Stoichiometry of Redox Reactions in Solutions
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CHXI08:REDOX REACTIONS

315437 2 mole of \(\mathrm{N_{2} H_{4}}\) loses 20 moles of electrons to form a compound Y. Assuming that all nitrogen appears in the new compound, if there is no change in O.N. of hydrogen, the O.N. of nitrogen in \(\mathrm{\mathrm{Y}}\) is

1 \({\rm{ - 3}}\)
2 \({\rm{ + 1}}\)
3 \({\rm{ + 5}}\)
4 \({\rm{ + 3}}\)
CHXI08:REDOX REACTIONS

315427 How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide?

1 1
2 2
3 3
4 4
AIIMS - 2010
CHXI08:REDOX REACTIONS

315428 Number of moles of \(\mathrm{MnO}_{4}^{-}\) required to oxidize one mole of ferrous oxalate completely in acidic medium will be

1 7.5 moles
2 0.2 moles
3 0.6 moles
4 0.4 moles
CHXI08:REDOX REACTIONS

315429 The number of electrons involved in the reduction of one nitrate ion to hydrazine is

1 8
2 5
3 3
4 7
AIIMS - 2009
CHXI08:REDOX REACTIONS

315430 The number of electrons required to reduce \(4.5 \times {10^{ - 5}}{\rm{g}}\) of Al is

1 \(1.03 \times {10^{18}}\)
2 \(3.01 \times {10^{18}}\)
3 \(4.95 \times {10^{26}}\)
4 \(7.31 \times {10^{20}}\)
NEET DIGITAL LIBRARY
CHXI08:REDOX REACTIONS

315437 2 mole of \(\mathrm{N_{2} H_{4}}\) loses 20 moles of electrons to form a compound Y. Assuming that all nitrogen appears in the new compound, if there is no change in O.N. of hydrogen, the O.N. of nitrogen in \(\mathrm{\mathrm{Y}}\) is

1 \({\rm{ - 3}}\)
2 \({\rm{ + 1}}\)
3 \({\rm{ + 5}}\)
4 \({\rm{ + 3}}\)
CHXI08:REDOX REACTIONS

315427 How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide?

1 1
2 2
3 3
4 4
AIIMS - 2010
CHXI08:REDOX REACTIONS

315428 Number of moles of \(\mathrm{MnO}_{4}^{-}\) required to oxidize one mole of ferrous oxalate completely in acidic medium will be

1 7.5 moles
2 0.2 moles
3 0.6 moles
4 0.4 moles
CHXI08:REDOX REACTIONS

315429 The number of electrons involved in the reduction of one nitrate ion to hydrazine is

1 8
2 5
3 3
4 7
AIIMS - 2009
CHXI08:REDOX REACTIONS

315430 The number of electrons required to reduce \(4.5 \times {10^{ - 5}}{\rm{g}}\) of Al is

1 \(1.03 \times {10^{18}}\)
2 \(3.01 \times {10^{18}}\)
3 \(4.95 \times {10^{26}}\)
4 \(7.31 \times {10^{20}}\)
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CHXI08:REDOX REACTIONS

315437 2 mole of \(\mathrm{N_{2} H_{4}}\) loses 20 moles of electrons to form a compound Y. Assuming that all nitrogen appears in the new compound, if there is no change in O.N. of hydrogen, the O.N. of nitrogen in \(\mathrm{\mathrm{Y}}\) is

1 \({\rm{ - 3}}\)
2 \({\rm{ + 1}}\)
3 \({\rm{ + 5}}\)
4 \({\rm{ + 3}}\)
CHXI08:REDOX REACTIONS

315427 How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide?

1 1
2 2
3 3
4 4
AIIMS - 2010
CHXI08:REDOX REACTIONS

315428 Number of moles of \(\mathrm{MnO}_{4}^{-}\) required to oxidize one mole of ferrous oxalate completely in acidic medium will be

1 7.5 moles
2 0.2 moles
3 0.6 moles
4 0.4 moles
CHXI08:REDOX REACTIONS

315429 The number of electrons involved in the reduction of one nitrate ion to hydrazine is

1 8
2 5
3 3
4 7
AIIMS - 2009
CHXI08:REDOX REACTIONS

315430 The number of electrons required to reduce \(4.5 \times {10^{ - 5}}{\rm{g}}\) of Al is

1 \(1.03 \times {10^{18}}\)
2 \(3.01 \times {10^{18}}\)
3 \(4.95 \times {10^{26}}\)
4 \(7.31 \times {10^{20}}\)
For More Updates join with Us
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CHXI08:REDOX REACTIONS

315437 2 mole of \(\mathrm{N_{2} H_{4}}\) loses 20 moles of electrons to form a compound Y. Assuming that all nitrogen appears in the new compound, if there is no change in O.N. of hydrogen, the O.N. of nitrogen in \(\mathrm{\mathrm{Y}}\) is

1 \({\rm{ - 3}}\)
2 \({\rm{ + 1}}\)
3 \({\rm{ + 5}}\)
4 \({\rm{ + 3}}\)
CHXI08:REDOX REACTIONS

315427 How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide?

1 1
2 2
3 3
4 4
AIIMS - 2010
CHXI08:REDOX REACTIONS

315428 Number of moles of \(\mathrm{MnO}_{4}^{-}\) required to oxidize one mole of ferrous oxalate completely in acidic medium will be

1 7.5 moles
2 0.2 moles
3 0.6 moles
4 0.4 moles
CHXI08:REDOX REACTIONS

315429 The number of electrons involved in the reduction of one nitrate ion to hydrazine is

1 8
2 5
3 3
4 7
AIIMS - 2009
CHXI08:REDOX REACTIONS

315430 The number of electrons required to reduce \(4.5 \times {10^{ - 5}}{\rm{g}}\) of Al is

1 \(1.03 \times {10^{18}}\)
2 \(3.01 \times {10^{18}}\)
3 \(4.95 \times {10^{26}}\)
4 \(7.31 \times {10^{20}}\)
NEET DIGITAL LIBRARY
CHXI08:REDOX REACTIONS

315437 2 mole of \(\mathrm{N_{2} H_{4}}\) loses 20 moles of electrons to form a compound Y. Assuming that all nitrogen appears in the new compound, if there is no change in O.N. of hydrogen, the O.N. of nitrogen in \(\mathrm{\mathrm{Y}}\) is

1 \({\rm{ - 3}}\)
2 \({\rm{ + 1}}\)
3 \({\rm{ + 5}}\)
4 \({\rm{ + 3}}\)
CHXI08:REDOX REACTIONS

315427 How many moles of iodine are liberated when 1 mole of potassium dichromate reacts with potassium iodide?

1 1
2 2
3 3
4 4
AIIMS - 2010
CHXI08:REDOX REACTIONS

315428 Number of moles of \(\mathrm{MnO}_{4}^{-}\) required to oxidize one mole of ferrous oxalate completely in acidic medium will be

1 7.5 moles
2 0.2 moles
3 0.6 moles
4 0.4 moles
CHXI08:REDOX REACTIONS

315429 The number of electrons involved in the reduction of one nitrate ion to hydrazine is

1 8
2 5
3 3
4 7
AIIMS - 2009
CHXI08:REDOX REACTIONS

315430 The number of electrons required to reduce \(4.5 \times {10^{ - 5}}{\rm{g}}\) of Al is

1 \(1.03 \times {10^{18}}\)
2 \(3.01 \times {10^{18}}\)
3 \(4.95 \times {10^{26}}\)
4 \(7.31 \times {10^{20}}\)