Oxidation Number
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CHXI08:REDOX REACTIONS

315252 Match column I (compound) with column II (oxidation state of nitrogen element) and choose the correct option.
Column I
Column II
A
\(\mathrm{\mathrm{N}_{2} \mathrm{O}_{3}}\)
P
\({\rm{ - 3}}\)
B
\(\mathrm{\mathrm{HNO}_{3}}\)
Q
\({\rm{ + 5}}\)
C
\(\mathrm{\mathrm{NO}}\)
R
\({\rm{ + 3}}\)
D
\(\mathrm{\mathrm{NH}_{4} \mathrm{OH}}\)
S
\({\rm{ + 2}}\)

1 A - Q, B - R, C - S, D- P
2 A - P, B - Q, C - R, D - S
3 A - S, B - P, C - Q, D - R
4 A - R,B - Q, C - S, D - P
CHXI08:REDOX REACTIONS

315253 The correct decreasing order of oxidation number of oxygen in compounds is

1 \(\mathrm{\mathrm{BaO}_{2}>\mathrm{KO}_{2}>\mathrm{O}_{3}>\mathrm{OF}_{2}}\)
2 \(\mathrm{\mathrm{OF}_{2}>\mathrm{O}_{3}>\mathrm{KO}_{2}>\mathrm{BaO}_{2}}\)
3 \(\mathrm{\mathrm{KO}_{2}>\mathrm{OF}_{2}>\mathrm{O}_{3}>\mathrm{BaO}_{2}}\)
4 \(\mathrm{\mathrm{BaO}_{2}>\mathrm{O}_{3}>\mathrm{OF}_{2}>\mathrm{KO}_{2}}\)
CHXI08:REDOX REACTIONS

315254 In which of the following compounds, nitrogen exhibits the highest oxidation state?

1 \(\mathrm{\mathrm{N}_{3} \mathrm{H}}\)
2 \(\mathrm{\mathrm{NH}_{2} \mathrm{OH}}\)
3 \(\mathrm{\mathrm{N}_{2} \mathrm{H}_{4}}\)
4 \(\mathrm{\mathrm{NH}_{3}}\)
CHXI08:REDOX REACTIONS

315255 Oxidation state of carbon in \(\mathrm{\mathrm{HCOOH}}\) will be :

1 \({\rm{ + 1}}\)
2 \({\rm{ + 2}}\)
3 \({\rm{ - 4}}\)
4 \({\rm{0}}\)
CHXI08:REDOX REACTIONS

315256 The oxidation number of \(\mathrm{\mathrm{S}}\) in \(\mathrm{\left(\mathrm{CH}_{3}\right)_{2} \mathrm{SO}}\) is

1 1
2 2
3 0
4 3
NEET DIGITAL LIBRARY
CHXI08:REDOX REACTIONS

315252 Match column I (compound) with column II (oxidation state of nitrogen element) and choose the correct option.
Column I
Column II
A
\(\mathrm{\mathrm{N}_{2} \mathrm{O}_{3}}\)
P
\({\rm{ - 3}}\)
B
\(\mathrm{\mathrm{HNO}_{3}}\)
Q
\({\rm{ + 5}}\)
C
\(\mathrm{\mathrm{NO}}\)
R
\({\rm{ + 3}}\)
D
\(\mathrm{\mathrm{NH}_{4} \mathrm{OH}}\)
S
\({\rm{ + 2}}\)

1 A - Q, B - R, C - S, D- P
2 A - P, B - Q, C - R, D - S
3 A - S, B - P, C - Q, D - R
4 A - R,B - Q, C - S, D - P
CHXI08:REDOX REACTIONS

315253 The correct decreasing order of oxidation number of oxygen in compounds is

1 \(\mathrm{\mathrm{BaO}_{2}>\mathrm{KO}_{2}>\mathrm{O}_{3}>\mathrm{OF}_{2}}\)
2 \(\mathrm{\mathrm{OF}_{2}>\mathrm{O}_{3}>\mathrm{KO}_{2}>\mathrm{BaO}_{2}}\)
3 \(\mathrm{\mathrm{KO}_{2}>\mathrm{OF}_{2}>\mathrm{O}_{3}>\mathrm{BaO}_{2}}\)
4 \(\mathrm{\mathrm{BaO}_{2}>\mathrm{O}_{3}>\mathrm{OF}_{2}>\mathrm{KO}_{2}}\)
CHXI08:REDOX REACTIONS

315254 In which of the following compounds, nitrogen exhibits the highest oxidation state?

1 \(\mathrm{\mathrm{N}_{3} \mathrm{H}}\)
2 \(\mathrm{\mathrm{NH}_{2} \mathrm{OH}}\)
3 \(\mathrm{\mathrm{N}_{2} \mathrm{H}_{4}}\)
4 \(\mathrm{\mathrm{NH}_{3}}\)
CHXI08:REDOX REACTIONS

315255 Oxidation state of carbon in \(\mathrm{\mathrm{HCOOH}}\) will be :

1 \({\rm{ + 1}}\)
2 \({\rm{ + 2}}\)
3 \({\rm{ - 4}}\)
4 \({\rm{0}}\)
CHXI08:REDOX REACTIONS

315256 The oxidation number of \(\mathrm{\mathrm{S}}\) in \(\mathrm{\left(\mathrm{CH}_{3}\right)_{2} \mathrm{SO}}\) is

1 1
2 2
3 0
4 3
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CHXI08:REDOX REACTIONS

315252 Match column I (compound) with column II (oxidation state of nitrogen element) and choose the correct option.
Column I
Column II
A
\(\mathrm{\mathrm{N}_{2} \mathrm{O}_{3}}\)
P
\({\rm{ - 3}}\)
B
\(\mathrm{\mathrm{HNO}_{3}}\)
Q
\({\rm{ + 5}}\)
C
\(\mathrm{\mathrm{NO}}\)
R
\({\rm{ + 3}}\)
D
\(\mathrm{\mathrm{NH}_{4} \mathrm{OH}}\)
S
\({\rm{ + 2}}\)

1 A - Q, B - R, C - S, D- P
2 A - P, B - Q, C - R, D - S
3 A - S, B - P, C - Q, D - R
4 A - R,B - Q, C - S, D - P
CHXI08:REDOX REACTIONS

315253 The correct decreasing order of oxidation number of oxygen in compounds is

1 \(\mathrm{\mathrm{BaO}_{2}>\mathrm{KO}_{2}>\mathrm{O}_{3}>\mathrm{OF}_{2}}\)
2 \(\mathrm{\mathrm{OF}_{2}>\mathrm{O}_{3}>\mathrm{KO}_{2}>\mathrm{BaO}_{2}}\)
3 \(\mathrm{\mathrm{KO}_{2}>\mathrm{OF}_{2}>\mathrm{O}_{3}>\mathrm{BaO}_{2}}\)
4 \(\mathrm{\mathrm{BaO}_{2}>\mathrm{O}_{3}>\mathrm{OF}_{2}>\mathrm{KO}_{2}}\)
CHXI08:REDOX REACTIONS

315254 In which of the following compounds, nitrogen exhibits the highest oxidation state?

1 \(\mathrm{\mathrm{N}_{3} \mathrm{H}}\)
2 \(\mathrm{\mathrm{NH}_{2} \mathrm{OH}}\)
3 \(\mathrm{\mathrm{N}_{2} \mathrm{H}_{4}}\)
4 \(\mathrm{\mathrm{NH}_{3}}\)
CHXI08:REDOX REACTIONS

315255 Oxidation state of carbon in \(\mathrm{\mathrm{HCOOH}}\) will be :

1 \({\rm{ + 1}}\)
2 \({\rm{ + 2}}\)
3 \({\rm{ - 4}}\)
4 \({\rm{0}}\)
CHXI08:REDOX REACTIONS

315256 The oxidation number of \(\mathrm{\mathrm{S}}\) in \(\mathrm{\left(\mathrm{CH}_{3}\right)_{2} \mathrm{SO}}\) is

1 1
2 2
3 0
4 3
For More Updates join with Us
CHXI08:REDOX REACTIONS

315252 Match column I (compound) with column II (oxidation state of nitrogen element) and choose the correct option.
Column I
Column II
A
\(\mathrm{\mathrm{N}_{2} \mathrm{O}_{3}}\)
P
\({\rm{ - 3}}\)
B
\(\mathrm{\mathrm{HNO}_{3}}\)
Q
\({\rm{ + 5}}\)
C
\(\mathrm{\mathrm{NO}}\)
R
\({\rm{ + 3}}\)
D
\(\mathrm{\mathrm{NH}_{4} \mathrm{OH}}\)
S
\({\rm{ + 2}}\)

1 A - Q, B - R, C - S, D- P
2 A - P, B - Q, C - R, D - S
3 A - S, B - P, C - Q, D - R
4 A - R,B - Q, C - S, D - P
CHXI08:REDOX REACTIONS

315253 The correct decreasing order of oxidation number of oxygen in compounds is

1 \(\mathrm{\mathrm{BaO}_{2}>\mathrm{KO}_{2}>\mathrm{O}_{3}>\mathrm{OF}_{2}}\)
2 \(\mathrm{\mathrm{OF}_{2}>\mathrm{O}_{3}>\mathrm{KO}_{2}>\mathrm{BaO}_{2}}\)
3 \(\mathrm{\mathrm{KO}_{2}>\mathrm{OF}_{2}>\mathrm{O}_{3}>\mathrm{BaO}_{2}}\)
4 \(\mathrm{\mathrm{BaO}_{2}>\mathrm{O}_{3}>\mathrm{OF}_{2}>\mathrm{KO}_{2}}\)
CHXI08:REDOX REACTIONS

315254 In which of the following compounds, nitrogen exhibits the highest oxidation state?

1 \(\mathrm{\mathrm{N}_{3} \mathrm{H}}\)
2 \(\mathrm{\mathrm{NH}_{2} \mathrm{OH}}\)
3 \(\mathrm{\mathrm{N}_{2} \mathrm{H}_{4}}\)
4 \(\mathrm{\mathrm{NH}_{3}}\)
CHXI08:REDOX REACTIONS

315255 Oxidation state of carbon in \(\mathrm{\mathrm{HCOOH}}\) will be :

1 \({\rm{ + 1}}\)
2 \({\rm{ + 2}}\)
3 \({\rm{ - 4}}\)
4 \({\rm{0}}\)
CHXI08:REDOX REACTIONS

315256 The oxidation number of \(\mathrm{\mathrm{S}}\) in \(\mathrm{\left(\mathrm{CH}_{3}\right)_{2} \mathrm{SO}}\) is

1 1
2 2
3 0
4 3
NEET DIGITAL LIBRARY
CHXI08:REDOX REACTIONS

315252 Match column I (compound) with column II (oxidation state of nitrogen element) and choose the correct option.
Column I
Column II
A
\(\mathrm{\mathrm{N}_{2} \mathrm{O}_{3}}\)
P
\({\rm{ - 3}}\)
B
\(\mathrm{\mathrm{HNO}_{3}}\)
Q
\({\rm{ + 5}}\)
C
\(\mathrm{\mathrm{NO}}\)
R
\({\rm{ + 3}}\)
D
\(\mathrm{\mathrm{NH}_{4} \mathrm{OH}}\)
S
\({\rm{ + 2}}\)

1 A - Q, B - R, C - S, D- P
2 A - P, B - Q, C - R, D - S
3 A - S, B - P, C - Q, D - R
4 A - R,B - Q, C - S, D - P
CHXI08:REDOX REACTIONS

315253 The correct decreasing order of oxidation number of oxygen in compounds is

1 \(\mathrm{\mathrm{BaO}_{2}>\mathrm{KO}_{2}>\mathrm{O}_{3}>\mathrm{OF}_{2}}\)
2 \(\mathrm{\mathrm{OF}_{2}>\mathrm{O}_{3}>\mathrm{KO}_{2}>\mathrm{BaO}_{2}}\)
3 \(\mathrm{\mathrm{KO}_{2}>\mathrm{OF}_{2}>\mathrm{O}_{3}>\mathrm{BaO}_{2}}\)
4 \(\mathrm{\mathrm{BaO}_{2}>\mathrm{O}_{3}>\mathrm{OF}_{2}>\mathrm{KO}_{2}}\)
CHXI08:REDOX REACTIONS

315254 In which of the following compounds, nitrogen exhibits the highest oxidation state?

1 \(\mathrm{\mathrm{N}_{3} \mathrm{H}}\)
2 \(\mathrm{\mathrm{NH}_{2} \mathrm{OH}}\)
3 \(\mathrm{\mathrm{N}_{2} \mathrm{H}_{4}}\)
4 \(\mathrm{\mathrm{NH}_{3}}\)
CHXI08:REDOX REACTIONS

315255 Oxidation state of carbon in \(\mathrm{\mathrm{HCOOH}}\) will be :

1 \({\rm{ + 1}}\)
2 \({\rm{ + 2}}\)
3 \({\rm{ - 4}}\)
4 \({\rm{0}}\)
CHXI08:REDOX REACTIONS

315256 The oxidation number of \(\mathrm{\mathrm{S}}\) in \(\mathrm{\left(\mathrm{CH}_{3}\right)_{2} \mathrm{SO}}\) is

1 1
2 2
3 0
4 3