Number of Atoms in a Unit Cell and Formula of the Solids
CHXII01:THE SOLID STATE

318868 The contribution of particle at the edge centre of a particular unit cell is

1 \(\dfrac{1}{2}\)
2 \(\dfrac{1}{4}\)
3 1
4 \(\dfrac{1}{8}\)
CHXII01:THE SOLID STATE

318869 A solid has a structure in which \(X\) atoms are located at cubic corners of unit cell, \(\mathrm{O}\) atoms are at the edge centres and \(\mathrm{Y}\) atoms are at cube centre. Then the formula of compound is \(X_{a} Y_{b} O_{c}\). If two atoms of \(\mathrm{O}\) are missing from any of two edge centres per unit cell, then the molecular formula is \(X_{p} Y_{q} O_{r}\). Then, find the value of \((\mathrm{p}+\mathrm{q}+\mathrm{r})-(\mathrm{a}+\mathrm{b}+\mathrm{c})\).

1 2
2 4
3 5
4 8
CHXII01:THE SOLID STATE

318870 A fcc unit cell of aluminium contains the equivalent of how many atoms?

1 1
2 2
3 3
4 4
CHXII01:THE SOLID STATE

318871 A compound formed by elements \(X\) and \(Y\) has a cubic structure in which \(X\) atoms are at the corner of cube and also at the face centres. Y atoms are present at the body centre and at the edge centres of the cube. The total number of atoms in a cube are

1 12
2 20
3 27
4 15
CHXII01:THE SOLID STATE

318872 In a face centred cubic lattice atoms \(A\) are at the corner points and atoms \(B\) at the face centred points. If atoms B is missing from one of the face centred points, the formula of the ionic compound is :

1 \(\mathrm{AB}_{2}\)
2 \(\mathrm{A}_{2} \mathrm{~B}_{3}\)
3 \(\mathrm{A}_{5} \mathrm{~B}_{2}\)
4 \(\mathrm{A}_{2} \mathrm{~B}_{5}\)
CHXII01:THE SOLID STATE

318868 The contribution of particle at the edge centre of a particular unit cell is

1 \(\dfrac{1}{2}\)
2 \(\dfrac{1}{4}\)
3 1
4 \(\dfrac{1}{8}\)
CHXII01:THE SOLID STATE

318869 A solid has a structure in which \(X\) atoms are located at cubic corners of unit cell, \(\mathrm{O}\) atoms are at the edge centres and \(\mathrm{Y}\) atoms are at cube centre. Then the formula of compound is \(X_{a} Y_{b} O_{c}\). If two atoms of \(\mathrm{O}\) are missing from any of two edge centres per unit cell, then the molecular formula is \(X_{p} Y_{q} O_{r}\). Then, find the value of \((\mathrm{p}+\mathrm{q}+\mathrm{r})-(\mathrm{a}+\mathrm{b}+\mathrm{c})\).

1 2
2 4
3 5
4 8
CHXII01:THE SOLID STATE

318870 A fcc unit cell of aluminium contains the equivalent of how many atoms?

1 1
2 2
3 3
4 4
CHXII01:THE SOLID STATE

318871 A compound formed by elements \(X\) and \(Y\) has a cubic structure in which \(X\) atoms are at the corner of cube and also at the face centres. Y atoms are present at the body centre and at the edge centres of the cube. The total number of atoms in a cube are

1 12
2 20
3 27
4 15
CHXII01:THE SOLID STATE

318872 In a face centred cubic lattice atoms \(A\) are at the corner points and atoms \(B\) at the face centred points. If atoms B is missing from one of the face centred points, the formula of the ionic compound is :

1 \(\mathrm{AB}_{2}\)
2 \(\mathrm{A}_{2} \mathrm{~B}_{3}\)
3 \(\mathrm{A}_{5} \mathrm{~B}_{2}\)
4 \(\mathrm{A}_{2} \mathrm{~B}_{5}\)
CHXII01:THE SOLID STATE

318868 The contribution of particle at the edge centre of a particular unit cell is

1 \(\dfrac{1}{2}\)
2 \(\dfrac{1}{4}\)
3 1
4 \(\dfrac{1}{8}\)
CHXII01:THE SOLID STATE

318869 A solid has a structure in which \(X\) atoms are located at cubic corners of unit cell, \(\mathrm{O}\) atoms are at the edge centres and \(\mathrm{Y}\) atoms are at cube centre. Then the formula of compound is \(X_{a} Y_{b} O_{c}\). If two atoms of \(\mathrm{O}\) are missing from any of two edge centres per unit cell, then the molecular formula is \(X_{p} Y_{q} O_{r}\). Then, find the value of \((\mathrm{p}+\mathrm{q}+\mathrm{r})-(\mathrm{a}+\mathrm{b}+\mathrm{c})\).

1 2
2 4
3 5
4 8
CHXII01:THE SOLID STATE

318870 A fcc unit cell of aluminium contains the equivalent of how many atoms?

1 1
2 2
3 3
4 4
CHXII01:THE SOLID STATE

318871 A compound formed by elements \(X\) and \(Y\) has a cubic structure in which \(X\) atoms are at the corner of cube and also at the face centres. Y atoms are present at the body centre and at the edge centres of the cube. The total number of atoms in a cube are

1 12
2 20
3 27
4 15
CHXII01:THE SOLID STATE

318872 In a face centred cubic lattice atoms \(A\) are at the corner points and atoms \(B\) at the face centred points. If atoms B is missing from one of the face centred points, the formula of the ionic compound is :

1 \(\mathrm{AB}_{2}\)
2 \(\mathrm{A}_{2} \mathrm{~B}_{3}\)
3 \(\mathrm{A}_{5} \mathrm{~B}_{2}\)
4 \(\mathrm{A}_{2} \mathrm{~B}_{5}\)
CHXII01:THE SOLID STATE

318868 The contribution of particle at the edge centre of a particular unit cell is

1 \(\dfrac{1}{2}\)
2 \(\dfrac{1}{4}\)
3 1
4 \(\dfrac{1}{8}\)
CHXII01:THE SOLID STATE

318869 A solid has a structure in which \(X\) atoms are located at cubic corners of unit cell, \(\mathrm{O}\) atoms are at the edge centres and \(\mathrm{Y}\) atoms are at cube centre. Then the formula of compound is \(X_{a} Y_{b} O_{c}\). If two atoms of \(\mathrm{O}\) are missing from any of two edge centres per unit cell, then the molecular formula is \(X_{p} Y_{q} O_{r}\). Then, find the value of \((\mathrm{p}+\mathrm{q}+\mathrm{r})-(\mathrm{a}+\mathrm{b}+\mathrm{c})\).

1 2
2 4
3 5
4 8
CHXII01:THE SOLID STATE

318870 A fcc unit cell of aluminium contains the equivalent of how many atoms?

1 1
2 2
3 3
4 4
CHXII01:THE SOLID STATE

318871 A compound formed by elements \(X\) and \(Y\) has a cubic structure in which \(X\) atoms are at the corner of cube and also at the face centres. Y atoms are present at the body centre and at the edge centres of the cube. The total number of atoms in a cube are

1 12
2 20
3 27
4 15
CHXII01:THE SOLID STATE

318872 In a face centred cubic lattice atoms \(A\) are at the corner points and atoms \(B\) at the face centred points. If atoms B is missing from one of the face centred points, the formula of the ionic compound is :

1 \(\mathrm{AB}_{2}\)
2 \(\mathrm{A}_{2} \mathrm{~B}_{3}\)
3 \(\mathrm{A}_{5} \mathrm{~B}_{2}\)
4 \(\mathrm{A}_{2} \mathrm{~B}_{5}\)
CHXII01:THE SOLID STATE

318868 The contribution of particle at the edge centre of a particular unit cell is

1 \(\dfrac{1}{2}\)
2 \(\dfrac{1}{4}\)
3 1
4 \(\dfrac{1}{8}\)
CHXII01:THE SOLID STATE

318869 A solid has a structure in which \(X\) atoms are located at cubic corners of unit cell, \(\mathrm{O}\) atoms are at the edge centres and \(\mathrm{Y}\) atoms are at cube centre. Then the formula of compound is \(X_{a} Y_{b} O_{c}\). If two atoms of \(\mathrm{O}\) are missing from any of two edge centres per unit cell, then the molecular formula is \(X_{p} Y_{q} O_{r}\). Then, find the value of \((\mathrm{p}+\mathrm{q}+\mathrm{r})-(\mathrm{a}+\mathrm{b}+\mathrm{c})\).

1 2
2 4
3 5
4 8
CHXII01:THE SOLID STATE

318870 A fcc unit cell of aluminium contains the equivalent of how many atoms?

1 1
2 2
3 3
4 4
CHXII01:THE SOLID STATE

318871 A compound formed by elements \(X\) and \(Y\) has a cubic structure in which \(X\) atoms are at the corner of cube and also at the face centres. Y atoms are present at the body centre and at the edge centres of the cube. The total number of atoms in a cube are

1 12
2 20
3 27
4 15
CHXII01:THE SOLID STATE

318872 In a face centred cubic lattice atoms \(A\) are at the corner points and atoms \(B\) at the face centred points. If atoms B is missing from one of the face centred points, the formula of the ionic compound is :

1 \(\mathrm{AB}_{2}\)
2 \(\mathrm{A}_{2} \mathrm{~B}_{3}\)
3 \(\mathrm{A}_{5} \mathrm{~B}_{2}\)
4 \(\mathrm{A}_{2} \mathrm{~B}_{5}\)