359606
A spherical planet has a mass \(M_{p}\) and diameter \(D_{p}\). A particle of mass \(m\) falling freely near the surface of the planet will experience an acceleration due to gravity, equal to
1 \(4 G M_{p} / D_{p}^{2}\)
2 \(G M_{p} m / D_{p}^{2}\)
3 \(4 G M_{p} m / D_{p}^{2}\)
4 \(G M_{p} / D_{p}^{2}\)
Explanation:
Gravitational attraction force on the particle is \(F=\dfrac{G M_{p} m}{(D / 2)^{2}}\) Acceleration of particle due to gravity \(a=\dfrac{F_{g}}{m}=\dfrac{4 G M_{p}}{D_{p}^{2}} .\)
PHXI08:GRAVITATION
359607
The radii of two planets are respectively \(R_{1}\) and \(R_{2}\) and their densities are respectively \(\rho_{1}\) and \(\rho_{2}\). The ratio of the acceleration due to gravity at their surfaces is
\(g=\dfrac{4}{3} \pi \rho G R\) \(\therefore \dfrac{g_{1}}{g_{2}}=\dfrac{R_{1} \rho_{1}}{R_{2} \rho_{2}}\)
PHXI08:GRAVITATION
359608
If the mass of a body is \(M\) on the surface of the earth, the mass of the same body on the surface of the moon is
1 \(M\)
2 Zero
3 \(M / 6\)
4 \(6\, M\)
Explanation:
The mass of a body doesn't depend on the acceleration due to gravity and remains the same at all places.
KCET - 2015
PHXI08:GRAVITATION
359609
Mass of the moon is \(7.34 \times {10^{22}}\;kg\). If the acceleration due to gravity on the moon is \(1.4\;m/{s^2}\), the radius of the moon is \(\left( {G = 6.667 \times {{10}^{ - 11}}N{m^2}/k{g^2}} \right)\)
359606
A spherical planet has a mass \(M_{p}\) and diameter \(D_{p}\). A particle of mass \(m\) falling freely near the surface of the planet will experience an acceleration due to gravity, equal to
1 \(4 G M_{p} / D_{p}^{2}\)
2 \(G M_{p} m / D_{p}^{2}\)
3 \(4 G M_{p} m / D_{p}^{2}\)
4 \(G M_{p} / D_{p}^{2}\)
Explanation:
Gravitational attraction force on the particle is \(F=\dfrac{G M_{p} m}{(D / 2)^{2}}\) Acceleration of particle due to gravity \(a=\dfrac{F_{g}}{m}=\dfrac{4 G M_{p}}{D_{p}^{2}} .\)
PHXI08:GRAVITATION
359607
The radii of two planets are respectively \(R_{1}\) and \(R_{2}\) and their densities are respectively \(\rho_{1}\) and \(\rho_{2}\). The ratio of the acceleration due to gravity at their surfaces is
\(g=\dfrac{4}{3} \pi \rho G R\) \(\therefore \dfrac{g_{1}}{g_{2}}=\dfrac{R_{1} \rho_{1}}{R_{2} \rho_{2}}\)
PHXI08:GRAVITATION
359608
If the mass of a body is \(M\) on the surface of the earth, the mass of the same body on the surface of the moon is
1 \(M\)
2 Zero
3 \(M / 6\)
4 \(6\, M\)
Explanation:
The mass of a body doesn't depend on the acceleration due to gravity and remains the same at all places.
KCET - 2015
PHXI08:GRAVITATION
359609
Mass of the moon is \(7.34 \times {10^{22}}\;kg\). If the acceleration due to gravity on the moon is \(1.4\;m/{s^2}\), the radius of the moon is \(\left( {G = 6.667 \times {{10}^{ - 11}}N{m^2}/k{g^2}} \right)\)
359606
A spherical planet has a mass \(M_{p}\) and diameter \(D_{p}\). A particle of mass \(m\) falling freely near the surface of the planet will experience an acceleration due to gravity, equal to
1 \(4 G M_{p} / D_{p}^{2}\)
2 \(G M_{p} m / D_{p}^{2}\)
3 \(4 G M_{p} m / D_{p}^{2}\)
4 \(G M_{p} / D_{p}^{2}\)
Explanation:
Gravitational attraction force on the particle is \(F=\dfrac{G M_{p} m}{(D / 2)^{2}}\) Acceleration of particle due to gravity \(a=\dfrac{F_{g}}{m}=\dfrac{4 G M_{p}}{D_{p}^{2}} .\)
PHXI08:GRAVITATION
359607
The radii of two planets are respectively \(R_{1}\) and \(R_{2}\) and their densities are respectively \(\rho_{1}\) and \(\rho_{2}\). The ratio of the acceleration due to gravity at their surfaces is
\(g=\dfrac{4}{3} \pi \rho G R\) \(\therefore \dfrac{g_{1}}{g_{2}}=\dfrac{R_{1} \rho_{1}}{R_{2} \rho_{2}}\)
PHXI08:GRAVITATION
359608
If the mass of a body is \(M\) on the surface of the earth, the mass of the same body on the surface of the moon is
1 \(M\)
2 Zero
3 \(M / 6\)
4 \(6\, M\)
Explanation:
The mass of a body doesn't depend on the acceleration due to gravity and remains the same at all places.
KCET - 2015
PHXI08:GRAVITATION
359609
Mass of the moon is \(7.34 \times {10^{22}}\;kg\). If the acceleration due to gravity on the moon is \(1.4\;m/{s^2}\), the radius of the moon is \(\left( {G = 6.667 \times {{10}^{ - 11}}N{m^2}/k{g^2}} \right)\)
359606
A spherical planet has a mass \(M_{p}\) and diameter \(D_{p}\). A particle of mass \(m\) falling freely near the surface of the planet will experience an acceleration due to gravity, equal to
1 \(4 G M_{p} / D_{p}^{2}\)
2 \(G M_{p} m / D_{p}^{2}\)
3 \(4 G M_{p} m / D_{p}^{2}\)
4 \(G M_{p} / D_{p}^{2}\)
Explanation:
Gravitational attraction force on the particle is \(F=\dfrac{G M_{p} m}{(D / 2)^{2}}\) Acceleration of particle due to gravity \(a=\dfrac{F_{g}}{m}=\dfrac{4 G M_{p}}{D_{p}^{2}} .\)
PHXI08:GRAVITATION
359607
The radii of two planets are respectively \(R_{1}\) and \(R_{2}\) and their densities are respectively \(\rho_{1}\) and \(\rho_{2}\). The ratio of the acceleration due to gravity at their surfaces is
\(g=\dfrac{4}{3} \pi \rho G R\) \(\therefore \dfrac{g_{1}}{g_{2}}=\dfrac{R_{1} \rho_{1}}{R_{2} \rho_{2}}\)
PHXI08:GRAVITATION
359608
If the mass of a body is \(M\) on the surface of the earth, the mass of the same body on the surface of the moon is
1 \(M\)
2 Zero
3 \(M / 6\)
4 \(6\, M\)
Explanation:
The mass of a body doesn't depend on the acceleration due to gravity and remains the same at all places.
KCET - 2015
PHXI08:GRAVITATION
359609
Mass of the moon is \(7.34 \times {10^{22}}\;kg\). If the acceleration due to gravity on the moon is \(1.4\;m/{s^2}\), the radius of the moon is \(\left( {G = 6.667 \times {{10}^{ - 11}}N{m^2}/k{g^2}} \right)\)