342183
In a plant, black seed color \((\mathrm{BB} / \mathrm{Bb})\) is dominant over white seed color (bb). In order to find out the genotype of the black seed plant, with which of the following genotype will you cross it?
1 BB
2 bb
3 Bb
4 BB / Bb
Explanation:
To determine the genotype of a black seed colour at \(F_{2}\), the black seed from \(F_{2}\) is crossed with the white seed colour. This is called a test cross. Therefore to determine the genotype of black seed we need to cross them with white seed i.e. bb.
NEET - 2024
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342184
When homozygous dominant parent is crossed with heterozygous parent, the percentage of offsprings with different phenotype than either parent is
1 75
2 25
3 50
4 0
Explanation:
When a homozygous dominant parent (i.e., TT) is crossed with heterozygous parent (i.e., Tt), the offspring produced is of the same phenotype as that of parents, that means 0% of offsprings of recessive character will be produced.
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342185
When two odd characters are present in a gene, this is known as
1 Heterogamous
2 Bigamous
3 Polymorphic
4 Heteromorphic
Explanation:
If an individual contains the two different characters, then it is called heterogamous.
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342186
A pea plant that is heterzygous for the flower gene makes gametes. What is the probability that one of its gametes contains the recessive white allele for flower color?
1 \(50\% \)
2 \(25\% \)
3 \(0\% \)
4 \(75\% \)
Explanation:
50 % of the gametes will have dominant allele and 50 % will have recessive allele.
342183
In a plant, black seed color \((\mathrm{BB} / \mathrm{Bb})\) is dominant over white seed color (bb). In order to find out the genotype of the black seed plant, with which of the following genotype will you cross it?
1 BB
2 bb
3 Bb
4 BB / Bb
Explanation:
To determine the genotype of a black seed colour at \(F_{2}\), the black seed from \(F_{2}\) is crossed with the white seed colour. This is called a test cross. Therefore to determine the genotype of black seed we need to cross them with white seed i.e. bb.
NEET - 2024
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342184
When homozygous dominant parent is crossed with heterozygous parent, the percentage of offsprings with different phenotype than either parent is
1 75
2 25
3 50
4 0
Explanation:
When a homozygous dominant parent (i.e., TT) is crossed with heterozygous parent (i.e., Tt), the offspring produced is of the same phenotype as that of parents, that means 0% of offsprings of recessive character will be produced.
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342185
When two odd characters are present in a gene, this is known as
1 Heterogamous
2 Bigamous
3 Polymorphic
4 Heteromorphic
Explanation:
If an individual contains the two different characters, then it is called heterogamous.
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342186
A pea plant that is heterzygous for the flower gene makes gametes. What is the probability that one of its gametes contains the recessive white allele for flower color?
1 \(50\% \)
2 \(25\% \)
3 \(0\% \)
4 \(75\% \)
Explanation:
50 % of the gametes will have dominant allele and 50 % will have recessive allele.
342183
In a plant, black seed color \((\mathrm{BB} / \mathrm{Bb})\) is dominant over white seed color (bb). In order to find out the genotype of the black seed plant, with which of the following genotype will you cross it?
1 BB
2 bb
3 Bb
4 BB / Bb
Explanation:
To determine the genotype of a black seed colour at \(F_{2}\), the black seed from \(F_{2}\) is crossed with the white seed colour. This is called a test cross. Therefore to determine the genotype of black seed we need to cross them with white seed i.e. bb.
NEET - 2024
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342184
When homozygous dominant parent is crossed with heterozygous parent, the percentage of offsprings with different phenotype than either parent is
1 75
2 25
3 50
4 0
Explanation:
When a homozygous dominant parent (i.e., TT) is crossed with heterozygous parent (i.e., Tt), the offspring produced is of the same phenotype as that of parents, that means 0% of offsprings of recessive character will be produced.
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342185
When two odd characters are present in a gene, this is known as
1 Heterogamous
2 Bigamous
3 Polymorphic
4 Heteromorphic
Explanation:
If an individual contains the two different characters, then it is called heterogamous.
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342186
A pea plant that is heterzygous for the flower gene makes gametes. What is the probability that one of its gametes contains the recessive white allele for flower color?
1 \(50\% \)
2 \(25\% \)
3 \(0\% \)
4 \(75\% \)
Explanation:
50 % of the gametes will have dominant allele and 50 % will have recessive allele.
NEET Test Series from KOTA - 10 Papers In MS WORD
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BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342191
Match the columns I and II.
Column I
Column II
A. \({F_1}\)Generation
P. 3/4 are dominant
B. \({F_2}\) Generation
Q. All are dominant, heterozygous
R. 1/4 recessive
1 A – R, B – P, A – Q
2 A – Q, B – R, B – P
3 A – P , B – R, A – Q
4 A – Q, B – P, B – R
Explanation:
A-Q, B-R, B-P
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342183
In a plant, black seed color \((\mathrm{BB} / \mathrm{Bb})\) is dominant over white seed color (bb). In order to find out the genotype of the black seed plant, with which of the following genotype will you cross it?
1 BB
2 bb
3 Bb
4 BB / Bb
Explanation:
To determine the genotype of a black seed colour at \(F_{2}\), the black seed from \(F_{2}\) is crossed with the white seed colour. This is called a test cross. Therefore to determine the genotype of black seed we need to cross them with white seed i.e. bb.
NEET - 2024
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342184
When homozygous dominant parent is crossed with heterozygous parent, the percentage of offsprings with different phenotype than either parent is
1 75
2 25
3 50
4 0
Explanation:
When a homozygous dominant parent (i.e., TT) is crossed with heterozygous parent (i.e., Tt), the offspring produced is of the same phenotype as that of parents, that means 0% of offsprings of recessive character will be produced.
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342185
When two odd characters are present in a gene, this is known as
1 Heterogamous
2 Bigamous
3 Polymorphic
4 Heteromorphic
Explanation:
If an individual contains the two different characters, then it is called heterogamous.
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342186
A pea plant that is heterzygous for the flower gene makes gametes. What is the probability that one of its gametes contains the recessive white allele for flower color?
1 \(50\% \)
2 \(25\% \)
3 \(0\% \)
4 \(75\% \)
Explanation:
50 % of the gametes will have dominant allele and 50 % will have recessive allele.
342183
In a plant, black seed color \((\mathrm{BB} / \mathrm{Bb})\) is dominant over white seed color (bb). In order to find out the genotype of the black seed plant, with which of the following genotype will you cross it?
1 BB
2 bb
3 Bb
4 BB / Bb
Explanation:
To determine the genotype of a black seed colour at \(F_{2}\), the black seed from \(F_{2}\) is crossed with the white seed colour. This is called a test cross. Therefore to determine the genotype of black seed we need to cross them with white seed i.e. bb.
NEET - 2024
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342184
When homozygous dominant parent is crossed with heterozygous parent, the percentage of offsprings with different phenotype than either parent is
1 75
2 25
3 50
4 0
Explanation:
When a homozygous dominant parent (i.e., TT) is crossed with heterozygous parent (i.e., Tt), the offspring produced is of the same phenotype as that of parents, that means 0% of offsprings of recessive character will be produced.
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342185
When two odd characters are present in a gene, this is known as
1 Heterogamous
2 Bigamous
3 Polymorphic
4 Heteromorphic
Explanation:
If an individual contains the two different characters, then it is called heterogamous.
BIOXII05: PRINCIPLES OF INHERITANCE AND VARIATION
342186
A pea plant that is heterzygous for the flower gene makes gametes. What is the probability that one of its gametes contains the recessive white allele for flower color?
1 \(50\% \)
2 \(25\% \)
3 \(0\% \)
4 \(75\% \)
Explanation:
50 % of the gametes will have dominant allele and 50 % will have recessive allele.