CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317123
A hydrocarbon has carbon and hydrogen. Its molecular weight is 28 . Its possible formula would be
1 \(\mathrm{C}_{3} \mathrm{H}_{6}\)
2 \(\mathrm{C}_{2} \mathrm{H}_{4}\)
3 \(\mathrm{CH}_{4}\)
4 \(\mathrm{C}_{4} \mathrm{H}_{8}\)
Explanation:
Hence the formula of the given compound is \({{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{4}}}\)
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317124
An oxygen containing organic compound was found to contain \(52 \%\) carbon and \(13 \%\) of hydrogen. It vapour density is 2 . The compound reacts with sodium metal to liberate hydrogen. A functional isomer of this compound is
1 ethanol
2 ethanal
3 methoxy methane
4 methoxy ethane.
Explanation:
Molecular mass \(=2 \times\) vapour density Molecular mass \(=2 \times 23=46\) Empirical formula \(=\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}\) Empirical formula mass \(=12 \times 2+6 \times 1+16=46\) \(\mathrm{n}=\dfrac{\text { Empirical formula mass }}{\text { Molecular formula mass }}=\dfrac{46}{46}=1\) Molecular formula \(=\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}\) Alcohols liberate hydrogen on reaction with sodium metal. The functional isomer of ethanol is methoxy methane. \(\underset{\text { Ethanol }}{\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}} \quad \underset{\text { Methoxy methane }}{\mathrm{CH}_{3} \mathrm{OCH}_{3}}\)
KCET - 2012
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317125
A hydrocarbon contains \(20 \%\) of hydrogen and \(80 \%\) of carbon. The empirical formula is
1 \(\mathrm{CH}_{4}\)
2 \(\mathrm{CH}_{3}\)
3 \(\mathrm{CH}_{2}\)
4 \(\mathrm{CH}\)
Explanation:
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317126
6 litres of an alkene require 27 litres of oxygen at constant temperature and pressure for complete combustion. The alkene is:
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317123
A hydrocarbon has carbon and hydrogen. Its molecular weight is 28 . Its possible formula would be
1 \(\mathrm{C}_{3} \mathrm{H}_{6}\)
2 \(\mathrm{C}_{2} \mathrm{H}_{4}\)
3 \(\mathrm{CH}_{4}\)
4 \(\mathrm{C}_{4} \mathrm{H}_{8}\)
Explanation:
Hence the formula of the given compound is \({{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{4}}}\)
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317124
An oxygen containing organic compound was found to contain \(52 \%\) carbon and \(13 \%\) of hydrogen. It vapour density is 2 . The compound reacts with sodium metal to liberate hydrogen. A functional isomer of this compound is
1 ethanol
2 ethanal
3 methoxy methane
4 methoxy ethane.
Explanation:
Molecular mass \(=2 \times\) vapour density Molecular mass \(=2 \times 23=46\) Empirical formula \(=\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}\) Empirical formula mass \(=12 \times 2+6 \times 1+16=46\) \(\mathrm{n}=\dfrac{\text { Empirical formula mass }}{\text { Molecular formula mass }}=\dfrac{46}{46}=1\) Molecular formula \(=\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}\) Alcohols liberate hydrogen on reaction with sodium metal. The functional isomer of ethanol is methoxy methane. \(\underset{\text { Ethanol }}{\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}} \quad \underset{\text { Methoxy methane }}{\mathrm{CH}_{3} \mathrm{OCH}_{3}}\)
KCET - 2012
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317125
A hydrocarbon contains \(20 \%\) of hydrogen and \(80 \%\) of carbon. The empirical formula is
1 \(\mathrm{CH}_{4}\)
2 \(\mathrm{CH}_{3}\)
3 \(\mathrm{CH}_{2}\)
4 \(\mathrm{CH}\)
Explanation:
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317126
6 litres of an alkene require 27 litres of oxygen at constant temperature and pressure for complete combustion. The alkene is:
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317123
A hydrocarbon has carbon and hydrogen. Its molecular weight is 28 . Its possible formula would be
1 \(\mathrm{C}_{3} \mathrm{H}_{6}\)
2 \(\mathrm{C}_{2} \mathrm{H}_{4}\)
3 \(\mathrm{CH}_{4}\)
4 \(\mathrm{C}_{4} \mathrm{H}_{8}\)
Explanation:
Hence the formula of the given compound is \({{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{4}}}\)
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317124
An oxygen containing organic compound was found to contain \(52 \%\) carbon and \(13 \%\) of hydrogen. It vapour density is 2 . The compound reacts with sodium metal to liberate hydrogen. A functional isomer of this compound is
1 ethanol
2 ethanal
3 methoxy methane
4 methoxy ethane.
Explanation:
Molecular mass \(=2 \times\) vapour density Molecular mass \(=2 \times 23=46\) Empirical formula \(=\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}\) Empirical formula mass \(=12 \times 2+6 \times 1+16=46\) \(\mathrm{n}=\dfrac{\text { Empirical formula mass }}{\text { Molecular formula mass }}=\dfrac{46}{46}=1\) Molecular formula \(=\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}\) Alcohols liberate hydrogen on reaction with sodium metal. The functional isomer of ethanol is methoxy methane. \(\underset{\text { Ethanol }}{\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}} \quad \underset{\text { Methoxy methane }}{\mathrm{CH}_{3} \mathrm{OCH}_{3}}\)
KCET - 2012
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317125
A hydrocarbon contains \(20 \%\) of hydrogen and \(80 \%\) of carbon. The empirical formula is
1 \(\mathrm{CH}_{4}\)
2 \(\mathrm{CH}_{3}\)
3 \(\mathrm{CH}_{2}\)
4 \(\mathrm{CH}\)
Explanation:
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317126
6 litres of an alkene require 27 litres of oxygen at constant temperature and pressure for complete combustion. The alkene is:
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317123
A hydrocarbon has carbon and hydrogen. Its molecular weight is 28 . Its possible formula would be
1 \(\mathrm{C}_{3} \mathrm{H}_{6}\)
2 \(\mathrm{C}_{2} \mathrm{H}_{4}\)
3 \(\mathrm{CH}_{4}\)
4 \(\mathrm{C}_{4} \mathrm{H}_{8}\)
Explanation:
Hence the formula of the given compound is \({{\rm{C}}_{\rm{2}}}{{\rm{H}}_{\rm{4}}}\)
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317124
An oxygen containing organic compound was found to contain \(52 \%\) carbon and \(13 \%\) of hydrogen. It vapour density is 2 . The compound reacts with sodium metal to liberate hydrogen. A functional isomer of this compound is
1 ethanol
2 ethanal
3 methoxy methane
4 methoxy ethane.
Explanation:
Molecular mass \(=2 \times\) vapour density Molecular mass \(=2 \times 23=46\) Empirical formula \(=\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}\) Empirical formula mass \(=12 \times 2+6 \times 1+16=46\) \(\mathrm{n}=\dfrac{\text { Empirical formula mass }}{\text { Molecular formula mass }}=\dfrac{46}{46}=1\) Molecular formula \(=\mathrm{C}_{2} \mathrm{H}_{6} \mathrm{O}\) Alcohols liberate hydrogen on reaction with sodium metal. The functional isomer of ethanol is methoxy methane. \(\underset{\text { Ethanol }}{\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}} \quad \underset{\text { Methoxy methane }}{\mathrm{CH}_{3} \mathrm{OCH}_{3}}\)
KCET - 2012
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317125
A hydrocarbon contains \(20 \%\) of hydrogen and \(80 \%\) of carbon. The empirical formula is
1 \(\mathrm{CH}_{4}\)
2 \(\mathrm{CH}_{3}\)
3 \(\mathrm{CH}_{2}\)
4 \(\mathrm{CH}\)
Explanation:
CHXI12:ORGANIC CHEMISTRY SOME BASIC PRINCIPLES AND TECHNIQUES
317126
6 litres of an alkene require 27 litres of oxygen at constant temperature and pressure for complete combustion. The alkene is:
