QBManager

CHXII13:AMINES

324067 Match Column I with Column II.
supporting img

Choose the correct answer from the options given below:

1 A - R, B - S, C - Q , D - P

2 A - R, B - Q , C - S, D - P

3 A - P, B - S, C - Q , D - R

4 A - R, B - Q , C - P, D - S

Explanation:

Stronger the base, higher the value of $K_{b}$ and lower will be the value of ${pK}_{b}$ .
The decreasing order of basic strength of given amines is
${(C_{2} H_{5})}_{2} NH > {(C_{2} H_{5})}_{3} N$
$> C_{2} H_{5} {NH}_{2} > C_{6} H_{5} {NH}_{2}$
Hence, the order of ${pK}_{b}$ will be
supporting img

JEE - 2023

CHXII13:AMINES

324068 Which of the following amine is weakest base?

1 Trimethyl amine

2 Methyl amine

3 Diethyl amine

4 Aniline

MHTCET - 2021

CHXII13:AMINES

324069 Which of the following orders is correct regarding basicity of indicated molecules?

1 N, N- Dimethyltoluidine

> p

- toluidine

>

aniline

> p

- nitroaniline

2 Aniline

> N, N

- dimethyl -

p

- toluidine

>

p

- toluidine

>

aniline

3

p

-Toluidine

> N, N

- dimethyl -

p

- toluidine

>

aniline

> p

- nitroaniline

4 N, N-Dimethyltoluidine

>

aniline

> p

toluidine

> p

- nitroaniline

Explanation:

$- {CH}_{3}$ group is electron releasing group whereas ${NO}_{2}$ group is electron withdrawing group.

CHXII13:AMINES

324070 The one which is least basic is

1

{NH}_{3}

2

C_{6} H_{5} {NH}_{2}

3

{(C_{6} H_{5})}_{3} N

4

{(C_{6} H_{5})}_{2} NH

Explanation:

Presence of electron withdrawing group like phenyl group decreases the electron density of nitrogen and hence, the lone pair of nitrogen is not available for donation.
Thus, ${(C_{6} H_{5})}_{3} N$ is least basic because of the presence of three electron withdrawing phenyl groups.

CHXII13:AMINES

324071 Pyridine is less basic than triethylamine because

1 Pyridine has aromatic character

2 Nitrogen in pyridine is

{sp}^{2} -

hybridised

3 Pyridine is a cyclic system

4 In pyridine lone pair of nitrogen is delocalised

Explanation:

Triethylamine is highly basic (in gaseous state or in non - polar medium) due to $+ I$ - effect of $- C_{2} H_{5}$ groups which increases electron density over $N$ atom where as in pyridine electorn density over $N$ atom is less due to resonance.
supporting img

AIIMS - 2005

CHXII13:AMINES

324067 Match Column I with Column II.
supporting img

Choose the correct answer from the options given below:

1 A - R, B - S, C - Q , D - P

2 A - R, B - Q , C - S, D - P

3 A - P, B - S, C - Q , D - R

4 A - R, B - Q , C - P, D - S

Explanation:

Stronger the base, higher the value of $K_{b}$ and lower will be the value of ${pK}_{b}$ .
The decreasing order of basic strength of given amines is
${(C_{2} H_{5})}_{2} NH > {(C_{2} H_{5})}_{3} N$
$> C_{2} H_{5} {NH}_{2} > C_{6} H_{5} {NH}_{2}$
Hence, the order of ${pK}_{b}$ will be
supporting img

JEE - 2023

CHXII13:AMINES

324068 Which of the following amine is weakest base?

1 Trimethyl amine

2 Methyl amine

3 Diethyl amine

4 Aniline

MHTCET - 2021

CHXII13:AMINES

324069 Which of the following orders is correct regarding basicity of indicated molecules?

1 N, N- Dimethyltoluidine

> p

- toluidine

>

aniline

> p

- nitroaniline

2 Aniline

> N, N

- dimethyl -

p

- toluidine

>

p

- toluidine

>

aniline

3

p

-Toluidine

> N, N

- dimethyl -

p

- toluidine

>

aniline

> p

- nitroaniline

4 N, N-Dimethyltoluidine

>

aniline

> p

toluidine

> p

- nitroaniline

Explanation:

$- {CH}_{3}$ group is electron releasing group whereas ${NO}_{2}$ group is electron withdrawing group.

CHXII13:AMINES

324070 The one which is least basic is

1

{NH}_{3}

2

C_{6} H_{5} {NH}_{2}

3

{(C_{6} H_{5})}_{3} N

4

{(C_{6} H_{5})}_{2} NH

Explanation:

Presence of electron withdrawing group like phenyl group decreases the electron density of nitrogen and hence, the lone pair of nitrogen is not available for donation.
Thus, ${(C_{6} H_{5})}_{3} N$ is least basic because of the presence of three electron withdrawing phenyl groups.

CHXII13:AMINES

324071 Pyridine is less basic than triethylamine because

1 Pyridine has aromatic character

2 Nitrogen in pyridine is

{sp}^{2} -

hybridised

3 Pyridine is a cyclic system

4 In pyridine lone pair of nitrogen is delocalised

Explanation:

Triethylamine is highly basic (in gaseous state or in non - polar medium) due to $+ I$ - effect of $- C_{2} H_{5}$ groups which increases electron density over $N$ atom where as in pyridine electorn density over $N$ atom is less due to resonance.
supporting img

AIIMS - 2005

CHXII13:AMINES

324067 Match Column I with Column II.
supporting img

Choose the correct answer from the options given below:

1 A - R, B - S, C - Q , D - P

2 A - R, B - Q , C - S, D - P

3 A - P, B - S, C - Q , D - R

4 A - R, B - Q , C - P, D - S

Explanation:

Stronger the base, higher the value of $K_{b}$ and lower will be the value of ${pK}_{b}$ .
The decreasing order of basic strength of given amines is
${(C_{2} H_{5})}_{2} NH > {(C_{2} H_{5})}_{3} N$
$> C_{2} H_{5} {NH}_{2} > C_{6} H_{5} {NH}_{2}$
Hence, the order of ${pK}_{b}$ will be
supporting img

JEE - 2023

CHXII13:AMINES

324068 Which of the following amine is weakest base?

1 Trimethyl amine

2 Methyl amine

3 Diethyl amine

4 Aniline

MHTCET - 2021

CHXII13:AMINES

324069 Which of the following orders is correct regarding basicity of indicated molecules?

1 N, N- Dimethyltoluidine

> p

- toluidine

>

aniline

> p

- nitroaniline

2 Aniline

> N, N

- dimethyl -

p

- toluidine

>

p

- toluidine

>

aniline

3

p

-Toluidine

> N, N

- dimethyl -

p

- toluidine

>

aniline

> p

- nitroaniline

4 N, N-Dimethyltoluidine

>

aniline

> p

toluidine

> p

- nitroaniline

Explanation:

$- {CH}_{3}$ group is electron releasing group whereas ${NO}_{2}$ group is electron withdrawing group.

CHXII13:AMINES

324070 The one which is least basic is

1

{NH}_{3}

2

C_{6} H_{5} {NH}_{2}

3

{(C_{6} H_{5})}_{3} N

4

{(C_{6} H_{5})}_{2} NH

Explanation:

Presence of electron withdrawing group like phenyl group decreases the electron density of nitrogen and hence, the lone pair of nitrogen is not available for donation.
Thus, ${(C_{6} H_{5})}_{3} N$ is least basic because of the presence of three electron withdrawing phenyl groups.

CHXII13:AMINES

324071 Pyridine is less basic than triethylamine because

1 Pyridine has aromatic character

2 Nitrogen in pyridine is

{sp}^{2} -

hybridised

3 Pyridine is a cyclic system

4 In pyridine lone pair of nitrogen is delocalised

Explanation:

Triethylamine is highly basic (in gaseous state or in non - polar medium) due to $+ I$ - effect of $- C_{2} H_{5}$ groups which increases electron density over $N$ atom where as in pyridine electorn density over $N$ atom is less due to resonance.
supporting img

AIIMS - 2005

CHXII13:AMINES

324067 Match Column I with Column II.
supporting img

Choose the correct answer from the options given below:

1 A - R, B - S, C - Q , D - P

2 A - R, B - Q , C - S, D - P

3 A - P, B - S, C - Q , D - R

4 A - R, B - Q , C - P, D - S

Explanation:

Stronger the base, higher the value of $K_{b}$ and lower will be the value of ${pK}_{b}$ .
The decreasing order of basic strength of given amines is
${(C_{2} H_{5})}_{2} NH > {(C_{2} H_{5})}_{3} N$
$> C_{2} H_{5} {NH}_{2} > C_{6} H_{5} {NH}_{2}$
Hence, the order of ${pK}_{b}$ will be
supporting img

JEE - 2023

CHXII13:AMINES

324068 Which of the following amine is weakest base?

1 Trimethyl amine

2 Methyl amine

3 Diethyl amine

4 Aniline

MHTCET - 2021

CHXII13:AMINES

324069 Which of the following orders is correct regarding basicity of indicated molecules?

1 N, N- Dimethyltoluidine

> p

- toluidine

>

aniline

> p

- nitroaniline

2 Aniline

> N, N

- dimethyl -

p

- toluidine

>

p

- toluidine

>

aniline

3

p

-Toluidine

> N, N

- dimethyl -

p

- toluidine

>

aniline

> p

- nitroaniline

4 N, N-Dimethyltoluidine

>

aniline

> p

toluidine

> p

- nitroaniline

Explanation:

$- {CH}_{3}$ group is electron releasing group whereas ${NO}_{2}$ group is electron withdrawing group.

CHXII13:AMINES

324070 The one which is least basic is

1

{NH}_{3}

2

C_{6} H_{5} {NH}_{2}

3

{(C_{6} H_{5})}_{3} N

4

{(C_{6} H_{5})}_{2} NH

Explanation:

Presence of electron withdrawing group like phenyl group decreases the electron density of nitrogen and hence, the lone pair of nitrogen is not available for donation.
Thus, ${(C_{6} H_{5})}_{3} N$ is least basic because of the presence of three electron withdrawing phenyl groups.

CHXII13:AMINES

324071 Pyridine is less basic than triethylamine because

1 Pyridine has aromatic character

2 Nitrogen in pyridine is

{sp}^{2} -

hybridised

3 Pyridine is a cyclic system

4 In pyridine lone pair of nitrogen is delocalised

Explanation:

Triethylamine is highly basic (in gaseous state or in non - polar medium) due to $+ I$ - effect of $- C_{2} H_{5}$ groups which increases electron density over $N$ atom where as in pyridine electorn density over $N$ atom is less due to resonance.
supporting img

AIIMS - 2005

CHXII13:AMINES

324067 Match Column I with Column II.
supporting img

Choose the correct answer from the options given below:

1 A - R, B - S, C - Q , D - P

2 A - R, B - Q , C - S, D - P

3 A - P, B - S, C - Q , D - R

4 A - R, B - Q , C - P, D - S

Explanation:

Stronger the base, higher the value of $K_{b}$ and lower will be the value of ${pK}_{b}$ .
The decreasing order of basic strength of given amines is
${(C_{2} H_{5})}_{2} NH > {(C_{2} H_{5})}_{3} N$
$> C_{2} H_{5} {NH}_{2} > C_{6} H_{5} {NH}_{2}$
Hence, the order of ${pK}_{b}$ will be
supporting img

JEE - 2023

CHXII13:AMINES

324068 Which of the following amine is weakest base?

1 Trimethyl amine

2 Methyl amine

3 Diethyl amine

4 Aniline

MHTCET - 2021

CHXII13:AMINES

324069 Which of the following orders is correct regarding basicity of indicated molecules?

1 N, N- Dimethyltoluidine

> p

- toluidine

>

aniline

> p

- nitroaniline

2 Aniline

> N, N

- dimethyl -

p

- toluidine

>

p

- toluidine

>

aniline

3

p

-Toluidine

> N, N

- dimethyl -

p

- toluidine

>

aniline

> p

- nitroaniline

4 N, N-Dimethyltoluidine

>

aniline

> p

toluidine

> p

- nitroaniline

Explanation:

$- {CH}_{3}$ group is electron releasing group whereas ${NO}_{2}$ group is electron withdrawing group.

CHXII13:AMINES

324070 The one which is least basic is

1

{NH}_{3}

2

C_{6} H_{5} {NH}_{2}

3

{(C_{6} H_{5})}_{3} N

4

{(C_{6} H_{5})}_{2} NH

Explanation:

Presence of electron withdrawing group like phenyl group decreases the electron density of nitrogen and hence, the lone pair of nitrogen is not available for donation.
Thus, ${(C_{6} H_{5})}_{3} N$ is least basic because of the presence of three electron withdrawing phenyl groups.

CHXII13:AMINES

324071 Pyridine is less basic than triethylamine because

1 Pyridine has aromatic character

2 Nitrogen in pyridine is

{sp}^{2} -

hybridised

3 Pyridine is a cyclic system

4 In pyridine lone pair of nitrogen is delocalised

Explanation:

Triethylamine is highly basic (in gaseous state or in non - polar medium) due to $+ I$ - effect of $- C_{2} H_{5}$ groups which increases electron density over $N$ atom where as in pyridine electorn density over $N$ atom is less due to resonance.
supporting img

AIIMS - 2005