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CHXII13:AMINES

324048 Which of the following factors explain the basic strength of amine?
(i) Inductive effect
(ii) Steric hinderance
(iii) Solvation effect
(iv) Solubility in organic solvents.

1 (i) and (iv)

2 (i), (ii) and (iii)

3 (ii) and (iii)

4 (ii) and (iv)

CHXII13:AMINES

324049 Which among the following compounds is a weakest base?

1 Phenylmethanamine

2

N

-Methylaniline

3 Benzenamine

4 N,N-Dimethylaniline

MHTCET - 2021

CHXII13:AMINES

324050 Arrange the following in the correct order of their basic character in gaseous phase
I. ${NH}_{3}$
II. ${RNH}_{2}$
III. $R_{2} NH$
IV. $R_{3} N$

1 IV

>

III

>

II

>

I

2 III

>

IV

>

II

>

I

3 III

>

II

>

IV

>

I

4 I

>

II

>

III

>

IV

Explanation:

$3^{0} > 2^{0} > 1^{0} > {NH}_{3}$ due to + I.E. of alkyl group.

CHXII13:AMINES

324051 The increasing order of basicity of $RCN, RCH = NR$ and ${RNH}_{2}$ is

1

RCN < RCH = NR < {RNH}_{2}

2

{RNH}_{2} < RCN < RCH = NR

3

RCH = NR < {RNH}_{2} < RCN

4

{RNH}_{2} < RCH = NR < RCN

Explanation:

In $RCN, N$ – atom is sp hybridized. In $RCH = NR, N$ -atom is ${sp}^{2}$ hybridized In ${RNH}_{2} N$ -atom is ${sp}^{3}$ hybridized. As ' $s$ ' character increases in hybridization, electro-negativity increases and basicity decreases.

CHXII13:AMINES

324062 The basicity of aniline is less than that of cyclohexylamine. This is due to

1

+ R

effect of

- {NH}_{2}

group

2 -I effect of

- {NH}_{2}

group

3

- R

effect of

- {NH}_{2}

group

4 hyperconjugation effect

Explanation:

$- {NH}_{2}$ has a $+ R$ effect, it donates electrons to the benzene ring. As a result of resonance, the lone pair of electrons on the $N$ atom gets delocalized over the benzene ring and thus it is less readily available for protonation. Hence aniline is a weaker base than cyclohexyl amine.
supporting img

KCET - 2006

CHXII13:AMINES

324048 Which of the following factors explain the basic strength of amine?
(i) Inductive effect
(ii) Steric hinderance
(iii) Solvation effect
(iv) Solubility in organic solvents.

1 (i) and (iv)

2 (i), (ii) and (iii)

3 (ii) and (iii)

4 (ii) and (iv)

CHXII13:AMINES

324049 Which among the following compounds is a weakest base?

1 Phenylmethanamine

2

N

-Methylaniline

3 Benzenamine

4 N,N-Dimethylaniline

MHTCET - 2021

CHXII13:AMINES

324050 Arrange the following in the correct order of their basic character in gaseous phase
I. ${NH}_{3}$
II. ${RNH}_{2}$
III. $R_{2} NH$
IV. $R_{3} N$

1 IV

>

III

>

II

>

I

2 III

>

IV

>

II

>

I

3 III

>

II

>

IV

>

I

4 I

>

II

>

III

>

IV

Explanation:

$3^{0} > 2^{0} > 1^{0} > {NH}_{3}$ due to + I.E. of alkyl group.

CHXII13:AMINES

324051 The increasing order of basicity of $RCN, RCH = NR$ and ${RNH}_{2}$ is

1

RCN < RCH = NR < {RNH}_{2}

2

{RNH}_{2} < RCN < RCH = NR

3

RCH = NR < {RNH}_{2} < RCN

4

{RNH}_{2} < RCH = NR < RCN

Explanation:

In $RCN, N$ – atom is sp hybridized. In $RCH = NR, N$ -atom is ${sp}^{2}$ hybridized In ${RNH}_{2} N$ -atom is ${sp}^{3}$ hybridized. As ' $s$ ' character increases in hybridization, electro-negativity increases and basicity decreases.

CHXII13:AMINES

324062 The basicity of aniline is less than that of cyclohexylamine. This is due to

1

+ R

effect of

- {NH}_{2}

group

2 -I effect of

- {NH}_{2}

group

3

- R

effect of

- {NH}_{2}

group

4 hyperconjugation effect

Explanation:

$- {NH}_{2}$ has a $+ R$ effect, it donates electrons to the benzene ring. As a result of resonance, the lone pair of electrons on the $N$ atom gets delocalized over the benzene ring and thus it is less readily available for protonation. Hence aniline is a weaker base than cyclohexyl amine.
supporting img

KCET - 2006

CHXII13:AMINES

324048 Which of the following factors explain the basic strength of amine?
(i) Inductive effect
(ii) Steric hinderance
(iii) Solvation effect
(iv) Solubility in organic solvents.

1 (i) and (iv)

2 (i), (ii) and (iii)

3 (ii) and (iii)

4 (ii) and (iv)

CHXII13:AMINES

324049 Which among the following compounds is a weakest base?

1 Phenylmethanamine

2

N

-Methylaniline

3 Benzenamine

4 N,N-Dimethylaniline

MHTCET - 2021

CHXII13:AMINES

324050 Arrange the following in the correct order of their basic character in gaseous phase
I. ${NH}_{3}$
II. ${RNH}_{2}$
III. $R_{2} NH$
IV. $R_{3} N$

1 IV

>

III

>

II

>

I

2 III

>

IV

>

II

>

I

3 III

>

II

>

IV

>

I

4 I

>

II

>

III

>

IV

Explanation:

$3^{0} > 2^{0} > 1^{0} > {NH}_{3}$ due to + I.E. of alkyl group.

CHXII13:AMINES

324051 The increasing order of basicity of $RCN, RCH = NR$ and ${RNH}_{2}$ is

1

RCN < RCH = NR < {RNH}_{2}

2

{RNH}_{2} < RCN < RCH = NR

3

RCH = NR < {RNH}_{2} < RCN

4

{RNH}_{2} < RCH = NR < RCN

Explanation:

In $RCN, N$ – atom is sp hybridized. In $RCH = NR, N$ -atom is ${sp}^{2}$ hybridized In ${RNH}_{2} N$ -atom is ${sp}^{3}$ hybridized. As ' $s$ ' character increases in hybridization, electro-negativity increases and basicity decreases.

CHXII13:AMINES

324062 The basicity of aniline is less than that of cyclohexylamine. This is due to

1

+ R

effect of

- {NH}_{2}

group

2 -I effect of

- {NH}_{2}

group

3

- R

effect of

- {NH}_{2}

group

4 hyperconjugation effect

Explanation:

$- {NH}_{2}$ has a $+ R$ effect, it donates electrons to the benzene ring. As a result of resonance, the lone pair of electrons on the $N$ atom gets delocalized over the benzene ring and thus it is less readily available for protonation. Hence aniline is a weaker base than cyclohexyl amine.
supporting img

KCET - 2006

CHXII13:AMINES

324048 Which of the following factors explain the basic strength of amine?
(i) Inductive effect
(ii) Steric hinderance
(iii) Solvation effect
(iv) Solubility in organic solvents.

1 (i) and (iv)

2 (i), (ii) and (iii)

3 (ii) and (iii)

4 (ii) and (iv)

CHXII13:AMINES

324049 Which among the following compounds is a weakest base?

1 Phenylmethanamine

2

N

-Methylaniline

3 Benzenamine

4 N,N-Dimethylaniline

MHTCET - 2021

CHXII13:AMINES

324050 Arrange the following in the correct order of their basic character in gaseous phase
I. ${NH}_{3}$
II. ${RNH}_{2}$
III. $R_{2} NH$
IV. $R_{3} N$

1 IV

>

III

>

II

>

I

2 III

>

IV

>

II

>

I

3 III

>

II

>

IV

>

I

4 I

>

II

>

III

>

IV

Explanation:

$3^{0} > 2^{0} > 1^{0} > {NH}_{3}$ due to + I.E. of alkyl group.

CHXII13:AMINES

324051 The increasing order of basicity of $RCN, RCH = NR$ and ${RNH}_{2}$ is

1

RCN < RCH = NR < {RNH}_{2}

2

{RNH}_{2} < RCN < RCH = NR

3

RCH = NR < {RNH}_{2} < RCN

4

{RNH}_{2} < RCH = NR < RCN

Explanation:

In $RCN, N$ – atom is sp hybridized. In $RCH = NR, N$ -atom is ${sp}^{2}$ hybridized In ${RNH}_{2} N$ -atom is ${sp}^{3}$ hybridized. As ' $s$ ' character increases in hybridization, electro-negativity increases and basicity decreases.

CHXII13:AMINES

324062 The basicity of aniline is less than that of cyclohexylamine. This is due to

1

+ R

effect of

- {NH}_{2}

group

2 -I effect of

- {NH}_{2}

group

3

- R

effect of

- {NH}_{2}

group

4 hyperconjugation effect

Explanation:

$- {NH}_{2}$ has a $+ R$ effect, it donates electrons to the benzene ring. As a result of resonance, the lone pair of electrons on the $N$ atom gets delocalized over the benzene ring and thus it is less readily available for protonation. Hence aniline is a weaker base than cyclohexyl amine.
supporting img

KCET - 2006

CHXII13:AMINES

324048 Which of the following factors explain the basic strength of amine?
(i) Inductive effect
(ii) Steric hinderance
(iii) Solvation effect
(iv) Solubility in organic solvents.

1 (i) and (iv)

2 (i), (ii) and (iii)

3 (ii) and (iii)

4 (ii) and (iv)

CHXII13:AMINES

324049 Which among the following compounds is a weakest base?

1 Phenylmethanamine

2

N

-Methylaniline

3 Benzenamine

4 N,N-Dimethylaniline

MHTCET - 2021

CHXII13:AMINES

324050 Arrange the following in the correct order of their basic character in gaseous phase
I. ${NH}_{3}$
II. ${RNH}_{2}$
III. $R_{2} NH$
IV. $R_{3} N$

1 IV

>

III

>

II

>

I

2 III

>

IV

>

II

>

I

3 III

>

II

>

IV

>

I

4 I

>

II

>

III

>

IV

Explanation:

$3^{0} > 2^{0} > 1^{0} > {NH}_{3}$ due to + I.E. of alkyl group.

CHXII13:AMINES

324051 The increasing order of basicity of $RCN, RCH = NR$ and ${RNH}_{2}$ is

1

RCN < RCH = NR < {RNH}_{2}

2

{RNH}_{2} < RCN < RCH = NR

3

RCH = NR < {RNH}_{2} < RCN

4

{RNH}_{2} < RCH = NR < RCN

Explanation:

In $RCN, N$ – atom is sp hybridized. In $RCH = NR, N$ -atom is ${sp}^{2}$ hybridized In ${RNH}_{2} N$ -atom is ${sp}^{3}$ hybridized. As ' $s$ ' character increases in hybridization, electro-negativity increases and basicity decreases.

CHXII13:AMINES

324062 The basicity of aniline is less than that of cyclohexylamine. This is due to

1

+ R

effect of

- {NH}_{2}

group

2 -I effect of

- {NH}_{2}

group

3

- R

effect of

- {NH}_{2}

group

4 hyperconjugation effect

Explanation:

$- {NH}_{2}$ has a $+ R$ effect, it donates electrons to the benzene ring. As a result of resonance, the lone pair of electrons on the $N$ atom gets delocalized over the benzene ring and thus it is less readily available for protonation. Hence aniline is a weaker base than cyclohexyl amine.
supporting img

KCET - 2006