PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365307
If \(V_{A}\) and \(V_{B}\) denote the potentials of \(A\) and \(B\), then the equivalent resistance between \(A\) and \(B\) in the adjoint electric circuit is
1 \(10\,ohm\) if \(V_{A}>V_{B}\)
2 \(5\,ohm\) if \(V_{A} < V_{B}\)
3 \(5\,ohm\) if \(V_{A}>V_{B}\)
4 \(20\,ohm\) if \(V_{A}>V_{B}\)
Explanation:
If \(V_{A}>V_{B}\), the diode gets forward biased and has nearly zero resistance. \(\Rightarrow\) Given resistors will be in parallel.
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365308
The circuit shown in figure contains two diodes each with a forward resistance of 50 \(ohm\) and with infinite reverse resistance. If the battery voltage is 6 \(V\), the current through the 100 \(ohm\) resistance is
1 \(0.04\,A\)
2 \(0.01\,A\)
3 \(0.02\,A\)
4 \(0.03\,A\)
Explanation:
As per given circuit, diode \({D_1}\) is forward biased and offers a resistance of 50 ohm. Diode \({D_2}\) is reverse biased and as its corresponding resistance is infinite, no current flows through it. Thus the equivalent circuit is as shown in Figure. As all the three resistances are in series,the current through the circuit is \(I = \frac{{6V}}{{\left( {50 + 150 + 100} \right)\Omega }} = \frac{6}{{300}}A = 0.02A\) Current through \({D_2}\) is zero Current through \({D_1}\) and \(100k\Omega \) is \( = 0.02A\)
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365309
In a reverse biased diode, when the applied voltage changes by 1\(V\), the current is found to change by \(0.5\mu A\). The reverse bias resistance of the diode is
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PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365307
If \(V_{A}\) and \(V_{B}\) denote the potentials of \(A\) and \(B\), then the equivalent resistance between \(A\) and \(B\) in the adjoint electric circuit is
1 \(10\,ohm\) if \(V_{A}>V_{B}\)
2 \(5\,ohm\) if \(V_{A} < V_{B}\)
3 \(5\,ohm\) if \(V_{A}>V_{B}\)
4 \(20\,ohm\) if \(V_{A}>V_{B}\)
Explanation:
If \(V_{A}>V_{B}\), the diode gets forward biased and has nearly zero resistance. \(\Rightarrow\) Given resistors will be in parallel.
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365308
The circuit shown in figure contains two diodes each with a forward resistance of 50 \(ohm\) and with infinite reverse resistance. If the battery voltage is 6 \(V\), the current through the 100 \(ohm\) resistance is
1 \(0.04\,A\)
2 \(0.01\,A\)
3 \(0.02\,A\)
4 \(0.03\,A\)
Explanation:
As per given circuit, diode \({D_1}\) is forward biased and offers a resistance of 50 ohm. Diode \({D_2}\) is reverse biased and as its corresponding resistance is infinite, no current flows through it. Thus the equivalent circuit is as shown in Figure. As all the three resistances are in series,the current through the circuit is \(I = \frac{{6V}}{{\left( {50 + 150 + 100} \right)\Omega }} = \frac{6}{{300}}A = 0.02A\) Current through \({D_2}\) is zero Current through \({D_1}\) and \(100k\Omega \) is \( = 0.02A\)
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365309
In a reverse biased diode, when the applied voltage changes by 1\(V\), the current is found to change by \(0.5\mu A\). The reverse bias resistance of the diode is
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365307
If \(V_{A}\) and \(V_{B}\) denote the potentials of \(A\) and \(B\), then the equivalent resistance between \(A\) and \(B\) in the adjoint electric circuit is
1 \(10\,ohm\) if \(V_{A}>V_{B}\)
2 \(5\,ohm\) if \(V_{A} < V_{B}\)
3 \(5\,ohm\) if \(V_{A}>V_{B}\)
4 \(20\,ohm\) if \(V_{A}>V_{B}\)
Explanation:
If \(V_{A}>V_{B}\), the diode gets forward biased and has nearly zero resistance. \(\Rightarrow\) Given resistors will be in parallel.
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365308
The circuit shown in figure contains two diodes each with a forward resistance of 50 \(ohm\) and with infinite reverse resistance. If the battery voltage is 6 \(V\), the current through the 100 \(ohm\) resistance is
1 \(0.04\,A\)
2 \(0.01\,A\)
3 \(0.02\,A\)
4 \(0.03\,A\)
Explanation:
As per given circuit, diode \({D_1}\) is forward biased and offers a resistance of 50 ohm. Diode \({D_2}\) is reverse biased and as its corresponding resistance is infinite, no current flows through it. Thus the equivalent circuit is as shown in Figure. As all the three resistances are in series,the current through the circuit is \(I = \frac{{6V}}{{\left( {50 + 150 + 100} \right)\Omega }} = \frac{6}{{300}}A = 0.02A\) Current through \({D_2}\) is zero Current through \({D_1}\) and \(100k\Omega \) is \( = 0.02A\)
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365309
In a reverse biased diode, when the applied voltage changes by 1\(V\), the current is found to change by \(0.5\mu A\). The reverse bias resistance of the diode is
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365307
If \(V_{A}\) and \(V_{B}\) denote the potentials of \(A\) and \(B\), then the equivalent resistance between \(A\) and \(B\) in the adjoint electric circuit is
1 \(10\,ohm\) if \(V_{A}>V_{B}\)
2 \(5\,ohm\) if \(V_{A} < V_{B}\)
3 \(5\,ohm\) if \(V_{A}>V_{B}\)
4 \(20\,ohm\) if \(V_{A}>V_{B}\)
Explanation:
If \(V_{A}>V_{B}\), the diode gets forward biased and has nearly zero resistance. \(\Rightarrow\) Given resistors will be in parallel.
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365308
The circuit shown in figure contains two diodes each with a forward resistance of 50 \(ohm\) and with infinite reverse resistance. If the battery voltage is 6 \(V\), the current through the 100 \(ohm\) resistance is
1 \(0.04\,A\)
2 \(0.01\,A\)
3 \(0.02\,A\)
4 \(0.03\,A\)
Explanation:
As per given circuit, diode \({D_1}\) is forward biased and offers a resistance of 50 ohm. Diode \({D_2}\) is reverse biased and as its corresponding resistance is infinite, no current flows through it. Thus the equivalent circuit is as shown in Figure. As all the three resistances are in series,the current through the circuit is \(I = \frac{{6V}}{{\left( {50 + 150 + 100} \right)\Omega }} = \frac{6}{{300}}A = 0.02A\) Current through \({D_2}\) is zero Current through \({D_1}\) and \(100k\Omega \) is \( = 0.02A\)
PHXII14:SEMICONDUCTOR ELECTRONICS- MATERIALS- DEVICES AND SIMPLE CIRCUITS
365309
In a reverse biased diode, when the applied voltage changes by 1\(V\), the current is found to change by \(0.5\mu A\). The reverse bias resistance of the diode is
