NEET Test Series from KOTA - 10 Papers In MS WORD
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PHXII09:RAY OPTICS AND OPTICAL INSTRUMENTS
365050
The angle of minimum deviation for an incident light ray on an equilateral prism is equal to its refracting angle. The refractive index of its material is
365051
When a thin prism \(\left( {\mu = 3{\rm{/}}2} \right)\) is immersed in water \(\left( {\mu = 4{\rm{/}}3} \right)\) then deviation through the prism becomes how much times of the deviation (when the prism is in air)?
365053
A thin hollow prism of refracting angle \(3^\circ \) , filled with water gives a deviation of \(1^\circ \) . The refractive index of water is
1 1.59
2 1.33
3 1.46
4 1.51
Explanation:
Angle of deviation of the light ray produced by prism is \(\delta = A\left( {\mu - 1} \right)\) where, \(\delta \) = angle of deviation A = angle of prisms and \(\mu \)= refractive index of the prism Given, A = \({3^o}\) ,\(\delta \) =\({1^o}\) and\(\mu \) = ? Substituting the given values in eq.(1), we get \(1^\circ = 3^\circ \left( {\mu - 1} \right)\)\( \Rightarrow \mu = \frac{4}{3} = 1.33\) Hence, the refractive index of the prism is 1.33
365050
The angle of minimum deviation for an incident light ray on an equilateral prism is equal to its refracting angle. The refractive index of its material is
365051
When a thin prism \(\left( {\mu = 3{\rm{/}}2} \right)\) is immersed in water \(\left( {\mu = 4{\rm{/}}3} \right)\) then deviation through the prism becomes how much times of the deviation (when the prism is in air)?
365053
A thin hollow prism of refracting angle \(3^\circ \) , filled with water gives a deviation of \(1^\circ \) . The refractive index of water is
1 1.59
2 1.33
3 1.46
4 1.51
Explanation:
Angle of deviation of the light ray produced by prism is \(\delta = A\left( {\mu - 1} \right)\) where, \(\delta \) = angle of deviation A = angle of prisms and \(\mu \)= refractive index of the prism Given, A = \({3^o}\) ,\(\delta \) =\({1^o}\) and\(\mu \) = ? Substituting the given values in eq.(1), we get \(1^\circ = 3^\circ \left( {\mu - 1} \right)\)\( \Rightarrow \mu = \frac{4}{3} = 1.33\) Hence, the refractive index of the prism is 1.33
365050
The angle of minimum deviation for an incident light ray on an equilateral prism is equal to its refracting angle. The refractive index of its material is
365051
When a thin prism \(\left( {\mu = 3{\rm{/}}2} \right)\) is immersed in water \(\left( {\mu = 4{\rm{/}}3} \right)\) then deviation through the prism becomes how much times of the deviation (when the prism is in air)?
365053
A thin hollow prism of refracting angle \(3^\circ \) , filled with water gives a deviation of \(1^\circ \) . The refractive index of water is
1 1.59
2 1.33
3 1.46
4 1.51
Explanation:
Angle of deviation of the light ray produced by prism is \(\delta = A\left( {\mu - 1} \right)\) where, \(\delta \) = angle of deviation A = angle of prisms and \(\mu \)= refractive index of the prism Given, A = \({3^o}\) ,\(\delta \) =\({1^o}\) and\(\mu \) = ? Substituting the given values in eq.(1), we get \(1^\circ = 3^\circ \left( {\mu - 1} \right)\)\( \Rightarrow \mu = \frac{4}{3} = 1.33\) Hence, the refractive index of the prism is 1.33
365050
The angle of minimum deviation for an incident light ray on an equilateral prism is equal to its refracting angle. The refractive index of its material is
365051
When a thin prism \(\left( {\mu = 3{\rm{/}}2} \right)\) is immersed in water \(\left( {\mu = 4{\rm{/}}3} \right)\) then deviation through the prism becomes how much times of the deviation (when the prism is in air)?
365053
A thin hollow prism of refracting angle \(3^\circ \) , filled with water gives a deviation of \(1^\circ \) . The refractive index of water is
1 1.59
2 1.33
3 1.46
4 1.51
Explanation:
Angle of deviation of the light ray produced by prism is \(\delta = A\left( {\mu - 1} \right)\) where, \(\delta \) = angle of deviation A = angle of prisms and \(\mu \)= refractive index of the prism Given, A = \({3^o}\) ,\(\delta \) =\({1^o}\) and\(\mu \) = ? Substituting the given values in eq.(1), we get \(1^\circ = 3^\circ \left( {\mu - 1} \right)\)\( \Rightarrow \mu = \frac{4}{3} = 1.33\) Hence, the refractive index of the prism is 1.33
