355037
Two open pipes of length \(50\;cm\) and \(51\;cm\) produce 6 beats when sounded together, find the speed of sound.
1 \(316\;m{s^{ - 1}}\)
2 \(330\;m{s^{ - 1}}\)
3 \(360\;m{s^{ - 1}}\)
4 \(306\;m{s^{ - 1}}\)
Explanation:
\(f_{1}-f_{2}=6\) or \(\dfrac{v}{2 l_{1}}-\dfrac{v}{2 l_{2}}=6\) \(\frac{v}{{2(0.5)}} - \frac{v}{{2(0.51)}} = 6{\text{ or }}v = 306\;m{s^{ - 1}}.\)
PHXI15:WAVES
355038
A fork \(A\) has frequency \(2 \%\) more than the standard fork and \(B\) has a frequency \(3 \%\) less than the frequency of same standard fork. The forks \(A\) and \(B\) when sounded together produced 6 beats/s. The frequency of fork \(A\) is
1 \(116.4\;Hz\)
2 \(120\;Hz\)
3 \(122.4\;Hz\)
4 \(238.8\;Hz\)
Explanation:
The frequency of \(A\), \(n_{A}=n+\dfrac{2}{100} n\) and the frequency of \(B\), \(n_{B}=n-\dfrac{3}{100} n\) According to the question, \({n_A} - {n_B} = 6\) \( \Rightarrow \left( {n + \frac{2}{{100}}n} \right) - \left( {n - \frac{3}{{100}}n} \right) = 6\) \( \Rightarrow \frac{5}{{100}}n = 6\) \( \Rightarrow n = \frac{{600}}{5} = 120\;Hz\) The frequency of \(A\) \({n_A} = \left( {n + \frac{2}{{100}}n} \right)\) \( = 120 + \frac{2}{{100}} \times 120\) \( = 122.4\;Hz\)
AIIMS - 2010
PHXI15:WAVES
355039
A tuning fork having frequency \(500\;Hz\) produces 4 beats/sec with sitar wire. If we decrease tension in the wire it becomes unison with tuning fork. The frequency of the wire before change is :
1 \(504\;Hz\)
2 \(498\;Hz\)
3 \(496\;Hz\)
4 \(500\;Hz\)
Explanation:
Decrease in tension decreases the frequency of wire. The frequency of the wire initially is \(504 \mathrm{~Hz}\).
PHXI15:WAVES
355040
Beat phenomenon is physically meaningful only, if
355041
Two wires are producing fundamental notes of same frequency. The change in which of the following factors of one wire does not produce beats between them
355037
Two open pipes of length \(50\;cm\) and \(51\;cm\) produce 6 beats when sounded together, find the speed of sound.
1 \(316\;m{s^{ - 1}}\)
2 \(330\;m{s^{ - 1}}\)
3 \(360\;m{s^{ - 1}}\)
4 \(306\;m{s^{ - 1}}\)
Explanation:
\(f_{1}-f_{2}=6\) or \(\dfrac{v}{2 l_{1}}-\dfrac{v}{2 l_{2}}=6\) \(\frac{v}{{2(0.5)}} - \frac{v}{{2(0.51)}} = 6{\text{ or }}v = 306\;m{s^{ - 1}}.\)
PHXI15:WAVES
355038
A fork \(A\) has frequency \(2 \%\) more than the standard fork and \(B\) has a frequency \(3 \%\) less than the frequency of same standard fork. The forks \(A\) and \(B\) when sounded together produced 6 beats/s. The frequency of fork \(A\) is
1 \(116.4\;Hz\)
2 \(120\;Hz\)
3 \(122.4\;Hz\)
4 \(238.8\;Hz\)
Explanation:
The frequency of \(A\), \(n_{A}=n+\dfrac{2}{100} n\) and the frequency of \(B\), \(n_{B}=n-\dfrac{3}{100} n\) According to the question, \({n_A} - {n_B} = 6\) \( \Rightarrow \left( {n + \frac{2}{{100}}n} \right) - \left( {n - \frac{3}{{100}}n} \right) = 6\) \( \Rightarrow \frac{5}{{100}}n = 6\) \( \Rightarrow n = \frac{{600}}{5} = 120\;Hz\) The frequency of \(A\) \({n_A} = \left( {n + \frac{2}{{100}}n} \right)\) \( = 120 + \frac{2}{{100}} \times 120\) \( = 122.4\;Hz\)
AIIMS - 2010
PHXI15:WAVES
355039
A tuning fork having frequency \(500\;Hz\) produces 4 beats/sec with sitar wire. If we decrease tension in the wire it becomes unison with tuning fork. The frequency of the wire before change is :
1 \(504\;Hz\)
2 \(498\;Hz\)
3 \(496\;Hz\)
4 \(500\;Hz\)
Explanation:
Decrease in tension decreases the frequency of wire. The frequency of the wire initially is \(504 \mathrm{~Hz}\).
PHXI15:WAVES
355040
Beat phenomenon is physically meaningful only, if
355041
Two wires are producing fundamental notes of same frequency. The change in which of the following factors of one wire does not produce beats between them
355037
Two open pipes of length \(50\;cm\) and \(51\;cm\) produce 6 beats when sounded together, find the speed of sound.
1 \(316\;m{s^{ - 1}}\)
2 \(330\;m{s^{ - 1}}\)
3 \(360\;m{s^{ - 1}}\)
4 \(306\;m{s^{ - 1}}\)
Explanation:
\(f_{1}-f_{2}=6\) or \(\dfrac{v}{2 l_{1}}-\dfrac{v}{2 l_{2}}=6\) \(\frac{v}{{2(0.5)}} - \frac{v}{{2(0.51)}} = 6{\text{ or }}v = 306\;m{s^{ - 1}}.\)
PHXI15:WAVES
355038
A fork \(A\) has frequency \(2 \%\) more than the standard fork and \(B\) has a frequency \(3 \%\) less than the frequency of same standard fork. The forks \(A\) and \(B\) when sounded together produced 6 beats/s. The frequency of fork \(A\) is
1 \(116.4\;Hz\)
2 \(120\;Hz\)
3 \(122.4\;Hz\)
4 \(238.8\;Hz\)
Explanation:
The frequency of \(A\), \(n_{A}=n+\dfrac{2}{100} n\) and the frequency of \(B\), \(n_{B}=n-\dfrac{3}{100} n\) According to the question, \({n_A} - {n_B} = 6\) \( \Rightarrow \left( {n + \frac{2}{{100}}n} \right) - \left( {n - \frac{3}{{100}}n} \right) = 6\) \( \Rightarrow \frac{5}{{100}}n = 6\) \( \Rightarrow n = \frac{{600}}{5} = 120\;Hz\) The frequency of \(A\) \({n_A} = \left( {n + \frac{2}{{100}}n} \right)\) \( = 120 + \frac{2}{{100}} \times 120\) \( = 122.4\;Hz\)
AIIMS - 2010
PHXI15:WAVES
355039
A tuning fork having frequency \(500\;Hz\) produces 4 beats/sec with sitar wire. If we decrease tension in the wire it becomes unison with tuning fork. The frequency of the wire before change is :
1 \(504\;Hz\)
2 \(498\;Hz\)
3 \(496\;Hz\)
4 \(500\;Hz\)
Explanation:
Decrease in tension decreases the frequency of wire. The frequency of the wire initially is \(504 \mathrm{~Hz}\).
PHXI15:WAVES
355040
Beat phenomenon is physically meaningful only, if
355041
Two wires are producing fundamental notes of same frequency. The change in which of the following factors of one wire does not produce beats between them
NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXI15:WAVES
355037
Two open pipes of length \(50\;cm\) and \(51\;cm\) produce 6 beats when sounded together, find the speed of sound.
1 \(316\;m{s^{ - 1}}\)
2 \(330\;m{s^{ - 1}}\)
3 \(360\;m{s^{ - 1}}\)
4 \(306\;m{s^{ - 1}}\)
Explanation:
\(f_{1}-f_{2}=6\) or \(\dfrac{v}{2 l_{1}}-\dfrac{v}{2 l_{2}}=6\) \(\frac{v}{{2(0.5)}} - \frac{v}{{2(0.51)}} = 6{\text{ or }}v = 306\;m{s^{ - 1}}.\)
PHXI15:WAVES
355038
A fork \(A\) has frequency \(2 \%\) more than the standard fork and \(B\) has a frequency \(3 \%\) less than the frequency of same standard fork. The forks \(A\) and \(B\) when sounded together produced 6 beats/s. The frequency of fork \(A\) is
1 \(116.4\;Hz\)
2 \(120\;Hz\)
3 \(122.4\;Hz\)
4 \(238.8\;Hz\)
Explanation:
The frequency of \(A\), \(n_{A}=n+\dfrac{2}{100} n\) and the frequency of \(B\), \(n_{B}=n-\dfrac{3}{100} n\) According to the question, \({n_A} - {n_B} = 6\) \( \Rightarrow \left( {n + \frac{2}{{100}}n} \right) - \left( {n - \frac{3}{{100}}n} \right) = 6\) \( \Rightarrow \frac{5}{{100}}n = 6\) \( \Rightarrow n = \frac{{600}}{5} = 120\;Hz\) The frequency of \(A\) \({n_A} = \left( {n + \frac{2}{{100}}n} \right)\) \( = 120 + \frac{2}{{100}} \times 120\) \( = 122.4\;Hz\)
AIIMS - 2010
PHXI15:WAVES
355039
A tuning fork having frequency \(500\;Hz\) produces 4 beats/sec with sitar wire. If we decrease tension in the wire it becomes unison with tuning fork. The frequency of the wire before change is :
1 \(504\;Hz\)
2 \(498\;Hz\)
3 \(496\;Hz\)
4 \(500\;Hz\)
Explanation:
Decrease in tension decreases the frequency of wire. The frequency of the wire initially is \(504 \mathrm{~Hz}\).
PHXI15:WAVES
355040
Beat phenomenon is physically meaningful only, if
355041
Two wires are producing fundamental notes of same frequency. The change in which of the following factors of one wire does not produce beats between them
355037
Two open pipes of length \(50\;cm\) and \(51\;cm\) produce 6 beats when sounded together, find the speed of sound.
1 \(316\;m{s^{ - 1}}\)
2 \(330\;m{s^{ - 1}}\)
3 \(360\;m{s^{ - 1}}\)
4 \(306\;m{s^{ - 1}}\)
Explanation:
\(f_{1}-f_{2}=6\) or \(\dfrac{v}{2 l_{1}}-\dfrac{v}{2 l_{2}}=6\) \(\frac{v}{{2(0.5)}} - \frac{v}{{2(0.51)}} = 6{\text{ or }}v = 306\;m{s^{ - 1}}.\)
PHXI15:WAVES
355038
A fork \(A\) has frequency \(2 \%\) more than the standard fork and \(B\) has a frequency \(3 \%\) less than the frequency of same standard fork. The forks \(A\) and \(B\) when sounded together produced 6 beats/s. The frequency of fork \(A\) is
1 \(116.4\;Hz\)
2 \(120\;Hz\)
3 \(122.4\;Hz\)
4 \(238.8\;Hz\)
Explanation:
The frequency of \(A\), \(n_{A}=n+\dfrac{2}{100} n\) and the frequency of \(B\), \(n_{B}=n-\dfrac{3}{100} n\) According to the question, \({n_A} - {n_B} = 6\) \( \Rightarrow \left( {n + \frac{2}{{100}}n} \right) - \left( {n - \frac{3}{{100}}n} \right) = 6\) \( \Rightarrow \frac{5}{{100}}n = 6\) \( \Rightarrow n = \frac{{600}}{5} = 120\;Hz\) The frequency of \(A\) \({n_A} = \left( {n + \frac{2}{{100}}n} \right)\) \( = 120 + \frac{2}{{100}} \times 120\) \( = 122.4\;Hz\)
AIIMS - 2010
PHXI15:WAVES
355039
A tuning fork having frequency \(500\;Hz\) produces 4 beats/sec with sitar wire. If we decrease tension in the wire it becomes unison with tuning fork. The frequency of the wire before change is :
1 \(504\;Hz\)
2 \(498\;Hz\)
3 \(496\;Hz\)
4 \(500\;Hz\)
Explanation:
Decrease in tension decreases the frequency of wire. The frequency of the wire initially is \(504 \mathrm{~Hz}\).
PHXI15:WAVES
355040
Beat phenomenon is physically meaningful only, if
355041
Two wires are producing fundamental notes of same frequency. The change in which of the following factors of one wire does not produce beats between them