Earth Satellites
« Previous Topic: Acceleration Due to Gravity of the Earth Next Topic: Escape Speed »
PHXI08:GRAVITATION

359757 If satellite is revolving around a planet of mass \(M\) in an elliptical orbit of semi-major axis \(a\), find the orbital speed of the satellite when it is at a distance \(r\) from the focus.

1 \(v^{2}=G\left[\dfrac{2}{r}-\dfrac{1}{a}\right]\)
2 \(v^{2}=G M\left[\dfrac{2}{r^{2}}-\dfrac{1}{a^{2}}\right]\)
3 \(v^{2}=G M\left[\dfrac{2}{r^{2}}-\dfrac{1}{a}\right]\)
4 \(v^{2}=G M\left[\dfrac{2}{r}-\dfrac{1}{a}\right]\)
PHXI08:GRAVITATION

359758 The time period of an artificial satellite in a circular orbit is independent of

1 The mass of the satellite
2 Mass of the earth and radius of the earth
3 Radius of the orbit
4 None of these
PHXI08:GRAVITATION

359759 If the gravitational force between two objects were proportional to \(1/R\) (and not as \(1/{R^2}\)) where \(R\) is separation between them, then a particle in circular orbit under such a force would have its orbital speed proportional to

1 \(R^{0}\)
2 \(1 / R^{2}\)
3 \(1 / R\)
4 \(R^{1}\)
PHXI08:GRAVITATION

359760 A satellite revolving around a planet in stationery orbit has time period 6 hours. The mass of planet is one-fourth the mass of earth. The radius orbit of planet is (Given : Radius of geo-stationary orbit for earth is \(4.2 \times {10^4}\;km\) )

1 \(1.68 \times {10^5}\;km\)
2 \(1.05 \times {10^4}\;km\)
3 \(8.4 \times {10^4}\;km\)
4 \(1.4 \times {10^4}\;km\)
JEE - 2024
PHXI08:GRAVITATION

359761 A satellite moves eastwards very near the surface of the Earth in equitorial plane with speed \(\left(v_{0}\right)\). Another satellite moves at the same height with the same speed in the equitorial plane but westwards. If \(R=\) radius of the earth and \(\omega\) be its angular speed of the Earth about its own axis then find the approximate difference in the two time period as observed on the Earth.

1 \(\dfrac{2 \pi \omega R^{2}}{v_{0}^{2}+R^{2} \omega^{2}}\)
2 \(\dfrac{4 \pi \omega R^{2}}{v_{0}^{2}-R^{2} \omega^{2}}\)
3 \(\dfrac{4 \pi \omega R^{2}}{v_{0}^{2}+R^{2} \omega^{2}}\)
4 \(\dfrac{2 \pi \omega R^{2}}{v_{0}^{2}-R^{2} \omega^{2}}\)
NEET DIGITAL LIBRARY
PHXI08:GRAVITATION

359757 If satellite is revolving around a planet of mass \(M\) in an elliptical orbit of semi-major axis \(a\), find the orbital speed of the satellite when it is at a distance \(r\) from the focus.

1 \(v^{2}=G\left[\dfrac{2}{r}-\dfrac{1}{a}\right]\)
2 \(v^{2}=G M\left[\dfrac{2}{r^{2}}-\dfrac{1}{a^{2}}\right]\)
3 \(v^{2}=G M\left[\dfrac{2}{r^{2}}-\dfrac{1}{a}\right]\)
4 \(v^{2}=G M\left[\dfrac{2}{r}-\dfrac{1}{a}\right]\)
PHXI08:GRAVITATION

359758 The time period of an artificial satellite in a circular orbit is independent of

1 The mass of the satellite
2 Mass of the earth and radius of the earth
3 Radius of the orbit
4 None of these
PHXI08:GRAVITATION

359759 If the gravitational force between two objects were proportional to \(1/R\) (and not as \(1/{R^2}\)) where \(R\) is separation between them, then a particle in circular orbit under such a force would have its orbital speed proportional to

1 \(R^{0}\)
2 \(1 / R^{2}\)
3 \(1 / R\)
4 \(R^{1}\)
PHXI08:GRAVITATION

359760 A satellite revolving around a planet in stationery orbit has time period 6 hours. The mass of planet is one-fourth the mass of earth. The radius orbit of planet is (Given : Radius of geo-stationary orbit for earth is \(4.2 \times {10^4}\;km\) )

1 \(1.68 \times {10^5}\;km\)
2 \(1.05 \times {10^4}\;km\)
3 \(8.4 \times {10^4}\;km\)
4 \(1.4 \times {10^4}\;km\)
JEE - 2024
PHXI08:GRAVITATION

359761 A satellite moves eastwards very near the surface of the Earth in equitorial plane with speed \(\left(v_{0}\right)\). Another satellite moves at the same height with the same speed in the equitorial plane but westwards. If \(R=\) radius of the earth and \(\omega\) be its angular speed of the Earth about its own axis then find the approximate difference in the two time period as observed on the Earth.

1 \(\dfrac{2 \pi \omega R^{2}}{v_{0}^{2}+R^{2} \omega^{2}}\)
2 \(\dfrac{4 \pi \omega R^{2}}{v_{0}^{2}-R^{2} \omega^{2}}\)
3 \(\dfrac{4 \pi \omega R^{2}}{v_{0}^{2}+R^{2} \omega^{2}}\)
4 \(\dfrac{2 \pi \omega R^{2}}{v_{0}^{2}-R^{2} \omega^{2}}\)
Join With Us for More Updates
PHXI08:GRAVITATION

359757 If satellite is revolving around a planet of mass \(M\) in an elliptical orbit of semi-major axis \(a\), find the orbital speed of the satellite when it is at a distance \(r\) from the focus.

1 \(v^{2}=G\left[\dfrac{2}{r}-\dfrac{1}{a}\right]\)
2 \(v^{2}=G M\left[\dfrac{2}{r^{2}}-\dfrac{1}{a^{2}}\right]\)
3 \(v^{2}=G M\left[\dfrac{2}{r^{2}}-\dfrac{1}{a}\right]\)
4 \(v^{2}=G M\left[\dfrac{2}{r}-\dfrac{1}{a}\right]\)
PHXI08:GRAVITATION

359758 The time period of an artificial satellite in a circular orbit is independent of

1 The mass of the satellite
2 Mass of the earth and radius of the earth
3 Radius of the orbit
4 None of these
PHXI08:GRAVITATION

359759 If the gravitational force between two objects were proportional to \(1/R\) (and not as \(1/{R^2}\)) where \(R\) is separation between them, then a particle in circular orbit under such a force would have its orbital speed proportional to

1 \(R^{0}\)
2 \(1 / R^{2}\)
3 \(1 / R\)
4 \(R^{1}\)
PHXI08:GRAVITATION

359760 A satellite revolving around a planet in stationery orbit has time period 6 hours. The mass of planet is one-fourth the mass of earth. The radius orbit of planet is (Given : Radius of geo-stationary orbit for earth is \(4.2 \times {10^4}\;km\) )

1 \(1.68 \times {10^5}\;km\)
2 \(1.05 \times {10^4}\;km\)
3 \(8.4 \times {10^4}\;km\)
4 \(1.4 \times {10^4}\;km\)
JEE - 2024
PHXI08:GRAVITATION

359761 A satellite moves eastwards very near the surface of the Earth in equitorial plane with speed \(\left(v_{0}\right)\). Another satellite moves at the same height with the same speed in the equitorial plane but westwards. If \(R=\) radius of the earth and \(\omega\) be its angular speed of the Earth about its own axis then find the approximate difference in the two time period as observed on the Earth.

1 \(\dfrac{2 \pi \omega R^{2}}{v_{0}^{2}+R^{2} \omega^{2}}\)
2 \(\dfrac{4 \pi \omega R^{2}}{v_{0}^{2}-R^{2} \omega^{2}}\)
3 \(\dfrac{4 \pi \omega R^{2}}{v_{0}^{2}+R^{2} \omega^{2}}\)
4 \(\dfrac{2 \pi \omega R^{2}}{v_{0}^{2}-R^{2} \omega^{2}}\)
For More Updates join with Us
PHXI08:GRAVITATION

359757 If satellite is revolving around a planet of mass \(M\) in an elliptical orbit of semi-major axis \(a\), find the orbital speed of the satellite when it is at a distance \(r\) from the focus.

1 \(v^{2}=G\left[\dfrac{2}{r}-\dfrac{1}{a}\right]\)
2 \(v^{2}=G M\left[\dfrac{2}{r^{2}}-\dfrac{1}{a^{2}}\right]\)
3 \(v^{2}=G M\left[\dfrac{2}{r^{2}}-\dfrac{1}{a}\right]\)
4 \(v^{2}=G M\left[\dfrac{2}{r}-\dfrac{1}{a}\right]\)
PHXI08:GRAVITATION

359758 The time period of an artificial satellite in a circular orbit is independent of

1 The mass of the satellite
2 Mass of the earth and radius of the earth
3 Radius of the orbit
4 None of these
PHXI08:GRAVITATION

359759 If the gravitational force between two objects were proportional to \(1/R\) (and not as \(1/{R^2}\)) where \(R\) is separation between them, then a particle in circular orbit under such a force would have its orbital speed proportional to

1 \(R^{0}\)
2 \(1 / R^{2}\)
3 \(1 / R\)
4 \(R^{1}\)
PHXI08:GRAVITATION

359760 A satellite revolving around a planet in stationery orbit has time period 6 hours. The mass of planet is one-fourth the mass of earth. The radius orbit of planet is (Given : Radius of geo-stationary orbit for earth is \(4.2 \times {10^4}\;km\) )

1 \(1.68 \times {10^5}\;km\)
2 \(1.05 \times {10^4}\;km\)
3 \(8.4 \times {10^4}\;km\)
4 \(1.4 \times {10^4}\;km\)
JEE - 2024
PHXI08:GRAVITATION

359761 A satellite moves eastwards very near the surface of the Earth in equitorial plane with speed \(\left(v_{0}\right)\). Another satellite moves at the same height with the same speed in the equitorial plane but westwards. If \(R=\) radius of the earth and \(\omega\) be its angular speed of the Earth about its own axis then find the approximate difference in the two time period as observed on the Earth.

1 \(\dfrac{2 \pi \omega R^{2}}{v_{0}^{2}+R^{2} \omega^{2}}\)
2 \(\dfrac{4 \pi \omega R^{2}}{v_{0}^{2}-R^{2} \omega^{2}}\)
3 \(\dfrac{4 \pi \omega R^{2}}{v_{0}^{2}+R^{2} \omega^{2}}\)
4 \(\dfrac{2 \pi \omega R^{2}}{v_{0}^{2}-R^{2} \omega^{2}}\)
NEET DIGITAL LIBRARY
PHXI08:GRAVITATION

359757 If satellite is revolving around a planet of mass \(M\) in an elliptical orbit of semi-major axis \(a\), find the orbital speed of the satellite when it is at a distance \(r\) from the focus.

1 \(v^{2}=G\left[\dfrac{2}{r}-\dfrac{1}{a}\right]\)
2 \(v^{2}=G M\left[\dfrac{2}{r^{2}}-\dfrac{1}{a^{2}}\right]\)
3 \(v^{2}=G M\left[\dfrac{2}{r^{2}}-\dfrac{1}{a}\right]\)
4 \(v^{2}=G M\left[\dfrac{2}{r}-\dfrac{1}{a}\right]\)
PHXI08:GRAVITATION

359758 The time period of an artificial satellite in a circular orbit is independent of

1 The mass of the satellite
2 Mass of the earth and radius of the earth
3 Radius of the orbit
4 None of these
PHXI08:GRAVITATION

359759 If the gravitational force between two objects were proportional to \(1/R\) (and not as \(1/{R^2}\)) where \(R\) is separation between them, then a particle in circular orbit under such a force would have its orbital speed proportional to

1 \(R^{0}\)
2 \(1 / R^{2}\)
3 \(1 / R\)
4 \(R^{1}\)
PHXI08:GRAVITATION

359760 A satellite revolving around a planet in stationery orbit has time period 6 hours. The mass of planet is one-fourth the mass of earth. The radius orbit of planet is (Given : Radius of geo-stationary orbit for earth is \(4.2 \times {10^4}\;km\) )

1 \(1.68 \times {10^5}\;km\)
2 \(1.05 \times {10^4}\;km\)
3 \(8.4 \times {10^4}\;km\)
4 \(1.4 \times {10^4}\;km\)
JEE - 2024
PHXI08:GRAVITATION

359761 A satellite moves eastwards very near the surface of the Earth in equitorial plane with speed \(\left(v_{0}\right)\). Another satellite moves at the same height with the same speed in the equitorial plane but westwards. If \(R=\) radius of the earth and \(\omega\) be its angular speed of the Earth about its own axis then find the approximate difference in the two time period as observed on the Earth.

1 \(\dfrac{2 \pi \omega R^{2}}{v_{0}^{2}+R^{2} \omega^{2}}\)
2 \(\dfrac{4 \pi \omega R^{2}}{v_{0}^{2}-R^{2} \omega^{2}}\)
3 \(\dfrac{4 \pi \omega R^{2}}{v_{0}^{2}+R^{2} \omega^{2}}\)
4 \(\dfrac{2 \pi \omega R^{2}}{v_{0}^{2}-R^{2} \omega^{2}}\)