324048
Which of the following factors explain the basic strength of amine? (i) Inductive effect (ii) Steric hinderance (iii) Solvation effect (iv) Solubility in organic solvents.
1 (i) and (iv)
2 (i), (ii) and (iii)
3 (ii) and (iii)
4 (ii) and (iv)
Explanation:
Conceptual Questions
CHXII13:AMINES
324049
Which among the following compounds is a weakest base?
1 Phenylmethanamine
2 \(\mathrm{N}\)-Methylaniline
3 Benzenamine
4 N,N-Dimethylaniline
Explanation:
Aniline or benzenamine is weak base due to resonance, compared to alkyl amines.
MHTCET - 2021
CHXII13:AMINES
324050
Arrange the following in the correct order of their basic character in gaseous phase I. \(\mathrm{NH}_{3}\) II. \(\mathrm{RNH}_{2}\) III. \(\mathrm{R}_{2} \mathrm{NH}\) IV. \(\mathrm{R}_{3} \mathrm{~N}\)
1 IV \(>\) III \(>\) II \(>\) I
2 III \(>\) IV \(>\) II \(>\) I
3 III \(>\) II \(>\) IV \(>\) I
4 I \(>\) II \(>\) III \(>\) IV
Explanation:
\(3^{0}>2^{0}>1^{0}>\mathrm{NH}_{3}\) due to + I.E. of alkyl group.
CHXII13:AMINES
324051
The increasing order of basicity of \(\mathrm{RCN}, \mathrm{RCH}=\mathrm{NR}\) and \(\mathrm{RNH}_{2}\) is
In \({\mathrm{\mathrm{RCN}, \mathrm{N}}}\) – atom is sp hybridized. In \({\mathrm{\mathrm{RCH}=\mathrm{NR}, \mathrm{N}}}\)-atom is \({\mathrm{\mathrm{sp}^{2}}}\) hybridized In \({\mathrm{\mathrm{RNH}_{2} \mathrm{~N}}}\)-atom is \({\mathrm{\mathrm{sp}^{3}}}\) hybridized. As ' \({\mathrm{s}}\) ' character increases in hybridization, electro-negativity increases and basicity decreases.
CHXII13:AMINES
324062
The basicity of aniline is less than that of cyclohexylamine. This is due to
1 \(+\mathrm{R}\) effect of \(-\mathrm{NH}_{2}\) group
2 -I effect of \(-\mathrm{NH}_{2}\) group
3 \(-\mathrm{R}\) effect of \(-\mathrm{NH}_{2}\) group
4 hyperconjugation effect
Explanation:
\(-\mathrm{NH}_{2}\) has a \(+\mathrm{R}\) effect, it donates electrons to the benzene ring. As a result of resonance, the lone pair of electrons on the \(\mathrm{N}\) atom gets delocalized over the benzene ring and thus it is less readily available for protonation. Hence aniline is a weaker base than cyclohexyl amine.
324048
Which of the following factors explain the basic strength of amine? (i) Inductive effect (ii) Steric hinderance (iii) Solvation effect (iv) Solubility in organic solvents.
1 (i) and (iv)
2 (i), (ii) and (iii)
3 (ii) and (iii)
4 (ii) and (iv)
Explanation:
Conceptual Questions
CHXII13:AMINES
324049
Which among the following compounds is a weakest base?
1 Phenylmethanamine
2 \(\mathrm{N}\)-Methylaniline
3 Benzenamine
4 N,N-Dimethylaniline
Explanation:
Aniline or benzenamine is weak base due to resonance, compared to alkyl amines.
MHTCET - 2021
CHXII13:AMINES
324050
Arrange the following in the correct order of their basic character in gaseous phase I. \(\mathrm{NH}_{3}\) II. \(\mathrm{RNH}_{2}\) III. \(\mathrm{R}_{2} \mathrm{NH}\) IV. \(\mathrm{R}_{3} \mathrm{~N}\)
1 IV \(>\) III \(>\) II \(>\) I
2 III \(>\) IV \(>\) II \(>\) I
3 III \(>\) II \(>\) IV \(>\) I
4 I \(>\) II \(>\) III \(>\) IV
Explanation:
\(3^{0}>2^{0}>1^{0}>\mathrm{NH}_{3}\) due to + I.E. of alkyl group.
CHXII13:AMINES
324051
The increasing order of basicity of \(\mathrm{RCN}, \mathrm{RCH}=\mathrm{NR}\) and \(\mathrm{RNH}_{2}\) is
In \({\mathrm{\mathrm{RCN}, \mathrm{N}}}\) – atom is sp hybridized. In \({\mathrm{\mathrm{RCH}=\mathrm{NR}, \mathrm{N}}}\)-atom is \({\mathrm{\mathrm{sp}^{2}}}\) hybridized In \({\mathrm{\mathrm{RNH}_{2} \mathrm{~N}}}\)-atom is \({\mathrm{\mathrm{sp}^{3}}}\) hybridized. As ' \({\mathrm{s}}\) ' character increases in hybridization, electro-negativity increases and basicity decreases.
CHXII13:AMINES
324062
The basicity of aniline is less than that of cyclohexylamine. This is due to
1 \(+\mathrm{R}\) effect of \(-\mathrm{NH}_{2}\) group
2 -I effect of \(-\mathrm{NH}_{2}\) group
3 \(-\mathrm{R}\) effect of \(-\mathrm{NH}_{2}\) group
4 hyperconjugation effect
Explanation:
\(-\mathrm{NH}_{2}\) has a \(+\mathrm{R}\) effect, it donates electrons to the benzene ring. As a result of resonance, the lone pair of electrons on the \(\mathrm{N}\) atom gets delocalized over the benzene ring and thus it is less readily available for protonation. Hence aniline is a weaker base than cyclohexyl amine.
324048
Which of the following factors explain the basic strength of amine? (i) Inductive effect (ii) Steric hinderance (iii) Solvation effect (iv) Solubility in organic solvents.
1 (i) and (iv)
2 (i), (ii) and (iii)
3 (ii) and (iii)
4 (ii) and (iv)
Explanation:
Conceptual Questions
CHXII13:AMINES
324049
Which among the following compounds is a weakest base?
1 Phenylmethanamine
2 \(\mathrm{N}\)-Methylaniline
3 Benzenamine
4 N,N-Dimethylaniline
Explanation:
Aniline or benzenamine is weak base due to resonance, compared to alkyl amines.
MHTCET - 2021
CHXII13:AMINES
324050
Arrange the following in the correct order of their basic character in gaseous phase I. \(\mathrm{NH}_{3}\) II. \(\mathrm{RNH}_{2}\) III. \(\mathrm{R}_{2} \mathrm{NH}\) IV. \(\mathrm{R}_{3} \mathrm{~N}\)
1 IV \(>\) III \(>\) II \(>\) I
2 III \(>\) IV \(>\) II \(>\) I
3 III \(>\) II \(>\) IV \(>\) I
4 I \(>\) II \(>\) III \(>\) IV
Explanation:
\(3^{0}>2^{0}>1^{0}>\mathrm{NH}_{3}\) due to + I.E. of alkyl group.
CHXII13:AMINES
324051
The increasing order of basicity of \(\mathrm{RCN}, \mathrm{RCH}=\mathrm{NR}\) and \(\mathrm{RNH}_{2}\) is
In \({\mathrm{\mathrm{RCN}, \mathrm{N}}}\) – atom is sp hybridized. In \({\mathrm{\mathrm{RCH}=\mathrm{NR}, \mathrm{N}}}\)-atom is \({\mathrm{\mathrm{sp}^{2}}}\) hybridized In \({\mathrm{\mathrm{RNH}_{2} \mathrm{~N}}}\)-atom is \({\mathrm{\mathrm{sp}^{3}}}\) hybridized. As ' \({\mathrm{s}}\) ' character increases in hybridization, electro-negativity increases and basicity decreases.
CHXII13:AMINES
324062
The basicity of aniline is less than that of cyclohexylamine. This is due to
1 \(+\mathrm{R}\) effect of \(-\mathrm{NH}_{2}\) group
2 -I effect of \(-\mathrm{NH}_{2}\) group
3 \(-\mathrm{R}\) effect of \(-\mathrm{NH}_{2}\) group
4 hyperconjugation effect
Explanation:
\(-\mathrm{NH}_{2}\) has a \(+\mathrm{R}\) effect, it donates electrons to the benzene ring. As a result of resonance, the lone pair of electrons on the \(\mathrm{N}\) atom gets delocalized over the benzene ring and thus it is less readily available for protonation. Hence aniline is a weaker base than cyclohexyl amine.
324048
Which of the following factors explain the basic strength of amine? (i) Inductive effect (ii) Steric hinderance (iii) Solvation effect (iv) Solubility in organic solvents.
1 (i) and (iv)
2 (i), (ii) and (iii)
3 (ii) and (iii)
4 (ii) and (iv)
Explanation:
Conceptual Questions
CHXII13:AMINES
324049
Which among the following compounds is a weakest base?
1 Phenylmethanamine
2 \(\mathrm{N}\)-Methylaniline
3 Benzenamine
4 N,N-Dimethylaniline
Explanation:
Aniline or benzenamine is weak base due to resonance, compared to alkyl amines.
MHTCET - 2021
CHXII13:AMINES
324050
Arrange the following in the correct order of their basic character in gaseous phase I. \(\mathrm{NH}_{3}\) II. \(\mathrm{RNH}_{2}\) III. \(\mathrm{R}_{2} \mathrm{NH}\) IV. \(\mathrm{R}_{3} \mathrm{~N}\)
1 IV \(>\) III \(>\) II \(>\) I
2 III \(>\) IV \(>\) II \(>\) I
3 III \(>\) II \(>\) IV \(>\) I
4 I \(>\) II \(>\) III \(>\) IV
Explanation:
\(3^{0}>2^{0}>1^{0}>\mathrm{NH}_{3}\) due to + I.E. of alkyl group.
CHXII13:AMINES
324051
The increasing order of basicity of \(\mathrm{RCN}, \mathrm{RCH}=\mathrm{NR}\) and \(\mathrm{RNH}_{2}\) is
In \({\mathrm{\mathrm{RCN}, \mathrm{N}}}\) – atom is sp hybridized. In \({\mathrm{\mathrm{RCH}=\mathrm{NR}, \mathrm{N}}}\)-atom is \({\mathrm{\mathrm{sp}^{2}}}\) hybridized In \({\mathrm{\mathrm{RNH}_{2} \mathrm{~N}}}\)-atom is \({\mathrm{\mathrm{sp}^{3}}}\) hybridized. As ' \({\mathrm{s}}\) ' character increases in hybridization, electro-negativity increases and basicity decreases.
CHXII13:AMINES
324062
The basicity of aniline is less than that of cyclohexylamine. This is due to
1 \(+\mathrm{R}\) effect of \(-\mathrm{NH}_{2}\) group
2 -I effect of \(-\mathrm{NH}_{2}\) group
3 \(-\mathrm{R}\) effect of \(-\mathrm{NH}_{2}\) group
4 hyperconjugation effect
Explanation:
\(-\mathrm{NH}_{2}\) has a \(+\mathrm{R}\) effect, it donates electrons to the benzene ring. As a result of resonance, the lone pair of electrons on the \(\mathrm{N}\) atom gets delocalized over the benzene ring and thus it is less readily available for protonation. Hence aniline is a weaker base than cyclohexyl amine.
324048
Which of the following factors explain the basic strength of amine? (i) Inductive effect (ii) Steric hinderance (iii) Solvation effect (iv) Solubility in organic solvents.
1 (i) and (iv)
2 (i), (ii) and (iii)
3 (ii) and (iii)
4 (ii) and (iv)
Explanation:
Conceptual Questions
CHXII13:AMINES
324049
Which among the following compounds is a weakest base?
1 Phenylmethanamine
2 \(\mathrm{N}\)-Methylaniline
3 Benzenamine
4 N,N-Dimethylaniline
Explanation:
Aniline or benzenamine is weak base due to resonance, compared to alkyl amines.
MHTCET - 2021
CHXII13:AMINES
324050
Arrange the following in the correct order of their basic character in gaseous phase I. \(\mathrm{NH}_{3}\) II. \(\mathrm{RNH}_{2}\) III. \(\mathrm{R}_{2} \mathrm{NH}\) IV. \(\mathrm{R}_{3} \mathrm{~N}\)
1 IV \(>\) III \(>\) II \(>\) I
2 III \(>\) IV \(>\) II \(>\) I
3 III \(>\) II \(>\) IV \(>\) I
4 I \(>\) II \(>\) III \(>\) IV
Explanation:
\(3^{0}>2^{0}>1^{0}>\mathrm{NH}_{3}\) due to + I.E. of alkyl group.
CHXII13:AMINES
324051
The increasing order of basicity of \(\mathrm{RCN}, \mathrm{RCH}=\mathrm{NR}\) and \(\mathrm{RNH}_{2}\) is
In \({\mathrm{\mathrm{RCN}, \mathrm{N}}}\) – atom is sp hybridized. In \({\mathrm{\mathrm{RCH}=\mathrm{NR}, \mathrm{N}}}\)-atom is \({\mathrm{\mathrm{sp}^{2}}}\) hybridized In \({\mathrm{\mathrm{RNH}_{2} \mathrm{~N}}}\)-atom is \({\mathrm{\mathrm{sp}^{3}}}\) hybridized. As ' \({\mathrm{s}}\) ' character increases in hybridization, electro-negativity increases and basicity decreases.
CHXII13:AMINES
324062
The basicity of aniline is less than that of cyclohexylamine. This is due to
1 \(+\mathrm{R}\) effect of \(-\mathrm{NH}_{2}\) group
2 -I effect of \(-\mathrm{NH}_{2}\) group
3 \(-\mathrm{R}\) effect of \(-\mathrm{NH}_{2}\) group
4 hyperconjugation effect
Explanation:
\(-\mathrm{NH}_{2}\) has a \(+\mathrm{R}\) effect, it donates electrons to the benzene ring. As a result of resonance, the lone pair of electrons on the \(\mathrm{N}\) atom gets delocalized over the benzene ring and thus it is less readily available for protonation. Hence aniline is a weaker base than cyclohexyl amine.
