323577
An organic compound X is oxidised by using acidified \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\). The product obtained reacts with phenyl hydrazine but does not answer silver mirror test. The possible structure of \(\mathrm{X}\) is
The oxidation product of X reacts with phenyl hydrazine, thus it contains The same product does not answer silver mirror test thus, it is a ketone, because only aldehydes gives this test. Thus the compound \(\mathrm{X}\) must be a \(2^{\circ}\) alcohol, as only secondary alcohols give ketones on oxidation and hence \(\mathrm{X}\) is \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHOH}\).
KCET - 2009
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323578
Match Column I with Column II.
Choose the correct answer from the options given below:
1 A - R, B - S, C - P, D - Q
2 A - S, B - P, C - Q , D - R
3 A - Q , B - S, C - R, D - P
4 A - R, B - S, C - Q , D - P
Explanation:
A - R; Benedict's reagent is a solution of copper sulphate, sodium carbonate and sodium citrate in water. It is a deep-blue alkaline solution used to test for the presence of the aldehyde functional group. B -S; Neutral \(\mathrm{FeCl}_{3}\) solution is used to determine the presence of phenolic group in a given sample. C - Q; Alkaline chloroform solution is used in the isocyanide test, whereas amines when treated with chloroform in the presence of alkali, form isocyanide. D - P; A solution of potassium iodide and sodium hypochlorite is used to detect the presence of functional group. It is iodoform test. So, the correct option is (4).
JEE - 2023
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323579
Isopropyl alcohol on oxidation forms a compound "A" which is less reactive than formaldehyde and acetaldehyde towards nucleophilic substituion reaction. Compound "A" is
1 Acetaldehyde
2 Ethylene
3 Ether
4 Acetone
Explanation:
\(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{3} \rightarrow \mathrm{CH}_{3} \mathrm{COCH}_{3}\) Acetone is less reactive than formaldehyde and acetaldehyde due to + I.E. and steric effect.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323580
Which of the following will react with water?
323577
An organic compound X is oxidised by using acidified \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\). The product obtained reacts with phenyl hydrazine but does not answer silver mirror test. The possible structure of \(\mathrm{X}\) is
The oxidation product of X reacts with phenyl hydrazine, thus it contains The same product does not answer silver mirror test thus, it is a ketone, because only aldehydes gives this test. Thus the compound \(\mathrm{X}\) must be a \(2^{\circ}\) alcohol, as only secondary alcohols give ketones on oxidation and hence \(\mathrm{X}\) is \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHOH}\).
KCET - 2009
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323578
Match Column I with Column II.
Choose the correct answer from the options given below:
1 A - R, B - S, C - P, D - Q
2 A - S, B - P, C - Q , D - R
3 A - Q , B - S, C - R, D - P
4 A - R, B - S, C - Q , D - P
Explanation:
A - R; Benedict's reagent is a solution of copper sulphate, sodium carbonate and sodium citrate in water. It is a deep-blue alkaline solution used to test for the presence of the aldehyde functional group. B -S; Neutral \(\mathrm{FeCl}_{3}\) solution is used to determine the presence of phenolic group in a given sample. C - Q; Alkaline chloroform solution is used in the isocyanide test, whereas amines when treated with chloroform in the presence of alkali, form isocyanide. D - P; A solution of potassium iodide and sodium hypochlorite is used to detect the presence of functional group. It is iodoform test. So, the correct option is (4).
JEE - 2023
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323579
Isopropyl alcohol on oxidation forms a compound "A" which is less reactive than formaldehyde and acetaldehyde towards nucleophilic substituion reaction. Compound "A" is
1 Acetaldehyde
2 Ethylene
3 Ether
4 Acetone
Explanation:
\(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{3} \rightarrow \mathrm{CH}_{3} \mathrm{COCH}_{3}\) Acetone is less reactive than formaldehyde and acetaldehyde due to + I.E. and steric effect.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323580
Which of the following will react with water?
323577
An organic compound X is oxidised by using acidified \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\). The product obtained reacts with phenyl hydrazine but does not answer silver mirror test. The possible structure of \(\mathrm{X}\) is
The oxidation product of X reacts with phenyl hydrazine, thus it contains The same product does not answer silver mirror test thus, it is a ketone, because only aldehydes gives this test. Thus the compound \(\mathrm{X}\) must be a \(2^{\circ}\) alcohol, as only secondary alcohols give ketones on oxidation and hence \(\mathrm{X}\) is \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHOH}\).
KCET - 2009
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323578
Match Column I with Column II.
Choose the correct answer from the options given below:
1 A - R, B - S, C - P, D - Q
2 A - S, B - P, C - Q , D - R
3 A - Q , B - S, C - R, D - P
4 A - R, B - S, C - Q , D - P
Explanation:
A - R; Benedict's reagent is a solution of copper sulphate, sodium carbonate and sodium citrate in water. It is a deep-blue alkaline solution used to test for the presence of the aldehyde functional group. B -S; Neutral \(\mathrm{FeCl}_{3}\) solution is used to determine the presence of phenolic group in a given sample. C - Q; Alkaline chloroform solution is used in the isocyanide test, whereas amines when treated with chloroform in the presence of alkali, form isocyanide. D - P; A solution of potassium iodide and sodium hypochlorite is used to detect the presence of functional group. It is iodoform test. So, the correct option is (4).
JEE - 2023
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323579
Isopropyl alcohol on oxidation forms a compound "A" which is less reactive than formaldehyde and acetaldehyde towards nucleophilic substituion reaction. Compound "A" is
1 Acetaldehyde
2 Ethylene
3 Ether
4 Acetone
Explanation:
\(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{3} \rightarrow \mathrm{CH}_{3} \mathrm{COCH}_{3}\) Acetone is less reactive than formaldehyde and acetaldehyde due to + I.E. and steric effect.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323580
Which of the following will react with water?
323577
An organic compound X is oxidised by using acidified \(\mathrm{K}_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\). The product obtained reacts with phenyl hydrazine but does not answer silver mirror test. The possible structure of \(\mathrm{X}\) is
The oxidation product of X reacts with phenyl hydrazine, thus it contains The same product does not answer silver mirror test thus, it is a ketone, because only aldehydes gives this test. Thus the compound \(\mathrm{X}\) must be a \(2^{\circ}\) alcohol, as only secondary alcohols give ketones on oxidation and hence \(\mathrm{X}\) is \(\left(\mathrm{CH}_{3}\right)_{2} \mathrm{CHOH}\).
KCET - 2009
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323578
Match Column I with Column II.
Choose the correct answer from the options given below:
1 A - R, B - S, C - P, D - Q
2 A - S, B - P, C - Q , D - R
3 A - Q , B - S, C - R, D - P
4 A - R, B - S, C - Q , D - P
Explanation:
A - R; Benedict's reagent is a solution of copper sulphate, sodium carbonate and sodium citrate in water. It is a deep-blue alkaline solution used to test for the presence of the aldehyde functional group. B -S; Neutral \(\mathrm{FeCl}_{3}\) solution is used to determine the presence of phenolic group in a given sample. C - Q; Alkaline chloroform solution is used in the isocyanide test, whereas amines when treated with chloroform in the presence of alkali, form isocyanide. D - P; A solution of potassium iodide and sodium hypochlorite is used to detect the presence of functional group. It is iodoform test. So, the correct option is (4).
JEE - 2023
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323579
Isopropyl alcohol on oxidation forms a compound "A" which is less reactive than formaldehyde and acetaldehyde towards nucleophilic substituion reaction. Compound "A" is
1 Acetaldehyde
2 Ethylene
3 Ether
4 Acetone
Explanation:
\(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{3} \rightarrow \mathrm{CH}_{3} \mathrm{COCH}_{3}\) Acetone is less reactive than formaldehyde and acetaldehyde due to + I.E. and steric effect.
CHXII12:ALDEHYDES KETONES AND CARBOXYLIC ACIDS
323580
Which of the following will react with water?
