323483
Trichloroacetaldehyde was subjected to Cannizzaro's reaction by using \(\mathrm{NaOH}\). The mixture of the products contains sodium trichloroacetate ion and another compound. The other compound is
1 2, 2, 2-trichloropropanol
2 chloroform
3 2, 2, 2-trichloroethanol
4 trichloromethanol
Explanation:
Cannizzaro's reaction is given by aldehydes (RCHO) lacking \(\mathrm{H}\) at \(\alpha\) - carbon or lacking \(\alpha\)-carbon (as in \(\mathrm{HCHO}\) ). With \(\mathrm{NaOH}\), there is formation of acid salt \(\left(\mathrm{RCOO}^{-}\right)\)by oxidation and alcohol \(\left(\mathrm{RCH}_{2} \mathrm{OH}\right)\) by reduction. \({\text{2CC}}{{\text{l}}_{\text{3}}}{\text{CHO}}\xrightarrow{{{\text{O}}{{\text{H}}^{{\text{ - }}}}}}{\text{CC}}{{\text{l}}_{\text{3}}}{\text{CO}}{{\text{O}}^{{\text{ - }}}}{\text{ + }}\mathop {{\text{CC}}{{\text{l}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{OH}}}\limits_{{\mkern 1mu} {\text{2,}}\,{\text{2,}}\,{\text{2 - }}{\mkern 1mu} {\mkern 1mu} {\text{trichloro}}\,\,{\text{ethanol}}} \)
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323484
Assertion : Benzaldehyde undergoes aldol condensation. Reason : Aldehydes that do not have \(\alpha\) hydrogen undergo Cannizzaro reaction.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Aldehydes with a hydrogen in the \(\alpha \) -position undergo aldol condensation, forming \(\beta \)-hydroxy aldehydes, known as aldols, through dimerization in the presence of a base at low temperatures. Benzaldehyde, \(\alpha \) - hydrogen. Thus it cannot undergo aldol condensation. Instead, it undergoes Cannizzaro reaction. So the option (4) is correct.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323485
Which of the following will respond to Cannizzaro's reaction?
1 2,2-dimethylpropanal
2 Acetaldehyde
3 Propionaldehyde
4 Cinnamaldehyde
Explanation:
The aldehydes which do not contain \(\alpha\)-hydrogen atom, give Cannizzaro's reaction. 2,2-dimethylpropanal does not contain any \(\alpha\)-hydrogen atom and hence, undergoes Cannizzaro's reaction.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323486
HCHO was treated with a reagent X. The product formed upon hydrolysis in the presence of an acid gave \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\). The reagent \(\mathrm{X}\) is
1 Aqueous \(\mathrm{KOH}\)
2 Alcoholic \(\mathrm{KOH}\)
3 Alcoholic KCN
4 \(\mathrm{CH}_{3} \mathrm{MgI}\).
Explanation:
Formaldehyde reacts with Grignard reagent to give primary alcohol. \({\text{HCHO + C}}{{\text{H}}_{\text{3}}}{\text{MgI}}\xrightarrow[{{{\text{H}}^{\text{ + }}}}]{{{\text{Dry ether}}}}{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{OH}}\)
323483
Trichloroacetaldehyde was subjected to Cannizzaro's reaction by using \(\mathrm{NaOH}\). The mixture of the products contains sodium trichloroacetate ion and another compound. The other compound is
1 2, 2, 2-trichloropropanol
2 chloroform
3 2, 2, 2-trichloroethanol
4 trichloromethanol
Explanation:
Cannizzaro's reaction is given by aldehydes (RCHO) lacking \(\mathrm{H}\) at \(\alpha\) - carbon or lacking \(\alpha\)-carbon (as in \(\mathrm{HCHO}\) ). With \(\mathrm{NaOH}\), there is formation of acid salt \(\left(\mathrm{RCOO}^{-}\right)\)by oxidation and alcohol \(\left(\mathrm{RCH}_{2} \mathrm{OH}\right)\) by reduction. \({\text{2CC}}{{\text{l}}_{\text{3}}}{\text{CHO}}\xrightarrow{{{\text{O}}{{\text{H}}^{{\text{ - }}}}}}{\text{CC}}{{\text{l}}_{\text{3}}}{\text{CO}}{{\text{O}}^{{\text{ - }}}}{\text{ + }}\mathop {{\text{CC}}{{\text{l}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{OH}}}\limits_{{\mkern 1mu} {\text{2,}}\,{\text{2,}}\,{\text{2 - }}{\mkern 1mu} {\mkern 1mu} {\text{trichloro}}\,\,{\text{ethanol}}} \)
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323484
Assertion : Benzaldehyde undergoes aldol condensation. Reason : Aldehydes that do not have \(\alpha\) hydrogen undergo Cannizzaro reaction.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Aldehydes with a hydrogen in the \(\alpha \) -position undergo aldol condensation, forming \(\beta \)-hydroxy aldehydes, known as aldols, through dimerization in the presence of a base at low temperatures. Benzaldehyde, \(\alpha \) - hydrogen. Thus it cannot undergo aldol condensation. Instead, it undergoes Cannizzaro reaction. So the option (4) is correct.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323485
Which of the following will respond to Cannizzaro's reaction?
1 2,2-dimethylpropanal
2 Acetaldehyde
3 Propionaldehyde
4 Cinnamaldehyde
Explanation:
The aldehydes which do not contain \(\alpha\)-hydrogen atom, give Cannizzaro's reaction. 2,2-dimethylpropanal does not contain any \(\alpha\)-hydrogen atom and hence, undergoes Cannizzaro's reaction.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323486
HCHO was treated with a reagent X. The product formed upon hydrolysis in the presence of an acid gave \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\). The reagent \(\mathrm{X}\) is
1 Aqueous \(\mathrm{KOH}\)
2 Alcoholic \(\mathrm{KOH}\)
3 Alcoholic KCN
4 \(\mathrm{CH}_{3} \mathrm{MgI}\).
Explanation:
Formaldehyde reacts with Grignard reagent to give primary alcohol. \({\text{HCHO + C}}{{\text{H}}_{\text{3}}}{\text{MgI}}\xrightarrow[{{{\text{H}}^{\text{ + }}}}]{{{\text{Dry ether}}}}{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{OH}}\)
323483
Trichloroacetaldehyde was subjected to Cannizzaro's reaction by using \(\mathrm{NaOH}\). The mixture of the products contains sodium trichloroacetate ion and another compound. The other compound is
1 2, 2, 2-trichloropropanol
2 chloroform
3 2, 2, 2-trichloroethanol
4 trichloromethanol
Explanation:
Cannizzaro's reaction is given by aldehydes (RCHO) lacking \(\mathrm{H}\) at \(\alpha\) - carbon or lacking \(\alpha\)-carbon (as in \(\mathrm{HCHO}\) ). With \(\mathrm{NaOH}\), there is formation of acid salt \(\left(\mathrm{RCOO}^{-}\right)\)by oxidation and alcohol \(\left(\mathrm{RCH}_{2} \mathrm{OH}\right)\) by reduction. \({\text{2CC}}{{\text{l}}_{\text{3}}}{\text{CHO}}\xrightarrow{{{\text{O}}{{\text{H}}^{{\text{ - }}}}}}{\text{CC}}{{\text{l}}_{\text{3}}}{\text{CO}}{{\text{O}}^{{\text{ - }}}}{\text{ + }}\mathop {{\text{CC}}{{\text{l}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{OH}}}\limits_{{\mkern 1mu} {\text{2,}}\,{\text{2,}}\,{\text{2 - }}{\mkern 1mu} {\mkern 1mu} {\text{trichloro}}\,\,{\text{ethanol}}} \)
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323484
Assertion : Benzaldehyde undergoes aldol condensation. Reason : Aldehydes that do not have \(\alpha\) hydrogen undergo Cannizzaro reaction.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Aldehydes with a hydrogen in the \(\alpha \) -position undergo aldol condensation, forming \(\beta \)-hydroxy aldehydes, known as aldols, through dimerization in the presence of a base at low temperatures. Benzaldehyde, \(\alpha \) - hydrogen. Thus it cannot undergo aldol condensation. Instead, it undergoes Cannizzaro reaction. So the option (4) is correct.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323485
Which of the following will respond to Cannizzaro's reaction?
1 2,2-dimethylpropanal
2 Acetaldehyde
3 Propionaldehyde
4 Cinnamaldehyde
Explanation:
The aldehydes which do not contain \(\alpha\)-hydrogen atom, give Cannizzaro's reaction. 2,2-dimethylpropanal does not contain any \(\alpha\)-hydrogen atom and hence, undergoes Cannizzaro's reaction.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323486
HCHO was treated with a reagent X. The product formed upon hydrolysis in the presence of an acid gave \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\). The reagent \(\mathrm{X}\) is
1 Aqueous \(\mathrm{KOH}\)
2 Alcoholic \(\mathrm{KOH}\)
3 Alcoholic KCN
4 \(\mathrm{CH}_{3} \mathrm{MgI}\).
Explanation:
Formaldehyde reacts with Grignard reagent to give primary alcohol. \({\text{HCHO + C}}{{\text{H}}_{\text{3}}}{\text{MgI}}\xrightarrow[{{{\text{H}}^{\text{ + }}}}]{{{\text{Dry ether}}}}{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{OH}}\)
323483
Trichloroacetaldehyde was subjected to Cannizzaro's reaction by using \(\mathrm{NaOH}\). The mixture of the products contains sodium trichloroacetate ion and another compound. The other compound is
1 2, 2, 2-trichloropropanol
2 chloroform
3 2, 2, 2-trichloroethanol
4 trichloromethanol
Explanation:
Cannizzaro's reaction is given by aldehydes (RCHO) lacking \(\mathrm{H}\) at \(\alpha\) - carbon or lacking \(\alpha\)-carbon (as in \(\mathrm{HCHO}\) ). With \(\mathrm{NaOH}\), there is formation of acid salt \(\left(\mathrm{RCOO}^{-}\right)\)by oxidation and alcohol \(\left(\mathrm{RCH}_{2} \mathrm{OH}\right)\) by reduction. \({\text{2CC}}{{\text{l}}_{\text{3}}}{\text{CHO}}\xrightarrow{{{\text{O}}{{\text{H}}^{{\text{ - }}}}}}{\text{CC}}{{\text{l}}_{\text{3}}}{\text{CO}}{{\text{O}}^{{\text{ - }}}}{\text{ + }}\mathop {{\text{CC}}{{\text{l}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{OH}}}\limits_{{\mkern 1mu} {\text{2,}}\,{\text{2,}}\,{\text{2 - }}{\mkern 1mu} {\mkern 1mu} {\text{trichloro}}\,\,{\text{ethanol}}} \)
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323484
Assertion : Benzaldehyde undergoes aldol condensation. Reason : Aldehydes that do not have \(\alpha\) hydrogen undergo Cannizzaro reaction.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Aldehydes with a hydrogen in the \(\alpha \) -position undergo aldol condensation, forming \(\beta \)-hydroxy aldehydes, known as aldols, through dimerization in the presence of a base at low temperatures. Benzaldehyde, \(\alpha \) - hydrogen. Thus it cannot undergo aldol condensation. Instead, it undergoes Cannizzaro reaction. So the option (4) is correct.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323485
Which of the following will respond to Cannizzaro's reaction?
1 2,2-dimethylpropanal
2 Acetaldehyde
3 Propionaldehyde
4 Cinnamaldehyde
Explanation:
The aldehydes which do not contain \(\alpha\)-hydrogen atom, give Cannizzaro's reaction. 2,2-dimethylpropanal does not contain any \(\alpha\)-hydrogen atom and hence, undergoes Cannizzaro's reaction.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323486
HCHO was treated with a reagent X. The product formed upon hydrolysis in the presence of an acid gave \(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}\). The reagent \(\mathrm{X}\) is
1 Aqueous \(\mathrm{KOH}\)
2 Alcoholic \(\mathrm{KOH}\)
3 Alcoholic KCN
4 \(\mathrm{CH}_{3} \mathrm{MgI}\).
Explanation:
Formaldehyde reacts with Grignard reagent to give primary alcohol. \({\text{HCHO + C}}{{\text{H}}_{\text{3}}}{\text{MgI}}\xrightarrow[{{{\text{H}}^{\text{ + }}}}]{{{\text{Dry ether}}}}{\text{C}}{{\text{H}}_{\text{3}}}{\text{C}}{{\text{H}}_{\text{2}}}{\text{OH}}\)
