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CHXII01:THE SOLID STATE

318933 The ionic radii of $A^{+}$ and $B^{-}$ ions are $0.98 \times 10^{- 10}$ and $1.81 \times 10^{- 10} m$ . The coordination number of each ion in $AB$ is:

1 2

2 6

3 4

4 8

Explanation:

$\frac{r_{A^{+}}}{r_{B^{+}}} = \frac{0.98 \times 10^{- 10}}{1.81 \times 10^{- 10}} = 0.54$
As $\frac{r^{+}}{r^{-}}$ is in range $0.414 - 0.732$ , the structure is octahedral.
Co-ordination no. of each ion is 6 like $NaCl$ structure.

NEET - 2016

CHXII01:THE SOLID STATE

318934 In $A^{+} B^{-}$ ionic compound, radii of $A^{+}$ and $B^{-}$ ions are $180 pm$ and $187 pm$ respectively. The crystal structure of this compound will be

1 CsCl type

2

NaCl

type

3 Similar to diamond

4 Zns type

Explanation:

$\frac{r_{+}}{r_{-}} = \frac{180}{187} = 0.962$ which lies in the range of $0.732 - 0.999$ , hence, co-ordination number $=$ 8, i.e., the structure is $CsCl$ type.

CHXII01:THE SOLID STATE

318935 For tetrahedral coordination, the radius ratio $(\frac{r_{+}}{r_{-}})$ should be

1

0.414 - 0.732

2

> 0.732

3

0.156 - 0.225

4

0.225 - 0.414

Explanation:

For tetrahedral coordination, the radius ratio $(\frac{r_{+}}{r_{-}})$ should be $0.225 - 0.414$ .
For other, the radius ratio are as follows:
$0.414 - 0.732 \to$ Octahedral coordination;
$0.732 - 1 \to$ Cubic or body centred;
0.156-0.225 $\to$ Planar triangular

CHXII01:THE SOLID STATE

318936 The limiting radius ratio for tetrahedral shape is

1 0 to 0.155

2 0.225 to 0.414

3

0.115 - 0.225

4

0.414 - 0.732

CHXII01:THE SOLID STATE

318933 The ionic radii of $A^{+}$ and $B^{-}$ ions are $0.98 \times 10^{- 10}$ and $1.81 \times 10^{- 10} m$ . The coordination number of each ion in $AB$ is:

1 2

2 6

3 4

4 8

Explanation:

$\frac{r_{A^{+}}}{r_{B^{+}}} = \frac{0.98 \times 10^{- 10}}{1.81 \times 10^{- 10}} = 0.54$
As $\frac{r^{+}}{r^{-}}$ is in range $0.414 - 0.732$ , the structure is octahedral.
Co-ordination no. of each ion is 6 like $NaCl$ structure.

NEET - 2016

CHXII01:THE SOLID STATE

318934 In $A^{+} B^{-}$ ionic compound, radii of $A^{+}$ and $B^{-}$ ions are $180 pm$ and $187 pm$ respectively. The crystal structure of this compound will be

1 CsCl type

2

NaCl

type

3 Similar to diamond

4 Zns type

Explanation:

$\frac{r_{+}}{r_{-}} = \frac{180}{187} = 0.962$ which lies in the range of $0.732 - 0.999$ , hence, co-ordination number $=$ 8, i.e., the structure is $CsCl$ type.

CHXII01:THE SOLID STATE

318935 For tetrahedral coordination, the radius ratio $(\frac{r_{+}}{r_{-}})$ should be

1

0.414 - 0.732

2

> 0.732

3

0.156 - 0.225

4

0.225 - 0.414

Explanation:

For tetrahedral coordination, the radius ratio $(\frac{r_{+}}{r_{-}})$ should be $0.225 - 0.414$ .
For other, the radius ratio are as follows:
$0.414 - 0.732 \to$ Octahedral coordination;
$0.732 - 1 \to$ Cubic or body centred;
0.156-0.225 $\to$ Planar triangular

CHXII01:THE SOLID STATE

318936 The limiting radius ratio for tetrahedral shape is

1 0 to 0.155

2 0.225 to 0.414

3

0.115 - 0.225

4

0.414 - 0.732

CHXII01:THE SOLID STATE

318933 The ionic radii of $A^{+}$ and $B^{-}$ ions are $0.98 \times 10^{- 10}$ and $1.81 \times 10^{- 10} m$ . The coordination number of each ion in $AB$ is:

1 2

2 6

3 4

4 8

Explanation:

$\frac{r_{A^{+}}}{r_{B^{+}}} = \frac{0.98 \times 10^{- 10}}{1.81 \times 10^{- 10}} = 0.54$
As $\frac{r^{+}}{r^{-}}$ is in range $0.414 - 0.732$ , the structure is octahedral.
Co-ordination no. of each ion is 6 like $NaCl$ structure.

NEET - 2016

CHXII01:THE SOLID STATE

318934 In $A^{+} B^{-}$ ionic compound, radii of $A^{+}$ and $B^{-}$ ions are $180 pm$ and $187 pm$ respectively. The crystal structure of this compound will be

1 CsCl type

2

NaCl

type

3 Similar to diamond

4 Zns type

Explanation:

$\frac{r_{+}}{r_{-}} = \frac{180}{187} = 0.962$ which lies in the range of $0.732 - 0.999$ , hence, co-ordination number $=$ 8, i.e., the structure is $CsCl$ type.

CHXII01:THE SOLID STATE

318935 For tetrahedral coordination, the radius ratio $(\frac{r_{+}}{r_{-}})$ should be

1

0.414 - 0.732

2

> 0.732

3

0.156 - 0.225

4

0.225 - 0.414

Explanation:

For tetrahedral coordination, the radius ratio $(\frac{r_{+}}{r_{-}})$ should be $0.225 - 0.414$ .
For other, the radius ratio are as follows:
$0.414 - 0.732 \to$ Octahedral coordination;
$0.732 - 1 \to$ Cubic or body centred;
0.156-0.225 $\to$ Planar triangular

CHXII01:THE SOLID STATE

318936 The limiting radius ratio for tetrahedral shape is

1 0 to 0.155

2 0.225 to 0.414

3

0.115 - 0.225

4

0.414 - 0.732

CHXII01:THE SOLID STATE

318933 The ionic radii of $A^{+}$ and $B^{-}$ ions are $0.98 \times 10^{- 10}$ and $1.81 \times 10^{- 10} m$ . The coordination number of each ion in $AB$ is:

1 2

2 6

3 4

4 8

Explanation:

$\frac{r_{A^{+}}}{r_{B^{+}}} = \frac{0.98 \times 10^{- 10}}{1.81 \times 10^{- 10}} = 0.54$
As $\frac{r^{+}}{r^{-}}$ is in range $0.414 - 0.732$ , the structure is octahedral.
Co-ordination no. of each ion is 6 like $NaCl$ structure.

NEET - 2016

CHXII01:THE SOLID STATE

318934 In $A^{+} B^{-}$ ionic compound, radii of $A^{+}$ and $B^{-}$ ions are $180 pm$ and $187 pm$ respectively. The crystal structure of this compound will be

1 CsCl type

2

NaCl

type

3 Similar to diamond

4 Zns type

Explanation:

$\frac{r_{+}}{r_{-}} = \frac{180}{187} = 0.962$ which lies in the range of $0.732 - 0.999$ , hence, co-ordination number $=$ 8, i.e., the structure is $CsCl$ type.

CHXII01:THE SOLID STATE

318935 For tetrahedral coordination, the radius ratio $(\frac{r_{+}}{r_{-}})$ should be

1

0.414 - 0.732

2

> 0.732

3

0.156 - 0.225

4

0.225 - 0.414

Explanation:

For tetrahedral coordination, the radius ratio $(\frac{r_{+}}{r_{-}})$ should be $0.225 - 0.414$ .
For other, the radius ratio are as follows:
$0.414 - 0.732 \to$ Octahedral coordination;
$0.732 - 1 \to$ Cubic or body centred;
0.156-0.225 $\to$ Planar triangular

CHXII01:THE SOLID STATE

318936 The limiting radius ratio for tetrahedral shape is

1 0 to 0.155

2 0.225 to 0.414

3

0.115 - 0.225

4

0.414 - 0.732