NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317383
Which from the following statements is NOT correct for heterolysis?
1 In this electron rich and electron deficient species are formed.
2 Heterolysis of methyl bromide forms methyl carbocation.
3 It occurs when bonded atoms have different electronegativity.
4 Movement of a single electron from a bond occurs. shared pair of covalent bond occurs.
Explanation:
In heterolytic cleavage of covalent bond, both shared electrons go to one of the two bonded atoms.
MHTCET - 2021
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317384
In \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\), the bond that undergoes heterolytic cleavage most readily is
1 \(\mathrm{C}-\mathrm{C}\)
2 \(\mathrm{C}-\mathrm{O}\)
3 \(\mathrm{C}-\mathrm{H}\)
4 \(\mathrm{O}-\mathrm{H}\)
Explanation:
Conceptual Questions
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317385
In which of the following, homolytic bond fission takes place?
1 Free radical chlorination of methane
2 Alkaline hydrolysis of ethyl chloride
3 Addition of \(\mathrm{HBr}\) to double bond
4 Nitration of Benzene
Explanation:
Free radical formation takes place due to homolytic cleavage.
KCET - 2017
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317386
Heterolysis of propane gives
1 Methyl and ethyl free radicals
2 Methylcarbocation and ethyl free radicals
3 Methyl carbanion and ethyl carbocation
4 Methylfree radical and ethylcarbocation
Explanation:
Heterolysis of a covalent bond form carbocation and carbanion. \({\rm{C}}{{\rm{H}}_{\rm{3}}} - {\rm{C}}{{\rm{H}}_{\rm{2}}} - {\rm{C}}{{\rm{H}}_{\rm{3}}} \to {\rm{C}}{{\rm{H}}_{\rm{3}}}\mathop {\rm{C}}\limits^{\rm{ + }} {{\rm{H}}_{\rm{2}}} + \mathop {\rm{C}}\limits^{\rm{ - }} {{\rm{H}}_{\rm{3}}}\) Due to inductive effect, \({\rm{C}}{{\rm{H}}_{\rm{3}}}\mathop {\rm{C}}\limits^{\rm{ + }} {{\rm{H}}_{\rm{2}}}\) and \(\mathop {{\rm{ C}}}\limits^\Theta {{\rm{H}}_{\rm{3}}}\) are fromed as major species during heterolysis of propane
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317383
Which from the following statements is NOT correct for heterolysis?
1 In this electron rich and electron deficient species are formed.
2 Heterolysis of methyl bromide forms methyl carbocation.
3 It occurs when bonded atoms have different electronegativity.
4 Movement of a single electron from a bond occurs. shared pair of covalent bond occurs.
Explanation:
In heterolytic cleavage of covalent bond, both shared electrons go to one of the two bonded atoms.
MHTCET - 2021
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317384
In \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\), the bond that undergoes heterolytic cleavage most readily is
1 \(\mathrm{C}-\mathrm{C}\)
2 \(\mathrm{C}-\mathrm{O}\)
3 \(\mathrm{C}-\mathrm{H}\)
4 \(\mathrm{O}-\mathrm{H}\)
Explanation:
Conceptual Questions
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317385
In which of the following, homolytic bond fission takes place?
1 Free radical chlorination of methane
2 Alkaline hydrolysis of ethyl chloride
3 Addition of \(\mathrm{HBr}\) to double bond
4 Nitration of Benzene
Explanation:
Free radical formation takes place due to homolytic cleavage.
KCET - 2017
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317386
Heterolysis of propane gives
1 Methyl and ethyl free radicals
2 Methylcarbocation and ethyl free radicals
3 Methyl carbanion and ethyl carbocation
4 Methylfree radical and ethylcarbocation
Explanation:
Heterolysis of a covalent bond form carbocation and carbanion. \({\rm{C}}{{\rm{H}}_{\rm{3}}} - {\rm{C}}{{\rm{H}}_{\rm{2}}} - {\rm{C}}{{\rm{H}}_{\rm{3}}} \to {\rm{C}}{{\rm{H}}_{\rm{3}}}\mathop {\rm{C}}\limits^{\rm{ + }} {{\rm{H}}_{\rm{2}}} + \mathop {\rm{C}}\limits^{\rm{ - }} {{\rm{H}}_{\rm{3}}}\) Due to inductive effect, \({\rm{C}}{{\rm{H}}_{\rm{3}}}\mathop {\rm{C}}\limits^{\rm{ + }} {{\rm{H}}_{\rm{2}}}\) and \(\mathop {{\rm{ C}}}\limits^\Theta {{\rm{H}}_{\rm{3}}}\) are fromed as major species during heterolysis of propane
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317383
Which from the following statements is NOT correct for heterolysis?
1 In this electron rich and electron deficient species are formed.
2 Heterolysis of methyl bromide forms methyl carbocation.
3 It occurs when bonded atoms have different electronegativity.
4 Movement of a single electron from a bond occurs. shared pair of covalent bond occurs.
Explanation:
In heterolytic cleavage of covalent bond, both shared electrons go to one of the two bonded atoms.
MHTCET - 2021
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317384
In \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\), the bond that undergoes heterolytic cleavage most readily is
1 \(\mathrm{C}-\mathrm{C}\)
2 \(\mathrm{C}-\mathrm{O}\)
3 \(\mathrm{C}-\mathrm{H}\)
4 \(\mathrm{O}-\mathrm{H}\)
Explanation:
Conceptual Questions
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317385
In which of the following, homolytic bond fission takes place?
1 Free radical chlorination of methane
2 Alkaline hydrolysis of ethyl chloride
3 Addition of \(\mathrm{HBr}\) to double bond
4 Nitration of Benzene
Explanation:
Free radical formation takes place due to homolytic cleavage.
KCET - 2017
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317386
Heterolysis of propane gives
1 Methyl and ethyl free radicals
2 Methylcarbocation and ethyl free radicals
3 Methyl carbanion and ethyl carbocation
4 Methylfree radical and ethylcarbocation
Explanation:
Heterolysis of a covalent bond form carbocation and carbanion. \({\rm{C}}{{\rm{H}}_{\rm{3}}} - {\rm{C}}{{\rm{H}}_{\rm{2}}} - {\rm{C}}{{\rm{H}}_{\rm{3}}} \to {\rm{C}}{{\rm{H}}_{\rm{3}}}\mathop {\rm{C}}\limits^{\rm{ + }} {{\rm{H}}_{\rm{2}}} + \mathop {\rm{C}}\limits^{\rm{ - }} {{\rm{H}}_{\rm{3}}}\) Due to inductive effect, \({\rm{C}}{{\rm{H}}_{\rm{3}}}\mathop {\rm{C}}\limits^{\rm{ + }} {{\rm{H}}_{\rm{2}}}\) and \(\mathop {{\rm{ C}}}\limits^\Theta {{\rm{H}}_{\rm{3}}}\) are fromed as major species during heterolysis of propane
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317383
Which from the following statements is NOT correct for heterolysis?
1 In this electron rich and electron deficient species are formed.
2 Heterolysis of methyl bromide forms methyl carbocation.
3 It occurs when bonded atoms have different electronegativity.
4 Movement of a single electron from a bond occurs. shared pair of covalent bond occurs.
Explanation:
In heterolytic cleavage of covalent bond, both shared electrons go to one of the two bonded atoms.
MHTCET - 2021
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317384
In \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\), the bond that undergoes heterolytic cleavage most readily is
1 \(\mathrm{C}-\mathrm{C}\)
2 \(\mathrm{C}-\mathrm{O}\)
3 \(\mathrm{C}-\mathrm{H}\)
4 \(\mathrm{O}-\mathrm{H}\)
Explanation:
Conceptual Questions
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317385
In which of the following, homolytic bond fission takes place?
1 Free radical chlorination of methane
2 Alkaline hydrolysis of ethyl chloride
3 Addition of \(\mathrm{HBr}\) to double bond
4 Nitration of Benzene
Explanation:
Free radical formation takes place due to homolytic cleavage.
KCET - 2017
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317386
Heterolysis of propane gives
1 Methyl and ethyl free radicals
2 Methylcarbocation and ethyl free radicals
3 Methyl carbanion and ethyl carbocation
4 Methylfree radical and ethylcarbocation
Explanation:
Heterolysis of a covalent bond form carbocation and carbanion. \({\rm{C}}{{\rm{H}}_{\rm{3}}} - {\rm{C}}{{\rm{H}}_{\rm{2}}} - {\rm{C}}{{\rm{H}}_{\rm{3}}} \to {\rm{C}}{{\rm{H}}_{\rm{3}}}\mathop {\rm{C}}\limits^{\rm{ + }} {{\rm{H}}_{\rm{2}}} + \mathop {\rm{C}}\limits^{\rm{ - }} {{\rm{H}}_{\rm{3}}}\) Due to inductive effect, \({\rm{C}}{{\rm{H}}_{\rm{3}}}\mathop {\rm{C}}\limits^{\rm{ + }} {{\rm{H}}_{\rm{2}}}\) and \(\mathop {{\rm{ C}}}\limits^\Theta {{\rm{H}}_{\rm{3}}}\) are fromed as major species during heterolysis of propane
