321314
\(\mathrm{KMnO}_{4}\) oxidises \({{\rm{I}}^ - }\) in acidic and neutral/faintly alkaline solution, respectively to
1 \(\mathrm{IO}_{3}^{-}\) and \(\mathrm{IO}_{3}^{-}\)
2 \(\mathrm{I}_{2}\) and \(\mathrm{IO}_{3}^{-}\)
3 \(\mathrm{IO}_{3}^{-}\) and \(\mathrm{I}_{2}\)
4 \(\mathrm{I}_{2}\) and \(\mathrm{I}_{2}\)
Explanation:
\(\mathrm{KMnO}_{4}\) oxidises \(\mathrm{I}^{-}\)in acidic and neutral/ faintly alkaline solution to \(\mathrm{I}_{2}\) and \(\mathrm{IO}_{3}^{-}\), respectively. In acidic solution : \(10{{\rm{I}}^ - } + 2{\rm{MnO}}_4^ - + 16{{\rm{H}}^ + } \to 2{\rm{M}}{{\rm{n}}^{2 + }} + 8{{\rm{H}}_2}{\rm{O}} + 5{{\rm{I}}_2}\) In neutral or faintly alkaline solution : \(2 \mathrm{MnO}_{4}^{-}+\mathrm{H}_{2} \mathrm{O}+\mathrm{I}^{-} \rightarrow 2 \mathrm{MnO}_{2}+2 \mathrm{OH}^{-}+\mathrm{IO}_{3}^{-}\)
JEE - 2023
CHXII08:THE D- & F-BLOCK ELEMENTS
321315
When a solution containing \(\mathrm{\mathrm{Mn}^{2+}}\) is boiled with \(\mathrm{\mathrm{PbO}_{2}}\) and concentrated \(\mathrm{\mathrm{HNO}_{3}}\) for a while and left standing, the supernatant liquid will be pink in colour due to the formation of
1 \(\mathrm{\mathrm{MnO}_{2}}\)
2 potassium permanganate
3 permanganic acid
4 manganic acid
Explanation:
The pink colour is due to permanganic acid, \(\mathrm{\mathrm{HMnO}_{4}}\), which has \(\mathrm{\mathrm{MnO}_{4}^{-}}\)ion in it.
CHXII08:THE D- & F-BLOCK ELEMENTS
321316
\(\mathrm{Mn}^{2+}\) can be converted into \(\mathrm{Mn}^{7+}\) by reacting with
1 \(\mathrm{SO}_{2}\)
2 \(\mathrm{Cl}_{2}\)
3 \(\mathrm{PbO}_{2}\)
4 \(\mathrm{SnCl}_{2}\)
Explanation:
Strong oxidising agents such as \(\mathrm{PbO}_{2}\) or sodium bismuthate \(\left(\mathrm{NaBiO}_{3}\right)\) oxidise \(\mathrm{Mn}^{2+}\) to \(\mathrm{MnO}_{4}^{-}\)or \(\mathrm{Mn}^{7+}\).
CHXII08:THE D- & F-BLOCK ELEMENTS
321317
The electrolysis of potassium manganate solution gives
321314
\(\mathrm{KMnO}_{4}\) oxidises \({{\rm{I}}^ - }\) in acidic and neutral/faintly alkaline solution, respectively to
1 \(\mathrm{IO}_{3}^{-}\) and \(\mathrm{IO}_{3}^{-}\)
2 \(\mathrm{I}_{2}\) and \(\mathrm{IO}_{3}^{-}\)
3 \(\mathrm{IO}_{3}^{-}\) and \(\mathrm{I}_{2}\)
4 \(\mathrm{I}_{2}\) and \(\mathrm{I}_{2}\)
Explanation:
\(\mathrm{KMnO}_{4}\) oxidises \(\mathrm{I}^{-}\)in acidic and neutral/ faintly alkaline solution to \(\mathrm{I}_{2}\) and \(\mathrm{IO}_{3}^{-}\), respectively. In acidic solution : \(10{{\rm{I}}^ - } + 2{\rm{MnO}}_4^ - + 16{{\rm{H}}^ + } \to 2{\rm{M}}{{\rm{n}}^{2 + }} + 8{{\rm{H}}_2}{\rm{O}} + 5{{\rm{I}}_2}\) In neutral or faintly alkaline solution : \(2 \mathrm{MnO}_{4}^{-}+\mathrm{H}_{2} \mathrm{O}+\mathrm{I}^{-} \rightarrow 2 \mathrm{MnO}_{2}+2 \mathrm{OH}^{-}+\mathrm{IO}_{3}^{-}\)
JEE - 2023
CHXII08:THE D- & F-BLOCK ELEMENTS
321315
When a solution containing \(\mathrm{\mathrm{Mn}^{2+}}\) is boiled with \(\mathrm{\mathrm{PbO}_{2}}\) and concentrated \(\mathrm{\mathrm{HNO}_{3}}\) for a while and left standing, the supernatant liquid will be pink in colour due to the formation of
1 \(\mathrm{\mathrm{MnO}_{2}}\)
2 potassium permanganate
3 permanganic acid
4 manganic acid
Explanation:
The pink colour is due to permanganic acid, \(\mathrm{\mathrm{HMnO}_{4}}\), which has \(\mathrm{\mathrm{MnO}_{4}^{-}}\)ion in it.
CHXII08:THE D- & F-BLOCK ELEMENTS
321316
\(\mathrm{Mn}^{2+}\) can be converted into \(\mathrm{Mn}^{7+}\) by reacting with
1 \(\mathrm{SO}_{2}\)
2 \(\mathrm{Cl}_{2}\)
3 \(\mathrm{PbO}_{2}\)
4 \(\mathrm{SnCl}_{2}\)
Explanation:
Strong oxidising agents such as \(\mathrm{PbO}_{2}\) or sodium bismuthate \(\left(\mathrm{NaBiO}_{3}\right)\) oxidise \(\mathrm{Mn}^{2+}\) to \(\mathrm{MnO}_{4}^{-}\)or \(\mathrm{Mn}^{7+}\).
CHXII08:THE D- & F-BLOCK ELEMENTS
321317
The electrolysis of potassium manganate solution gives
321314
\(\mathrm{KMnO}_{4}\) oxidises \({{\rm{I}}^ - }\) in acidic and neutral/faintly alkaline solution, respectively to
1 \(\mathrm{IO}_{3}^{-}\) and \(\mathrm{IO}_{3}^{-}\)
2 \(\mathrm{I}_{2}\) and \(\mathrm{IO}_{3}^{-}\)
3 \(\mathrm{IO}_{3}^{-}\) and \(\mathrm{I}_{2}\)
4 \(\mathrm{I}_{2}\) and \(\mathrm{I}_{2}\)
Explanation:
\(\mathrm{KMnO}_{4}\) oxidises \(\mathrm{I}^{-}\)in acidic and neutral/ faintly alkaline solution to \(\mathrm{I}_{2}\) and \(\mathrm{IO}_{3}^{-}\), respectively. In acidic solution : \(10{{\rm{I}}^ - } + 2{\rm{MnO}}_4^ - + 16{{\rm{H}}^ + } \to 2{\rm{M}}{{\rm{n}}^{2 + }} + 8{{\rm{H}}_2}{\rm{O}} + 5{{\rm{I}}_2}\) In neutral or faintly alkaline solution : \(2 \mathrm{MnO}_{4}^{-}+\mathrm{H}_{2} \mathrm{O}+\mathrm{I}^{-} \rightarrow 2 \mathrm{MnO}_{2}+2 \mathrm{OH}^{-}+\mathrm{IO}_{3}^{-}\)
JEE - 2023
CHXII08:THE D- & F-BLOCK ELEMENTS
321315
When a solution containing \(\mathrm{\mathrm{Mn}^{2+}}\) is boiled with \(\mathrm{\mathrm{PbO}_{2}}\) and concentrated \(\mathrm{\mathrm{HNO}_{3}}\) for a while and left standing, the supernatant liquid will be pink in colour due to the formation of
1 \(\mathrm{\mathrm{MnO}_{2}}\)
2 potassium permanganate
3 permanganic acid
4 manganic acid
Explanation:
The pink colour is due to permanganic acid, \(\mathrm{\mathrm{HMnO}_{4}}\), which has \(\mathrm{\mathrm{MnO}_{4}^{-}}\)ion in it.
CHXII08:THE D- & F-BLOCK ELEMENTS
321316
\(\mathrm{Mn}^{2+}\) can be converted into \(\mathrm{Mn}^{7+}\) by reacting with
1 \(\mathrm{SO}_{2}\)
2 \(\mathrm{Cl}_{2}\)
3 \(\mathrm{PbO}_{2}\)
4 \(\mathrm{SnCl}_{2}\)
Explanation:
Strong oxidising agents such as \(\mathrm{PbO}_{2}\) or sodium bismuthate \(\left(\mathrm{NaBiO}_{3}\right)\) oxidise \(\mathrm{Mn}^{2+}\) to \(\mathrm{MnO}_{4}^{-}\)or \(\mathrm{Mn}^{7+}\).
CHXII08:THE D- & F-BLOCK ELEMENTS
321317
The electrolysis of potassium manganate solution gives
321314
\(\mathrm{KMnO}_{4}\) oxidises \({{\rm{I}}^ - }\) in acidic and neutral/faintly alkaline solution, respectively to
1 \(\mathrm{IO}_{3}^{-}\) and \(\mathrm{IO}_{3}^{-}\)
2 \(\mathrm{I}_{2}\) and \(\mathrm{IO}_{3}^{-}\)
3 \(\mathrm{IO}_{3}^{-}\) and \(\mathrm{I}_{2}\)
4 \(\mathrm{I}_{2}\) and \(\mathrm{I}_{2}\)
Explanation:
\(\mathrm{KMnO}_{4}\) oxidises \(\mathrm{I}^{-}\)in acidic and neutral/ faintly alkaline solution to \(\mathrm{I}_{2}\) and \(\mathrm{IO}_{3}^{-}\), respectively. In acidic solution : \(10{{\rm{I}}^ - } + 2{\rm{MnO}}_4^ - + 16{{\rm{H}}^ + } \to 2{\rm{M}}{{\rm{n}}^{2 + }} + 8{{\rm{H}}_2}{\rm{O}} + 5{{\rm{I}}_2}\) In neutral or faintly alkaline solution : \(2 \mathrm{MnO}_{4}^{-}+\mathrm{H}_{2} \mathrm{O}+\mathrm{I}^{-} \rightarrow 2 \mathrm{MnO}_{2}+2 \mathrm{OH}^{-}+\mathrm{IO}_{3}^{-}\)
JEE - 2023
CHXII08:THE D- & F-BLOCK ELEMENTS
321315
When a solution containing \(\mathrm{\mathrm{Mn}^{2+}}\) is boiled with \(\mathrm{\mathrm{PbO}_{2}}\) and concentrated \(\mathrm{\mathrm{HNO}_{3}}\) for a while and left standing, the supernatant liquid will be pink in colour due to the formation of
1 \(\mathrm{\mathrm{MnO}_{2}}\)
2 potassium permanganate
3 permanganic acid
4 manganic acid
Explanation:
The pink colour is due to permanganic acid, \(\mathrm{\mathrm{HMnO}_{4}}\), which has \(\mathrm{\mathrm{MnO}_{4}^{-}}\)ion in it.
CHXII08:THE D- & F-BLOCK ELEMENTS
321316
\(\mathrm{Mn}^{2+}\) can be converted into \(\mathrm{Mn}^{7+}\) by reacting with
1 \(\mathrm{SO}_{2}\)
2 \(\mathrm{Cl}_{2}\)
3 \(\mathrm{PbO}_{2}\)
4 \(\mathrm{SnCl}_{2}\)
Explanation:
Strong oxidising agents such as \(\mathrm{PbO}_{2}\) or sodium bismuthate \(\left(\mathrm{NaBiO}_{3}\right)\) oxidise \(\mathrm{Mn}^{2+}\) to \(\mathrm{MnO}_{4}^{-}\)or \(\mathrm{Mn}^{7+}\).
CHXII08:THE D- & F-BLOCK ELEMENTS
321317
The electrolysis of potassium manganate solution gives
