NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323287
\({\text{Phenol}}\xrightarrow{{\text{x}}}\) forms a tribromo derivative. " \(\mathrm{X}\) " is
1 bromine in benzene
2 bromine in water
3 potassium bromide solution
4 bromine in carbon tetrachloride at \(0^{0} \mathrm{C}\).
Explanation:
KCET - 2010
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323288
Read the Statement - A and Statement - B carefully to mark the correct options given below Statement A : Picric acid is 2,4,6-trinitrotoluene. Statement B : Phenol-2,4-disulphonic acid is treated with conc. \({\mathrm{\mathrm{HNO}_{3}}}\) to get picric acid.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Statement A is incorrect as 2,4,6- Trinitrophenol is picric acid. When phenol-2,4-disulphonic acid is treated with conc. \({\mathrm{\mathrm{HNO}_{3}}}\) picric acid is obtained. Thus statement B is correct. So, correct option is (2).
JEE Main - 2024
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323289
Identify the product (A) obtained in the following reaction \({\text{Phenol + Concentrated}}\,\,{\text{Nitric}}\,{\text{acid}}\xrightarrow[{{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}}]{{{\text{Concentrated}}}}{\text{A}}\)
1 o-Nitrophenol
2 p-Nitrophenol
3 Mixture of o-Nitrophenol and p-Nitrophenol
4 2,4,-6 Trinitrophenol
Explanation:
Phenol with conc. \(\mathrm{HNO}_{3}\) gives picric acid.
MHTCET - 2021
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323290
Statement A : In case of phenol bromination takes place even in absence of lewis acid whereas bromination of benzene takes place in presence of Lewis acid like \(\mathrm{FeBr}_{3}\). Statement B : - OH group attached to benzene ring is highly deactivating.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both statements are incorrect.
Explanation:
The usual halogenation of benzene takes place in the presence of a Lewis acid. such as \(\mathrm{FeBr}_{3}\), which polarises the halogen molecule. In case of phenol, the polarisation of bromine molecule takes place even in the absence of Lewis acid. It is due to the highly activating effect of \(-\mathrm{OH}\) group attached to the benzene ring.
323287
\({\text{Phenol}}\xrightarrow{{\text{x}}}\) forms a tribromo derivative. " \(\mathrm{X}\) " is
1 bromine in benzene
2 bromine in water
3 potassium bromide solution
4 bromine in carbon tetrachloride at \(0^{0} \mathrm{C}\).
Explanation:
KCET - 2010
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323288
Read the Statement - A and Statement - B carefully to mark the correct options given below Statement A : Picric acid is 2,4,6-trinitrotoluene. Statement B : Phenol-2,4-disulphonic acid is treated with conc. \({\mathrm{\mathrm{HNO}_{3}}}\) to get picric acid.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Statement A is incorrect as 2,4,6- Trinitrophenol is picric acid. When phenol-2,4-disulphonic acid is treated with conc. \({\mathrm{\mathrm{HNO}_{3}}}\) picric acid is obtained. Thus statement B is correct. So, correct option is (2).
JEE Main - 2024
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323289
Identify the product (A) obtained in the following reaction \({\text{Phenol + Concentrated}}\,\,{\text{Nitric}}\,{\text{acid}}\xrightarrow[{{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}}]{{{\text{Concentrated}}}}{\text{A}}\)
1 o-Nitrophenol
2 p-Nitrophenol
3 Mixture of o-Nitrophenol and p-Nitrophenol
4 2,4,-6 Trinitrophenol
Explanation:
Phenol with conc. \(\mathrm{HNO}_{3}\) gives picric acid.
MHTCET - 2021
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323290
Statement A : In case of phenol bromination takes place even in absence of lewis acid whereas bromination of benzene takes place in presence of Lewis acid like \(\mathrm{FeBr}_{3}\). Statement B : - OH group attached to benzene ring is highly deactivating.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both statements are incorrect.
Explanation:
The usual halogenation of benzene takes place in the presence of a Lewis acid. such as \(\mathrm{FeBr}_{3}\), which polarises the halogen molecule. In case of phenol, the polarisation of bromine molecule takes place even in the absence of Lewis acid. It is due to the highly activating effect of \(-\mathrm{OH}\) group attached to the benzene ring.
323287
\({\text{Phenol}}\xrightarrow{{\text{x}}}\) forms a tribromo derivative. " \(\mathrm{X}\) " is
1 bromine in benzene
2 bromine in water
3 potassium bromide solution
4 bromine in carbon tetrachloride at \(0^{0} \mathrm{C}\).
Explanation:
KCET - 2010
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323288
Read the Statement - A and Statement - B carefully to mark the correct options given below Statement A : Picric acid is 2,4,6-trinitrotoluene. Statement B : Phenol-2,4-disulphonic acid is treated with conc. \({\mathrm{\mathrm{HNO}_{3}}}\) to get picric acid.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Statement A is incorrect as 2,4,6- Trinitrophenol is picric acid. When phenol-2,4-disulphonic acid is treated with conc. \({\mathrm{\mathrm{HNO}_{3}}}\) picric acid is obtained. Thus statement B is correct. So, correct option is (2).
JEE Main - 2024
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323289
Identify the product (A) obtained in the following reaction \({\text{Phenol + Concentrated}}\,\,{\text{Nitric}}\,{\text{acid}}\xrightarrow[{{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}}]{{{\text{Concentrated}}}}{\text{A}}\)
1 o-Nitrophenol
2 p-Nitrophenol
3 Mixture of o-Nitrophenol and p-Nitrophenol
4 2,4,-6 Trinitrophenol
Explanation:
Phenol with conc. \(\mathrm{HNO}_{3}\) gives picric acid.
MHTCET - 2021
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323290
Statement A : In case of phenol bromination takes place even in absence of lewis acid whereas bromination of benzene takes place in presence of Lewis acid like \(\mathrm{FeBr}_{3}\). Statement B : - OH group attached to benzene ring is highly deactivating.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both statements are incorrect.
Explanation:
The usual halogenation of benzene takes place in the presence of a Lewis acid. such as \(\mathrm{FeBr}_{3}\), which polarises the halogen molecule. In case of phenol, the polarisation of bromine molecule takes place even in the absence of Lewis acid. It is due to the highly activating effect of \(-\mathrm{OH}\) group attached to the benzene ring.
323287
\({\text{Phenol}}\xrightarrow{{\text{x}}}\) forms a tribromo derivative. " \(\mathrm{X}\) " is
1 bromine in benzene
2 bromine in water
3 potassium bromide solution
4 bromine in carbon tetrachloride at \(0^{0} \mathrm{C}\).
Explanation:
KCET - 2010
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323288
Read the Statement - A and Statement - B carefully to mark the correct options given below Statement A : Picric acid is 2,4,6-trinitrotoluene. Statement B : Phenol-2,4-disulphonic acid is treated with conc. \({\mathrm{\mathrm{HNO}_{3}}}\) to get picric acid.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both Statements are incorrect.
Explanation:
Statement A is incorrect as 2,4,6- Trinitrophenol is picric acid. When phenol-2,4-disulphonic acid is treated with conc. \({\mathrm{\mathrm{HNO}_{3}}}\) picric acid is obtained. Thus statement B is correct. So, correct option is (2).
JEE Main - 2024
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323289
Identify the product (A) obtained in the following reaction \({\text{Phenol + Concentrated}}\,\,{\text{Nitric}}\,{\text{acid}}\xrightarrow[{{{\text{H}}_{\text{2}}}{\text{S}}{{\text{O}}_{\text{4}}}}]{{{\text{Concentrated}}}}{\text{A}}\)
1 o-Nitrophenol
2 p-Nitrophenol
3 Mixture of o-Nitrophenol and p-Nitrophenol
4 2,4,-6 Trinitrophenol
Explanation:
Phenol with conc. \(\mathrm{HNO}_{3}\) gives picric acid.
MHTCET - 2021
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
323290
Statement A : In case of phenol bromination takes place even in absence of lewis acid whereas bromination of benzene takes place in presence of Lewis acid like \(\mathrm{FeBr}_{3}\). Statement B : - OH group attached to benzene ring is highly deactivating.
1 Statement A is correct but Statement B is incorrect.
2 Statement A is incorrect but Statement B is correct.
3 Both statements are correct.
4 Both statements are incorrect.
Explanation:
The usual halogenation of benzene takes place in the presence of a Lewis acid. such as \(\mathrm{FeBr}_{3}\), which polarises the halogen molecule. In case of phenol, the polarisation of bromine molecule takes place even in the absence of Lewis acid. It is due to the highly activating effect of \(-\mathrm{OH}\) group attached to the benzene ring.