 force between the molecules
4 average potential energy of the molecules
Explanation:
\(P=\left(\dfrac{M}{3 V}\right) v_{r m s}^{2}\) \(\Rightarrow P=\dfrac{2}{3} E\) \(\Rightarrow P \propto E\) Correct option is (2).
KCET - 2023
PHXI13:KINETIC THEORY
360218
In an ideal gas at temperature \(T\), the average force that a molecule applies on the walls of a closed container depends on\(T\) as \({T^q}\). A good estimate for \(q\) is:
1 \(\dfrac{1}{2}\)
2 2
3 1
4 \(\dfrac{1}{4}\)
Explanation:
Pressure, \(P=\dfrac{1}{3} \dfrac{m N}{V} v_{r m s}^{2}\) \(P \propto\left(v_{r m s}\right)^{2} \propto T\) So, force \(\propto\left(v_{r m s}\right)^{2} \propto T\) i.e., Value of \(q = 1\)
JEE - 2015
PHXI13:KINETIC THEORY
360219
Relationship between \(P, V\) and \(E\) for a gas is ( \(E\) is the kinetic energy of the gas)
1 \(P V=\dfrac{3}{2} E\)
2 \(V=\dfrac{2}{3} E P\)
3 \(P=\dfrac{3}{2} E V\)
4 \(P V=\dfrac{2}{3} E\)
Explanation:
\(P V=\dfrac{1}{3} m N c^{2}=\dfrac{2}{3} N\left(\dfrac{1}{2} m c^{2}\right)\) \(P V=\dfrac{2}{3} E\)
PHXI13:KINETIC THEORY
360220
In outer space there are 10 molecules per \(c{m^3}\) on the average and the temperature there is \(3 K\). The average pressure of this light gas is
360217
Pressure of ideal gas at constant volume is proportional to
1 total energy of the gas
2 average kinetic energy of the molecules
3 force between the molecules
4 average potential energy of the molecules
Explanation:
\(P=\left(\dfrac{M}{3 V}\right) v_{r m s}^{2}\) \(\Rightarrow P=\dfrac{2}{3} E\) \(\Rightarrow P \propto E\) Correct option is (2).
KCET - 2023
PHXI13:KINETIC THEORY
360218
In an ideal gas at temperature \(T\), the average force that a molecule applies on the walls of a closed container depends on\(T\) as \({T^q}\). A good estimate for \(q\) is:
1 \(\dfrac{1}{2}\)
2 2
3 1
4 \(\dfrac{1}{4}\)
Explanation:
Pressure, \(P=\dfrac{1}{3} \dfrac{m N}{V} v_{r m s}^{2}\) \(P \propto\left(v_{r m s}\right)^{2} \propto T\) So, force \(\propto\left(v_{r m s}\right)^{2} \propto T\) i.e., Value of \(q = 1\)
JEE - 2015
PHXI13:KINETIC THEORY
360219
Relationship between \(P, V\) and \(E\) for a gas is ( \(E\) is the kinetic energy of the gas)
1 \(P V=\dfrac{3}{2} E\)
2 \(V=\dfrac{2}{3} E P\)
3 \(P=\dfrac{3}{2} E V\)
4 \(P V=\dfrac{2}{3} E\)
Explanation:
\(P V=\dfrac{1}{3} m N c^{2}=\dfrac{2}{3} N\left(\dfrac{1}{2} m c^{2}\right)\) \(P V=\dfrac{2}{3} E\)
PHXI13:KINETIC THEORY
360220
In outer space there are 10 molecules per \(c{m^3}\) on the average and the temperature there is \(3 K\). The average pressure of this light gas is
360217
Pressure of ideal gas at constant volume is proportional to
1 total energy of the gas
2 average kinetic energy of the molecules
3 force between the molecules
4 average potential energy of the molecules
Explanation:
\(P=\left(\dfrac{M}{3 V}\right) v_{r m s}^{2}\) \(\Rightarrow P=\dfrac{2}{3} E\) \(\Rightarrow P \propto E\) Correct option is (2).
KCET - 2023
PHXI13:KINETIC THEORY
360218
In an ideal gas at temperature \(T\), the average force that a molecule applies on the walls of a closed container depends on\(T\) as \({T^q}\). A good estimate for \(q\) is:
1 \(\dfrac{1}{2}\)
2 2
3 1
4 \(\dfrac{1}{4}\)
Explanation:
Pressure, \(P=\dfrac{1}{3} \dfrac{m N}{V} v_{r m s}^{2}\) \(P \propto\left(v_{r m s}\right)^{2} \propto T\) So, force \(\propto\left(v_{r m s}\right)^{2} \propto T\) i.e., Value of \(q = 1\)
JEE - 2015
PHXI13:KINETIC THEORY
360219
Relationship between \(P, V\) and \(E\) for a gas is ( \(E\) is the kinetic energy of the gas)
1 \(P V=\dfrac{3}{2} E\)
2 \(V=\dfrac{2}{3} E P\)
3 \(P=\dfrac{3}{2} E V\)
4 \(P V=\dfrac{2}{3} E\)
Explanation:
\(P V=\dfrac{1}{3} m N c^{2}=\dfrac{2}{3} N\left(\dfrac{1}{2} m c^{2}\right)\) \(P V=\dfrac{2}{3} E\)
PHXI13:KINETIC THEORY
360220
In outer space there are 10 molecules per \(c{m^3}\) on the average and the temperature there is \(3 K\). The average pressure of this light gas is
360217
Pressure of ideal gas at constant volume is proportional to
1 total energy of the gas
2 average kinetic energy of the molecules
3 force between the molecules
4 average potential energy of the molecules
Explanation:
\(P=\left(\dfrac{M}{3 V}\right) v_{r m s}^{2}\) \(\Rightarrow P=\dfrac{2}{3} E\) \(\Rightarrow P \propto E\) Correct option is (2).
KCET - 2023
PHXI13:KINETIC THEORY
360218
In an ideal gas at temperature \(T\), the average force that a molecule applies on the walls of a closed container depends on\(T\) as \({T^q}\). A good estimate for \(q\) is:
1 \(\dfrac{1}{2}\)
2 2
3 1
4 \(\dfrac{1}{4}\)
Explanation:
Pressure, \(P=\dfrac{1}{3} \dfrac{m N}{V} v_{r m s}^{2}\) \(P \propto\left(v_{r m s}\right)^{2} \propto T\) So, force \(\propto\left(v_{r m s}\right)^{2} \propto T\) i.e., Value of \(q = 1\)
JEE - 2015
PHXI13:KINETIC THEORY
360219
Relationship between \(P, V\) and \(E\) for a gas is ( \(E\) is the kinetic energy of the gas)
1 \(P V=\dfrac{3}{2} E\)
2 \(V=\dfrac{2}{3} E P\)
3 \(P=\dfrac{3}{2} E V\)
4 \(P V=\dfrac{2}{3} E\)
Explanation:
\(P V=\dfrac{1}{3} m N c^{2}=\dfrac{2}{3} N\left(\dfrac{1}{2} m c^{2}\right)\) \(P V=\dfrac{2}{3} E\)
PHXI13:KINETIC THEORY
360220
In outer space there are 10 molecules per \(c{m^3}\) on the average and the temperature there is \(3 K\). The average pressure of this light gas is
