322885
In the hydroboration - oxidation reaction of propene with, \(\mathrm{H}_{2} \mathrm{O}_{2}\) and \(\mathrm{NaOH}\), the organic compound formed is :
322887
Propene, \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}\), can be converted to propan-2-ol. Which set of reagents among the following is ideal to effect the conversion?
1 \(\mathrm{B}_{2} \mathrm{H}_{6}\) and alkaline \(\mathrm{H}_{2} \mathrm{O}_{2}\)
2 Alkaline \(\mathrm{KMnO}_{4}\)
3 \(\mathrm{HCl}\) followed by hydrolysis with aqueous \(\mathrm{KOH}\)
4 \(\mathrm{O}_{3} / \mathrm{Zn}\) dust
Explanation:
\(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2}+\mathrm{HCl} \rightarrow \mathrm{CH}_{3} \mathrm{CH}(\mathrm{Cl}) \mathrm{CH}_{3}\) The above product formation is based on Markownikov's rule. \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{Cl}) \mathrm{CH}_{3}+\mathrm{KOH} \rightarrow\) \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{3}+\mathrm{KCl}\)
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322888
The product of the following reaction is
1 1-Pentanol
2 2-Pentanol
3 Pentane
4 1, 2-Pentanediol
Explanation:
Hydroboration-oxidation leads to antiMarkownikoff's hydration, thus pentanol.
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CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322885
In the hydroboration - oxidation reaction of propene with, \(\mathrm{H}_{2} \mathrm{O}_{2}\) and \(\mathrm{NaOH}\), the organic compound formed is :
322887
Propene, \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}\), can be converted to propan-2-ol. Which set of reagents among the following is ideal to effect the conversion?
1 \(\mathrm{B}_{2} \mathrm{H}_{6}\) and alkaline \(\mathrm{H}_{2} \mathrm{O}_{2}\)
2 Alkaline \(\mathrm{KMnO}_{4}\)
3 \(\mathrm{HCl}\) followed by hydrolysis with aqueous \(\mathrm{KOH}\)
4 \(\mathrm{O}_{3} / \mathrm{Zn}\) dust
Explanation:
\(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2}+\mathrm{HCl} \rightarrow \mathrm{CH}_{3} \mathrm{CH}(\mathrm{Cl}) \mathrm{CH}_{3}\) The above product formation is based on Markownikov's rule. \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{Cl}) \mathrm{CH}_{3}+\mathrm{KOH} \rightarrow\) \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{3}+\mathrm{KCl}\)
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322888
The product of the following reaction is
1 1-Pentanol
2 2-Pentanol
3 Pentane
4 1, 2-Pentanediol
Explanation:
Hydroboration-oxidation leads to antiMarkownikoff's hydration, thus pentanol.
322885
In the hydroboration - oxidation reaction of propene with, \(\mathrm{H}_{2} \mathrm{O}_{2}\) and \(\mathrm{NaOH}\), the organic compound formed is :
322887
Propene, \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}\), can be converted to propan-2-ol. Which set of reagents among the following is ideal to effect the conversion?
1 \(\mathrm{B}_{2} \mathrm{H}_{6}\) and alkaline \(\mathrm{H}_{2} \mathrm{O}_{2}\)
2 Alkaline \(\mathrm{KMnO}_{4}\)
3 \(\mathrm{HCl}\) followed by hydrolysis with aqueous \(\mathrm{KOH}\)
4 \(\mathrm{O}_{3} / \mathrm{Zn}\) dust
Explanation:
\(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2}+\mathrm{HCl} \rightarrow \mathrm{CH}_{3} \mathrm{CH}(\mathrm{Cl}) \mathrm{CH}_{3}\) The above product formation is based on Markownikov's rule. \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{Cl}) \mathrm{CH}_{3}+\mathrm{KOH} \rightarrow\) \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{3}+\mathrm{KCl}\)
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322888
The product of the following reaction is
1 1-Pentanol
2 2-Pentanol
3 Pentane
4 1, 2-Pentanediol
Explanation:
Hydroboration-oxidation leads to antiMarkownikoff's hydration, thus pentanol.
322885
In the hydroboration - oxidation reaction of propene with, \(\mathrm{H}_{2} \mathrm{O}_{2}\) and \(\mathrm{NaOH}\), the organic compound formed is :
322887
Propene, \(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}_{2}\), can be converted to propan-2-ol. Which set of reagents among the following is ideal to effect the conversion?
1 \(\mathrm{B}_{2} \mathrm{H}_{6}\) and alkaline \(\mathrm{H}_{2} \mathrm{O}_{2}\)
2 Alkaline \(\mathrm{KMnO}_{4}\)
3 \(\mathrm{HCl}\) followed by hydrolysis with aqueous \(\mathrm{KOH}\)
4 \(\mathrm{O}_{3} / \mathrm{Zn}\) dust
Explanation:
\(\mathrm{CH}_{3} \mathrm{CH}=\mathrm{CH}_{2}+\mathrm{HCl} \rightarrow \mathrm{CH}_{3} \mathrm{CH}(\mathrm{Cl}) \mathrm{CH}_{3}\) The above product formation is based on Markownikov's rule. \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{Cl}) \mathrm{CH}_{3}+\mathrm{KOH} \rightarrow\) \(\mathrm{CH}_{3} \mathrm{CH}(\mathrm{OH}) \mathrm{CH}_{3}+\mathrm{KCl}\)
CHXII11:ALCOHOLS, PHENOLS AND ETHERS
322888
The product of the following reaction is
1 1-Pentanol
2 2-Pentanol
3 Pentane
4 1, 2-Pentanediol
Explanation:
Hydroboration-oxidation leads to antiMarkownikoff's hydration, thus pentanol.