365745 Assertion :
The centre of mass of two particle system lies on the line joining the two particles, being closer to the heavier particle.
Reason :
This is because product of mass of one particle and its distance from centre of mass is numerically equal to product of mass of other particle and its distance from centre of mass.

365746 From a uniform disc of radius \(R\), an equilateral triangle of side \(\sqrt{3} R\) is cut as shown in the figure. The new position of centre of mass is:

365747 From the circular disc of radius \(4R\) two small disc of radius \(R\) are cut off. The centre of mass of the new structure will be:

365748 Figure shows a square plate of uniform thickness and side length \(\sqrt 2 \;m\). One fourth of the plate is removed as indicated. The distance of centre of mass of the remaining portion from the centre of the original square plate is

365745 Assertion :
The centre of mass of two particle system lies on the line joining the two particles, being closer to the heavier particle.
Reason :
This is because product of mass of one particle and its distance from centre of mass is numerically equal to product of mass of other particle and its distance from centre of mass.

365746 From a uniform disc of radius \(R\), an equilateral triangle of side \(\sqrt{3} R\) is cut as shown in the figure. The new position of centre of mass is:

365747 From the circular disc of radius \(4R\) two small disc of radius \(R\) are cut off. The centre of mass of the new structure will be:

365748 Figure shows a square plate of uniform thickness and side length \(\sqrt 2 \;m\). One fourth of the plate is removed as indicated. The distance of centre of mass of the remaining portion from the centre of the original square plate is

365745 Assertion :
The centre of mass of two particle system lies on the line joining the two particles, being closer to the heavier particle.
Reason :
This is because product of mass of one particle and its distance from centre of mass is numerically equal to product of mass of other particle and its distance from centre of mass.

365746 From a uniform disc of radius \(R\), an equilateral triangle of side \(\sqrt{3} R\) is cut as shown in the figure. The new position of centre of mass is:

365747 From the circular disc of radius \(4R\) two small disc of radius \(R\) are cut off. The centre of mass of the new structure will be:

365748 Figure shows a square plate of uniform thickness and side length \(\sqrt 2 \;m\). One fourth of the plate is removed as indicated. The distance of centre of mass of the remaining portion from the centre of the original square plate is

365745 Assertion :
The centre of mass of two particle system lies on the line joining the two particles, being closer to the heavier particle.
Reason :
This is because product of mass of one particle and its distance from centre of mass is numerically equal to product of mass of other particle and its distance from centre of mass.

365746 From a uniform disc of radius \(R\), an equilateral triangle of side \(\sqrt{3} R\) is cut as shown in the figure. The new position of centre of mass is:

365747 From the circular disc of radius \(4R\) two small disc of radius \(R\) are cut off. The centre of mass of the new structure will be:

365748 Figure shows a square plate of uniform thickness and side length \(\sqrt 2 \;m\). One fourth of the plate is removed as indicated. The distance of centre of mass of the remaining portion from the centre of the original square plate is