324614
D-glucose reacts with anhydrous methyl alcohol in the presence of dry \(\mathrm{\mathrm{HCl}}\) gas to form :
1 2, 3, 4, 5, 6-penta -O -methyl D-glucose
2 \(\mathrm{\alpha}\)-methyl D- glucopyranoside
3 \(\mathrm{\beta}\)-methyl D-glucopyranoside
4 Both (2) and (3)
Explanation:
Conceptual Questions
CHXII14:BIOMOLECULES
324615
Assertion : Glucose when treated with \(\mathrm{CH}_{3} \mathrm{OH}\) in presence of dry \(\mathrm{HCl}\) gas gives \(\alpha\) and \(\beta\)-methyl glucosides. Reason : Glucose reacts with phenyl hydrazine to form crystalline osazone.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Due to the ring structure formed by glucose, the carbon atom labeled as \(\left(\mathrm{C}_{1}\right)\) becomes chiral. As a result, glucose exists in two stereoisomeric forms: \(\alpha\)-glucose and \(\beta\)-glucose, corresponding to each stereoisomeric configuration. Furthermore, glucose can form two distinct methyl glucosides, known as \(\alpha\)-methyl glucoside and \(\beta\)-methyl glucoside. These different isomeric forms and derivatives are a result of the variations in the spatial arrangement of atoms around carbon atom \(\left(\mathrm{C}_{1}\right)\) in the glucose molecule. So, option (2) is correct.
CHXII14:BIOMOLECULES
324616
Assertion : Glucose gives reddish brown precipitate with Fehling solution. Reason : Reaction of glucose with Fehling solution gives \(\mathrm{CuO}\) and gluconic acid.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are correct.
Explanation:
Glucose gives reddish brown precipitate with Fehling solution consists of \(\mathrm{Cu}^{2+}\) which gets reduced to \(\mathrm{Cu}^{+}\left(\mathrm{Cu}_{2} \mathrm{O}\right)\), not to \(\mathrm{CuO}\). \(\mathop {{{\text{C}}_{\text{6}}}{{\text{H}}_{{\text{12}}}}{{\text{O}}_{\text{6}}}}\limits_{{\text{ Glu cose }}} {\text{ + 2CuO}}\xrightarrow{{{\text{O}}{{\text{H}}^{\text{ - }}}}}{{\text{C}}_{\text{5}}}\mathop {{{\text{H}}_{{\text{11}}}}{{\text{O}}_{\text{5}}}{\text{COOH}}}\limits_{{\text{ Gluconic acid }}} {\text{ + C}}{{\text{u}}_{\text{2}}}{\text{O}}\)
AIIMS - 2017
CHXII14:BIOMOLECULES
324617
D-Glucose reacts with phenylhydrazine to make osazone. How many molecules of phenylhydrazine are used for this reaction per molecule of D-glucose?
324614
D-glucose reacts with anhydrous methyl alcohol in the presence of dry \(\mathrm{\mathrm{HCl}}\) gas to form :
1 2, 3, 4, 5, 6-penta -O -methyl D-glucose
2 \(\mathrm{\alpha}\)-methyl D- glucopyranoside
3 \(\mathrm{\beta}\)-methyl D-glucopyranoside
4 Both (2) and (3)
Explanation:
Conceptual Questions
CHXII14:BIOMOLECULES
324615
Assertion : Glucose when treated with \(\mathrm{CH}_{3} \mathrm{OH}\) in presence of dry \(\mathrm{HCl}\) gas gives \(\alpha\) and \(\beta\)-methyl glucosides. Reason : Glucose reacts with phenyl hydrazine to form crystalline osazone.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Due to the ring structure formed by glucose, the carbon atom labeled as \(\left(\mathrm{C}_{1}\right)\) becomes chiral. As a result, glucose exists in two stereoisomeric forms: \(\alpha\)-glucose and \(\beta\)-glucose, corresponding to each stereoisomeric configuration. Furthermore, glucose can form two distinct methyl glucosides, known as \(\alpha\)-methyl glucoside and \(\beta\)-methyl glucoside. These different isomeric forms and derivatives are a result of the variations in the spatial arrangement of atoms around carbon atom \(\left(\mathrm{C}_{1}\right)\) in the glucose molecule. So, option (2) is correct.
CHXII14:BIOMOLECULES
324616
Assertion : Glucose gives reddish brown precipitate with Fehling solution. Reason : Reaction of glucose with Fehling solution gives \(\mathrm{CuO}\) and gluconic acid.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are correct.
Explanation:
Glucose gives reddish brown precipitate with Fehling solution consists of \(\mathrm{Cu}^{2+}\) which gets reduced to \(\mathrm{Cu}^{+}\left(\mathrm{Cu}_{2} \mathrm{O}\right)\), not to \(\mathrm{CuO}\). \(\mathop {{{\text{C}}_{\text{6}}}{{\text{H}}_{{\text{12}}}}{{\text{O}}_{\text{6}}}}\limits_{{\text{ Glu cose }}} {\text{ + 2CuO}}\xrightarrow{{{\text{O}}{{\text{H}}^{\text{ - }}}}}{{\text{C}}_{\text{5}}}\mathop {{{\text{H}}_{{\text{11}}}}{{\text{O}}_{\text{5}}}{\text{COOH}}}\limits_{{\text{ Gluconic acid }}} {\text{ + C}}{{\text{u}}_{\text{2}}}{\text{O}}\)
AIIMS - 2017
CHXII14:BIOMOLECULES
324617
D-Glucose reacts with phenylhydrazine to make osazone. How many molecules of phenylhydrazine are used for this reaction per molecule of D-glucose?
324614
D-glucose reacts with anhydrous methyl alcohol in the presence of dry \(\mathrm{\mathrm{HCl}}\) gas to form :
1 2, 3, 4, 5, 6-penta -O -methyl D-glucose
2 \(\mathrm{\alpha}\)-methyl D- glucopyranoside
3 \(\mathrm{\beta}\)-methyl D-glucopyranoside
4 Both (2) and (3)
Explanation:
Conceptual Questions
CHXII14:BIOMOLECULES
324615
Assertion : Glucose when treated with \(\mathrm{CH}_{3} \mathrm{OH}\) in presence of dry \(\mathrm{HCl}\) gas gives \(\alpha\) and \(\beta\)-methyl glucosides. Reason : Glucose reacts with phenyl hydrazine to form crystalline osazone.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Due to the ring structure formed by glucose, the carbon atom labeled as \(\left(\mathrm{C}_{1}\right)\) becomes chiral. As a result, glucose exists in two stereoisomeric forms: \(\alpha\)-glucose and \(\beta\)-glucose, corresponding to each stereoisomeric configuration. Furthermore, glucose can form two distinct methyl glucosides, known as \(\alpha\)-methyl glucoside and \(\beta\)-methyl glucoside. These different isomeric forms and derivatives are a result of the variations in the spatial arrangement of atoms around carbon atom \(\left(\mathrm{C}_{1}\right)\) in the glucose molecule. So, option (2) is correct.
CHXII14:BIOMOLECULES
324616
Assertion : Glucose gives reddish brown precipitate with Fehling solution. Reason : Reaction of glucose with Fehling solution gives \(\mathrm{CuO}\) and gluconic acid.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are correct.
Explanation:
Glucose gives reddish brown precipitate with Fehling solution consists of \(\mathrm{Cu}^{2+}\) which gets reduced to \(\mathrm{Cu}^{+}\left(\mathrm{Cu}_{2} \mathrm{O}\right)\), not to \(\mathrm{CuO}\). \(\mathop {{{\text{C}}_{\text{6}}}{{\text{H}}_{{\text{12}}}}{{\text{O}}_{\text{6}}}}\limits_{{\text{ Glu cose }}} {\text{ + 2CuO}}\xrightarrow{{{\text{O}}{{\text{H}}^{\text{ - }}}}}{{\text{C}}_{\text{5}}}\mathop {{{\text{H}}_{{\text{11}}}}{{\text{O}}_{\text{5}}}{\text{COOH}}}\limits_{{\text{ Gluconic acid }}} {\text{ + C}}{{\text{u}}_{\text{2}}}{\text{O}}\)
AIIMS - 2017
CHXII14:BIOMOLECULES
324617
D-Glucose reacts with phenylhydrazine to make osazone. How many molecules of phenylhydrazine are used for this reaction per molecule of D-glucose?
324614
D-glucose reacts with anhydrous methyl alcohol in the presence of dry \(\mathrm{\mathrm{HCl}}\) gas to form :
1 2, 3, 4, 5, 6-penta -O -methyl D-glucose
2 \(\mathrm{\alpha}\)-methyl D- glucopyranoside
3 \(\mathrm{\beta}\)-methyl D-glucopyranoside
4 Both (2) and (3)
Explanation:
Conceptual Questions
CHXII14:BIOMOLECULES
324615
Assertion : Glucose when treated with \(\mathrm{CH}_{3} \mathrm{OH}\) in presence of dry \(\mathrm{HCl}\) gas gives \(\alpha\) and \(\beta\)-methyl glucosides. Reason : Glucose reacts with phenyl hydrazine to form crystalline osazone.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Due to the ring structure formed by glucose, the carbon atom labeled as \(\left(\mathrm{C}_{1}\right)\) becomes chiral. As a result, glucose exists in two stereoisomeric forms: \(\alpha\)-glucose and \(\beta\)-glucose, corresponding to each stereoisomeric configuration. Furthermore, glucose can form two distinct methyl glucosides, known as \(\alpha\)-methyl glucoside and \(\beta\)-methyl glucoside. These different isomeric forms and derivatives are a result of the variations in the spatial arrangement of atoms around carbon atom \(\left(\mathrm{C}_{1}\right)\) in the glucose molecule. So, option (2) is correct.
CHXII14:BIOMOLECULES
324616
Assertion : Glucose gives reddish brown precipitate with Fehling solution. Reason : Reaction of glucose with Fehling solution gives \(\mathrm{CuO}\) and gluconic acid.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Both Assertion and Reason are correct.
Explanation:
Glucose gives reddish brown precipitate with Fehling solution consists of \(\mathrm{Cu}^{2+}\) which gets reduced to \(\mathrm{Cu}^{+}\left(\mathrm{Cu}_{2} \mathrm{O}\right)\), not to \(\mathrm{CuO}\). \(\mathop {{{\text{C}}_{\text{6}}}{{\text{H}}_{{\text{12}}}}{{\text{O}}_{\text{6}}}}\limits_{{\text{ Glu cose }}} {\text{ + 2CuO}}\xrightarrow{{{\text{O}}{{\text{H}}^{\text{ - }}}}}{{\text{C}}_{\text{5}}}\mathop {{{\text{H}}_{{\text{11}}}}{{\text{O}}_{\text{5}}}{\text{COOH}}}\limits_{{\text{ Gluconic acid }}} {\text{ + C}}{{\text{u}}_{\text{2}}}{\text{O}}\)
AIIMS - 2017
CHXII14:BIOMOLECULES
324617
D-Glucose reacts with phenylhydrazine to make osazone. How many molecules of phenylhydrazine are used for this reaction per molecule of D-glucose?
