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CHXII03:ELECTROCHEMISTRY

330454 For a strong electrolyte, a plot of molar conductivity against (concentration) $^{1 / 2}$ is a straight line, with a negative slope, the correct unit for the slope is

1

S {cm}^{2} {mol}^{- 1} L^{1 / 2}

2

S {cm}^{2} {mol}^{- 3 / 2} L

3

S {cm}^{2} {mol}^{- 3 / 2} L^{- 1 / 2}

4

S {cm}^{2} {mol}^{- 3 / 2} L^{1 / 2}

Explanation:

For strong electrolyte, $Λ_{m} = Λ_{m}^{\circ} - A \sqrt{C}$
$\begin{aligned} Slope, A = \frac{Λ_{m}^{\circ} - Λ_{m}}{\sqrt{C}} \\ \begin{aligned} ∴ Units of A & = \frac{S \cdot {cm}^{2} \cdot {mol}^{-}}{{{({mol}^{-} \cdot lit)}^{-})}^{\frac{1}{2}}} \\ = {S cm}^{2} {mol}^{- 3 / 2} L^{1 / 2} \end{aligned} \end{aligned}$
So, the correct option is (4).

JEE Main - 2024

CHXII03:ELECTROCHEMISTRY

330470 $NaCl, {MgCl}_{2}$ and ${CaSO}_{4}$ are known as:

1 1-1,2-1,2-2 type of electrolytes respectively.

2 Strong, weak and strong electrolytes respectively.

3 Electrolytes with different value of A.

4 Electrolytes with same molar conductivity.

Explanation:

Depending on the charges on the cation and anion produced in the dissociation of the electrolyte in solution, the type of electrolytes are known as $1 - 1, 2 - 1$ and $2 - 2$ electrolytes respectively.
$NaCl \to {Na}^{+} + {Cl}^{-} (1 - 1)$
${MgCl}_{2} \to {Mg}^{2 +} + 2 {Cl}^{-} (2 - 1)$
${CaSO}_{4} \to {Ca}^{2 +} + {SO}_{4}^{2 -} (2 - 2)$

CHXII03:ELECTROCHEMISTRY

330455 Which out of the following is a correct equation to show change in molar conductivity with respect to concentration for a weak electrolyte, if the symbols carry their usual meaning?

1

Λ_{m}^{2} C - K_{a} Λ_{m}^{\circ 2} + K_{a} Λ_{m} Λ_{m}^{\circ} = 0

2

Λ_{m} - Λ_{m}^{\circ} - {AC}^{1 / 2} = 0

3

Λ_{m} - Λ_{m}^{\circ} + {AC}^{1 / 2} = 0

4

Λ_{m}^{2} C + K_{a} Λ_{m}^{\circ 2} - K_{a} Λ_{m} Λ_{m}^{\circ} = 0

Explanation:

For weak electrolyte $K_{a} = \frac{C α^{2}}{1 - α}$
$(D e g r e e o f d i s s o c i a t i o n) α = \frac{Λ_{m}}{{Λ_{m}}^{\circ}}$
$K_{a} = \frac{C {(\frac{Λ_{m}}{Λ_{m}^{\circ}})}^{2}}{1 - \frac{Λ {^{\circ}}_{m}}{Λ {^{\circ}}_{m}}}$
$K_{a} = \frac{C Λ_{m}^{2}}{Λ {^{\circ}}_{m} (Λ {^{\circ}}_{m} - Λ_{m})}$
$K_{a} = \frac{C Λ_{m}^{2}}{Λ {^{\circ}}^{2}_{m} - Λ_{m} Λ {^{\circ}}_{m}}$
$K_{a} (Λ {^{\circ}}^{2}_{m} - Λ {^{\circ}}_{m} Λ_{m}) = C Λ_{m}^{2}$
$Λ_{m}^{2} C - K_{a} Λ {^{\circ}}^{2}_{m} + K_{a} Λ {^{\circ}}_{m} Λ_{m} = 0$
$S o, t h e c o r r e c t o p t i o n i s (1) .$

JEE Main - 2024

CHXII03:ELECTROCHEMISTRY

330456 Assertion :
Specific conductance decreases with dilution whereas equivalent conductance increases.
Reason :
On dilution, number of ions per millilitre decreases but total number of ions increases considerably.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

CHXII03:ELECTROCHEMISTRY

330454 For a strong electrolyte, a plot of molar conductivity against (concentration) $^{1 / 2}$ is a straight line, with a negative slope, the correct unit for the slope is

1

S {cm}^{2} {mol}^{- 1} L^{1 / 2}

2

S {cm}^{2} {mol}^{- 3 / 2} L

3

S {cm}^{2} {mol}^{- 3 / 2} L^{- 1 / 2}

4

S {cm}^{2} {mol}^{- 3 / 2} L^{1 / 2}

Explanation:

For strong electrolyte, $Λ_{m} = Λ_{m}^{\circ} - A \sqrt{C}$
$\begin{aligned} Slope, A = \frac{Λ_{m}^{\circ} - Λ_{m}}{\sqrt{C}} \\ \begin{aligned} ∴ Units of A & = \frac{S \cdot {cm}^{2} \cdot {mol}^{-}}{{{({mol}^{-} \cdot lit)}^{-})}^{\frac{1}{2}}} \\ = {S cm}^{2} {mol}^{- 3 / 2} L^{1 / 2} \end{aligned} \end{aligned}$
So, the correct option is (4).

JEE Main - 2024

CHXII03:ELECTROCHEMISTRY

330470 $NaCl, {MgCl}_{2}$ and ${CaSO}_{4}$ are known as:

1 1-1,2-1,2-2 type of electrolytes respectively.

2 Strong, weak and strong electrolytes respectively.

3 Electrolytes with different value of A.

4 Electrolytes with same molar conductivity.

Explanation:

Depending on the charges on the cation and anion produced in the dissociation of the electrolyte in solution, the type of electrolytes are known as $1 - 1, 2 - 1$ and $2 - 2$ electrolytes respectively.
$NaCl \to {Na}^{+} + {Cl}^{-} (1 - 1)$
${MgCl}_{2} \to {Mg}^{2 +} + 2 {Cl}^{-} (2 - 1)$
${CaSO}_{4} \to {Ca}^{2 +} + {SO}_{4}^{2 -} (2 - 2)$

CHXII03:ELECTROCHEMISTRY

330455 Which out of the following is a correct equation to show change in molar conductivity with respect to concentration for a weak electrolyte, if the symbols carry their usual meaning?

1

Λ_{m}^{2} C - K_{a} Λ_{m}^{\circ 2} + K_{a} Λ_{m} Λ_{m}^{\circ} = 0

2

Λ_{m} - Λ_{m}^{\circ} - {AC}^{1 / 2} = 0

3

Λ_{m} - Λ_{m}^{\circ} + {AC}^{1 / 2} = 0

4

Λ_{m}^{2} C + K_{a} Λ_{m}^{\circ 2} - K_{a} Λ_{m} Λ_{m}^{\circ} = 0

Explanation:

For weak electrolyte $K_{a} = \frac{C α^{2}}{1 - α}$
$(D e g r e e o f d i s s o c i a t i o n) α = \frac{Λ_{m}}{{Λ_{m}}^{\circ}}$
$K_{a} = \frac{C {(\frac{Λ_{m}}{Λ_{m}^{\circ}})}^{2}}{1 - \frac{Λ {^{\circ}}_{m}}{Λ {^{\circ}}_{m}}}$
$K_{a} = \frac{C Λ_{m}^{2}}{Λ {^{\circ}}_{m} (Λ {^{\circ}}_{m} - Λ_{m})}$
$K_{a} = \frac{C Λ_{m}^{2}}{Λ {^{\circ}}^{2}_{m} - Λ_{m} Λ {^{\circ}}_{m}}$
$K_{a} (Λ {^{\circ}}^{2}_{m} - Λ {^{\circ}}_{m} Λ_{m}) = C Λ_{m}^{2}$
$Λ_{m}^{2} C - K_{a} Λ {^{\circ}}^{2}_{m} + K_{a} Λ {^{\circ}}_{m} Λ_{m} = 0$
$S o, t h e c o r r e c t o p t i o n i s (1) .$

JEE Main - 2024

CHXII03:ELECTROCHEMISTRY

330456 Assertion :
Specific conductance decreases with dilution whereas equivalent conductance increases.
Reason :
On dilution, number of ions per millilitre decreases but total number of ions increases considerably.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

CHXII03:ELECTROCHEMISTRY

330454 For a strong electrolyte, a plot of molar conductivity against (concentration) $^{1 / 2}$ is a straight line, with a negative slope, the correct unit for the slope is

1

S {cm}^{2} {mol}^{- 1} L^{1 / 2}

2

S {cm}^{2} {mol}^{- 3 / 2} L

3

S {cm}^{2} {mol}^{- 3 / 2} L^{- 1 / 2}

4

S {cm}^{2} {mol}^{- 3 / 2} L^{1 / 2}

Explanation:

For strong electrolyte, $Λ_{m} = Λ_{m}^{\circ} - A \sqrt{C}$
$\begin{aligned} Slope, A = \frac{Λ_{m}^{\circ} - Λ_{m}}{\sqrt{C}} \\ \begin{aligned} ∴ Units of A & = \frac{S \cdot {cm}^{2} \cdot {mol}^{-}}{{{({mol}^{-} \cdot lit)}^{-})}^{\frac{1}{2}}} \\ = {S cm}^{2} {mol}^{- 3 / 2} L^{1 / 2} \end{aligned} \end{aligned}$
So, the correct option is (4).

JEE Main - 2024

CHXII03:ELECTROCHEMISTRY

330470 $NaCl, {MgCl}_{2}$ and ${CaSO}_{4}$ are known as:

1 1-1,2-1,2-2 type of electrolytes respectively.

2 Strong, weak and strong electrolytes respectively.

3 Electrolytes with different value of A.

4 Electrolytes with same molar conductivity.

Explanation:

Depending on the charges on the cation and anion produced in the dissociation of the electrolyte in solution, the type of electrolytes are known as $1 - 1, 2 - 1$ and $2 - 2$ electrolytes respectively.
$NaCl \to {Na}^{+} + {Cl}^{-} (1 - 1)$
${MgCl}_{2} \to {Mg}^{2 +} + 2 {Cl}^{-} (2 - 1)$
${CaSO}_{4} \to {Ca}^{2 +} + {SO}_{4}^{2 -} (2 - 2)$

CHXII03:ELECTROCHEMISTRY

330455 Which out of the following is a correct equation to show change in molar conductivity with respect to concentration for a weak electrolyte, if the symbols carry their usual meaning?

1

Λ_{m}^{2} C - K_{a} Λ_{m}^{\circ 2} + K_{a} Λ_{m} Λ_{m}^{\circ} = 0

2

Λ_{m} - Λ_{m}^{\circ} - {AC}^{1 / 2} = 0

3

Λ_{m} - Λ_{m}^{\circ} + {AC}^{1 / 2} = 0

4

Λ_{m}^{2} C + K_{a} Λ_{m}^{\circ 2} - K_{a} Λ_{m} Λ_{m}^{\circ} = 0

Explanation:

For weak electrolyte $K_{a} = \frac{C α^{2}}{1 - α}$
$(D e g r e e o f d i s s o c i a t i o n) α = \frac{Λ_{m}}{{Λ_{m}}^{\circ}}$
$K_{a} = \frac{C {(\frac{Λ_{m}}{Λ_{m}^{\circ}})}^{2}}{1 - \frac{Λ {^{\circ}}_{m}}{Λ {^{\circ}}_{m}}}$
$K_{a} = \frac{C Λ_{m}^{2}}{Λ {^{\circ}}_{m} (Λ {^{\circ}}_{m} - Λ_{m})}$
$K_{a} = \frac{C Λ_{m}^{2}}{Λ {^{\circ}}^{2}_{m} - Λ_{m} Λ {^{\circ}}_{m}}$
$K_{a} (Λ {^{\circ}}^{2}_{m} - Λ {^{\circ}}_{m} Λ_{m}) = C Λ_{m}^{2}$
$Λ_{m}^{2} C - K_{a} Λ {^{\circ}}^{2}_{m} + K_{a} Λ {^{\circ}}_{m} Λ_{m} = 0$
$S o, t h e c o r r e c t o p t i o n i s (1) .$

JEE Main - 2024

CHXII03:ELECTROCHEMISTRY

330456 Assertion :
Specific conductance decreases with dilution whereas equivalent conductance increases.
Reason :
On dilution, number of ions per millilitre decreases but total number of ions increases considerably.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.

CHXII03:ELECTROCHEMISTRY

330454 For a strong electrolyte, a plot of molar conductivity against (concentration) $^{1 / 2}$ is a straight line, with a negative slope, the correct unit for the slope is

1

S {cm}^{2} {mol}^{- 1} L^{1 / 2}

2

S {cm}^{2} {mol}^{- 3 / 2} L

3

S {cm}^{2} {mol}^{- 3 / 2} L^{- 1 / 2}

4

S {cm}^{2} {mol}^{- 3 / 2} L^{1 / 2}

Explanation:

For strong electrolyte, $Λ_{m} = Λ_{m}^{\circ} - A \sqrt{C}$
$\begin{aligned} Slope, A = \frac{Λ_{m}^{\circ} - Λ_{m}}{\sqrt{C}} \\ \begin{aligned} ∴ Units of A & = \frac{S \cdot {cm}^{2} \cdot {mol}^{-}}{{{({mol}^{-} \cdot lit)}^{-})}^{\frac{1}{2}}} \\ = {S cm}^{2} {mol}^{- 3 / 2} L^{1 / 2} \end{aligned} \end{aligned}$
So, the correct option is (4).

JEE Main - 2024

CHXII03:ELECTROCHEMISTRY

330470 $NaCl, {MgCl}_{2}$ and ${CaSO}_{4}$ are known as:

1 1-1,2-1,2-2 type of electrolytes respectively.

2 Strong, weak and strong electrolytes respectively.

3 Electrolytes with different value of A.

4 Electrolytes with same molar conductivity.

Explanation:

Depending on the charges on the cation and anion produced in the dissociation of the electrolyte in solution, the type of electrolytes are known as $1 - 1, 2 - 1$ and $2 - 2$ electrolytes respectively.
$NaCl \to {Na}^{+} + {Cl}^{-} (1 - 1)$
${MgCl}_{2} \to {Mg}^{2 +} + 2 {Cl}^{-} (2 - 1)$
${CaSO}_{4} \to {Ca}^{2 +} + {SO}_{4}^{2 -} (2 - 2)$

CHXII03:ELECTROCHEMISTRY

330455 Which out of the following is a correct equation to show change in molar conductivity with respect to concentration for a weak electrolyte, if the symbols carry their usual meaning?

1

Λ_{m}^{2} C - K_{a} Λ_{m}^{\circ 2} + K_{a} Λ_{m} Λ_{m}^{\circ} = 0

2

Λ_{m} - Λ_{m}^{\circ} - {AC}^{1 / 2} = 0

3

Λ_{m} - Λ_{m}^{\circ} + {AC}^{1 / 2} = 0

4

Λ_{m}^{2} C + K_{a} Λ_{m}^{\circ 2} - K_{a} Λ_{m} Λ_{m}^{\circ} = 0

Explanation:

For weak electrolyte $K_{a} = \frac{C α^{2}}{1 - α}$
$(D e g r e e o f d i s s o c i a t i o n) α = \frac{Λ_{m}}{{Λ_{m}}^{\circ}}$
$K_{a} = \frac{C {(\frac{Λ_{m}}{Λ_{m}^{\circ}})}^{2}}{1 - \frac{Λ {^{\circ}}_{m}}{Λ {^{\circ}}_{m}}}$
$K_{a} = \frac{C Λ_{m}^{2}}{Λ {^{\circ}}_{m} (Λ {^{\circ}}_{m} - Λ_{m})}$
$K_{a} = \frac{C Λ_{m}^{2}}{Λ {^{\circ}}^{2}_{m} - Λ_{m} Λ {^{\circ}}_{m}}$
$K_{a} (Λ {^{\circ}}^{2}_{m} - Λ {^{\circ}}_{m} Λ_{m}) = C Λ_{m}^{2}$
$Λ_{m}^{2} C - K_{a} Λ {^{\circ}}^{2}_{m} + K_{a} Λ {^{\circ}}_{m} Λ_{m} = 0$
$S o, t h e c o r r e c t o p t i o n i s (1) .$

JEE Main - 2024

CHXII03:ELECTROCHEMISTRY

330456 Assertion :
Specific conductance decreases with dilution whereas equivalent conductance increases.
Reason :
On dilution, number of ions per millilitre decreases but total number of ions increases considerably.

1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.

2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.

3 Assertion is correct but Reason is incorrect.

4 Assertion is incorrect but Reason is correct.