CHXI09:HYDROGEN
315506
The metal that produces \(\mathrm{\mathrm{H}_{2}}\) with both dil \(\mathrm{\mathrm{HCl}}\) and \(\mathrm{\mathrm{NaOH}_{(\mathrm{aq})}}\) is
1 \(\mathrm{\mathrm{Mg}}\)
2 \(\mathrm{\mathrm{Ca}}\)
3 \(\mathrm{\mathrm{Fe}}\)
4 \(\mathrm{\mathrm{Zn}}\)
Explanation:
\(\mathrm{\mathrm{Zn}}\) liberates \(\mathrm{\mathrm{H}_{2}}\) gas with both dil. \(\mathrm{\mathrm{HCl}}\) and \(\mathrm{\mathrm{NaOH}_{(\mathrm{aq})}}\).\[\rm{\begin{aligned}&
\mathrm{Zn}_{(\mathrm{s})}+2 \mathrm{HCl}_{(\mathrm{aq})} \rightarrow \mathrm{ZnCl}_{2(\mathrm{aq})}+\mathrm{H}_{2(\mathrm{~g})} \uparrow \\& \mathrm{Zn}_{(\mathrm{s})}+2 \mathrm{NaOH}_{(\mathrm{aq})} \rightarrow \underset{\text { (sodium zincate) }}{\mathrm{Na}_{2} \mathrm{ZnO}_{2(\mathrm{aq})}+\mathrm{H}_{2(\mathrm{~g})} \uparrow}\end{aligned}}\]