Higher the charge on ion, higher is the coagulating (or) flocculating power and lower the flocculating value. So, the correct option is (4).
KCET - 2024
CHXII05:SURFACE CHEMISTRY
320910
The electrolyte having maximum flocculation value for \(\mathrm{AgI} / \mathrm{Ag}^{+}\)sol is
1 \(\mathrm{Na}_{2} \mathrm{~S}\)
2 \(\mathrm{Na}_{3} \mathrm{PO}_{4}\)
3 \(\mathrm{NaCl}\)
4 \(\mathrm{Na}_{2} \mathrm{SO}_{4}\)
Explanation:
Flocculation value is inversley proportional to flocculation power. For the flocculation of positively charged sol \(\mathrm{PO}_{4}^{3-}\) ions have maximum flocculation power while \(\mathrm{Cl}^{-}\)have minimum flocculation power. Hence, \(\mathrm{NaCl}\) will have maximum flocculation value.
KCET - 2015
CHXII05:SURFACE CHEMISTRY
320911
Bleeding due to a cut can be stopped by applying ferric chloride solution in the laboratory. This is due to
1 coagulation of negatively charged blood particles by \(\mathrm{Fe}^{3+}\) ions.
2 coagulation of positively charged blood particles by \(\mathrm{Cl}^{-}\)ions.
3 reaction taking place between ferric ions and the haemoglobin forming a complex.
4 common element, iron, in both \(\mathrm{FeCl}_{3}\) and haemoglobin.
Explanation:
Bleeding due to a cut can be stopped by applying \(\mathrm{FeCl}_{3}\) or alum solution. This is due to coagulation of negatively charged colloidal blood particles (albuminoid substance) by positively charged \(\mathrm{Fe}^{3+}\) ions. These substances are used as styptic (which check the flow of blood).
CHXII05:SURFACE CHEMISTRY
320912
A negatively charged suspension of clay in water will need for precipitation the minimum amount of
1 Aluminium chloride
2 Potassium sulphate
3 Sodiumhydroxide
4 Hydrochloric acid
Explanation:
Negatively charged sols require minium amount of electrolyte having higher valence of cation.
Higher the charge on ion, higher is the coagulating (or) flocculating power and lower the flocculating value. So, the correct option is (4).
KCET - 2024
CHXII05:SURFACE CHEMISTRY
320910
The electrolyte having maximum flocculation value for \(\mathrm{AgI} / \mathrm{Ag}^{+}\)sol is
1 \(\mathrm{Na}_{2} \mathrm{~S}\)
2 \(\mathrm{Na}_{3} \mathrm{PO}_{4}\)
3 \(\mathrm{NaCl}\)
4 \(\mathrm{Na}_{2} \mathrm{SO}_{4}\)
Explanation:
Flocculation value is inversley proportional to flocculation power. For the flocculation of positively charged sol \(\mathrm{PO}_{4}^{3-}\) ions have maximum flocculation power while \(\mathrm{Cl}^{-}\)have minimum flocculation power. Hence, \(\mathrm{NaCl}\) will have maximum flocculation value.
KCET - 2015
CHXII05:SURFACE CHEMISTRY
320911
Bleeding due to a cut can be stopped by applying ferric chloride solution in the laboratory. This is due to
1 coagulation of negatively charged blood particles by \(\mathrm{Fe}^{3+}\) ions.
2 coagulation of positively charged blood particles by \(\mathrm{Cl}^{-}\)ions.
3 reaction taking place between ferric ions and the haemoglobin forming a complex.
4 common element, iron, in both \(\mathrm{FeCl}_{3}\) and haemoglobin.
Explanation:
Bleeding due to a cut can be stopped by applying \(\mathrm{FeCl}_{3}\) or alum solution. This is due to coagulation of negatively charged colloidal blood particles (albuminoid substance) by positively charged \(\mathrm{Fe}^{3+}\) ions. These substances are used as styptic (which check the flow of blood).
CHXII05:SURFACE CHEMISTRY
320912
A negatively charged suspension of clay in water will need for precipitation the minimum amount of
1 Aluminium chloride
2 Potassium sulphate
3 Sodiumhydroxide
4 Hydrochloric acid
Explanation:
Negatively charged sols require minium amount of electrolyte having higher valence of cation.
Higher the charge on ion, higher is the coagulating (or) flocculating power and lower the flocculating value. So, the correct option is (4).
KCET - 2024
CHXII05:SURFACE CHEMISTRY
320910
The electrolyte having maximum flocculation value for \(\mathrm{AgI} / \mathrm{Ag}^{+}\)sol is
1 \(\mathrm{Na}_{2} \mathrm{~S}\)
2 \(\mathrm{Na}_{3} \mathrm{PO}_{4}\)
3 \(\mathrm{NaCl}\)
4 \(\mathrm{Na}_{2} \mathrm{SO}_{4}\)
Explanation:
Flocculation value is inversley proportional to flocculation power. For the flocculation of positively charged sol \(\mathrm{PO}_{4}^{3-}\) ions have maximum flocculation power while \(\mathrm{Cl}^{-}\)have minimum flocculation power. Hence, \(\mathrm{NaCl}\) will have maximum flocculation value.
KCET - 2015
CHXII05:SURFACE CHEMISTRY
320911
Bleeding due to a cut can be stopped by applying ferric chloride solution in the laboratory. This is due to
1 coagulation of negatively charged blood particles by \(\mathrm{Fe}^{3+}\) ions.
2 coagulation of positively charged blood particles by \(\mathrm{Cl}^{-}\)ions.
3 reaction taking place between ferric ions and the haemoglobin forming a complex.
4 common element, iron, in both \(\mathrm{FeCl}_{3}\) and haemoglobin.
Explanation:
Bleeding due to a cut can be stopped by applying \(\mathrm{FeCl}_{3}\) or alum solution. This is due to coagulation of negatively charged colloidal blood particles (albuminoid substance) by positively charged \(\mathrm{Fe}^{3+}\) ions. These substances are used as styptic (which check the flow of blood).
CHXII05:SURFACE CHEMISTRY
320912
A negatively charged suspension of clay in water will need for precipitation the minimum amount of
1 Aluminium chloride
2 Potassium sulphate
3 Sodiumhydroxide
4 Hydrochloric acid
Explanation:
Negatively charged sols require minium amount of electrolyte having higher valence of cation.
Higher the charge on ion, higher is the coagulating (or) flocculating power and lower the flocculating value. So, the correct option is (4).
KCET - 2024
CHXII05:SURFACE CHEMISTRY
320910
The electrolyte having maximum flocculation value for \(\mathrm{AgI} / \mathrm{Ag}^{+}\)sol is
1 \(\mathrm{Na}_{2} \mathrm{~S}\)
2 \(\mathrm{Na}_{3} \mathrm{PO}_{4}\)
3 \(\mathrm{NaCl}\)
4 \(\mathrm{Na}_{2} \mathrm{SO}_{4}\)
Explanation:
Flocculation value is inversley proportional to flocculation power. For the flocculation of positively charged sol \(\mathrm{PO}_{4}^{3-}\) ions have maximum flocculation power while \(\mathrm{Cl}^{-}\)have minimum flocculation power. Hence, \(\mathrm{NaCl}\) will have maximum flocculation value.
KCET - 2015
CHXII05:SURFACE CHEMISTRY
320911
Bleeding due to a cut can be stopped by applying ferric chloride solution in the laboratory. This is due to
1 coagulation of negatively charged blood particles by \(\mathrm{Fe}^{3+}\) ions.
2 coagulation of positively charged blood particles by \(\mathrm{Cl}^{-}\)ions.
3 reaction taking place between ferric ions and the haemoglobin forming a complex.
4 common element, iron, in both \(\mathrm{FeCl}_{3}\) and haemoglobin.
Explanation:
Bleeding due to a cut can be stopped by applying \(\mathrm{FeCl}_{3}\) or alum solution. This is due to coagulation of negatively charged colloidal blood particles (albuminoid substance) by positively charged \(\mathrm{Fe}^{3+}\) ions. These substances are used as styptic (which check the flow of blood).
CHXII05:SURFACE CHEMISTRY
320912
A negatively charged suspension of clay in water will need for precipitation the minimum amount of
1 Aluminium chloride
2 Potassium sulphate
3 Sodiumhydroxide
4 Hydrochloric acid
Explanation:
Negatively charged sols require minium amount of electrolyte having higher valence of cation.