346565
In a population of 800 rabbits showing Hardy– Weinberg equilibrium, the frequency of recessive individuals was 0.16. What is the frequency of heterozygous individuals?
1 0.48
2 0.84
3 0.36
4 0.4
Explanation:
0.48
Total population = 800 rabbits in H.W equilibrium
[ p2 + 2pq + q2 = 800]
Given q2 = 0.16
Then q = 0.16
q = 0.4
[p + q = 1]
If q = 0.4
p = 1-q
p = 1- 0.4
p = 0.6
Frequency of heterozygous individuals (2pq) = ?
2pq = 2 × 0.6 × 0.4
= 0.48.
KCET - 2023
BIOXII07:EVOLUTION
346566
The Hardy-Weinberg law of equilibrium was based on the following
1 Random mating, natural selection, gene flow
2 Random mating, genetic drift, gene flow
3 Non-random mating, mutation, gene flow
4 Random mating, no mutation, no gene flow
Explanation:
The Hardy-Weinberg principle relies on a number of assumptions: (1) random mating (i.e, population structure is absent and matings occur in proportion to genotype frequencies), (2) the absence of natural selection, (3) a very large population size (i.e., genetic drift is negligible), (4) no gene flow or migration,
BIOXII07:EVOLUTION
346567
A gene locus has two alleles \(A\), a. If the frequency of dominant allele \(\mathrm{A}\) is 0.4 , then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population?
Frequency of dominant allele (say p) \(=0.4\) Frequency of recessive allele (say q)\(=1-0.4=0.6\) Frequency of homozygous dominant individuals (AA) \(=\mathrm{p}^{2}=(0.4)^{2}=0.16\) Frequency of heterozygous individuals (Aa) \(=2 \mathrm{pq}=2(0.4)(0.6)=0.48\) Frequency of homozygous recessive individuals (aa) \(=\mathrm{q}^{2}=(0.6)^{2}=0.36\)
NEET - 2019
BIOXII07:EVOLUTION
346568
\({{\rm{(p + q)}}^{\rm{2}}}{\rm{ = }}{{\rm{p}}^{\rm{2}}}{\rm{ + 2pq + }}{{\rm{q}}^{\rm{2}}}{\rm{ = 1}}\) represents an equation used in
1 Population genetics
2 Mendelian genetics
3 Biometrics
4 Molecular genetics
Explanation:
\({{\rm{(p + q)}}^{\rm{2}}}{\rm{ = }}{{\rm{p}}^{\rm{2}}}{\rm{ + 2pq + }}{{\rm{q}}^{\rm{2}}}{\rm{ = 1}}\) is a mathematical representation of 'Hardy-Weinberg principle' used in population genetics. It states that the allelic and genotypic frequencies of a population are stable and is constant over generations.
NCERT Exemplar
BIOXII07:EVOLUTION
346569
Hardy - Weinberg principle is expresed by following equation:
In the equation, \({{\rm{p}}^{\rm{2}}}\) represents the frequency of the homozygous genotype AA, \({{\rm{q}}^{\rm{2}}}\) represents the frequency of the homozygous genotype aa, and \(2 \mathrm{pq}\) represents the frequency of the heterozygous genotype Aa. In addition, the sum of the allele frequencies for all the alleles at the locus must be 1, so \({\rm{p + q = 1}}\).
346565
In a population of 800 rabbits showing Hardy– Weinberg equilibrium, the frequency of recessive individuals was 0.16. What is the frequency of heterozygous individuals?
1 0.48
2 0.84
3 0.36
4 0.4
Explanation:
0.48
Total population = 800 rabbits in H.W equilibrium
[ p2 + 2pq + q2 = 800]
Given q2 = 0.16
Then q = 0.16
q = 0.4
[p + q = 1]
If q = 0.4
p = 1-q
p = 1- 0.4
p = 0.6
Frequency of heterozygous individuals (2pq) = ?
2pq = 2 × 0.6 × 0.4
= 0.48.
KCET - 2023
BIOXII07:EVOLUTION
346566
The Hardy-Weinberg law of equilibrium was based on the following
1 Random mating, natural selection, gene flow
2 Random mating, genetic drift, gene flow
3 Non-random mating, mutation, gene flow
4 Random mating, no mutation, no gene flow
Explanation:
The Hardy-Weinberg principle relies on a number of assumptions: (1) random mating (i.e, population structure is absent and matings occur in proportion to genotype frequencies), (2) the absence of natural selection, (3) a very large population size (i.e., genetic drift is negligible), (4) no gene flow or migration,
BIOXII07:EVOLUTION
346567
A gene locus has two alleles \(A\), a. If the frequency of dominant allele \(\mathrm{A}\) is 0.4 , then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population?
Frequency of dominant allele (say p) \(=0.4\) Frequency of recessive allele (say q)\(=1-0.4=0.6\) Frequency of homozygous dominant individuals (AA) \(=\mathrm{p}^{2}=(0.4)^{2}=0.16\) Frequency of heterozygous individuals (Aa) \(=2 \mathrm{pq}=2(0.4)(0.6)=0.48\) Frequency of homozygous recessive individuals (aa) \(=\mathrm{q}^{2}=(0.6)^{2}=0.36\)
NEET - 2019
BIOXII07:EVOLUTION
346568
\({{\rm{(p + q)}}^{\rm{2}}}{\rm{ = }}{{\rm{p}}^{\rm{2}}}{\rm{ + 2pq + }}{{\rm{q}}^{\rm{2}}}{\rm{ = 1}}\) represents an equation used in
1 Population genetics
2 Mendelian genetics
3 Biometrics
4 Molecular genetics
Explanation:
\({{\rm{(p + q)}}^{\rm{2}}}{\rm{ = }}{{\rm{p}}^{\rm{2}}}{\rm{ + 2pq + }}{{\rm{q}}^{\rm{2}}}{\rm{ = 1}}\) is a mathematical representation of 'Hardy-Weinberg principle' used in population genetics. It states that the allelic and genotypic frequencies of a population are stable and is constant over generations.
NCERT Exemplar
BIOXII07:EVOLUTION
346569
Hardy - Weinberg principle is expresed by following equation:
In the equation, \({{\rm{p}}^{\rm{2}}}\) represents the frequency of the homozygous genotype AA, \({{\rm{q}}^{\rm{2}}}\) represents the frequency of the homozygous genotype aa, and \(2 \mathrm{pq}\) represents the frequency of the heterozygous genotype Aa. In addition, the sum of the allele frequencies for all the alleles at the locus must be 1, so \({\rm{p + q = 1}}\).
346565
In a population of 800 rabbits showing Hardy– Weinberg equilibrium, the frequency of recessive individuals was 0.16. What is the frequency of heterozygous individuals?
1 0.48
2 0.84
3 0.36
4 0.4
Explanation:
0.48
Total population = 800 rabbits in H.W equilibrium
[ p2 + 2pq + q2 = 800]
Given q2 = 0.16
Then q = 0.16
q = 0.4
[p + q = 1]
If q = 0.4
p = 1-q
p = 1- 0.4
p = 0.6
Frequency of heterozygous individuals (2pq) = ?
2pq = 2 × 0.6 × 0.4
= 0.48.
KCET - 2023
BIOXII07:EVOLUTION
346566
The Hardy-Weinberg law of equilibrium was based on the following
1 Random mating, natural selection, gene flow
2 Random mating, genetic drift, gene flow
3 Non-random mating, mutation, gene flow
4 Random mating, no mutation, no gene flow
Explanation:
The Hardy-Weinberg principle relies on a number of assumptions: (1) random mating (i.e, population structure is absent and matings occur in proportion to genotype frequencies), (2) the absence of natural selection, (3) a very large population size (i.e., genetic drift is negligible), (4) no gene flow or migration,
BIOXII07:EVOLUTION
346567
A gene locus has two alleles \(A\), a. If the frequency of dominant allele \(\mathrm{A}\) is 0.4 , then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population?
Frequency of dominant allele (say p) \(=0.4\) Frequency of recessive allele (say q)\(=1-0.4=0.6\) Frequency of homozygous dominant individuals (AA) \(=\mathrm{p}^{2}=(0.4)^{2}=0.16\) Frequency of heterozygous individuals (Aa) \(=2 \mathrm{pq}=2(0.4)(0.6)=0.48\) Frequency of homozygous recessive individuals (aa) \(=\mathrm{q}^{2}=(0.6)^{2}=0.36\)
NEET - 2019
BIOXII07:EVOLUTION
346568
\({{\rm{(p + q)}}^{\rm{2}}}{\rm{ = }}{{\rm{p}}^{\rm{2}}}{\rm{ + 2pq + }}{{\rm{q}}^{\rm{2}}}{\rm{ = 1}}\) represents an equation used in
1 Population genetics
2 Mendelian genetics
3 Biometrics
4 Molecular genetics
Explanation:
\({{\rm{(p + q)}}^{\rm{2}}}{\rm{ = }}{{\rm{p}}^{\rm{2}}}{\rm{ + 2pq + }}{{\rm{q}}^{\rm{2}}}{\rm{ = 1}}\) is a mathematical representation of 'Hardy-Weinberg principle' used in population genetics. It states that the allelic and genotypic frequencies of a population are stable and is constant over generations.
NCERT Exemplar
BIOXII07:EVOLUTION
346569
Hardy - Weinberg principle is expresed by following equation:
In the equation, \({{\rm{p}}^{\rm{2}}}\) represents the frequency of the homozygous genotype AA, \({{\rm{q}}^{\rm{2}}}\) represents the frequency of the homozygous genotype aa, and \(2 \mathrm{pq}\) represents the frequency of the heterozygous genotype Aa. In addition, the sum of the allele frequencies for all the alleles at the locus must be 1, so \({\rm{p + q = 1}}\).
346565
In a population of 800 rabbits showing Hardy– Weinberg equilibrium, the frequency of recessive individuals was 0.16. What is the frequency of heterozygous individuals?
1 0.48
2 0.84
3 0.36
4 0.4
Explanation:
0.48
Total population = 800 rabbits in H.W equilibrium
[ p2 + 2pq + q2 = 800]
Given q2 = 0.16
Then q = 0.16
q = 0.4
[p + q = 1]
If q = 0.4
p = 1-q
p = 1- 0.4
p = 0.6
Frequency of heterozygous individuals (2pq) = ?
2pq = 2 × 0.6 × 0.4
= 0.48.
KCET - 2023
BIOXII07:EVOLUTION
346566
The Hardy-Weinberg law of equilibrium was based on the following
1 Random mating, natural selection, gene flow
2 Random mating, genetic drift, gene flow
3 Non-random mating, mutation, gene flow
4 Random mating, no mutation, no gene flow
Explanation:
The Hardy-Weinberg principle relies on a number of assumptions: (1) random mating (i.e, population structure is absent and matings occur in proportion to genotype frequencies), (2) the absence of natural selection, (3) a very large population size (i.e., genetic drift is negligible), (4) no gene flow or migration,
BIOXII07:EVOLUTION
346567
A gene locus has two alleles \(A\), a. If the frequency of dominant allele \(\mathrm{A}\) is 0.4 , then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population?
Frequency of dominant allele (say p) \(=0.4\) Frequency of recessive allele (say q)\(=1-0.4=0.6\) Frequency of homozygous dominant individuals (AA) \(=\mathrm{p}^{2}=(0.4)^{2}=0.16\) Frequency of heterozygous individuals (Aa) \(=2 \mathrm{pq}=2(0.4)(0.6)=0.48\) Frequency of homozygous recessive individuals (aa) \(=\mathrm{q}^{2}=(0.6)^{2}=0.36\)
NEET - 2019
BIOXII07:EVOLUTION
346568
\({{\rm{(p + q)}}^{\rm{2}}}{\rm{ = }}{{\rm{p}}^{\rm{2}}}{\rm{ + 2pq + }}{{\rm{q}}^{\rm{2}}}{\rm{ = 1}}\) represents an equation used in
1 Population genetics
2 Mendelian genetics
3 Biometrics
4 Molecular genetics
Explanation:
\({{\rm{(p + q)}}^{\rm{2}}}{\rm{ = }}{{\rm{p}}^{\rm{2}}}{\rm{ + 2pq + }}{{\rm{q}}^{\rm{2}}}{\rm{ = 1}}\) is a mathematical representation of 'Hardy-Weinberg principle' used in population genetics. It states that the allelic and genotypic frequencies of a population are stable and is constant over generations.
NCERT Exemplar
BIOXII07:EVOLUTION
346569
Hardy - Weinberg principle is expresed by following equation:
In the equation, \({{\rm{p}}^{\rm{2}}}\) represents the frequency of the homozygous genotype AA, \({{\rm{q}}^{\rm{2}}}\) represents the frequency of the homozygous genotype aa, and \(2 \mathrm{pq}\) represents the frequency of the heterozygous genotype Aa. In addition, the sum of the allele frequencies for all the alleles at the locus must be 1, so \({\rm{p + q = 1}}\).
346565
In a population of 800 rabbits showing Hardy– Weinberg equilibrium, the frequency of recessive individuals was 0.16. What is the frequency of heterozygous individuals?
1 0.48
2 0.84
3 0.36
4 0.4
Explanation:
0.48
Total population = 800 rabbits in H.W equilibrium
[ p2 + 2pq + q2 = 800]
Given q2 = 0.16
Then q = 0.16
q = 0.4
[p + q = 1]
If q = 0.4
p = 1-q
p = 1- 0.4
p = 0.6
Frequency of heterozygous individuals (2pq) = ?
2pq = 2 × 0.6 × 0.4
= 0.48.
KCET - 2023
BIOXII07:EVOLUTION
346566
The Hardy-Weinberg law of equilibrium was based on the following
1 Random mating, natural selection, gene flow
2 Random mating, genetic drift, gene flow
3 Non-random mating, mutation, gene flow
4 Random mating, no mutation, no gene flow
Explanation:
The Hardy-Weinberg principle relies on a number of assumptions: (1) random mating (i.e, population structure is absent and matings occur in proportion to genotype frequencies), (2) the absence of natural selection, (3) a very large population size (i.e., genetic drift is negligible), (4) no gene flow or migration,
BIOXII07:EVOLUTION
346567
A gene locus has two alleles \(A\), a. If the frequency of dominant allele \(\mathrm{A}\) is 0.4 , then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population?
Frequency of dominant allele (say p) \(=0.4\) Frequency of recessive allele (say q)\(=1-0.4=0.6\) Frequency of homozygous dominant individuals (AA) \(=\mathrm{p}^{2}=(0.4)^{2}=0.16\) Frequency of heterozygous individuals (Aa) \(=2 \mathrm{pq}=2(0.4)(0.6)=0.48\) Frequency of homozygous recessive individuals (aa) \(=\mathrm{q}^{2}=(0.6)^{2}=0.36\)
NEET - 2019
BIOXII07:EVOLUTION
346568
\({{\rm{(p + q)}}^{\rm{2}}}{\rm{ = }}{{\rm{p}}^{\rm{2}}}{\rm{ + 2pq + }}{{\rm{q}}^{\rm{2}}}{\rm{ = 1}}\) represents an equation used in
1 Population genetics
2 Mendelian genetics
3 Biometrics
4 Molecular genetics
Explanation:
\({{\rm{(p + q)}}^{\rm{2}}}{\rm{ = }}{{\rm{p}}^{\rm{2}}}{\rm{ + 2pq + }}{{\rm{q}}^{\rm{2}}}{\rm{ = 1}}\) is a mathematical representation of 'Hardy-Weinberg principle' used in population genetics. It states that the allelic and genotypic frequencies of a population are stable and is constant over generations.
NCERT Exemplar
BIOXII07:EVOLUTION
346569
Hardy - Weinberg principle is expresed by following equation:
In the equation, \({{\rm{p}}^{\rm{2}}}\) represents the frequency of the homozygous genotype AA, \({{\rm{q}}^{\rm{2}}}\) represents the frequency of the homozygous genotype aa, and \(2 \mathrm{pq}\) represents the frequency of the heterozygous genotype Aa. In addition, the sum of the allele frequencies for all the alleles at the locus must be 1, so \({\rm{p + q = 1}}\).
