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CHXI13:HYDROCARBONS

317899 The organic reaction product from the reaction of methyl magnesium bromide and ethyl alcohol is

1 Methane

2 Ethane

3 Propane

4 Butane

CHXI13:HYDROCARBONS

317900 One gram of an aliphatic bromide was completely reacted with $Mg$ and then treated with water, $182 ml$ at STP, of a gas evolved in the process. The gas was found to be stable to ${KMnO}_{4}$ . The hydrocarbon is

1 Propane

2 Butane

3 Ethane

4 Isobutane

Explanation:

No. of moles of gas evolved $= \frac{182}{22400}$
No. of moles of bromide $= \frac{1}{M}$
$\frac{1}{M} = \frac{182}{22400} M = 123$
Molecular mass of the hydrocarbon $= 123 - 80$ $= 43$
Where 80 is the atomic mass of the bromine radical
Molecular mass of the hydrocarbon $= 44$
The hydrocarbon therefore is $C_{3} H_{8}$ i.e., propane.

CHXI13:HYDROCARBONS

317901 Which of the following statements are not correct for alkane?
(A) All $C - H$ and $C - C$ bonds have a length of $1 .112 \overset{o}{A} and 1 .54 \overset{o}{A}$ respectively
(B) All bond angles are tetrahedral, having a value of $109^{\circ} 28^{'}$
(C) The $C - C$ chain is linear and not zigzag
(D) All alkanes exhibit chain isomerism

1 (A), (B)

2 (B), (C)

3 (C) ,(D)

4 (B), (D)

Explanation:

The $C - C$ chain in alkane is zigzag & $C H_{4}, C_{2} H_{6} & C_{3} H_{8}$ do not exhibit chain isomerism

CHXI13:HYDROCARBONS

317902 Alkyl halides react with dialkyl copper reagents to give:

1 Alkenes

2 Alkyl copper halides

3 Alkanes

4 Alkenyl halides

Explanation:

Alkyl halides (R'X) react with dialkyl copper $R_{2} CuLi$ reagent to give alkanes and the reaction is known as Corey House synthesis.
$R_{2} CuLi + R^{'} X \overset{Δ}{\to} \underset{Alkane}{R R^{'}} + RCu + LiX$

CHXI13:HYDROCARBONS

317903 Match the following reactants in Column I with the corresponding reaction products in Column II and select the correct answer using the given codes below:
Column I
Column II
A
$Alkane + X_{2} \overset{hv}{\to}$
P
Water + carbon dioxide
B
$Alkane + O_{2} \overset{Δ}{\to}$
Q
Alkanal
C
$Alkane + O_{2} \overset{M o_{2} O_{3}}{\to}$
R
Haloalkanes
D
$n - hexane \to_{10 - 20 atm}^{Δ,777 K}$
S
Benzene

1

A  -  P, B  -  Q, C  -  R, D  -  S

2

A  -  P, B  -  Q, C  -  S, D  -  R

3

A  -  R, B  -  P, C  -  Q, D  -  S

4

A  -  R, B  -  P, C  -  S, D  -  Q

Explanation:

(A) Halogenation of alkane gives Haloalkanes
(B) On combustion of alkane gives ${CO}_{2}$ and $H_{2} O$
(C) On oxidation of alkane by ${Mo}_{2} O_{3}$ gives aldehydes (Alkanal)
(D) n-hexane aromatises to give benzene
So, the option (3) is correct

CHXI13:HYDROCARBONS

317899 The organic reaction product from the reaction of methyl magnesium bromide and ethyl alcohol is

1 Methane

2 Ethane

3 Propane

4 Butane

CHXI13:HYDROCARBONS

317900 One gram of an aliphatic bromide was completely reacted with $Mg$ and then treated with water, $182 ml$ at STP, of a gas evolved in the process. The gas was found to be stable to ${KMnO}_{4}$ . The hydrocarbon is

1 Propane

2 Butane

3 Ethane

4 Isobutane

Explanation:

No. of moles of gas evolved $= \frac{182}{22400}$
No. of moles of bromide $= \frac{1}{M}$
$\frac{1}{M} = \frac{182}{22400} M = 123$
Molecular mass of the hydrocarbon $= 123 - 80$ $= 43$
Where 80 is the atomic mass of the bromine radical
Molecular mass of the hydrocarbon $= 44$
The hydrocarbon therefore is $C_{3} H_{8}$ i.e., propane.

CHXI13:HYDROCARBONS

317901 Which of the following statements are not correct for alkane?
(A) All $C - H$ and $C - C$ bonds have a length of $1 .112 \overset{o}{A} and 1 .54 \overset{o}{A}$ respectively
(B) All bond angles are tetrahedral, having a value of $109^{\circ} 28^{'}$
(C) The $C - C$ chain is linear and not zigzag
(D) All alkanes exhibit chain isomerism

1 (A), (B)

2 (B), (C)

3 (C) ,(D)

4 (B), (D)

Explanation:

The $C - C$ chain in alkane is zigzag & $C H_{4}, C_{2} H_{6} & C_{3} H_{8}$ do not exhibit chain isomerism

CHXI13:HYDROCARBONS

317902 Alkyl halides react with dialkyl copper reagents to give:

1 Alkenes

2 Alkyl copper halides

3 Alkanes

4 Alkenyl halides

Explanation:

Alkyl halides (R'X) react with dialkyl copper $R_{2} CuLi$ reagent to give alkanes and the reaction is known as Corey House synthesis.
$R_{2} CuLi + R^{'} X \overset{Δ}{\to} \underset{Alkane}{R R^{'}} + RCu + LiX$

CHXI13:HYDROCARBONS

317903 Match the following reactants in Column I with the corresponding reaction products in Column II and select the correct answer using the given codes below:
Column I
Column II
A
$Alkane + X_{2} \overset{hv}{\to}$
P
Water + carbon dioxide
B
$Alkane + O_{2} \overset{Δ}{\to}$
Q
Alkanal
C
$Alkane + O_{2} \overset{M o_{2} O_{3}}{\to}$
R
Haloalkanes
D
$n - hexane \to_{10 - 20 atm}^{Δ,777 K}$
S
Benzene

1

A  -  P, B  -  Q, C  -  R, D  -  S

2

A  -  P, B  -  Q, C  -  S, D  -  R

3

A  -  R, B  -  P, C  -  Q, D  -  S

4

A  -  R, B  -  P, C  -  S, D  -  Q

Explanation:

(A) Halogenation of alkane gives Haloalkanes
(B) On combustion of alkane gives ${CO}_{2}$ and $H_{2} O$
(C) On oxidation of alkane by ${Mo}_{2} O_{3}$ gives aldehydes (Alkanal)
(D) n-hexane aromatises to give benzene
So, the option (3) is correct

CHXI13:HYDROCARBONS

317899 The organic reaction product from the reaction of methyl magnesium bromide and ethyl alcohol is

1 Methane

2 Ethane

3 Propane

4 Butane

CHXI13:HYDROCARBONS

317900 One gram of an aliphatic bromide was completely reacted with $Mg$ and then treated with water, $182 ml$ at STP, of a gas evolved in the process. The gas was found to be stable to ${KMnO}_{4}$ . The hydrocarbon is

1 Propane

2 Butane

3 Ethane

4 Isobutane

Explanation:

No. of moles of gas evolved $= \frac{182}{22400}$
No. of moles of bromide $= \frac{1}{M}$
$\frac{1}{M} = \frac{182}{22400} M = 123$
Molecular mass of the hydrocarbon $= 123 - 80$ $= 43$
Where 80 is the atomic mass of the bromine radical
Molecular mass of the hydrocarbon $= 44$
The hydrocarbon therefore is $C_{3} H_{8}$ i.e., propane.

CHXI13:HYDROCARBONS

317901 Which of the following statements are not correct for alkane?
(A) All $C - H$ and $C - C$ bonds have a length of $1 .112 \overset{o}{A} and 1 .54 \overset{o}{A}$ respectively
(B) All bond angles are tetrahedral, having a value of $109^{\circ} 28^{'}$
(C) The $C - C$ chain is linear and not zigzag
(D) All alkanes exhibit chain isomerism

1 (A), (B)

2 (B), (C)

3 (C) ,(D)

4 (B), (D)

Explanation:

The $C - C$ chain in alkane is zigzag & $C H_{4}, C_{2} H_{6} & C_{3} H_{8}$ do not exhibit chain isomerism

CHXI13:HYDROCARBONS

317902 Alkyl halides react with dialkyl copper reagents to give:

1 Alkenes

2 Alkyl copper halides

3 Alkanes

4 Alkenyl halides

Explanation:

Alkyl halides (R'X) react with dialkyl copper $R_{2} CuLi$ reagent to give alkanes and the reaction is known as Corey House synthesis.
$R_{2} CuLi + R^{'} X \overset{Δ}{\to} \underset{Alkane}{R R^{'}} + RCu + LiX$

CHXI13:HYDROCARBONS

317903 Match the following reactants in Column I with the corresponding reaction products in Column II and select the correct answer using the given codes below:
Column I
Column II
A
$Alkane + X_{2} \overset{hv}{\to}$
P
Water + carbon dioxide
B
$Alkane + O_{2} \overset{Δ}{\to}$
Q
Alkanal
C
$Alkane + O_{2} \overset{M o_{2} O_{3}}{\to}$
R
Haloalkanes
D
$n - hexane \to_{10 - 20 atm}^{Δ,777 K}$
S
Benzene

1

A  -  P, B  -  Q, C  -  R, D  -  S

2

A  -  P, B  -  Q, C  -  S, D  -  R

3

A  -  R, B  -  P, C  -  Q, D  -  S

4

A  -  R, B  -  P, C  -  S, D  -  Q

Explanation:

(A) Halogenation of alkane gives Haloalkanes
(B) On combustion of alkane gives ${CO}_{2}$ and $H_{2} O$
(C) On oxidation of alkane by ${Mo}_{2} O_{3}$ gives aldehydes (Alkanal)
(D) n-hexane aromatises to give benzene
So, the option (3) is correct

CHXI13:HYDROCARBONS

317899 The organic reaction product from the reaction of methyl magnesium bromide and ethyl alcohol is

1 Methane

2 Ethane

3 Propane

4 Butane

CHXI13:HYDROCARBONS

317900 One gram of an aliphatic bromide was completely reacted with $Mg$ and then treated with water, $182 ml$ at STP, of a gas evolved in the process. The gas was found to be stable to ${KMnO}_{4}$ . The hydrocarbon is

1 Propane

2 Butane

3 Ethane

4 Isobutane

Explanation:

No. of moles of gas evolved $= \frac{182}{22400}$
No. of moles of bromide $= \frac{1}{M}$
$\frac{1}{M} = \frac{182}{22400} M = 123$
Molecular mass of the hydrocarbon $= 123 - 80$ $= 43$
Where 80 is the atomic mass of the bromine radical
Molecular mass of the hydrocarbon $= 44$
The hydrocarbon therefore is $C_{3} H_{8}$ i.e., propane.

CHXI13:HYDROCARBONS

317901 Which of the following statements are not correct for alkane?
(A) All $C - H$ and $C - C$ bonds have a length of $1 .112 \overset{o}{A} and 1 .54 \overset{o}{A}$ respectively
(B) All bond angles are tetrahedral, having a value of $109^{\circ} 28^{'}$
(C) The $C - C$ chain is linear and not zigzag
(D) All alkanes exhibit chain isomerism

1 (A), (B)

2 (B), (C)

3 (C) ,(D)

4 (B), (D)

Explanation:

The $C - C$ chain in alkane is zigzag & $C H_{4}, C_{2} H_{6} & C_{3} H_{8}$ do not exhibit chain isomerism

CHXI13:HYDROCARBONS

317902 Alkyl halides react with dialkyl copper reagents to give:

1 Alkenes

2 Alkyl copper halides

3 Alkanes

4 Alkenyl halides

Explanation:

Alkyl halides (R'X) react with dialkyl copper $R_{2} CuLi$ reagent to give alkanes and the reaction is known as Corey House synthesis.
$R_{2} CuLi + R^{'} X \overset{Δ}{\to} \underset{Alkane}{R R^{'}} + RCu + LiX$

CHXI13:HYDROCARBONS

317903 Match the following reactants in Column I with the corresponding reaction products in Column II and select the correct answer using the given codes below:
Column I
Column II
A
$Alkane + X_{2} \overset{hv}{\to}$
P
Water + carbon dioxide
B
$Alkane + O_{2} \overset{Δ}{\to}$
Q
Alkanal
C
$Alkane + O_{2} \overset{M o_{2} O_{3}}{\to}$
R
Haloalkanes
D
$n - hexane \to_{10 - 20 atm}^{Δ,777 K}$
S
Benzene

1

A  -  P, B  -  Q, C  -  R, D  -  S

2

A  -  P, B  -  Q, C  -  S, D  -  R

3

A  -  R, B  -  P, C  -  Q, D  -  S

4

A  -  R, B  -  P, C  -  S, D  -  Q

Explanation:

(A) Halogenation of alkane gives Haloalkanes
(B) On combustion of alkane gives ${CO}_{2}$ and $H_{2} O$
(C) On oxidation of alkane by ${Mo}_{2} O_{3}$ gives aldehydes (Alkanal)
(D) n-hexane aromatises to give benzene
So, the option (3) is correct

CHXI13:HYDROCARBONS

317899 The organic reaction product from the reaction of methyl magnesium bromide and ethyl alcohol is

1 Methane

2 Ethane

3 Propane

4 Butane

CHXI13:HYDROCARBONS

317900 One gram of an aliphatic bromide was completely reacted with $Mg$ and then treated with water, $182 ml$ at STP, of a gas evolved in the process. The gas was found to be stable to ${KMnO}_{4}$ . The hydrocarbon is

1 Propane

2 Butane

3 Ethane

4 Isobutane

Explanation:

No. of moles of gas evolved $= \frac{182}{22400}$
No. of moles of bromide $= \frac{1}{M}$
$\frac{1}{M} = \frac{182}{22400} M = 123$
Molecular mass of the hydrocarbon $= 123 - 80$ $= 43$
Where 80 is the atomic mass of the bromine radical
Molecular mass of the hydrocarbon $= 44$
The hydrocarbon therefore is $C_{3} H_{8}$ i.e., propane.

CHXI13:HYDROCARBONS

317901 Which of the following statements are not correct for alkane?
(A) All $C - H$ and $C - C$ bonds have a length of $1 .112 \overset{o}{A} and 1 .54 \overset{o}{A}$ respectively
(B) All bond angles are tetrahedral, having a value of $109^{\circ} 28^{'}$
(C) The $C - C$ chain is linear and not zigzag
(D) All alkanes exhibit chain isomerism

1 (A), (B)

2 (B), (C)

3 (C) ,(D)

4 (B), (D)

Explanation:

The $C - C$ chain in alkane is zigzag & $C H_{4}, C_{2} H_{6} & C_{3} H_{8}$ do not exhibit chain isomerism

CHXI13:HYDROCARBONS

317902 Alkyl halides react with dialkyl copper reagents to give:

1 Alkenes

2 Alkyl copper halides

3 Alkanes

4 Alkenyl halides

Explanation:

Alkyl halides (R'X) react with dialkyl copper $R_{2} CuLi$ reagent to give alkanes and the reaction is known as Corey House synthesis.
$R_{2} CuLi + R^{'} X \overset{Δ}{\to} \underset{Alkane}{R R^{'}} + RCu + LiX$

CHXI13:HYDROCARBONS

317903 Match the following reactants in Column I with the corresponding reaction products in Column II and select the correct answer using the given codes below:
Column I
Column II
A
$Alkane + X_{2} \overset{hv}{\to}$
P
Water + carbon dioxide
B
$Alkane + O_{2} \overset{Δ}{\to}$
Q
Alkanal
C
$Alkane + O_{2} \overset{M o_{2} O_{3}}{\to}$
R
Haloalkanes
D
$n - hexane \to_{10 - 20 atm}^{Δ,777 K}$
S
Benzene

1

A  -  P, B  -  Q, C  -  R, D  -  S

2

A  -  P, B  -  Q, C  -  S, D  -  R

3

A  -  R, B  -  P, C  -  Q, D  -  S

4

A  -  R, B  -  P, C  -  S, D  -  Q

Explanation:

(A) Halogenation of alkane gives Haloalkanes
(B) On combustion of alkane gives ${CO}_{2}$ and $H_{2} O$
(C) On oxidation of alkane by ${Mo}_{2} O_{3}$ gives aldehydes (Alkanal)
(D) n-hexane aromatises to give benzene
So, the option (3) is correct

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