354617
A sound wave is passing through air column in the form of compression and rarefaction. In consecutive compression and rarefaction,
1 Density remains constant
2 Boyle's law is obeyed
3 Bulk modulus of air oscillates
4 There is no transfer of heat
Explanation:
There is no transfer of heat from compression to rarefaction as air is a bad conductor of heat. Since time of compression rarefaction is too small. Density of the medium is maximum and minimum at compression and rarefaction points. Bulk modulus remain constant.
NCERT Exemplar
PHXI15:WAVES
354618
Sound waves do not exhibit the property
1 Reflection
2 Refraction
3 Diffraction
4 Polarisation
Explanation:
Conceptual Question
PHXI15:WAVES
354619
The frequency of a pearson's voice is \(200\;Hz\) and its wavelength is 1 meter. If the wavelength of another pearson is \(1.5\;m\), then the frequency of the second voice is:
1 \(133\;Hz\)
2 \(150\;Hz\)
3 \(400\;Hz\)
4 \(650\;Hz\)
Explanation:
We can assume that velocity of sound wave is same since both waves travel in same medium. \({\lambda _1}{f_1} = {\lambda _1}{f_2}\) \({f_2} = \frac{{{\lambda _1}{f_1}}}{{{\lambda _2}}} = 133\;Hz\)
PHXI15:WAVES
354620
Sound waves of wavelength \(\lambda\) travelling in a medium with a speed of \(v\;m{\rm{/}}s\) enter into another medium where its speed in \(2\,v\,m{\rm{/}}s\). Wavelength of sound waves in the second medium is:
1 \(\lambda\)
2 \(\dfrac{\lambda}{2}\)
3 \(2\,\lambda \)
4 \(4\,\lambda \)
Explanation:
Let the frequency in the first medium is \(v\) and in the second medium is \(v\). Frequency remains same in both the medium. So, \(v=v^{\prime} \Rightarrow \dfrac{v}{\lambda}=\dfrac{v^{\prime}}{\lambda^{\prime}}\) \(\Rightarrow \lambda^{\prime}=\left(\dfrac{v^{\prime}}{v}\right) \lambda\) \(\lambda\) and \(\lambda^{\prime}, v\) and \(v^{\prime}\) are wavelengths and speeds in first and second medium respectively. So, \(\lambda^{\prime}=\left(\dfrac{2 V}{V}\right) \lambda=2 \lambda\)
354617
A sound wave is passing through air column in the form of compression and rarefaction. In consecutive compression and rarefaction,
1 Density remains constant
2 Boyle's law is obeyed
3 Bulk modulus of air oscillates
4 There is no transfer of heat
Explanation:
There is no transfer of heat from compression to rarefaction as air is a bad conductor of heat. Since time of compression rarefaction is too small. Density of the medium is maximum and minimum at compression and rarefaction points. Bulk modulus remain constant.
NCERT Exemplar
PHXI15:WAVES
354618
Sound waves do not exhibit the property
1 Reflection
2 Refraction
3 Diffraction
4 Polarisation
Explanation:
Conceptual Question
PHXI15:WAVES
354619
The frequency of a pearson's voice is \(200\;Hz\) and its wavelength is 1 meter. If the wavelength of another pearson is \(1.5\;m\), then the frequency of the second voice is:
1 \(133\;Hz\)
2 \(150\;Hz\)
3 \(400\;Hz\)
4 \(650\;Hz\)
Explanation:
We can assume that velocity of sound wave is same since both waves travel in same medium. \({\lambda _1}{f_1} = {\lambda _1}{f_2}\) \({f_2} = \frac{{{\lambda _1}{f_1}}}{{{\lambda _2}}} = 133\;Hz\)
PHXI15:WAVES
354620
Sound waves of wavelength \(\lambda\) travelling in a medium with a speed of \(v\;m{\rm{/}}s\) enter into another medium where its speed in \(2\,v\,m{\rm{/}}s\). Wavelength of sound waves in the second medium is:
1 \(\lambda\)
2 \(\dfrac{\lambda}{2}\)
3 \(2\,\lambda \)
4 \(4\,\lambda \)
Explanation:
Let the frequency in the first medium is \(v\) and in the second medium is \(v\). Frequency remains same in both the medium. So, \(v=v^{\prime} \Rightarrow \dfrac{v}{\lambda}=\dfrac{v^{\prime}}{\lambda^{\prime}}\) \(\Rightarrow \lambda^{\prime}=\left(\dfrac{v^{\prime}}{v}\right) \lambda\) \(\lambda\) and \(\lambda^{\prime}, v\) and \(v^{\prime}\) are wavelengths and speeds in first and second medium respectively. So, \(\lambda^{\prime}=\left(\dfrac{2 V}{V}\right) \lambda=2 \lambda\)
354617
A sound wave is passing through air column in the form of compression and rarefaction. In consecutive compression and rarefaction,
1 Density remains constant
2 Boyle's law is obeyed
3 Bulk modulus of air oscillates
4 There is no transfer of heat
Explanation:
There is no transfer of heat from compression to rarefaction as air is a bad conductor of heat. Since time of compression rarefaction is too small. Density of the medium is maximum and minimum at compression and rarefaction points. Bulk modulus remain constant.
NCERT Exemplar
PHXI15:WAVES
354618
Sound waves do not exhibit the property
1 Reflection
2 Refraction
3 Diffraction
4 Polarisation
Explanation:
Conceptual Question
PHXI15:WAVES
354619
The frequency of a pearson's voice is \(200\;Hz\) and its wavelength is 1 meter. If the wavelength of another pearson is \(1.5\;m\), then the frequency of the second voice is:
1 \(133\;Hz\)
2 \(150\;Hz\)
3 \(400\;Hz\)
4 \(650\;Hz\)
Explanation:
We can assume that velocity of sound wave is same since both waves travel in same medium. \({\lambda _1}{f_1} = {\lambda _1}{f_2}\) \({f_2} = \frac{{{\lambda _1}{f_1}}}{{{\lambda _2}}} = 133\;Hz\)
PHXI15:WAVES
354620
Sound waves of wavelength \(\lambda\) travelling in a medium with a speed of \(v\;m{\rm{/}}s\) enter into another medium where its speed in \(2\,v\,m{\rm{/}}s\). Wavelength of sound waves in the second medium is:
1 \(\lambda\)
2 \(\dfrac{\lambda}{2}\)
3 \(2\,\lambda \)
4 \(4\,\lambda \)
Explanation:
Let the frequency in the first medium is \(v\) and in the second medium is \(v\). Frequency remains same in both the medium. So, \(v=v^{\prime} \Rightarrow \dfrac{v}{\lambda}=\dfrac{v^{\prime}}{\lambda^{\prime}}\) \(\Rightarrow \lambda^{\prime}=\left(\dfrac{v^{\prime}}{v}\right) \lambda\) \(\lambda\) and \(\lambda^{\prime}, v\) and \(v^{\prime}\) are wavelengths and speeds in first and second medium respectively. So, \(\lambda^{\prime}=\left(\dfrac{2 V}{V}\right) \lambda=2 \lambda\)
354617
A sound wave is passing through air column in the form of compression and rarefaction. In consecutive compression and rarefaction,
1 Density remains constant
2 Boyle's law is obeyed
3 Bulk modulus of air oscillates
4 There is no transfer of heat
Explanation:
There is no transfer of heat from compression to rarefaction as air is a bad conductor of heat. Since time of compression rarefaction is too small. Density of the medium is maximum and minimum at compression and rarefaction points. Bulk modulus remain constant.
NCERT Exemplar
PHXI15:WAVES
354618
Sound waves do not exhibit the property
1 Reflection
2 Refraction
3 Diffraction
4 Polarisation
Explanation:
Conceptual Question
PHXI15:WAVES
354619
The frequency of a pearson's voice is \(200\;Hz\) and its wavelength is 1 meter. If the wavelength of another pearson is \(1.5\;m\), then the frequency of the second voice is:
1 \(133\;Hz\)
2 \(150\;Hz\)
3 \(400\;Hz\)
4 \(650\;Hz\)
Explanation:
We can assume that velocity of sound wave is same since both waves travel in same medium. \({\lambda _1}{f_1} = {\lambda _1}{f_2}\) \({f_2} = \frac{{{\lambda _1}{f_1}}}{{{\lambda _2}}} = 133\;Hz\)
PHXI15:WAVES
354620
Sound waves of wavelength \(\lambda\) travelling in a medium with a speed of \(v\;m{\rm{/}}s\) enter into another medium where its speed in \(2\,v\,m{\rm{/}}s\). Wavelength of sound waves in the second medium is:
1 \(\lambda\)
2 \(\dfrac{\lambda}{2}\)
3 \(2\,\lambda \)
4 \(4\,\lambda \)
Explanation:
Let the frequency in the first medium is \(v\) and in the second medium is \(v\). Frequency remains same in both the medium. So, \(v=v^{\prime} \Rightarrow \dfrac{v}{\lambda}=\dfrac{v^{\prime}}{\lambda^{\prime}}\) \(\Rightarrow \lambda^{\prime}=\left(\dfrac{v^{\prime}}{v}\right) \lambda\) \(\lambda\) and \(\lambda^{\prime}, v\) and \(v^{\prime}\) are wavelengths and speeds in first and second medium respectively. So, \(\lambda^{\prime}=\left(\dfrac{2 V}{V}\right) \lambda=2 \lambda\)
