322380
How many ions will be furnished by \(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) ?
1 3
2 4
3 Either (1) or (2)
4 2
Explanation:
\(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) forms the compounds \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}\) or \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2}\). So, the above compound can form 4 or 3 ions in the solution. So, the correct option is (3).
CHXII09:COORDINATION COMPOUNDS
322381
Both \(\mathrm{Co}^{3+}\) and \(\mathrm{Pt}^{4+}\) have a coordination number of six. Which of the following pair of complexes will show approximately the same electrical conductance for their \(0.001 \mathrm{M}\) aqueous solution? (Assume 100 % ionisation)
1 \(\mathrm{CoCl}_{3} .4 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} .4 \mathrm{NH}_{3}\)
2 \(\mathrm{CoCl}_{3} .3 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} .5 \mathrm{NH}_{3}\)
3 \(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} \cdot 3 \mathrm{NH}_{3}\)
4 \(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} \cdot 5 \mathrm{NH}_{3}\)
Explanation:
\(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) is represented as \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}\) Number of ions \(=4\) \(\mathrm{PtCl}_{4} .5 \mathrm{NH}_{3}\) is represented as \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{3}\) Number of ions \(=4\)
CHXII09:COORDINATION COMPOUNDS
322382
On treating 100 mL of 0.1 M aqueous solution of the complex \({\mathrm{\mathrm{CrCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}}}\) with excess of \({\mathrm{\mathrm{AgNO}_{3}, 2.86 \mathrm{~g}}}\) of AgCl was obtained. The complex is
No. of moles of \({\mathrm{\mathrm{AgCl}=\dfrac{2.86}{143}=0.02}}\) moles 0.01 moles of an aqueous solution of\({\mathrm{\mathrm{CrCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}}}\) gives 0.02 moles AgCl means, 1 mole of aqueous solution gives 2 moles of AgCl . so, \({\mathrm{2 \mathrm{Cl}^{-}}}\)ions should satisfy only primary valency and the compound will be \({\mathrm{\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2} \cdot \mathrm{H}_{2} \mathrm{O}}}\)
KCET - 2024
CHXII09:COORDINATION COMPOUNDS
322383
According to Werner's theory, the geometry of the complex is determined by
1 only from the primary valence in space
2 number and position of the primary valency in space
3 number and position of the secondary valency in space
4 only from the position of secondary valence in space
Explanation:
Werner's theory was used to describe the structure and formation of complex compounds or coordination compounds. According to this theory the primary valency gives the oxidation number and the secondary valency gives the coordination number. Also, the geometry of the complex is determined by number and position of secondary valences in space as the ligand satisfying seconday valences are always directed towards fixed position in space.
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CHXII09:COORDINATION COMPOUNDS
322380
How many ions will be furnished by \(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) ?
1 3
2 4
3 Either (1) or (2)
4 2
Explanation:
\(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) forms the compounds \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}\) or \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2}\). So, the above compound can form 4 or 3 ions in the solution. So, the correct option is (3).
CHXII09:COORDINATION COMPOUNDS
322381
Both \(\mathrm{Co}^{3+}\) and \(\mathrm{Pt}^{4+}\) have a coordination number of six. Which of the following pair of complexes will show approximately the same electrical conductance for their \(0.001 \mathrm{M}\) aqueous solution? (Assume 100 % ionisation)
1 \(\mathrm{CoCl}_{3} .4 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} .4 \mathrm{NH}_{3}\)
2 \(\mathrm{CoCl}_{3} .3 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} .5 \mathrm{NH}_{3}\)
3 \(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} \cdot 3 \mathrm{NH}_{3}\)
4 \(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} \cdot 5 \mathrm{NH}_{3}\)
Explanation:
\(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) is represented as \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}\) Number of ions \(=4\) \(\mathrm{PtCl}_{4} .5 \mathrm{NH}_{3}\) is represented as \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{3}\) Number of ions \(=4\)
CHXII09:COORDINATION COMPOUNDS
322382
On treating 100 mL of 0.1 M aqueous solution of the complex \({\mathrm{\mathrm{CrCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}}}\) with excess of \({\mathrm{\mathrm{AgNO}_{3}, 2.86 \mathrm{~g}}}\) of AgCl was obtained. The complex is
No. of moles of \({\mathrm{\mathrm{AgCl}=\dfrac{2.86}{143}=0.02}}\) moles 0.01 moles of an aqueous solution of\({\mathrm{\mathrm{CrCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}}}\) gives 0.02 moles AgCl means, 1 mole of aqueous solution gives 2 moles of AgCl . so, \({\mathrm{2 \mathrm{Cl}^{-}}}\)ions should satisfy only primary valency and the compound will be \({\mathrm{\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2} \cdot \mathrm{H}_{2} \mathrm{O}}}\)
KCET - 2024
CHXII09:COORDINATION COMPOUNDS
322383
According to Werner's theory, the geometry of the complex is determined by
1 only from the primary valence in space
2 number and position of the primary valency in space
3 number and position of the secondary valency in space
4 only from the position of secondary valence in space
Explanation:
Werner's theory was used to describe the structure and formation of complex compounds or coordination compounds. According to this theory the primary valency gives the oxidation number and the secondary valency gives the coordination number. Also, the geometry of the complex is determined by number and position of secondary valences in space as the ligand satisfying seconday valences are always directed towards fixed position in space.
322380
How many ions will be furnished by \(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) ?
1 3
2 4
3 Either (1) or (2)
4 2
Explanation:
\(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) forms the compounds \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}\) or \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2}\). So, the above compound can form 4 or 3 ions in the solution. So, the correct option is (3).
CHXII09:COORDINATION COMPOUNDS
322381
Both \(\mathrm{Co}^{3+}\) and \(\mathrm{Pt}^{4+}\) have a coordination number of six. Which of the following pair of complexes will show approximately the same electrical conductance for their \(0.001 \mathrm{M}\) aqueous solution? (Assume 100 % ionisation)
1 \(\mathrm{CoCl}_{3} .4 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} .4 \mathrm{NH}_{3}\)
2 \(\mathrm{CoCl}_{3} .3 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} .5 \mathrm{NH}_{3}\)
3 \(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} \cdot 3 \mathrm{NH}_{3}\)
4 \(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} \cdot 5 \mathrm{NH}_{3}\)
Explanation:
\(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) is represented as \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}\) Number of ions \(=4\) \(\mathrm{PtCl}_{4} .5 \mathrm{NH}_{3}\) is represented as \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{3}\) Number of ions \(=4\)
CHXII09:COORDINATION COMPOUNDS
322382
On treating 100 mL of 0.1 M aqueous solution of the complex \({\mathrm{\mathrm{CrCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}}}\) with excess of \({\mathrm{\mathrm{AgNO}_{3}, 2.86 \mathrm{~g}}}\) of AgCl was obtained. The complex is
No. of moles of \({\mathrm{\mathrm{AgCl}=\dfrac{2.86}{143}=0.02}}\) moles 0.01 moles of an aqueous solution of\({\mathrm{\mathrm{CrCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}}}\) gives 0.02 moles AgCl means, 1 mole of aqueous solution gives 2 moles of AgCl . so, \({\mathrm{2 \mathrm{Cl}^{-}}}\)ions should satisfy only primary valency and the compound will be \({\mathrm{\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2} \cdot \mathrm{H}_{2} \mathrm{O}}}\)
KCET - 2024
CHXII09:COORDINATION COMPOUNDS
322383
According to Werner's theory, the geometry of the complex is determined by
1 only from the primary valence in space
2 number and position of the primary valency in space
3 number and position of the secondary valency in space
4 only from the position of secondary valence in space
Explanation:
Werner's theory was used to describe the structure and formation of complex compounds or coordination compounds. According to this theory the primary valency gives the oxidation number and the secondary valency gives the coordination number. Also, the geometry of the complex is determined by number and position of secondary valences in space as the ligand satisfying seconday valences are always directed towards fixed position in space.
322380
How many ions will be furnished by \(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) ?
1 3
2 4
3 Either (1) or (2)
4 2
Explanation:
\(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) forms the compounds \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}\) or \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2}\). So, the above compound can form 4 or 3 ions in the solution. So, the correct option is (3).
CHXII09:COORDINATION COMPOUNDS
322381
Both \(\mathrm{Co}^{3+}\) and \(\mathrm{Pt}^{4+}\) have a coordination number of six. Which of the following pair of complexes will show approximately the same electrical conductance for their \(0.001 \mathrm{M}\) aqueous solution? (Assume 100 % ionisation)
1 \(\mathrm{CoCl}_{3} .4 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} .4 \mathrm{NH}_{3}\)
2 \(\mathrm{CoCl}_{3} .3 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} .5 \mathrm{NH}_{3}\)
3 \(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} \cdot 3 \mathrm{NH}_{3}\)
4 \(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) and \(\mathrm{PtCl}_{4} \cdot 5 \mathrm{NH}_{3}\)
Explanation:
\(\mathrm{CoCl}_{3} \cdot 6 \mathrm{NH}_{3}\) is represented as \(\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right] \mathrm{Cl}_{3}\) Number of ions \(=4\) \(\mathrm{PtCl}_{4} .5 \mathrm{NH}_{3}\) is represented as \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{3}\) Number of ions \(=4\)
CHXII09:COORDINATION COMPOUNDS
322382
On treating 100 mL of 0.1 M aqueous solution of the complex \({\mathrm{\mathrm{CrCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}}}\) with excess of \({\mathrm{\mathrm{AgNO}_{3}, 2.86 \mathrm{~g}}}\) of AgCl was obtained. The complex is
No. of moles of \({\mathrm{\mathrm{AgCl}=\dfrac{2.86}{143}=0.02}}\) moles 0.01 moles of an aqueous solution of\({\mathrm{\mathrm{CrCl}_{3} \cdot 6 \mathrm{H}_{2} \mathrm{O}}}\) gives 0.02 moles AgCl means, 1 mole of aqueous solution gives 2 moles of AgCl . so, \({\mathrm{2 \mathrm{Cl}^{-}}}\)ions should satisfy only primary valency and the compound will be \({\mathrm{\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{Cl}\right] \mathrm{Cl}_{2} \cdot \mathrm{H}_{2} \mathrm{O}}}\)
KCET - 2024
CHXII09:COORDINATION COMPOUNDS
322383
According to Werner's theory, the geometry of the complex is determined by
1 only from the primary valence in space
2 number and position of the primary valency in space
3 number and position of the secondary valency in space
4 only from the position of secondary valence in space
Explanation:
Werner's theory was used to describe the structure and formation of complex compounds or coordination compounds. According to this theory the primary valency gives the oxidation number and the secondary valency gives the coordination number. Also, the geometry of the complex is determined by number and position of secondary valences in space as the ligand satisfying seconday valences are always directed towards fixed position in space.