316898
Value of ' \({\text{x}}\) ' in potash alum, \(\mathrm{K}_{2} \mathrm{SO}_{4} \cdot \mathrm{Al}_{\mathrm{x}}\left(\mathrm{SO}_{4}\right)_{3}\). \(24 \mathrm{H}_{2} \mathrm{O}\) is:
1 4
2 1
3 2
4 None of these
Explanation:
The formula of potash alum is \(\mathrm{K}_{2} \mathrm{SO}_{4} \cdot \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} \cdot 24 \mathrm{H}_{2} \mathrm{O}\) \(\left( {{\text{A}}{{\text{l}}^{{\text{ + 3}}}}{\text{,SO}}_{\text{4}}^{{\text{ - 2}}}{\text{ions}}} \right)\)
CHXI11:THE P-BLOCK ELEMENTS
316899
Aluminium (III) chloride forms a dimer because aluminium
316898
Value of ' \({\text{x}}\) ' in potash alum, \(\mathrm{K}_{2} \mathrm{SO}_{4} \cdot \mathrm{Al}_{\mathrm{x}}\left(\mathrm{SO}_{4}\right)_{3}\). \(24 \mathrm{H}_{2} \mathrm{O}\) is:
1 4
2 1
3 2
4 None of these
Explanation:
The formula of potash alum is \(\mathrm{K}_{2} \mathrm{SO}_{4} \cdot \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} \cdot 24 \mathrm{H}_{2} \mathrm{O}\) \(\left( {{\text{A}}{{\text{l}}^{{\text{ + 3}}}}{\text{,SO}}_{\text{4}}^{{\text{ - 2}}}{\text{ions}}} \right)\)
CHXI11:THE P-BLOCK ELEMENTS
316899
Aluminium (III) chloride forms a dimer because aluminium
316898
Value of ' \({\text{x}}\) ' in potash alum, \(\mathrm{K}_{2} \mathrm{SO}_{4} \cdot \mathrm{Al}_{\mathrm{x}}\left(\mathrm{SO}_{4}\right)_{3}\). \(24 \mathrm{H}_{2} \mathrm{O}\) is:
1 4
2 1
3 2
4 None of these
Explanation:
The formula of potash alum is \(\mathrm{K}_{2} \mathrm{SO}_{4} \cdot \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} \cdot 24 \mathrm{H}_{2} \mathrm{O}\) \(\left( {{\text{A}}{{\text{l}}^{{\text{ + 3}}}}{\text{,SO}}_{\text{4}}^{{\text{ - 2}}}{\text{ions}}} \right)\)
CHXI11:THE P-BLOCK ELEMENTS
316899
Aluminium (III) chloride forms a dimer because aluminium
316898
Value of ' \({\text{x}}\) ' in potash alum, \(\mathrm{K}_{2} \mathrm{SO}_{4} \cdot \mathrm{Al}_{\mathrm{x}}\left(\mathrm{SO}_{4}\right)_{3}\). \(24 \mathrm{H}_{2} \mathrm{O}\) is:
1 4
2 1
3 2
4 None of these
Explanation:
The formula of potash alum is \(\mathrm{K}_{2} \mathrm{SO}_{4} \cdot \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} \cdot 24 \mathrm{H}_{2} \mathrm{O}\) \(\left( {{\text{A}}{{\text{l}}^{{\text{ + 3}}}}{\text{,SO}}_{\text{4}}^{{\text{ - 2}}}{\text{ions}}} \right)\)
CHXI11:THE P-BLOCK ELEMENTS
316899
Aluminium (III) chloride forms a dimer because aluminium