QBManager

PHXI06:WORK ENERGY AND POWER

355307 During inelastic collision between two bodies, which of the following quantities always remain conserved?

1 Total linear momentum

2 Speed of each body

3 Total kinetic energy

4 Total mechanical energy

NCERT Exemplar

PHXI06:WORK ENERGY AND POWER

355308 Assertion :
The principle of conservation of energy valid for inelastic collision.
Reason :
The principle of conservation of energy holds good in both elastic and inelastic collisions. In case of inelastic collision kinetic energy before and after collision is not same.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXI06:WORK ENERGY AND POWER

355309 Two identical mass $M$ moving with velocity $u_{1}$ and $u_{2}$ collide perfectly inelastically. The loss in energy is

1

\frac{M}{4} {(u_{2} - u_{1})}^{2}

2

\frac{M}{2} {(u_{2} - u_{1})}^{2}

3

\frac{M}{4} {(u_{1} - u_{2})}^{2}

4

\frac{M}{2} {(u_{1} - u_{2})}^{2}

Explanation:

$M u_{1} + M u_{2} = 2 M v$
$\begin{aligned} v & = \frac{M u_{1} + M u_{2}}{2 M} = \frac{u_{1} + u_{2}}{2} \\ K . E_{Loss} & = \frac{1}{2} M [u_{1}^{2} + u_{2}^{2}] - \frac{1}{2} (2 M) {(\frac{u_{1} + u_{2}}{2})}^{2} \\ = \frac{1}{2} M [u_{1}^{2} + u_{2}^{2} - \frac{{(u_{1} + u_{2})}^{2}}{2}] \\ = \frac{1}{4} M {[u_{1} - u_{2}]}^{2} \end{aligned}$

PHXI06:WORK ENERGY AND POWER

355310 Two bodies $A$ and $B$ of same mass undergo completely inelastic one dimensional collision. The body $A$ moves with velocity $v_{1}$ while body $B$ is at rest before collision. The velocity of the system after collision is $v_{2}$ . The ratio $v_{1} : v_{2}$ is

1

1 : 2

2

2 : 1

3

4 : 1

4

1 : 4

Explanation:

As the collision is completely inelastic so the bodies move with same velocity after collision Using conservation of linear momentum Initial momentum $=$ Final momentum
$\Rightarrow m v_{1} = m v_{2} + m v_{2}$
$\Rightarrow m v_{1} = 2 m v_{2}$
$\Rightarrow \frac{v_{1}}{v_{2}} = \frac{2}{1}$

NEET - 2024

PHXI06:WORK ENERGY AND POWER

355311 A metal ball of mass 2 $k g$ moving with speed of 36 $k m / h$ has a collision with a stationary balls of mass 3 $k g$ . If after collision, both the ball move together, the loss in kinetic energy due to collision is:

1 40

J

2 80

J

3 160

J

4 60

J

Explanation:

After collision the metal ball sticks with stationary ball, then the kinetic energy is lost in the form of heat,
From law of conservation of momentum,
$\begin{aligned} m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) v \\ \Rightarrow v = \frac{m_{1} u_{1} + m_{2} u_{2}}{(m_{1} + m_{2})} \end{aligned}$
Given,
$m_{1} = 2 k g, u_{1} = 36 \times \frac{5}{18} = 10 m / s,$
$m_{2} = 3 k g, u_{2} = 0$
$∴ v = \frac{2 \times 10 + 3 \times 0}{2 + 3} = 4 m / s$
Loss in kinetic energy is $Δ K = K_{i} - K_{f}$
$\begin{aligned} = {\frac{1}{2} m_{1} u_{1}^{2} + \frac{1}{2} m_{2} u_{2}^{2}} - {\frac{1}{2} (m_{1} + m_{2}) v^{2}} \\ = {\frac{1}{2} \times 2 \times (10)^{2} + \frac{1}{2} \times 3 \times (0)^{2}} - {\frac{1}{2} \times (2 + 3) (4)^{2}} \\ = 100 - 40 = 60 J \end{aligned}$

PHXI06:WORK ENERGY AND POWER

355307 During inelastic collision between two bodies, which of the following quantities always remain conserved?

1 Total linear momentum

2 Speed of each body

3 Total kinetic energy

4 Total mechanical energy

NCERT Exemplar

PHXI06:WORK ENERGY AND POWER

355308 Assertion :
The principle of conservation of energy valid for inelastic collision.
Reason :
The principle of conservation of energy holds good in both elastic and inelastic collisions. In case of inelastic collision kinetic energy before and after collision is not same.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXI06:WORK ENERGY AND POWER

355309 Two identical mass $M$ moving with velocity $u_{1}$ and $u_{2}$ collide perfectly inelastically. The loss in energy is

1

\frac{M}{4} {(u_{2} - u_{1})}^{2}

2

\frac{M}{2} {(u_{2} - u_{1})}^{2}

3

\frac{M}{4} {(u_{1} - u_{2})}^{2}

4

\frac{M}{2} {(u_{1} - u_{2})}^{2}

Explanation:

$M u_{1} + M u_{2} = 2 M v$
$\begin{aligned} v & = \frac{M u_{1} + M u_{2}}{2 M} = \frac{u_{1} + u_{2}}{2} \\ K . E_{Loss} & = \frac{1}{2} M [u_{1}^{2} + u_{2}^{2}] - \frac{1}{2} (2 M) {(\frac{u_{1} + u_{2}}{2})}^{2} \\ = \frac{1}{2} M [u_{1}^{2} + u_{2}^{2} - \frac{{(u_{1} + u_{2})}^{2}}{2}] \\ = \frac{1}{4} M {[u_{1} - u_{2}]}^{2} \end{aligned}$

PHXI06:WORK ENERGY AND POWER

355310 Two bodies $A$ and $B$ of same mass undergo completely inelastic one dimensional collision. The body $A$ moves with velocity $v_{1}$ while body $B$ is at rest before collision. The velocity of the system after collision is $v_{2}$ . The ratio $v_{1} : v_{2}$ is

1

1 : 2

2

2 : 1

3

4 : 1

4

1 : 4

Explanation:

As the collision is completely inelastic so the bodies move with same velocity after collision Using conservation of linear momentum Initial momentum $=$ Final momentum
$\Rightarrow m v_{1} = m v_{2} + m v_{2}$
$\Rightarrow m v_{1} = 2 m v_{2}$
$\Rightarrow \frac{v_{1}}{v_{2}} = \frac{2}{1}$

NEET - 2024

PHXI06:WORK ENERGY AND POWER

355311 A metal ball of mass 2 $k g$ moving with speed of 36 $k m / h$ has a collision with a stationary balls of mass 3 $k g$ . If after collision, both the ball move together, the loss in kinetic energy due to collision is:

1 40

J

2 80

J

3 160

J

4 60

J

Explanation:

After collision the metal ball sticks with stationary ball, then the kinetic energy is lost in the form of heat,
From law of conservation of momentum,
$\begin{aligned} m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) v \\ \Rightarrow v = \frac{m_{1} u_{1} + m_{2} u_{2}}{(m_{1} + m_{2})} \end{aligned}$
Given,
$m_{1} = 2 k g, u_{1} = 36 \times \frac{5}{18} = 10 m / s,$
$m_{2} = 3 k g, u_{2} = 0$
$∴ v = \frac{2 \times 10 + 3 \times 0}{2 + 3} = 4 m / s$
Loss in kinetic energy is $Δ K = K_{i} - K_{f}$
$\begin{aligned} = {\frac{1}{2} m_{1} u_{1}^{2} + \frac{1}{2} m_{2} u_{2}^{2}} - {\frac{1}{2} (m_{1} + m_{2}) v^{2}} \\ = {\frac{1}{2} \times 2 \times (10)^{2} + \frac{1}{2} \times 3 \times (0)^{2}} - {\frac{1}{2} \times (2 + 3) (4)^{2}} \\ = 100 - 40 = 60 J \end{aligned}$

PHXI06:WORK ENERGY AND POWER

355307 During inelastic collision between two bodies, which of the following quantities always remain conserved?

1 Total linear momentum

2 Speed of each body

3 Total kinetic energy

4 Total mechanical energy

NCERT Exemplar

PHXI06:WORK ENERGY AND POWER

355308 Assertion :
The principle of conservation of energy valid for inelastic collision.
Reason :
The principle of conservation of energy holds good in both elastic and inelastic collisions. In case of inelastic collision kinetic energy before and after collision is not same.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXI06:WORK ENERGY AND POWER

355309 Two identical mass $M$ moving with velocity $u_{1}$ and $u_{2}$ collide perfectly inelastically. The loss in energy is

1

\frac{M}{4} {(u_{2} - u_{1})}^{2}

2

\frac{M}{2} {(u_{2} - u_{1})}^{2}

3

\frac{M}{4} {(u_{1} - u_{2})}^{2}

4

\frac{M}{2} {(u_{1} - u_{2})}^{2}

Explanation:

$M u_{1} + M u_{2} = 2 M v$
$\begin{aligned} v & = \frac{M u_{1} + M u_{2}}{2 M} = \frac{u_{1} + u_{2}}{2} \\ K . E_{Loss} & = \frac{1}{2} M [u_{1}^{2} + u_{2}^{2}] - \frac{1}{2} (2 M) {(\frac{u_{1} + u_{2}}{2})}^{2} \\ = \frac{1}{2} M [u_{1}^{2} + u_{2}^{2} - \frac{{(u_{1} + u_{2})}^{2}}{2}] \\ = \frac{1}{4} M {[u_{1} - u_{2}]}^{2} \end{aligned}$

PHXI06:WORK ENERGY AND POWER

355310 Two bodies $A$ and $B$ of same mass undergo completely inelastic one dimensional collision. The body $A$ moves with velocity $v_{1}$ while body $B$ is at rest before collision. The velocity of the system after collision is $v_{2}$ . The ratio $v_{1} : v_{2}$ is

1

1 : 2

2

2 : 1

3

4 : 1

4

1 : 4

Explanation:

As the collision is completely inelastic so the bodies move with same velocity after collision Using conservation of linear momentum Initial momentum $=$ Final momentum
$\Rightarrow m v_{1} = m v_{2} + m v_{2}$
$\Rightarrow m v_{1} = 2 m v_{2}$
$\Rightarrow \frac{v_{1}}{v_{2}} = \frac{2}{1}$

NEET - 2024

PHXI06:WORK ENERGY AND POWER

355311 A metal ball of mass 2 $k g$ moving with speed of 36 $k m / h$ has a collision with a stationary balls of mass 3 $k g$ . If after collision, both the ball move together, the loss in kinetic energy due to collision is:

1 40

J

2 80

J

3 160

J

4 60

J

Explanation:

After collision the metal ball sticks with stationary ball, then the kinetic energy is lost in the form of heat,
From law of conservation of momentum,
$\begin{aligned} m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) v \\ \Rightarrow v = \frac{m_{1} u_{1} + m_{2} u_{2}}{(m_{1} + m_{2})} \end{aligned}$
Given,
$m_{1} = 2 k g, u_{1} = 36 \times \frac{5}{18} = 10 m / s,$
$m_{2} = 3 k g, u_{2} = 0$
$∴ v = \frac{2 \times 10 + 3 \times 0}{2 + 3} = 4 m / s$
Loss in kinetic energy is $Δ K = K_{i} - K_{f}$
$\begin{aligned} = {\frac{1}{2} m_{1} u_{1}^{2} + \frac{1}{2} m_{2} u_{2}^{2}} - {\frac{1}{2} (m_{1} + m_{2}) v^{2}} \\ = {\frac{1}{2} \times 2 \times (10)^{2} + \frac{1}{2} \times 3 \times (0)^{2}} - {\frac{1}{2} \times (2 + 3) (4)^{2}} \\ = 100 - 40 = 60 J \end{aligned}$

PHXI06:WORK ENERGY AND POWER

355307 During inelastic collision between two bodies, which of the following quantities always remain conserved?

1 Total linear momentum

2 Speed of each body

3 Total kinetic energy

4 Total mechanical energy

NCERT Exemplar

PHXI06:WORK ENERGY AND POWER

355308 Assertion :
The principle of conservation of energy valid for inelastic collision.
Reason :
The principle of conservation of energy holds good in both elastic and inelastic collisions. In case of inelastic collision kinetic energy before and after collision is not same.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXI06:WORK ENERGY AND POWER

355309 Two identical mass $M$ moving with velocity $u_{1}$ and $u_{2}$ collide perfectly inelastically. The loss in energy is

1

\frac{M}{4} {(u_{2} - u_{1})}^{2}

2

\frac{M}{2} {(u_{2} - u_{1})}^{2}

3

\frac{M}{4} {(u_{1} - u_{2})}^{2}

4

\frac{M}{2} {(u_{1} - u_{2})}^{2}

Explanation:

$M u_{1} + M u_{2} = 2 M v$
$\begin{aligned} v & = \frac{M u_{1} + M u_{2}}{2 M} = \frac{u_{1} + u_{2}}{2} \\ K . E_{Loss} & = \frac{1}{2} M [u_{1}^{2} + u_{2}^{2}] - \frac{1}{2} (2 M) {(\frac{u_{1} + u_{2}}{2})}^{2} \\ = \frac{1}{2} M [u_{1}^{2} + u_{2}^{2} - \frac{{(u_{1} + u_{2})}^{2}}{2}] \\ = \frac{1}{4} M {[u_{1} - u_{2}]}^{2} \end{aligned}$

PHXI06:WORK ENERGY AND POWER

355310 Two bodies $A$ and $B$ of same mass undergo completely inelastic one dimensional collision. The body $A$ moves with velocity $v_{1}$ while body $B$ is at rest before collision. The velocity of the system after collision is $v_{2}$ . The ratio $v_{1} : v_{2}$ is

1

1 : 2

2

2 : 1

3

4 : 1

4

1 : 4

Explanation:

As the collision is completely inelastic so the bodies move with same velocity after collision Using conservation of linear momentum Initial momentum $=$ Final momentum
$\Rightarrow m v_{1} = m v_{2} + m v_{2}$
$\Rightarrow m v_{1} = 2 m v_{2}$
$\Rightarrow \frac{v_{1}}{v_{2}} = \frac{2}{1}$

NEET - 2024

PHXI06:WORK ENERGY AND POWER

355311 A metal ball of mass 2 $k g$ moving with speed of 36 $k m / h$ has a collision with a stationary balls of mass 3 $k g$ . If after collision, both the ball move together, the loss in kinetic energy due to collision is:

1 40

J

2 80

J

3 160

J

4 60

J

Explanation:

After collision the metal ball sticks with stationary ball, then the kinetic energy is lost in the form of heat,
From law of conservation of momentum,
$\begin{aligned} m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) v \\ \Rightarrow v = \frac{m_{1} u_{1} + m_{2} u_{2}}{(m_{1} + m_{2})} \end{aligned}$
Given,
$m_{1} = 2 k g, u_{1} = 36 \times \frac{5}{18} = 10 m / s,$
$m_{2} = 3 k g, u_{2} = 0$
$∴ v = \frac{2 \times 10 + 3 \times 0}{2 + 3} = 4 m / s$
Loss in kinetic energy is $Δ K = K_{i} - K_{f}$
$\begin{aligned} = {\frac{1}{2} m_{1} u_{1}^{2} + \frac{1}{2} m_{2} u_{2}^{2}} - {\frac{1}{2} (m_{1} + m_{2}) v^{2}} \\ = {\frac{1}{2} \times 2 \times (10)^{2} + \frac{1}{2} \times 3 \times (0)^{2}} - {\frac{1}{2} \times (2 + 3) (4)^{2}} \\ = 100 - 40 = 60 J \end{aligned}$

PHXI06:WORK ENERGY AND POWER

355307 During inelastic collision between two bodies, which of the following quantities always remain conserved?

1 Total linear momentum

2 Speed of each body

3 Total kinetic energy

4 Total mechanical energy

NCERT Exemplar

PHXI06:WORK ENERGY AND POWER

355308 Assertion :
The principle of conservation of energy valid for inelastic collision.
Reason :
The principle of conservation of energy holds good in both elastic and inelastic collisions. In case of inelastic collision kinetic energy before and after collision is not same.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

PHXI06:WORK ENERGY AND POWER

355309 Two identical mass $M$ moving with velocity $u_{1}$ and $u_{2}$ collide perfectly inelastically. The loss in energy is

1

\frac{M}{4} {(u_{2} - u_{1})}^{2}

2

\frac{M}{2} {(u_{2} - u_{1})}^{2}

3

\frac{M}{4} {(u_{1} - u_{2})}^{2}

4

\frac{M}{2} {(u_{1} - u_{2})}^{2}

Explanation:

$M u_{1} + M u_{2} = 2 M v$
$\begin{aligned} v & = \frac{M u_{1} + M u_{2}}{2 M} = \frac{u_{1} + u_{2}}{2} \\ K . E_{Loss} & = \frac{1}{2} M [u_{1}^{2} + u_{2}^{2}] - \frac{1}{2} (2 M) {(\frac{u_{1} + u_{2}}{2})}^{2} \\ = \frac{1}{2} M [u_{1}^{2} + u_{2}^{2} - \frac{{(u_{1} + u_{2})}^{2}}{2}] \\ = \frac{1}{4} M {[u_{1} - u_{2}]}^{2} \end{aligned}$

PHXI06:WORK ENERGY AND POWER

355310 Two bodies $A$ and $B$ of same mass undergo completely inelastic one dimensional collision. The body $A$ moves with velocity $v_{1}$ while body $B$ is at rest before collision. The velocity of the system after collision is $v_{2}$ . The ratio $v_{1} : v_{2}$ is

1

1 : 2

2

2 : 1

3

4 : 1

4

1 : 4

Explanation:

As the collision is completely inelastic so the bodies move with same velocity after collision Using conservation of linear momentum Initial momentum $=$ Final momentum
$\Rightarrow m v_{1} = m v_{2} + m v_{2}$
$\Rightarrow m v_{1} = 2 m v_{2}$
$\Rightarrow \frac{v_{1}}{v_{2}} = \frac{2}{1}$

NEET - 2024

PHXI06:WORK ENERGY AND POWER

355311 A metal ball of mass 2 $k g$ moving with speed of 36 $k m / h$ has a collision with a stationary balls of mass 3 $k g$ . If after collision, both the ball move together, the loss in kinetic energy due to collision is:

1 40

J

2 80

J

3 160

J

4 60

J

Explanation:

After collision the metal ball sticks with stationary ball, then the kinetic energy is lost in the form of heat,
From law of conservation of momentum,
$\begin{aligned} m_{1} u_{1} + m_{2} u_{2} = (m_{1} + m_{2}) v \\ \Rightarrow v = \frac{m_{1} u_{1} + m_{2} u_{2}}{(m_{1} + m_{2})} \end{aligned}$
Given,
$m_{1} = 2 k g, u_{1} = 36 \times \frac{5}{18} = 10 m / s,$
$m_{2} = 3 k g, u_{2} = 0$
$∴ v = \frac{2 \times 10 + 3 \times 0}{2 + 3} = 4 m / s$
Loss in kinetic energy is $Δ K = K_{i} - K_{f}$
$\begin{aligned} = {\frac{1}{2} m_{1} u_{1}^{2} + \frac{1}{2} m_{2} u_{2}^{2}} - {\frac{1}{2} (m_{1} + m_{2}) v^{2}} \\ = {\frac{1}{2} \times 2 \times (10)^{2} + \frac{1}{2} \times 3 \times (0)^{2}} - {\frac{1}{2} \times (2 + 3) (4)^{2}} \\ = 100 - 40 = 60 J \end{aligned}$

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Question Bank Series

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation:

Explanation: