317979
Which of the following is NOT obtained when a mixture of bromomethane and bromoethane is treated with sodium in dry ether?
1 Propane
2 Butane
3 Methane
4 Ethane
Explanation:
Mixed Wurtz reaction \(\mathop {{\text{C}}{{\text{H}}_{\text{3}}}{\text{ - Br}}}\limits_{{\text{Bromomethane}}} {\text{ + 2Na}}\mathop {{\text{ + Br - C}}{{\text{H}}_{\text{2}}}}\limits_{{\text{Bromoethane}}} {\text{ - C}}{{\text{H}}_{\text{3}}}\xrightarrow{{{\text{Dry}}{\mkern 1mu} {\mkern 1mu} {\text{ether}}}}\) \(\mathop {{\text{C}}{{\text{H}}_{\text{3}}} - {\text{C}}{{\text{H}}_{\text{2}}}}\limits_{{\text{Propane}}} - {\text{C}}{{\text{H}}_{\text{3}}}{\text{ + 2NaBr}}\) Propane is Cross-coupling product. Ethane and Butane are self - coupling products. Methane can not be prepared by Wurtz reaction.
MHTCET - 2021
CHXI13:HYDROCARBONS
317980
In the reaction,\(\mathrm{CH}_{3} \mathrm{COONa}+\mathrm{H}_{2} \mathrm{O} \xrightarrow{\text { electrolysis }}\) Read the statements given below and choose option containing incorrect statement.
1 Gas produced at anode gives lime water test.
2 One of the gas produced at cathode gives pop sound test.
3 The pH of the reaction mixture increases as reaction progresses.
4 Alkane produced in this reaction cannot show conformational isomerism.
Explanation:
\(\mathrm{CO}_{2}\) gives lime water test and \(\mathrm{H}_{2}\) at cathode gives pop sound test. pH of solution increases as KOH is formed in the reaction.\(\mathrm{C}_{2} \mathrm{H}_{6}\) shows conformational isomerism.
CHXI13:HYDROCARBONS
317811
An alkane with molecular mass 72 formed only one substitution product. The number of \(1^{\circ}\) hydrogens in it is.
1 8
2 10
3 5
4 12
Explanation:
Let the molecular formula of the alkane be \(\mathrm{C}_{\mathrm{n}} \mathrm{H}_{2 \mathrm{n}+2}\). Molecular mass of the alkane \(=\mathrm{nC}+(2 \mathrm{n}+2) \mathrm{H}\) \( = {\rm{n}} \times 12 + (2{\rm{n}} + 2) \times 1\) \( = 14\,{\rm{n}} + 2\) \(14\,{\rm{n}} + 2 = 72\) \(14\,{\rm{n}} = 72 - 2 = 70\) \({\rm{n}} = \frac{{70}}{{14}} = 5\) Thus, the molecular formula of the alkane is \(\mathrm{C}_{5} \mathrm{H}_{12}\). It can have three isomers.
It is neopentane which forms one substitution product as it has only one type of hydrogen. Number of \(1^{\circ}\) hydrogens \(=12\).
CHXI13:HYDROCARBONS
317812 The given reaction is an example of
1 Isomerisation
2 Polymerisation
3 Cracking
4 Dehydrogenation
Explanation:
Conceptual Questions
CHXI13:HYDROCARBONS
317813
The one giving maximum number of isomeric alkenes on dehydrohalogenation reaction is (excluding rearrangement)
317979
Which of the following is NOT obtained when a mixture of bromomethane and bromoethane is treated with sodium in dry ether?
1 Propane
2 Butane
3 Methane
4 Ethane
Explanation:
Mixed Wurtz reaction \(\mathop {{\text{C}}{{\text{H}}_{\text{3}}}{\text{ - Br}}}\limits_{{\text{Bromomethane}}} {\text{ + 2Na}}\mathop {{\text{ + Br - C}}{{\text{H}}_{\text{2}}}}\limits_{{\text{Bromoethane}}} {\text{ - C}}{{\text{H}}_{\text{3}}}\xrightarrow{{{\text{Dry}}{\mkern 1mu} {\mkern 1mu} {\text{ether}}}}\) \(\mathop {{\text{C}}{{\text{H}}_{\text{3}}} - {\text{C}}{{\text{H}}_{\text{2}}}}\limits_{{\text{Propane}}} - {\text{C}}{{\text{H}}_{\text{3}}}{\text{ + 2NaBr}}\) Propane is Cross-coupling product. Ethane and Butane are self - coupling products. Methane can not be prepared by Wurtz reaction.
MHTCET - 2021
CHXI13:HYDROCARBONS
317980
In the reaction,\(\mathrm{CH}_{3} \mathrm{COONa}+\mathrm{H}_{2} \mathrm{O} \xrightarrow{\text { electrolysis }}\) Read the statements given below and choose option containing incorrect statement.
1 Gas produced at anode gives lime water test.
2 One of the gas produced at cathode gives pop sound test.
3 The pH of the reaction mixture increases as reaction progresses.
4 Alkane produced in this reaction cannot show conformational isomerism.
Explanation:
\(\mathrm{CO}_{2}\) gives lime water test and \(\mathrm{H}_{2}\) at cathode gives pop sound test. pH of solution increases as KOH is formed in the reaction.\(\mathrm{C}_{2} \mathrm{H}_{6}\) shows conformational isomerism.
CHXI13:HYDROCARBONS
317811
An alkane with molecular mass 72 formed only one substitution product. The number of \(1^{\circ}\) hydrogens in it is.
1 8
2 10
3 5
4 12
Explanation:
Let the molecular formula of the alkane be \(\mathrm{C}_{\mathrm{n}} \mathrm{H}_{2 \mathrm{n}+2}\). Molecular mass of the alkane \(=\mathrm{nC}+(2 \mathrm{n}+2) \mathrm{H}\) \( = {\rm{n}} \times 12 + (2{\rm{n}} + 2) \times 1\) \( = 14\,{\rm{n}} + 2\) \(14\,{\rm{n}} + 2 = 72\) \(14\,{\rm{n}} = 72 - 2 = 70\) \({\rm{n}} = \frac{{70}}{{14}} = 5\) Thus, the molecular formula of the alkane is \(\mathrm{C}_{5} \mathrm{H}_{12}\). It can have three isomers.
It is neopentane which forms one substitution product as it has only one type of hydrogen. Number of \(1^{\circ}\) hydrogens \(=12\).
CHXI13:HYDROCARBONS
317812 The given reaction is an example of
1 Isomerisation
2 Polymerisation
3 Cracking
4 Dehydrogenation
Explanation:
Conceptual Questions
CHXI13:HYDROCARBONS
317813
The one giving maximum number of isomeric alkenes on dehydrohalogenation reaction is (excluding rearrangement)
317979
Which of the following is NOT obtained when a mixture of bromomethane and bromoethane is treated with sodium in dry ether?
1 Propane
2 Butane
3 Methane
4 Ethane
Explanation:
Mixed Wurtz reaction \(\mathop {{\text{C}}{{\text{H}}_{\text{3}}}{\text{ - Br}}}\limits_{{\text{Bromomethane}}} {\text{ + 2Na}}\mathop {{\text{ + Br - C}}{{\text{H}}_{\text{2}}}}\limits_{{\text{Bromoethane}}} {\text{ - C}}{{\text{H}}_{\text{3}}}\xrightarrow{{{\text{Dry}}{\mkern 1mu} {\mkern 1mu} {\text{ether}}}}\) \(\mathop {{\text{C}}{{\text{H}}_{\text{3}}} - {\text{C}}{{\text{H}}_{\text{2}}}}\limits_{{\text{Propane}}} - {\text{C}}{{\text{H}}_{\text{3}}}{\text{ + 2NaBr}}\) Propane is Cross-coupling product. Ethane and Butane are self - coupling products. Methane can not be prepared by Wurtz reaction.
MHTCET - 2021
CHXI13:HYDROCARBONS
317980
In the reaction,\(\mathrm{CH}_{3} \mathrm{COONa}+\mathrm{H}_{2} \mathrm{O} \xrightarrow{\text { electrolysis }}\) Read the statements given below and choose option containing incorrect statement.
1 Gas produced at anode gives lime water test.
2 One of the gas produced at cathode gives pop sound test.
3 The pH of the reaction mixture increases as reaction progresses.
4 Alkane produced in this reaction cannot show conformational isomerism.
Explanation:
\(\mathrm{CO}_{2}\) gives lime water test and \(\mathrm{H}_{2}\) at cathode gives pop sound test. pH of solution increases as KOH is formed in the reaction.\(\mathrm{C}_{2} \mathrm{H}_{6}\) shows conformational isomerism.
CHXI13:HYDROCARBONS
317811
An alkane with molecular mass 72 formed only one substitution product. The number of \(1^{\circ}\) hydrogens in it is.
1 8
2 10
3 5
4 12
Explanation:
Let the molecular formula of the alkane be \(\mathrm{C}_{\mathrm{n}} \mathrm{H}_{2 \mathrm{n}+2}\). Molecular mass of the alkane \(=\mathrm{nC}+(2 \mathrm{n}+2) \mathrm{H}\) \( = {\rm{n}} \times 12 + (2{\rm{n}} + 2) \times 1\) \( = 14\,{\rm{n}} + 2\) \(14\,{\rm{n}} + 2 = 72\) \(14\,{\rm{n}} = 72 - 2 = 70\) \({\rm{n}} = \frac{{70}}{{14}} = 5\) Thus, the molecular formula of the alkane is \(\mathrm{C}_{5} \mathrm{H}_{12}\). It can have three isomers.
It is neopentane which forms one substitution product as it has only one type of hydrogen. Number of \(1^{\circ}\) hydrogens \(=12\).
CHXI13:HYDROCARBONS
317812 The given reaction is an example of
1 Isomerisation
2 Polymerisation
3 Cracking
4 Dehydrogenation
Explanation:
Conceptual Questions
CHXI13:HYDROCARBONS
317813
The one giving maximum number of isomeric alkenes on dehydrohalogenation reaction is (excluding rearrangement)
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CHXI13:HYDROCARBONS
317979
Which of the following is NOT obtained when a mixture of bromomethane and bromoethane is treated with sodium in dry ether?
1 Propane
2 Butane
3 Methane
4 Ethane
Explanation:
Mixed Wurtz reaction \(\mathop {{\text{C}}{{\text{H}}_{\text{3}}}{\text{ - Br}}}\limits_{{\text{Bromomethane}}} {\text{ + 2Na}}\mathop {{\text{ + Br - C}}{{\text{H}}_{\text{2}}}}\limits_{{\text{Bromoethane}}} {\text{ - C}}{{\text{H}}_{\text{3}}}\xrightarrow{{{\text{Dry}}{\mkern 1mu} {\mkern 1mu} {\text{ether}}}}\) \(\mathop {{\text{C}}{{\text{H}}_{\text{3}}} - {\text{C}}{{\text{H}}_{\text{2}}}}\limits_{{\text{Propane}}} - {\text{C}}{{\text{H}}_{\text{3}}}{\text{ + 2NaBr}}\) Propane is Cross-coupling product. Ethane and Butane are self - coupling products. Methane can not be prepared by Wurtz reaction.
MHTCET - 2021
CHXI13:HYDROCARBONS
317980
In the reaction,\(\mathrm{CH}_{3} \mathrm{COONa}+\mathrm{H}_{2} \mathrm{O} \xrightarrow{\text { electrolysis }}\) Read the statements given below and choose option containing incorrect statement.
1 Gas produced at anode gives lime water test.
2 One of the gas produced at cathode gives pop sound test.
3 The pH of the reaction mixture increases as reaction progresses.
4 Alkane produced in this reaction cannot show conformational isomerism.
Explanation:
\(\mathrm{CO}_{2}\) gives lime water test and \(\mathrm{H}_{2}\) at cathode gives pop sound test. pH of solution increases as KOH is formed in the reaction.\(\mathrm{C}_{2} \mathrm{H}_{6}\) shows conformational isomerism.
CHXI13:HYDROCARBONS
317811
An alkane with molecular mass 72 formed only one substitution product. The number of \(1^{\circ}\) hydrogens in it is.
1 8
2 10
3 5
4 12
Explanation:
Let the molecular formula of the alkane be \(\mathrm{C}_{\mathrm{n}} \mathrm{H}_{2 \mathrm{n}+2}\). Molecular mass of the alkane \(=\mathrm{nC}+(2 \mathrm{n}+2) \mathrm{H}\) \( = {\rm{n}} \times 12 + (2{\rm{n}} + 2) \times 1\) \( = 14\,{\rm{n}} + 2\) \(14\,{\rm{n}} + 2 = 72\) \(14\,{\rm{n}} = 72 - 2 = 70\) \({\rm{n}} = \frac{{70}}{{14}} = 5\) Thus, the molecular formula of the alkane is \(\mathrm{C}_{5} \mathrm{H}_{12}\). It can have three isomers.
It is neopentane which forms one substitution product as it has only one type of hydrogen. Number of \(1^{\circ}\) hydrogens \(=12\).
CHXI13:HYDROCARBONS
317812 The given reaction is an example of
1 Isomerisation
2 Polymerisation
3 Cracking
4 Dehydrogenation
Explanation:
Conceptual Questions
CHXI13:HYDROCARBONS
317813
The one giving maximum number of isomeric alkenes on dehydrohalogenation reaction is (excluding rearrangement)
317979
Which of the following is NOT obtained when a mixture of bromomethane and bromoethane is treated with sodium in dry ether?
1 Propane
2 Butane
3 Methane
4 Ethane
Explanation:
Mixed Wurtz reaction \(\mathop {{\text{C}}{{\text{H}}_{\text{3}}}{\text{ - Br}}}\limits_{{\text{Bromomethane}}} {\text{ + 2Na}}\mathop {{\text{ + Br - C}}{{\text{H}}_{\text{2}}}}\limits_{{\text{Bromoethane}}} {\text{ - C}}{{\text{H}}_{\text{3}}}\xrightarrow{{{\text{Dry}}{\mkern 1mu} {\mkern 1mu} {\text{ether}}}}\) \(\mathop {{\text{C}}{{\text{H}}_{\text{3}}} - {\text{C}}{{\text{H}}_{\text{2}}}}\limits_{{\text{Propane}}} - {\text{C}}{{\text{H}}_{\text{3}}}{\text{ + 2NaBr}}\) Propane is Cross-coupling product. Ethane and Butane are self - coupling products. Methane can not be prepared by Wurtz reaction.
MHTCET - 2021
CHXI13:HYDROCARBONS
317980
In the reaction,\(\mathrm{CH}_{3} \mathrm{COONa}+\mathrm{H}_{2} \mathrm{O} \xrightarrow{\text { electrolysis }}\) Read the statements given below and choose option containing incorrect statement.
1 Gas produced at anode gives lime water test.
2 One of the gas produced at cathode gives pop sound test.
3 The pH of the reaction mixture increases as reaction progresses.
4 Alkane produced in this reaction cannot show conformational isomerism.
Explanation:
\(\mathrm{CO}_{2}\) gives lime water test and \(\mathrm{H}_{2}\) at cathode gives pop sound test. pH of solution increases as KOH is formed in the reaction.\(\mathrm{C}_{2} \mathrm{H}_{6}\) shows conformational isomerism.
CHXI13:HYDROCARBONS
317811
An alkane with molecular mass 72 formed only one substitution product. The number of \(1^{\circ}\) hydrogens in it is.
1 8
2 10
3 5
4 12
Explanation:
Let the molecular formula of the alkane be \(\mathrm{C}_{\mathrm{n}} \mathrm{H}_{2 \mathrm{n}+2}\). Molecular mass of the alkane \(=\mathrm{nC}+(2 \mathrm{n}+2) \mathrm{H}\) \( = {\rm{n}} \times 12 + (2{\rm{n}} + 2) \times 1\) \( = 14\,{\rm{n}} + 2\) \(14\,{\rm{n}} + 2 = 72\) \(14\,{\rm{n}} = 72 - 2 = 70\) \({\rm{n}} = \frac{{70}}{{14}} = 5\) Thus, the molecular formula of the alkane is \(\mathrm{C}_{5} \mathrm{H}_{12}\). It can have three isomers.
It is neopentane which forms one substitution product as it has only one type of hydrogen. Number of \(1^{\circ}\) hydrogens \(=12\).
CHXI13:HYDROCARBONS
317812 The given reaction is an example of
1 Isomerisation
2 Polymerisation
3 Cracking
4 Dehydrogenation
Explanation:
Conceptual Questions
CHXI13:HYDROCARBONS
317813
The one giving maximum number of isomeric alkenes on dehydrohalogenation reaction is (excluding rearrangement)
