318893
The closest distance between two atoms (in terms of edge length) would be the highest for which of unit cell, assuming the edge length of each unit cell of be ' \(a\) ' ?
1 FCC unit cell
2 BCC unit cell
3 Diamond unit cell
4 Primitive unit cell
Explanation:
Closest distance between two atoms in \(\mathrm{FCC}, 2 \mathrm{r}=\dfrac{\sqrt{2} \mathrm{a}}{2}\) Closest distance between two atoms in BCC, \(2 r=\dfrac{\sqrt{3} a}{2}\) Closest distance between two atoms in diamond, \(2 \mathrm{r}=\dfrac{\sqrt{3} \mathrm{a}}{4}\) Closest distance between two atoms in primitive cubic, \(2 \mathrm{r}=\mathrm{a}\) The closest distance between two atoms in \(\mathrm{BCC}\) is highest
CHXII01:THE SOLID STATE
318894
Sodium metal crystallises in B.C.C. lattice with cell edge, \({\rm{4}}{\rm{.29}}\mathop {\rm{A}}\limits^{\rm{^\circ }} \). The length of the body diagonal of the unit cell is
318893
The closest distance between two atoms (in terms of edge length) would be the highest for which of unit cell, assuming the edge length of each unit cell of be ' \(a\) ' ?
1 FCC unit cell
2 BCC unit cell
3 Diamond unit cell
4 Primitive unit cell
Explanation:
Closest distance between two atoms in \(\mathrm{FCC}, 2 \mathrm{r}=\dfrac{\sqrt{2} \mathrm{a}}{2}\) Closest distance between two atoms in BCC, \(2 r=\dfrac{\sqrt{3} a}{2}\) Closest distance between two atoms in diamond, \(2 \mathrm{r}=\dfrac{\sqrt{3} \mathrm{a}}{4}\) Closest distance between two atoms in primitive cubic, \(2 \mathrm{r}=\mathrm{a}\) The closest distance between two atoms in \(\mathrm{BCC}\) is highest
CHXII01:THE SOLID STATE
318894
Sodium metal crystallises in B.C.C. lattice with cell edge, \({\rm{4}}{\rm{.29}}\mathop {\rm{A}}\limits^{\rm{^\circ }} \). The length of the body diagonal of the unit cell is
318893
The closest distance between two atoms (in terms of edge length) would be the highest for which of unit cell, assuming the edge length of each unit cell of be ' \(a\) ' ?
1 FCC unit cell
2 BCC unit cell
3 Diamond unit cell
4 Primitive unit cell
Explanation:
Closest distance between two atoms in \(\mathrm{FCC}, 2 \mathrm{r}=\dfrac{\sqrt{2} \mathrm{a}}{2}\) Closest distance between two atoms in BCC, \(2 r=\dfrac{\sqrt{3} a}{2}\) Closest distance between two atoms in diamond, \(2 \mathrm{r}=\dfrac{\sqrt{3} \mathrm{a}}{4}\) Closest distance between two atoms in primitive cubic, \(2 \mathrm{r}=\mathrm{a}\) The closest distance between two atoms in \(\mathrm{BCC}\) is highest
CHXII01:THE SOLID STATE
318894
Sodium metal crystallises in B.C.C. lattice with cell edge, \({\rm{4}}{\rm{.29}}\mathop {\rm{A}}\limits^{\rm{^\circ }} \). The length of the body diagonal of the unit cell is
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CHXII01:THE SOLID STATE
318893
The closest distance between two atoms (in terms of edge length) would be the highest for which of unit cell, assuming the edge length of each unit cell of be ' \(a\) ' ?
1 FCC unit cell
2 BCC unit cell
3 Diamond unit cell
4 Primitive unit cell
Explanation:
Closest distance between two atoms in \(\mathrm{FCC}, 2 \mathrm{r}=\dfrac{\sqrt{2} \mathrm{a}}{2}\) Closest distance between two atoms in BCC, \(2 r=\dfrac{\sqrt{3} a}{2}\) Closest distance between two atoms in diamond, \(2 \mathrm{r}=\dfrac{\sqrt{3} \mathrm{a}}{4}\) Closest distance between two atoms in primitive cubic, \(2 \mathrm{r}=\mathrm{a}\) The closest distance between two atoms in \(\mathrm{BCC}\) is highest
CHXII01:THE SOLID STATE
318894
Sodium metal crystallises in B.C.C. lattice with cell edge, \({\rm{4}}{\rm{.29}}\mathop {\rm{A}}\limits^{\rm{^\circ }} \). The length of the body diagonal of the unit cell is
318893
The closest distance between two atoms (in terms of edge length) would be the highest for which of unit cell, assuming the edge length of each unit cell of be ' \(a\) ' ?
1 FCC unit cell
2 BCC unit cell
3 Diamond unit cell
4 Primitive unit cell
Explanation:
Closest distance between two atoms in \(\mathrm{FCC}, 2 \mathrm{r}=\dfrac{\sqrt{2} \mathrm{a}}{2}\) Closest distance between two atoms in BCC, \(2 r=\dfrac{\sqrt{3} a}{2}\) Closest distance between two atoms in diamond, \(2 \mathrm{r}=\dfrac{\sqrt{3} \mathrm{a}}{4}\) Closest distance between two atoms in primitive cubic, \(2 \mathrm{r}=\mathrm{a}\) The closest distance between two atoms in \(\mathrm{BCC}\) is highest
CHXII01:THE SOLID STATE
318894
Sodium metal crystallises in B.C.C. lattice with cell edge, \({\rm{4}}{\rm{.29}}\mathop {\rm{A}}\limits^{\rm{^\circ }} \). The length of the body diagonal of the unit cell is