Explanation:
Moment of inertia of a solid sphere about its diameter is\(I = \frac{2}{5}M{R^2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,(1)\)
As the radius of a solid sphere is doubled then the new moment of inertia of the sphere will be
\({I^\prime } = \frac{2}{5}M{(2R)^2} = \frac{8}{5}M{R^2}\,\,\,\,\,\,\,\,\,\,(2)\)
From eq. (1) and (2), we get
\(\dfrac{I}{I^{\prime}}=\dfrac{\dfrac{2}{5} M R^{2}}{\dfrac{8}{5} M R^{2}}=\dfrac{1}{4}\)