\({\mathrm{(\mathrm{A}-\mathrm{S}) \alpha}}\) - Glucose and \({\mathrm{\alpha}}\)-Galactose differ in configuration of only one asymmetric carbon. So, they are called epimers. \({\mathrm{(\mathrm{B}-\mathrm{R}) \alpha}}\) and \({\mathrm{\beta}}\)-Glucose differ at anomeric carbon, thus they are anomers. (C - P) \({\mathrm{\alpha}}\) - Glucose and \({\mathrm{\alpha}}\) - Fructose are functional isomers, as they have aldehyde & ketone functional groups respectively. (D - Q) Ribose is pentose and glucose is hexose, so they are homologous.So, the correct option is (3).
JEE Main - 2024
CHXII14:BIOMOLECULES
324515
The correct set of stereochemical relationship amongst the following monosaccharides is
1 (I) and (III) are anomers; (III) and (IV) are epimers.
2 (I) and (II) are epimers; (III) and (IV) are anomers.
3 (I) and (III) are anomers; (I) and (II) are epimers.
4 (I) and (III) are epimers; (II) and (IV) are anomers.
Explanation:
(I) and (II) differ in configuration at \({{\text{C}}_{\text{1}}}\) and hence are anomers while (I) and (III) differ in configuration at \({{\text{C}}_{\text{4}}}\) and hence are epimers.
CHXII14:BIOMOLECULES
324516
Glucose and fructose are
1 Optical isomers
2 Tautomers
3 Functional isomers
4 Chain isomers
Explanation:
Glucose and fructose are functional isomers.
CHXII14:BIOMOLECULES
324517
Three cyclic structures of monosaccharides are given below which of these are anomers.
\({\mathrm{(\mathrm{A}-\mathrm{S}) \alpha}}\) - Glucose and \({\mathrm{\alpha}}\)-Galactose differ in configuration of only one asymmetric carbon. So, they are called epimers. \({\mathrm{(\mathrm{B}-\mathrm{R}) \alpha}}\) and \({\mathrm{\beta}}\)-Glucose differ at anomeric carbon, thus they are anomers. (C - P) \({\mathrm{\alpha}}\) - Glucose and \({\mathrm{\alpha}}\) - Fructose are functional isomers, as they have aldehyde & ketone functional groups respectively. (D - Q) Ribose is pentose and glucose is hexose, so they are homologous.So, the correct option is (3).
JEE Main - 2024
CHXII14:BIOMOLECULES
324515
The correct set of stereochemical relationship amongst the following monosaccharides is
1 (I) and (III) are anomers; (III) and (IV) are epimers.
2 (I) and (II) are epimers; (III) and (IV) are anomers.
3 (I) and (III) are anomers; (I) and (II) are epimers.
4 (I) and (III) are epimers; (II) and (IV) are anomers.
Explanation:
(I) and (II) differ in configuration at \({{\text{C}}_{\text{1}}}\) and hence are anomers while (I) and (III) differ in configuration at \({{\text{C}}_{\text{4}}}\) and hence are epimers.
CHXII14:BIOMOLECULES
324516
Glucose and fructose are
1 Optical isomers
2 Tautomers
3 Functional isomers
4 Chain isomers
Explanation:
Glucose and fructose are functional isomers.
CHXII14:BIOMOLECULES
324517
Three cyclic structures of monosaccharides are given below which of these are anomers.
\({\mathrm{(\mathrm{A}-\mathrm{S}) \alpha}}\) - Glucose and \({\mathrm{\alpha}}\)-Galactose differ in configuration of only one asymmetric carbon. So, they are called epimers. \({\mathrm{(\mathrm{B}-\mathrm{R}) \alpha}}\) and \({\mathrm{\beta}}\)-Glucose differ at anomeric carbon, thus they are anomers. (C - P) \({\mathrm{\alpha}}\) - Glucose and \({\mathrm{\alpha}}\) - Fructose are functional isomers, as they have aldehyde & ketone functional groups respectively. (D - Q) Ribose is pentose and glucose is hexose, so they are homologous.So, the correct option is (3).
JEE Main - 2024
CHXII14:BIOMOLECULES
324515
The correct set of stereochemical relationship amongst the following monosaccharides is
1 (I) and (III) are anomers; (III) and (IV) are epimers.
2 (I) and (II) are epimers; (III) and (IV) are anomers.
3 (I) and (III) are anomers; (I) and (II) are epimers.
4 (I) and (III) are epimers; (II) and (IV) are anomers.
Explanation:
(I) and (II) differ in configuration at \({{\text{C}}_{\text{1}}}\) and hence are anomers while (I) and (III) differ in configuration at \({{\text{C}}_{\text{4}}}\) and hence are epimers.
CHXII14:BIOMOLECULES
324516
Glucose and fructose are
1 Optical isomers
2 Tautomers
3 Functional isomers
4 Chain isomers
Explanation:
Glucose and fructose are functional isomers.
CHXII14:BIOMOLECULES
324517
Three cyclic structures of monosaccharides are given below which of these are anomers.
\({\mathrm{(\mathrm{A}-\mathrm{S}) \alpha}}\) - Glucose and \({\mathrm{\alpha}}\)-Galactose differ in configuration of only one asymmetric carbon. So, they are called epimers. \({\mathrm{(\mathrm{B}-\mathrm{R}) \alpha}}\) and \({\mathrm{\beta}}\)-Glucose differ at anomeric carbon, thus they are anomers. (C - P) \({\mathrm{\alpha}}\) - Glucose and \({\mathrm{\alpha}}\) - Fructose are functional isomers, as they have aldehyde & ketone functional groups respectively. (D - Q) Ribose is pentose and glucose is hexose, so they are homologous.So, the correct option is (3).
JEE Main - 2024
CHXII14:BIOMOLECULES
324515
The correct set of stereochemical relationship amongst the following monosaccharides is
1 (I) and (III) are anomers; (III) and (IV) are epimers.
2 (I) and (II) are epimers; (III) and (IV) are anomers.
3 (I) and (III) are anomers; (I) and (II) are epimers.
4 (I) and (III) are epimers; (II) and (IV) are anomers.
Explanation:
(I) and (II) differ in configuration at \({{\text{C}}_{\text{1}}}\) and hence are anomers while (I) and (III) differ in configuration at \({{\text{C}}_{\text{4}}}\) and hence are epimers.
CHXII14:BIOMOLECULES
324516
Glucose and fructose are
1 Optical isomers
2 Tautomers
3 Functional isomers
4 Chain isomers
Explanation:
Glucose and fructose are functional isomers.
CHXII14:BIOMOLECULES
324517
Three cyclic structures of monosaccharides are given below which of these are anomers.
