CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317539
Assertion : Sulphur is estimated as \(\mathrm{BaSO}_{4}\). Reason : Estimation of sulphur is done by Beilstein test.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Estimation of sulphur is done by Carius method. Sulphur is oxidised to \(\mathrm{H}_{2} \mathrm{SO}_{4}\), which is precipiatated as \(\mathrm{BaSO}_{4}\) by adding \(\mathrm{BaCl}_{2}\). So, the option (3) is correct.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317540
\(0.395 \mathrm{~g}\) of an organic compound by Carius method for the estimiation of sulphur gave \(0.582 \mathrm{~g}\) of \(\mathrm{BaSO}_{4}\). The percentage of sulphur in the compound is
1 20.24
2 35.36
3 40.15
4 45.84
Explanation:
Mass \(\mathrm{BaSO}_{4}=0.582 \mathrm{~g}\) We know \(\begin{array}{l}{\rm{BaS}}{{\rm{O}}_{\rm{4}}}{\rm{ = S}}\\\,\,\,{\rm{233}}\quad \,{\rm{32}}\end{array}\) \(233 \mathrm{~g}\) of \(\mathrm{BaSO}_{4}\) contain sulphur \(=32 \mathrm{~g}\) \(0.582 \mathrm{~g}\) of \(\mathrm{BaSO}_{4}\) contains sulphur \(=\dfrac{32}{233} \times 0.582\) Percentage of sulphur \(=\dfrac{\text { Wt.of sulphur }}{\text { Wt.of compound }} \times 100\) \(=\dfrac{32 \times 0.582}{233 \times 0.395} \times 100=20.24 \%\)
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317539
Assertion : Sulphur is estimated as \(\mathrm{BaSO}_{4}\). Reason : Estimation of sulphur is done by Beilstein test.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
Estimation of sulphur is done by Carius method. Sulphur is oxidised to \(\mathrm{H}_{2} \mathrm{SO}_{4}\), which is precipiatated as \(\mathrm{BaSO}_{4}\) by adding \(\mathrm{BaCl}_{2}\). So, the option (3) is correct.
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317540
\(0.395 \mathrm{~g}\) of an organic compound by Carius method for the estimiation of sulphur gave \(0.582 \mathrm{~g}\) of \(\mathrm{BaSO}_{4}\). The percentage of sulphur in the compound is
1 20.24
2 35.36
3 40.15
4 45.84
Explanation:
Mass \(\mathrm{BaSO}_{4}=0.582 \mathrm{~g}\) We know \(\begin{array}{l}{\rm{BaS}}{{\rm{O}}_{\rm{4}}}{\rm{ = S}}\\\,\,\,{\rm{233}}\quad \,{\rm{32}}\end{array}\) \(233 \mathrm{~g}\) of \(\mathrm{BaSO}_{4}\) contain sulphur \(=32 \mathrm{~g}\) \(0.582 \mathrm{~g}\) of \(\mathrm{BaSO}_{4}\) contains sulphur \(=\dfrac{32}{233} \times 0.582\) Percentage of sulphur \(=\dfrac{\text { Wt.of sulphur }}{\text { Wt.of compound }} \times 100\) \(=\dfrac{32 \times 0.582}{233 \times 0.395} \times 100=20.24 \%\)