324600
Fructose reduces Fehling's solution due to the presence of
1 hydroxyl group
2 aldehyde group
3 ketone group
4 alpha-hydroxyketone group
Explanation:
Carbohydrates with \(\mathrm{\alpha}\)-hydroxyketone group reduces Fehling's solution test.
CHXII14:BIOMOLECULES
324601
Assertion : Fructose reduces Fehling's solution and Tollens' reagent. Reason : Fructose does not contain any aldehyde group.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
When fructose is heated with dilute alkali, it undergoes a reaction that leads to the formation of an equilibrium mixture containing glucose, fructose, and mannose. There is isomerization of fructose into glucose and mannose during this process. This transformation is responsible for the reducing properties exhibited by fructose. Fructose has a keto group. So, option (2) is correct.
CHXII14:BIOMOLECULES
324602
Find the correct option listed below: Assertion : Fructose reacts with excess of HI in the presence of red phosphorus to give n-Hexane. Reason : A molecule of fructose has six carbon atoms in the form of unbranched chain.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Fructose reacts with excess of HI in the presence of red phosphorus at 373 K to give n-hexane. HI and red phosphorus is a strong reducing agent which reduces ketonic and alcoholic groups of fructose to \(-\mathrm{CH}_{2}\) group.
CHXII14:BIOMOLECULES
324603
When a monosaccharide forms a cyclic hemiacetal, the carbon atom that contained the carbonyl group is identified as the ____ carbon atom, because
1 D, the carbonyl group is drawn to the right
2 L, the carbonyl group is drawn to the left
3 acetal, it forms bond to an \(-\mathrm{OR}\) and an \(-\mathrm{OR}\) '
4 anomeric, its substituents can assume an \({\rm{\alpha }}\) or \({\rm{\beta }} - \) position.
Explanation:
A pair of stereoisomers which differ in configuration only around \({\text{C}} - 1\) are called anomers and the \(\mathrm{C}-1\) carbon is called the anomeric carbon.
CHXII14:BIOMOLECULES
324604
Match items of column I with those of column II.
324600
Fructose reduces Fehling's solution due to the presence of
1 hydroxyl group
2 aldehyde group
3 ketone group
4 alpha-hydroxyketone group
Explanation:
Carbohydrates with \(\mathrm{\alpha}\)-hydroxyketone group reduces Fehling's solution test.
CHXII14:BIOMOLECULES
324601
Assertion : Fructose reduces Fehling's solution and Tollens' reagent. Reason : Fructose does not contain any aldehyde group.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
When fructose is heated with dilute alkali, it undergoes a reaction that leads to the formation of an equilibrium mixture containing glucose, fructose, and mannose. There is isomerization of fructose into glucose and mannose during this process. This transformation is responsible for the reducing properties exhibited by fructose. Fructose has a keto group. So, option (2) is correct.
CHXII14:BIOMOLECULES
324602
Find the correct option listed below: Assertion : Fructose reacts with excess of HI in the presence of red phosphorus to give n-Hexane. Reason : A molecule of fructose has six carbon atoms in the form of unbranched chain.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Fructose reacts with excess of HI in the presence of red phosphorus at 373 K to give n-hexane. HI and red phosphorus is a strong reducing agent which reduces ketonic and alcoholic groups of fructose to \(-\mathrm{CH}_{2}\) group.
CHXII14:BIOMOLECULES
324603
When a monosaccharide forms a cyclic hemiacetal, the carbon atom that contained the carbonyl group is identified as the ____ carbon atom, because
1 D, the carbonyl group is drawn to the right
2 L, the carbonyl group is drawn to the left
3 acetal, it forms bond to an \(-\mathrm{OR}\) and an \(-\mathrm{OR}\) '
4 anomeric, its substituents can assume an \({\rm{\alpha }}\) or \({\rm{\beta }} - \) position.
Explanation:
A pair of stereoisomers which differ in configuration only around \({\text{C}} - 1\) are called anomers and the \(\mathrm{C}-1\) carbon is called the anomeric carbon.
CHXII14:BIOMOLECULES
324604
Match items of column I with those of column II.
324600
Fructose reduces Fehling's solution due to the presence of
1 hydroxyl group
2 aldehyde group
3 ketone group
4 alpha-hydroxyketone group
Explanation:
Carbohydrates with \(\mathrm{\alpha}\)-hydroxyketone group reduces Fehling's solution test.
CHXII14:BIOMOLECULES
324601
Assertion : Fructose reduces Fehling's solution and Tollens' reagent. Reason : Fructose does not contain any aldehyde group.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
When fructose is heated with dilute alkali, it undergoes a reaction that leads to the formation of an equilibrium mixture containing glucose, fructose, and mannose. There is isomerization of fructose into glucose and mannose during this process. This transformation is responsible for the reducing properties exhibited by fructose. Fructose has a keto group. So, option (2) is correct.
CHXII14:BIOMOLECULES
324602
Find the correct option listed below: Assertion : Fructose reacts with excess of HI in the presence of red phosphorus to give n-Hexane. Reason : A molecule of fructose has six carbon atoms in the form of unbranched chain.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Fructose reacts with excess of HI in the presence of red phosphorus at 373 K to give n-hexane. HI and red phosphorus is a strong reducing agent which reduces ketonic and alcoholic groups of fructose to \(-\mathrm{CH}_{2}\) group.
CHXII14:BIOMOLECULES
324603
When a monosaccharide forms a cyclic hemiacetal, the carbon atom that contained the carbonyl group is identified as the ____ carbon atom, because
1 D, the carbonyl group is drawn to the right
2 L, the carbonyl group is drawn to the left
3 acetal, it forms bond to an \(-\mathrm{OR}\) and an \(-\mathrm{OR}\) '
4 anomeric, its substituents can assume an \({\rm{\alpha }}\) or \({\rm{\beta }} - \) position.
Explanation:
A pair of stereoisomers which differ in configuration only around \({\text{C}} - 1\) are called anomers and the \(\mathrm{C}-1\) carbon is called the anomeric carbon.
CHXII14:BIOMOLECULES
324604
Match items of column I with those of column II.
324600
Fructose reduces Fehling's solution due to the presence of
1 hydroxyl group
2 aldehyde group
3 ketone group
4 alpha-hydroxyketone group
Explanation:
Carbohydrates with \(\mathrm{\alpha}\)-hydroxyketone group reduces Fehling's solution test.
CHXII14:BIOMOLECULES
324601
Assertion : Fructose reduces Fehling's solution and Tollens' reagent. Reason : Fructose does not contain any aldehyde group.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
When fructose is heated with dilute alkali, it undergoes a reaction that leads to the formation of an equilibrium mixture containing glucose, fructose, and mannose. There is isomerization of fructose into glucose and mannose during this process. This transformation is responsible for the reducing properties exhibited by fructose. Fructose has a keto group. So, option (2) is correct.
CHXII14:BIOMOLECULES
324602
Find the correct option listed below: Assertion : Fructose reacts with excess of HI in the presence of red phosphorus to give n-Hexane. Reason : A molecule of fructose has six carbon atoms in the form of unbranched chain.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Fructose reacts with excess of HI in the presence of red phosphorus at 373 K to give n-hexane. HI and red phosphorus is a strong reducing agent which reduces ketonic and alcoholic groups of fructose to \(-\mathrm{CH}_{2}\) group.
CHXII14:BIOMOLECULES
324603
When a monosaccharide forms a cyclic hemiacetal, the carbon atom that contained the carbonyl group is identified as the ____ carbon atom, because
1 D, the carbonyl group is drawn to the right
2 L, the carbonyl group is drawn to the left
3 acetal, it forms bond to an \(-\mathrm{OR}\) and an \(-\mathrm{OR}\) '
4 anomeric, its substituents can assume an \({\rm{\alpha }}\) or \({\rm{\beta }} - \) position.
Explanation:
A pair of stereoisomers which differ in configuration only around \({\text{C}} - 1\) are called anomers and the \(\mathrm{C}-1\) carbon is called the anomeric carbon.
CHXII14:BIOMOLECULES
324604
Match items of column I with those of column II.
324600
Fructose reduces Fehling's solution due to the presence of
1 hydroxyl group
2 aldehyde group
3 ketone group
4 alpha-hydroxyketone group
Explanation:
Carbohydrates with \(\mathrm{\alpha}\)-hydroxyketone group reduces Fehling's solution test.
CHXII14:BIOMOLECULES
324601
Assertion : Fructose reduces Fehling's solution and Tollens' reagent. Reason : Fructose does not contain any aldehyde group.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
When fructose is heated with dilute alkali, it undergoes a reaction that leads to the formation of an equilibrium mixture containing glucose, fructose, and mannose. There is isomerization of fructose into glucose and mannose during this process. This transformation is responsible for the reducing properties exhibited by fructose. Fructose has a keto group. So, option (2) is correct.
CHXII14:BIOMOLECULES
324602
Find the correct option listed below: Assertion : Fructose reacts with excess of HI in the presence of red phosphorus to give n-Hexane. Reason : A molecule of fructose has six carbon atoms in the form of unbranched chain.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Fructose reacts with excess of HI in the presence of red phosphorus at 373 K to give n-hexane. HI and red phosphorus is a strong reducing agent which reduces ketonic and alcoholic groups of fructose to \(-\mathrm{CH}_{2}\) group.
CHXII14:BIOMOLECULES
324603
When a monosaccharide forms a cyclic hemiacetal, the carbon atom that contained the carbonyl group is identified as the ____ carbon atom, because
1 D, the carbonyl group is drawn to the right
2 L, the carbonyl group is drawn to the left
3 acetal, it forms bond to an \(-\mathrm{OR}\) and an \(-\mathrm{OR}\) '
4 anomeric, its substituents can assume an \({\rm{\alpha }}\) or \({\rm{\beta }} - \) position.
Explanation:
A pair of stereoisomers which differ in configuration only around \({\text{C}} - 1\) are called anomers and the \(\mathrm{C}-1\) carbon is called the anomeric carbon.
CHXII14:BIOMOLECULES
324604
Match items of column I with those of column II.
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