QBManager

PHXI15:WAVES

355029 Phenomenon of beats can take place

1 For transverse waves only

2 For longitudinal waves only

3 For sound waves only

4 For both longitudinal and transverse

PHXI15:WAVES

355030 Assertion :
Where two vibrating tuning forks having frequencies $256 H z$ and $512 H z$ are held near each other, beats cannot be heard.
Reason :
The principle of superposition is valid only if the frequencies of the oscillators are nearly equal.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

Beats will not be heard when the frequencies of the tuning forks are $256 H z$ and $512 H z$ because they are not close enough in frequency for distinct beats to form. However, the reason is false because the principle of superposition is valid for a wide range of frequency differences. So correct option is (3).

PHXI15:WAVES

355031 When a guitar string is sounded with a $440 H z$ tunning fork, a beat frequency of $5 H z$ is heard. If the experiment is repeated with a tuning fork of $437 H z$ , the beat frequency is $8 H z$ . The string frequency $(H z)$ is :

1 435

2 445

3 448

4 429

Explanation:

When 5 Beats are heard with $440 H z$ then guitar may have $435 H z$ or $445 H z$ frequency for 2nd tuning fork of $437 H z$ is used and 8 beats are heard this condition is satisfied if guitar's frequency is $445 H z$ .

PHXI15:WAVES

355032 5 beats/s are produced on blowing together two closed organ pipes of the same diameter but of different lengths. If shorter pipe is of $10 c m$ length and speed of sound in air is $300 m / s$ , length of other pipe is

1

10.06 c m

2

11.22 c m

3

16 c m

4

14 c m

Explanation:

We know that,
$m = n_{1} - n_{2} = \frac{v}{4} [\frac{1}{l_{1}} - \frac{1}{l_{2}}]$
$v = 300 m / s = 300 c m / s$
$\Rightarrow \frac{1}{l_{1}} - \frac{1}{l_{2}} = \frac{20}{300 \times 100} = \frac{1}{1500}$
$\frac{1}{l_{2}} = \frac{1}{10} - \frac{1}{1500} \Rightarrow \frac{149}{1500}$
$\Rightarrow l_{2} = \frac{1500}{149} = 10.06 c m .$

PHXI15:WAVES

355029 Phenomenon of beats can take place

1 For transverse waves only

2 For longitudinal waves only

3 For sound waves only

4 For both longitudinal and transverse

PHXI15:WAVES

355030 Assertion :
Where two vibrating tuning forks having frequencies $256 H z$ and $512 H z$ are held near each other, beats cannot be heard.
Reason :
The principle of superposition is valid only if the frequencies of the oscillators are nearly equal.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

Beats will not be heard when the frequencies of the tuning forks are $256 H z$ and $512 H z$ because they are not close enough in frequency for distinct beats to form. However, the reason is false because the principle of superposition is valid for a wide range of frequency differences. So correct option is (3).

PHXI15:WAVES

355031 When a guitar string is sounded with a $440 H z$ tunning fork, a beat frequency of $5 H z$ is heard. If the experiment is repeated with a tuning fork of $437 H z$ , the beat frequency is $8 H z$ . The string frequency $(H z)$ is :

1 435

2 445

3 448

4 429

Explanation:

When 5 Beats are heard with $440 H z$ then guitar may have $435 H z$ or $445 H z$ frequency for 2nd tuning fork of $437 H z$ is used and 8 beats are heard this condition is satisfied if guitar's frequency is $445 H z$ .

PHXI15:WAVES

355032 5 beats/s are produced on blowing together two closed organ pipes of the same diameter but of different lengths. If shorter pipe is of $10 c m$ length and speed of sound in air is $300 m / s$ , length of other pipe is

1

10.06 c m

2

11.22 c m

3

16 c m

4

14 c m

Explanation:

We know that,
$m = n_{1} - n_{2} = \frac{v}{4} [\frac{1}{l_{1}} - \frac{1}{l_{2}}]$
$v = 300 m / s = 300 c m / s$
$\Rightarrow \frac{1}{l_{1}} - \frac{1}{l_{2}} = \frac{20}{300 \times 100} = \frac{1}{1500}$
$\frac{1}{l_{2}} = \frac{1}{10} - \frac{1}{1500} \Rightarrow \frac{149}{1500}$
$\Rightarrow l_{2} = \frac{1500}{149} = 10.06 c m .$

PHXI15:WAVES

355029 Phenomenon of beats can take place

1 For transverse waves only

2 For longitudinal waves only

3 For sound waves only

4 For both longitudinal and transverse

PHXI15:WAVES

355030 Assertion :
Where two vibrating tuning forks having frequencies $256 H z$ and $512 H z$ are held near each other, beats cannot be heard.
Reason :
The principle of superposition is valid only if the frequencies of the oscillators are nearly equal.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

Beats will not be heard when the frequencies of the tuning forks are $256 H z$ and $512 H z$ because they are not close enough in frequency for distinct beats to form. However, the reason is false because the principle of superposition is valid for a wide range of frequency differences. So correct option is (3).

PHXI15:WAVES

355031 When a guitar string is sounded with a $440 H z$ tunning fork, a beat frequency of $5 H z$ is heard. If the experiment is repeated with a tuning fork of $437 H z$ , the beat frequency is $8 H z$ . The string frequency $(H z)$ is :

1 435

2 445

3 448

4 429

Explanation:

When 5 Beats are heard with $440 H z$ then guitar may have $435 H z$ or $445 H z$ frequency for 2nd tuning fork of $437 H z$ is used and 8 beats are heard this condition is satisfied if guitar's frequency is $445 H z$ .

PHXI15:WAVES

355032 5 beats/s are produced on blowing together two closed organ pipes of the same diameter but of different lengths. If shorter pipe is of $10 c m$ length and speed of sound in air is $300 m / s$ , length of other pipe is

1

10.06 c m

2

11.22 c m

3

16 c m

4

14 c m

Explanation:

We know that,
$m = n_{1} - n_{2} = \frac{v}{4} [\frac{1}{l_{1}} - \frac{1}{l_{2}}]$
$v = 300 m / s = 300 c m / s$
$\Rightarrow \frac{1}{l_{1}} - \frac{1}{l_{2}} = \frac{20}{300 \times 100} = \frac{1}{1500}$
$\frac{1}{l_{2}} = \frac{1}{10} - \frac{1}{1500} \Rightarrow \frac{149}{1500}$
$\Rightarrow l_{2} = \frac{1500}{149} = 10.06 c m .$

PHXI15:WAVES

355029 Phenomenon of beats can take place

1 For transverse waves only

2 For longitudinal waves only

3 For sound waves only

4 For both longitudinal and transverse

PHXI15:WAVES

355030 Assertion :
Where two vibrating tuning forks having frequencies $256 H z$ and $512 H z$ are held near each other, beats cannot be heard.
Reason :
The principle of superposition is valid only if the frequencies of the oscillators are nearly equal.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but reason is correct.

Explanation:

Beats will not be heard when the frequencies of the tuning forks are $256 H z$ and $512 H z$ because they are not close enough in frequency for distinct beats to form. However, the reason is false because the principle of superposition is valid for a wide range of frequency differences. So correct option is (3).

PHXI15:WAVES

355031 When a guitar string is sounded with a $440 H z$ tunning fork, a beat frequency of $5 H z$ is heard. If the experiment is repeated with a tuning fork of $437 H z$ , the beat frequency is $8 H z$ . The string frequency $(H z)$ is :

1 435

2 445

3 448

4 429

Explanation:

When 5 Beats are heard with $440 H z$ then guitar may have $435 H z$ or $445 H z$ frequency for 2nd tuning fork of $437 H z$ is used and 8 beats are heard this condition is satisfied if guitar's frequency is $445 H z$ .

PHXI15:WAVES

355032 5 beats/s are produced on blowing together two closed organ pipes of the same diameter but of different lengths. If shorter pipe is of $10 c m$ length and speed of sound in air is $300 m / s$ , length of other pipe is

1

10.06 c m

2

11.22 c m

3

16 c m

4

14 c m

Explanation:

We know that,
$m = n_{1} - n_{2} = \frac{v}{4} [\frac{1}{l_{1}} - \frac{1}{l_{2}}]$
$v = 300 m / s = 300 c m / s$
$\Rightarrow \frac{1}{l_{1}} - \frac{1}{l_{2}} = \frac{20}{300 \times 100} = \frac{1}{1500}$
$\frac{1}{l_{2}} = \frac{1}{10} - \frac{1}{1500} \Rightarrow \frac{149}{1500}$
$\Rightarrow l_{2} = \frac{1500}{149} = 10.06 c m .$