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CHXI09:HYDROGEN

315647 A commercial sample of hydrogen peroxide is labeled as ' 10 volume'. Its percentage strength is nearly

1

1 %

2

3 %

3

10 %

4

90 %

Explanation:

$10$ $v o l$ $H_{2} O_{2}$ =3.03 % $w / v$

CHXI09:HYDROGEN

315648 "Perhydrol" is a solution of

1

50 %

H_{2} O_{2}

solution

2

70 %

H_{2} O_{2}

solution

3

30 %

H_{2} O_{2}

solution

4

100 %

Pure

H_{2} O_{2}

solution

CHXI09:HYDROGEN

315649 The molarity of a $100$ $m l$ solution containing 5.1 $g$ of hydrogen peroxide is

1

0 .15

M

2

1 .5

M

3

3 .0

M

4

50 .0

M

Explanation:

$M = \frac{5.1 \times 1000}{34 \times 100} = 1.5$ .

CHXI09:HYDROGEN

315581 Which of the following equation depicts reducing nature of $H_{2} O_{2}$ ?

1

2 {[Fe (CN)_{6}]}^{4 -} + 2 H^{+} + H_{2} O_{2} \to 2 {[Fe (CN)_{6}]}^{3 -} + 2 H_{2} O

2

I_{2} + H_{2} O_{2} + 2 {OH}^{-} \to 2 I^{-} + 2 H_{2} O + O_{2}

3

{Mn}^{2 +} + H_{2} O_{2} \to {Mn}^{4 +} + 2 {OH}^{-}

4

PbS + 4 H_{2} O_{2} \to {PbSO}_{4} + 4 H_{2} O

Explanation:

In reducing properties $O_{2}$ is released

CHXI09:HYDROGEN

315647 A commercial sample of hydrogen peroxide is labeled as ' 10 volume'. Its percentage strength is nearly

1

1 %

2

3 %

3

10 %

4

90 %

Explanation:

$10$ $v o l$ $H_{2} O_{2}$ =3.03 % $w / v$

CHXI09:HYDROGEN

315648 "Perhydrol" is a solution of

1

50 %

H_{2} O_{2}

solution

2

70 %

H_{2} O_{2}

solution

3

30 %

H_{2} O_{2}

solution

4

100 %

Pure

H_{2} O_{2}

solution

CHXI09:HYDROGEN

315649 The molarity of a $100$ $m l$ solution containing 5.1 $g$ of hydrogen peroxide is

1

0 .15

M

2

1 .5

M

3

3 .0

M

4

50 .0

M

Explanation:

$M = \frac{5.1 \times 1000}{34 \times 100} = 1.5$ .

CHXI09:HYDROGEN

315581 Which of the following equation depicts reducing nature of $H_{2} O_{2}$ ?

1

2 {[Fe (CN)_{6}]}^{4 -} + 2 H^{+} + H_{2} O_{2} \to 2 {[Fe (CN)_{6}]}^{3 -} + 2 H_{2} O

2

I_{2} + H_{2} O_{2} + 2 {OH}^{-} \to 2 I^{-} + 2 H_{2} O + O_{2}

3

{Mn}^{2 +} + H_{2} O_{2} \to {Mn}^{4 +} + 2 {OH}^{-}

4

PbS + 4 H_{2} O_{2} \to {PbSO}_{4} + 4 H_{2} O

Explanation:

In reducing properties $O_{2}$ is released

CHXI09:HYDROGEN

315647 A commercial sample of hydrogen peroxide is labeled as ' 10 volume'. Its percentage strength is nearly

1

1 %

2

3 %

3

10 %

4

90 %

Explanation:

$10$ $v o l$ $H_{2} O_{2}$ =3.03 % $w / v$

CHXI09:HYDROGEN

315648 "Perhydrol" is a solution of

1

50 %

H_{2} O_{2}

solution

2

70 %

H_{2} O_{2}

solution

3

30 %

H_{2} O_{2}

solution

4

100 %

Pure

H_{2} O_{2}

solution

CHXI09:HYDROGEN

315649 The molarity of a $100$ $m l$ solution containing 5.1 $g$ of hydrogen peroxide is

1

0 .15

M

2

1 .5

M

3

3 .0

M

4

50 .0

M

Explanation:

$M = \frac{5.1 \times 1000}{34 \times 100} = 1.5$ .

CHXI09:HYDROGEN

315581 Which of the following equation depicts reducing nature of $H_{2} O_{2}$ ?

1

2 {[Fe (CN)_{6}]}^{4 -} + 2 H^{+} + H_{2} O_{2} \to 2 {[Fe (CN)_{6}]}^{3 -} + 2 H_{2} O

2

I_{2} + H_{2} O_{2} + 2 {OH}^{-} \to 2 I^{-} + 2 H_{2} O + O_{2}

3

{Mn}^{2 +} + H_{2} O_{2} \to {Mn}^{4 +} + 2 {OH}^{-}

4

PbS + 4 H_{2} O_{2} \to {PbSO}_{4} + 4 H_{2} O

Explanation:

In reducing properties $O_{2}$ is released

CHXI09:HYDROGEN

315647 A commercial sample of hydrogen peroxide is labeled as ' 10 volume'. Its percentage strength is nearly

1

1 %

2

3 %

3

10 %

4

90 %

Explanation:

$10$ $v o l$ $H_{2} O_{2}$ =3.03 % $w / v$

CHXI09:HYDROGEN

315648 "Perhydrol" is a solution of

1

50 %

H_{2} O_{2}

solution

2

70 %

H_{2} O_{2}

solution

3

30 %

H_{2} O_{2}

solution

4

100 %

Pure

H_{2} O_{2}

solution

CHXI09:HYDROGEN

315649 The molarity of a $100$ $m l$ solution containing 5.1 $g$ of hydrogen peroxide is

1

0 .15

M

2

1 .5

M

3

3 .0

M

4

50 .0

M

Explanation:

$M = \frac{5.1 \times 1000}{34 \times 100} = 1.5$ .

CHXI09:HYDROGEN

315581 Which of the following equation depicts reducing nature of $H_{2} O_{2}$ ?

1

2 {[Fe (CN)_{6}]}^{4 -} + 2 H^{+} + H_{2} O_{2} \to 2 {[Fe (CN)_{6}]}^{3 -} + 2 H_{2} O

2

I_{2} + H_{2} O_{2} + 2 {OH}^{-} \to 2 I^{-} + 2 H_{2} O + O_{2}

3

{Mn}^{2 +} + H_{2} O_{2} \to {Mn}^{4 +} + 2 {OH}^{-}

4

PbS + 4 H_{2} O_{2} \to {PbSO}_{4} + 4 H_{2} O

Explanation:

In reducing properties $O_{2}$ is released

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