Methods to Determine Order of Reaction
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
CHXII04:CHEMICAL KINETICS

320519 For a reaction, the dimensions of rate constant are same as that of rate, hence order of reaction is

1 0
2 1
3 2
4 3
CHXII04:CHEMICAL KINETICS

320520 What will be the order of reaction and rate constant for a chemical change having \({\text{log}}\,{{\text{t}}_{{\text{50\% }}}}\) versus log concentration of ( 1\()\) curves as?
supporting img

1 \(0, \dfrac{1}{2}\)
2 1,1
3 2,2
4 3,1
CHXII04:CHEMICAL KINETICS

320521 For the reaction \({\mathrm{A+2 B \longrightarrow C}}\), the reaction rate is doubled if the concentration of A is doubled. The rate is increased by four times when concentrations of both A and B are increased by four times. The order of the reaction is ____.

1 1
2 \( - 1\)
3 0
4 2
CHXII04:CHEMICAL KINETICS

320522 \(\mathrm{A}+\mathrm{B} \rightarrow\) Product, \(\frac{{{\text{dx}}}}{{{\text{dt}}}} = {\text{k}}{[{\text{A}}]^{\text{a}}}{[{\text{B}}]^{\text{b}}}\). If \(\left( {\frac{{{\rm{dx}}}}{{{\rm{dt}}}}} \right) = {\rm{k}},\) then order of reaction is

1 4
2 3
3 1
4 0
CHXII04:CHEMICAL KINETICS

320519 For a reaction, the dimensions of rate constant are same as that of rate, hence order of reaction is

1 0
2 1
3 2
4 3
CHXII04:CHEMICAL KINETICS

320520 What will be the order of reaction and rate constant for a chemical change having \({\text{log}}\,{{\text{t}}_{{\text{50\% }}}}\) versus log concentration of ( 1\()\) curves as?
supporting img

1 \(0, \dfrac{1}{2}\)
2 1,1
3 2,2
4 3,1
CHXII04:CHEMICAL KINETICS

320521 For the reaction \({\mathrm{A+2 B \longrightarrow C}}\), the reaction rate is doubled if the concentration of A is doubled. The rate is increased by four times when concentrations of both A and B are increased by four times. The order of the reaction is ____.

1 1
2 \( - 1\)
3 0
4 2
CHXII04:CHEMICAL KINETICS

320522 \(\mathrm{A}+\mathrm{B} \rightarrow\) Product, \(\frac{{{\text{dx}}}}{{{\text{dt}}}} = {\text{k}}{[{\text{A}}]^{\text{a}}}{[{\text{B}}]^{\text{b}}}\). If \(\left( {\frac{{{\rm{dx}}}}{{{\rm{dt}}}}} \right) = {\rm{k}},\) then order of reaction is

1 4
2 3
3 1
4 0
CHXII04:CHEMICAL KINETICS

320519 For a reaction, the dimensions of rate constant are same as that of rate, hence order of reaction is

1 0
2 1
3 2
4 3
CHXII04:CHEMICAL KINETICS

320520 What will be the order of reaction and rate constant for a chemical change having \({\text{log}}\,{{\text{t}}_{{\text{50\% }}}}\) versus log concentration of ( 1\()\) curves as?
supporting img

1 \(0, \dfrac{1}{2}\)
2 1,1
3 2,2
4 3,1
CHXII04:CHEMICAL KINETICS

320521 For the reaction \({\mathrm{A+2 B \longrightarrow C}}\), the reaction rate is doubled if the concentration of A is doubled. The rate is increased by four times when concentrations of both A and B are increased by four times. The order of the reaction is ____.

1 1
2 \( - 1\)
3 0
4 2
CHXII04:CHEMICAL KINETICS

320522 \(\mathrm{A}+\mathrm{B} \rightarrow\) Product, \(\frac{{{\text{dx}}}}{{{\text{dt}}}} = {\text{k}}{[{\text{A}}]^{\text{a}}}{[{\text{B}}]^{\text{b}}}\). If \(\left( {\frac{{{\rm{dx}}}}{{{\rm{dt}}}}} \right) = {\rm{k}},\) then order of reaction is

1 4
2 3
3 1
4 0
NEET Test Series from KOTA - 10 Papers In MS WORD WhatsApp Here
CHXII04:CHEMICAL KINETICS

320519 For a reaction, the dimensions of rate constant are same as that of rate, hence order of reaction is

1 0
2 1
3 2
4 3
CHXII04:CHEMICAL KINETICS

320520 What will be the order of reaction and rate constant for a chemical change having \({\text{log}}\,{{\text{t}}_{{\text{50\% }}}}\) versus log concentration of ( 1\()\) curves as?
supporting img

1 \(0, \dfrac{1}{2}\)
2 1,1
3 2,2
4 3,1
CHXII04:CHEMICAL KINETICS

320521 For the reaction \({\mathrm{A+2 B \longrightarrow C}}\), the reaction rate is doubled if the concentration of A is doubled. The rate is increased by four times when concentrations of both A and B are increased by four times. The order of the reaction is ____.

1 1
2 \( - 1\)
3 0
4 2
CHXII04:CHEMICAL KINETICS

320522 \(\mathrm{A}+\mathrm{B} \rightarrow\) Product, \(\frac{{{\text{dx}}}}{{{\text{dt}}}} = {\text{k}}{[{\text{A}}]^{\text{a}}}{[{\text{B}}]^{\text{b}}}\). If \(\left( {\frac{{{\rm{dx}}}}{{{\rm{dt}}}}} \right) = {\rm{k}},\) then order of reaction is

1 4
2 3
3 1
4 0