Work
PHXI06:WORK ENERGY AND POWER

355804 Work done by a force \(F=(\hat{i}+2 \hat{j}+3 \hat{k}) N\) acting on a particle in displacing it from the point \(r_{1}=\hat{i}+\hat{j}+\hat{k}\) to the point \(r_{2}=\hat{i}-\hat{j}+2 \hat{k}\) is

1 \( - 3\,J\)
2 \( - 1\,J\)
3 zero
4 2 \(J\)
PHXI06:WORK ENERGY AND POWER

355805 In figure, shown all the surfaces are frictionless, and mass of the block is \(m=100 {~g}\). The block and the wedge are held initially at rest. Now the wedge is given a horizontal acceleration of \(10 {~m} {~s}^{-2}\) by applying a force on the wedge, so that the block does not slip on the wedge. Then find the work done in joules by the normal force in ground frame on the block in 1 \(s\) .
supporting img

1 \(1\,J\)
2 \(5\,J\)
3 \(3\,J\)
4 \(8\,J\)
PHXI06:WORK ENERGY AND POWER

355806 \(A\) force \((F) = - 5\hat i - 7\hat j + 3\hat k\) acting on a particle causes a displacement \((s) = 3\hat i - 2\hat j + a\hat k\) in its own direction. If the work done is 14 \(J\), then the value of ' \(a\) ' is

1 0
2 5
3 15
4 1
PHXI06:WORK ENERGY AND POWER

355807 The area of the acceleration-displacement curve of a body gives

1 Total change in energy
2 Change in KE per unit mass
3 Impulse
4 Change in momentum per unit mass
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXI06:WORK ENERGY AND POWER

355804 Work done by a force \(F=(\hat{i}+2 \hat{j}+3 \hat{k}) N\) acting on a particle in displacing it from the point \(r_{1}=\hat{i}+\hat{j}+\hat{k}\) to the point \(r_{2}=\hat{i}-\hat{j}+2 \hat{k}\) is

1 \( - 3\,J\)
2 \( - 1\,J\)
3 zero
4 2 \(J\)
PHXI06:WORK ENERGY AND POWER

355805 In figure, shown all the surfaces are frictionless, and mass of the block is \(m=100 {~g}\). The block and the wedge are held initially at rest. Now the wedge is given a horizontal acceleration of \(10 {~m} {~s}^{-2}\) by applying a force on the wedge, so that the block does not slip on the wedge. Then find the work done in joules by the normal force in ground frame on the block in 1 \(s\) .
supporting img

1 \(1\,J\)
2 \(5\,J\)
3 \(3\,J\)
4 \(8\,J\)
PHXI06:WORK ENERGY AND POWER

355806 \(A\) force \((F) = - 5\hat i - 7\hat j + 3\hat k\) acting on a particle causes a displacement \((s) = 3\hat i - 2\hat j + a\hat k\) in its own direction. If the work done is 14 \(J\), then the value of ' \(a\) ' is

1 0
2 5
3 15
4 1
PHXI06:WORK ENERGY AND POWER

355807 The area of the acceleration-displacement curve of a body gives

1 Total change in energy
2 Change in KE per unit mass
3 Impulse
4 Change in momentum per unit mass
PHXI06:WORK ENERGY AND POWER

355804 Work done by a force \(F=(\hat{i}+2 \hat{j}+3 \hat{k}) N\) acting on a particle in displacing it from the point \(r_{1}=\hat{i}+\hat{j}+\hat{k}\) to the point \(r_{2}=\hat{i}-\hat{j}+2 \hat{k}\) is

1 \( - 3\,J\)
2 \( - 1\,J\)
3 zero
4 2 \(J\)
PHXI06:WORK ENERGY AND POWER

355805 In figure, shown all the surfaces are frictionless, and mass of the block is \(m=100 {~g}\). The block and the wedge are held initially at rest. Now the wedge is given a horizontal acceleration of \(10 {~m} {~s}^{-2}\) by applying a force on the wedge, so that the block does not slip on the wedge. Then find the work done in joules by the normal force in ground frame on the block in 1 \(s\) .
supporting img

1 \(1\,J\)
2 \(5\,J\)
3 \(3\,J\)
4 \(8\,J\)
PHXI06:WORK ENERGY AND POWER

355806 \(A\) force \((F) = - 5\hat i - 7\hat j + 3\hat k\) acting on a particle causes a displacement \((s) = 3\hat i - 2\hat j + a\hat k\) in its own direction. If the work done is 14 \(J\), then the value of ' \(a\) ' is

1 0
2 5
3 15
4 1
PHXI06:WORK ENERGY AND POWER

355807 The area of the acceleration-displacement curve of a body gives

1 Total change in energy
2 Change in KE per unit mass
3 Impulse
4 Change in momentum per unit mass
PHXI06:WORK ENERGY AND POWER

355804 Work done by a force \(F=(\hat{i}+2 \hat{j}+3 \hat{k}) N\) acting on a particle in displacing it from the point \(r_{1}=\hat{i}+\hat{j}+\hat{k}\) to the point \(r_{2}=\hat{i}-\hat{j}+2 \hat{k}\) is

1 \( - 3\,J\)
2 \( - 1\,J\)
3 zero
4 2 \(J\)
PHXI06:WORK ENERGY AND POWER

355805 In figure, shown all the surfaces are frictionless, and mass of the block is \(m=100 {~g}\). The block and the wedge are held initially at rest. Now the wedge is given a horizontal acceleration of \(10 {~m} {~s}^{-2}\) by applying a force on the wedge, so that the block does not slip on the wedge. Then find the work done in joules by the normal force in ground frame on the block in 1 \(s\) .
supporting img

1 \(1\,J\)
2 \(5\,J\)
3 \(3\,J\)
4 \(8\,J\)
PHXI06:WORK ENERGY AND POWER

355806 \(A\) force \((F) = - 5\hat i - 7\hat j + 3\hat k\) acting on a particle causes a displacement \((s) = 3\hat i - 2\hat j + a\hat k\) in its own direction. If the work done is 14 \(J\), then the value of ' \(a\) ' is

1 0
2 5
3 15
4 1
PHXI06:WORK ENERGY AND POWER

355807 The area of the acceleration-displacement curve of a body gives

1 Total change in energy
2 Change in KE per unit mass
3 Impulse
4 Change in momentum per unit mass
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here