1 \(\mathrm{CH}_{2}=\mathrm{CHCH}_{3}\)
2 \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CHCl}\)
3 \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CHC}_{6} \mathrm{H}_{5}\)
4 \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CHCO}_{2} \mathrm{CH}_{3}\)
Explanation:
In cationic polymerisation, carbocations are formed. Greater the stability of the carbocation, more reactive is the alkene. Since, the stability of the intermediate carbocation follows the order :
\[\begin{array}{l}
{\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{ - }}\mathop {\rm{C}}\limits^{\rm{ + }} {\rm{H}}{{\rm{C}}_{\rm{6}}}{{\rm{H}}_{\rm{5}}}{\rm{ > }}\,{\rm{C}}{{\rm{H}}_{\rm{3}}} - \mathop {\rm{C}}\limits^{\rm{ + }} {\rm{HC}}{{\rm{H}}_{\rm{3}}}{\rm{ > }}\\
\,\,\,\,\,\,\,\,\,\,\,\,\,{\rm{C}}{{\rm{H}}_{\rm{3}}}\mathop { - \,{\rm{C}}}\limits^{\rm{ + }} {\rm{H}} - {\rm{Cl}}\,{\rm{ > }}\,{\rm{C}}{{\rm{H}}_{\rm{3}}} - \mathop {\rm{C}}\limits^{\rm{ + }} {\rm{HC}}{{\rm{O}}_{\rm{2}}}{\rm{C}}{{\rm{H}}_{\rm{3}}}
\end{array}\]
Therefore, reactivity decreases in the same order.
Thus, styrene \(\left[\mathrm{H}_{2} \mathrm{C}==\mathrm{CHC}_{6} \mathrm{H}_{5}\right]\) is most reactive.