320356 The reaction ; \({\text{A}} \to {\text{B}}\) follows first order kinetics. The time taken for 0.8 mole of A to produce 0.6 mole of \(\mathrm{B}\) is 1 hour. What is the time taken for conversion of 0.9 mole of \({\text{A}}\) to produce 0.675 mole of \(\mathrm{B}\) ?

320357 \({{\text{t}}_{{\text{1 / 2}}}}\) for a first order reaction is \(10 \mathrm{~min}\). Starting with \(10 \mathrm{M}\), the rate after \(20 \mathrm{~min}\) is

320358 Consider the following first order competing reactions:
\({\text{X}}\xrightarrow{{{{\text{k}}_{\text{1}}}}}{\text{A + B and Y}}\xrightarrow{{{{\text{k}}_{\text{2}}}}}{\text{C + D}}\)
If 50 % of the reaction of X was completed when 96 % of the reaction of Y was completed, the ratio of their rate constants \(\left( {{{\rm{k}}_{\rm{2}}}{\rm{/}}{{\rm{k}}_{\rm{1}}}} \right)\) is

320359 A first order reaction is \(30 \%\) complete in 20 minutes. The rate constant of the reaction is

320356 The reaction ; \({\text{A}} \to {\text{B}}\) follows first order kinetics. The time taken for 0.8 mole of A to produce 0.6 mole of \(\mathrm{B}\) is 1 hour. What is the time taken for conversion of 0.9 mole of \({\text{A}}\) to produce 0.675 mole of \(\mathrm{B}\) ?

320357 \({{\text{t}}_{{\text{1 / 2}}}}\) for a first order reaction is \(10 \mathrm{~min}\). Starting with \(10 \mathrm{M}\), the rate after \(20 \mathrm{~min}\) is

320358 Consider the following first order competing reactions:
\({\text{X}}\xrightarrow{{{{\text{k}}_{\text{1}}}}}{\text{A + B and Y}}\xrightarrow{{{{\text{k}}_{\text{2}}}}}{\text{C + D}}\)
If 50 % of the reaction of X was completed when 96 % of the reaction of Y was completed, the ratio of their rate constants \(\left( {{{\rm{k}}_{\rm{2}}}{\rm{/}}{{\rm{k}}_{\rm{1}}}} \right)\) is

320359 A first order reaction is \(30 \%\) complete in 20 minutes. The rate constant of the reaction is

320356 The reaction ; \({\text{A}} \to {\text{B}}\) follows first order kinetics. The time taken for 0.8 mole of A to produce 0.6 mole of \(\mathrm{B}\) is 1 hour. What is the time taken for conversion of 0.9 mole of \({\text{A}}\) to produce 0.675 mole of \(\mathrm{B}\) ?

320357 \({{\text{t}}_{{\text{1 / 2}}}}\) for a first order reaction is \(10 \mathrm{~min}\). Starting with \(10 \mathrm{M}\), the rate after \(20 \mathrm{~min}\) is

320358 Consider the following first order competing reactions:
\({\text{X}}\xrightarrow{{{{\text{k}}_{\text{1}}}}}{\text{A + B and Y}}\xrightarrow{{{{\text{k}}_{\text{2}}}}}{\text{C + D}}\)
If 50 % of the reaction of X was completed when 96 % of the reaction of Y was completed, the ratio of their rate constants \(\left( {{{\rm{k}}_{\rm{2}}}{\rm{/}}{{\rm{k}}_{\rm{1}}}} \right)\) is

320359 A first order reaction is \(30 \%\) complete in 20 minutes. The rate constant of the reaction is

320356 The reaction ; \({\text{A}} \to {\text{B}}\) follows first order kinetics. The time taken for 0.8 mole of A to produce 0.6 mole of \(\mathrm{B}\) is 1 hour. What is the time taken for conversion of 0.9 mole of \({\text{A}}\) to produce 0.675 mole of \(\mathrm{B}\) ?

320357 \({{\text{t}}_{{\text{1 / 2}}}}\) for a first order reaction is \(10 \mathrm{~min}\). Starting with \(10 \mathrm{M}\), the rate after \(20 \mathrm{~min}\) is

320358 Consider the following first order competing reactions:
\({\text{X}}\xrightarrow{{{{\text{k}}_{\text{1}}}}}{\text{A + B and Y}}\xrightarrow{{{{\text{k}}_{\text{2}}}}}{\text{C + D}}\)
If 50 % of the reaction of X was completed when 96 % of the reaction of Y was completed, the ratio of their rate constants \(\left( {{{\rm{k}}_{\rm{2}}}{\rm{/}}{{\rm{k}}_{\rm{1}}}} \right)\) is

320359 A first order reaction is \(30 \%\) complete in 20 minutes. The rate constant of the reaction is