The Concept of Potential Energy
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
PHXI06:WORK ENERGY AND POWER

355572 The potential energy of a 1 \(kg\) particle free to move along the \(x\)-axis is given by \(V(x)=\left(\dfrac{x^{4}}{4}-\dfrac{x^{2}}{2}\right) J\). The total mechanical energy of the particle is 2\(J\). Then, the maximum speed (in \(m/s\)) is

1 \(3 / \sqrt{2}\)
2 2
3 \(\sqrt{2}\)
4 \(1 / \sqrt{2}\)
PHXI06:WORK ENERGY AND POWER

355573 The potential energy function (in \(J\) ) of a particle in a region of space is given as\(U=\left(2 x^{2}+3 y^{3}+2 z\right)\). Here \(x, y\) and \(z\) are in meter. The magnitude of \(x\)-component of force (in \(N\) ) acting on the particle at point \(P(1,2,3) m\) is

1 8
2 4
3 6
4 2
PHXI06:WORK ENERGY AND POWER

355574 The potential energy \(U\) in joule of a particle of mass 1 \(kg\) moving in \(x-y\) plane obeys the law \(U=3 x+4 y\), where \((x, y)\) are the co-ordinates of the particle in metre. If the particle is at rest at \((6,4)\) at time \(t=0\) then identify the wrong statement:

1 The particle has constant acceleration
2 The particle has zero acceleration
3 The speed of the particle when it crosses \(y\) - axis is 10 \(m/s\)
4 Co-ordinates of particle at \(t=1\) sec is (4,5,2)
PHXI06:WORK ENERGY AND POWER

355575 The potential energy function for the force between two atoms in a diatomic molecule is approximately given by \(U(x)=\dfrac{a}{x^{12}}-\dfrac{b}{x^{6}}\), where \(a\) and \(b\) are constants and \(x\) is the distance between the atoms. The dissociation energy of the molecule is \(D = \left[ {U(x = \infty ) - {U_{{\rm{at}}\,\,{\rm{equilibrium }}}}} \right],D\) is

1 \(\dfrac{b^{2}}{6 a}\)
2 \(\dfrac{b^{2}}{4 a}\)
3 \(\dfrac{b^{2}}{2 a}\)
4 \(\dfrac{b^{2}}{12 a}\)
PHXI06:WORK ENERGY AND POWER

355572 The potential energy of a 1 \(kg\) particle free to move along the \(x\)-axis is given by \(V(x)=\left(\dfrac{x^{4}}{4}-\dfrac{x^{2}}{2}\right) J\). The total mechanical energy of the particle is 2\(J\). Then, the maximum speed (in \(m/s\)) is

1 \(3 / \sqrt{2}\)
2 2
3 \(\sqrt{2}\)
4 \(1 / \sqrt{2}\)
PHXI06:WORK ENERGY AND POWER

355573 The potential energy function (in \(J\) ) of a particle in a region of space is given as\(U=\left(2 x^{2}+3 y^{3}+2 z\right)\). Here \(x, y\) and \(z\) are in meter. The magnitude of \(x\)-component of force (in \(N\) ) acting on the particle at point \(P(1,2,3) m\) is

1 8
2 4
3 6
4 2
PHXI06:WORK ENERGY AND POWER

355574 The potential energy \(U\) in joule of a particle of mass 1 \(kg\) moving in \(x-y\) plane obeys the law \(U=3 x+4 y\), where \((x, y)\) are the co-ordinates of the particle in metre. If the particle is at rest at \((6,4)\) at time \(t=0\) then identify the wrong statement:

1 The particle has constant acceleration
2 The particle has zero acceleration
3 The speed of the particle when it crosses \(y\) - axis is 10 \(m/s\)
4 Co-ordinates of particle at \(t=1\) sec is (4,5,2)
PHXI06:WORK ENERGY AND POWER

355575 The potential energy function for the force between two atoms in a diatomic molecule is approximately given by \(U(x)=\dfrac{a}{x^{12}}-\dfrac{b}{x^{6}}\), where \(a\) and \(b\) are constants and \(x\) is the distance between the atoms. The dissociation energy of the molecule is \(D = \left[ {U(x = \infty ) - {U_{{\rm{at}}\,\,{\rm{equilibrium }}}}} \right],D\) is

1 \(\dfrac{b^{2}}{6 a}\)
2 \(\dfrac{b^{2}}{4 a}\)
3 \(\dfrac{b^{2}}{2 a}\)
4 \(\dfrac{b^{2}}{12 a}\)
PHXI06:WORK ENERGY AND POWER

355572 The potential energy of a 1 \(kg\) particle free to move along the \(x\)-axis is given by \(V(x)=\left(\dfrac{x^{4}}{4}-\dfrac{x^{2}}{2}\right) J\). The total mechanical energy of the particle is 2\(J\). Then, the maximum speed (in \(m/s\)) is

1 \(3 / \sqrt{2}\)
2 2
3 \(\sqrt{2}\)
4 \(1 / \sqrt{2}\)
PHXI06:WORK ENERGY AND POWER

355573 The potential energy function (in \(J\) ) of a particle in a region of space is given as\(U=\left(2 x^{2}+3 y^{3}+2 z\right)\). Here \(x, y\) and \(z\) are in meter. The magnitude of \(x\)-component of force (in \(N\) ) acting on the particle at point \(P(1,2,3) m\) is

1 8
2 4
3 6
4 2
PHXI06:WORK ENERGY AND POWER

355574 The potential energy \(U\) in joule of a particle of mass 1 \(kg\) moving in \(x-y\) plane obeys the law \(U=3 x+4 y\), where \((x, y)\) are the co-ordinates of the particle in metre. If the particle is at rest at \((6,4)\) at time \(t=0\) then identify the wrong statement:

1 The particle has constant acceleration
2 The particle has zero acceleration
3 The speed of the particle when it crosses \(y\) - axis is 10 \(m/s\)
4 Co-ordinates of particle at \(t=1\) sec is (4,5,2)
PHXI06:WORK ENERGY AND POWER

355575 The potential energy function for the force between two atoms in a diatomic molecule is approximately given by \(U(x)=\dfrac{a}{x^{12}}-\dfrac{b}{x^{6}}\), where \(a\) and \(b\) are constants and \(x\) is the distance between the atoms. The dissociation energy of the molecule is \(D = \left[ {U(x = \infty ) - {U_{{\rm{at}}\,\,{\rm{equilibrium }}}}} \right],D\) is

1 \(\dfrac{b^{2}}{6 a}\)
2 \(\dfrac{b^{2}}{4 a}\)
3 \(\dfrac{b^{2}}{2 a}\)
4 \(\dfrac{b^{2}}{12 a}\)
PHXI06:WORK ENERGY AND POWER

355572 The potential energy of a 1 \(kg\) particle free to move along the \(x\)-axis is given by \(V(x)=\left(\dfrac{x^{4}}{4}-\dfrac{x^{2}}{2}\right) J\). The total mechanical energy of the particle is 2\(J\). Then, the maximum speed (in \(m/s\)) is

1 \(3 / \sqrt{2}\)
2 2
3 \(\sqrt{2}\)
4 \(1 / \sqrt{2}\)
PHXI06:WORK ENERGY AND POWER

355573 The potential energy function (in \(J\) ) of a particle in a region of space is given as\(U=\left(2 x^{2}+3 y^{3}+2 z\right)\). Here \(x, y\) and \(z\) are in meter. The magnitude of \(x\)-component of force (in \(N\) ) acting on the particle at point \(P(1,2,3) m\) is

1 8
2 4
3 6
4 2
PHXI06:WORK ENERGY AND POWER

355574 The potential energy \(U\) in joule of a particle of mass 1 \(kg\) moving in \(x-y\) plane obeys the law \(U=3 x+4 y\), where \((x, y)\) are the co-ordinates of the particle in metre. If the particle is at rest at \((6,4)\) at time \(t=0\) then identify the wrong statement:

1 The particle has constant acceleration
2 The particle has zero acceleration
3 The speed of the particle when it crosses \(y\) - axis is 10 \(m/s\)
4 Co-ordinates of particle at \(t=1\) sec is (4,5,2)
PHXI06:WORK ENERGY AND POWER

355575 The potential energy function for the force between two atoms in a diatomic molecule is approximately given by \(U(x)=\dfrac{a}{x^{12}}-\dfrac{b}{x^{6}}\), where \(a\) and \(b\) are constants and \(x\) is the distance between the atoms. The dissociation energy of the molecule is \(D = \left[ {U(x = \infty ) - {U_{{\rm{at}}\,\,{\rm{equilibrium }}}}} \right],D\) is

1 \(\dfrac{b^{2}}{6 a}\)
2 \(\dfrac{b^{2}}{4 a}\)
3 \(\dfrac{b^{2}}{2 a}\)
4 \(\dfrac{b^{2}}{12 a}\)