314819
An inert gas is added to a dissociation reaction at equilibrium at constant pressure. The effect on the equilibrium is
1 More of the reactants will be formed
2 More of the products will be formed
3 Less of the products will be formed
4 Equilibrium remains unaffected
Explanation:
Addition of inert gas at constant pressure shifts the equilibrium towards larger number of moles and dissociation always produces larger number of moles of product.
Low pressure favours high moles side. \(\mathrm{PCl}_{5(\mathrm{~g})} \rightleftharpoons \mathrm{PCl}_{3}(\mathrm{~g})+\mathrm{Cl}_{2(\mathrm{~g})}\) Here, \(\Delta \mathrm{n}_{\mathrm{g}}=\mathrm{n}_{\mathrm{p}}-\mathrm{n}_{\mathrm{R}}=2-1=1\). It is favored by low pressure.
CHXI07:EQUILIBRIUM
314821
Which reaction is not affected by change in pressure?
The reaction in which number of gaseous products \(\left( {{{\rm{n}}_{\rm{p}}}} \right)\) is equal to number of gaseous reactants, is not affected by change in pressure. For reaction, \(\mathrm{H}_{2}+\mathrm{I}_{2} \rightleftharpoons 2 \mathrm{HI}\) Number of gaseous products \(=2\) Number of gaseous reactants \(=2\) Hence, it is not affected by change in pressure.
CHXI07:EQUILIBRIUM
314799
\({{\text{N}}_{{\text{2(g)}}}}{\text{ + 3}}{{\text{H}}_{{\text{2(g)}}}} \rightleftharpoons {\text{2N}}{{\text{H}}_{{\text{3(g)}}}}\). If some \(\mathrm{HCl}\) gas is passed into the reaction mixture at the equilibrium of this reaction,
1 Equilibrium shifts towards left
2 Equilibrium shifts towards right
3 Concentration of \(\mathrm{H}_{2}\) increases
4 The equilibrium is not affected
Explanation:
Due to the decrease in concentration of \(\mathrm {\mathrm{NH}_{3}}\) as it reacts with \(\mathrm {\mathrm{HCl}}\).
CHXI07:EQUILIBRIUM
314800
In which of the following reactions, an increase in the volume of the container will favour the formation of products?
If volume increases pressure decreases, reaction proceed in which direction where number of gases mole increases. \(\rm { 2 N O_{(2)}(g) \rightleftharpoons 2 N O(g)+O_{2}(g) \\ \Delta n_{g}=(2+1)-2=1}\)
314819
An inert gas is added to a dissociation reaction at equilibrium at constant pressure. The effect on the equilibrium is
1 More of the reactants will be formed
2 More of the products will be formed
3 Less of the products will be formed
4 Equilibrium remains unaffected
Explanation:
Addition of inert gas at constant pressure shifts the equilibrium towards larger number of moles and dissociation always produces larger number of moles of product.
Low pressure favours high moles side. \(\mathrm{PCl}_{5(\mathrm{~g})} \rightleftharpoons \mathrm{PCl}_{3}(\mathrm{~g})+\mathrm{Cl}_{2(\mathrm{~g})}\) Here, \(\Delta \mathrm{n}_{\mathrm{g}}=\mathrm{n}_{\mathrm{p}}-\mathrm{n}_{\mathrm{R}}=2-1=1\). It is favored by low pressure.
CHXI07:EQUILIBRIUM
314821
Which reaction is not affected by change in pressure?
The reaction in which number of gaseous products \(\left( {{{\rm{n}}_{\rm{p}}}} \right)\) is equal to number of gaseous reactants, is not affected by change in pressure. For reaction, \(\mathrm{H}_{2}+\mathrm{I}_{2} \rightleftharpoons 2 \mathrm{HI}\) Number of gaseous products \(=2\) Number of gaseous reactants \(=2\) Hence, it is not affected by change in pressure.
CHXI07:EQUILIBRIUM
314799
\({{\text{N}}_{{\text{2(g)}}}}{\text{ + 3}}{{\text{H}}_{{\text{2(g)}}}} \rightleftharpoons {\text{2N}}{{\text{H}}_{{\text{3(g)}}}}\). If some \(\mathrm{HCl}\) gas is passed into the reaction mixture at the equilibrium of this reaction,
1 Equilibrium shifts towards left
2 Equilibrium shifts towards right
3 Concentration of \(\mathrm{H}_{2}\) increases
4 The equilibrium is not affected
Explanation:
Due to the decrease in concentration of \(\mathrm {\mathrm{NH}_{3}}\) as it reacts with \(\mathrm {\mathrm{HCl}}\).
CHXI07:EQUILIBRIUM
314800
In which of the following reactions, an increase in the volume of the container will favour the formation of products?
If volume increases pressure decreases, reaction proceed in which direction where number of gases mole increases. \(\rm { 2 N O_{(2)}(g) \rightleftharpoons 2 N O(g)+O_{2}(g) \\ \Delta n_{g}=(2+1)-2=1}\)
314819
An inert gas is added to a dissociation reaction at equilibrium at constant pressure. The effect on the equilibrium is
1 More of the reactants will be formed
2 More of the products will be formed
3 Less of the products will be formed
4 Equilibrium remains unaffected
Explanation:
Addition of inert gas at constant pressure shifts the equilibrium towards larger number of moles and dissociation always produces larger number of moles of product.
Low pressure favours high moles side. \(\mathrm{PCl}_{5(\mathrm{~g})} \rightleftharpoons \mathrm{PCl}_{3}(\mathrm{~g})+\mathrm{Cl}_{2(\mathrm{~g})}\) Here, \(\Delta \mathrm{n}_{\mathrm{g}}=\mathrm{n}_{\mathrm{p}}-\mathrm{n}_{\mathrm{R}}=2-1=1\). It is favored by low pressure.
CHXI07:EQUILIBRIUM
314821
Which reaction is not affected by change in pressure?
The reaction in which number of gaseous products \(\left( {{{\rm{n}}_{\rm{p}}}} \right)\) is equal to number of gaseous reactants, is not affected by change in pressure. For reaction, \(\mathrm{H}_{2}+\mathrm{I}_{2} \rightleftharpoons 2 \mathrm{HI}\) Number of gaseous products \(=2\) Number of gaseous reactants \(=2\) Hence, it is not affected by change in pressure.
CHXI07:EQUILIBRIUM
314799
\({{\text{N}}_{{\text{2(g)}}}}{\text{ + 3}}{{\text{H}}_{{\text{2(g)}}}} \rightleftharpoons {\text{2N}}{{\text{H}}_{{\text{3(g)}}}}\). If some \(\mathrm{HCl}\) gas is passed into the reaction mixture at the equilibrium of this reaction,
1 Equilibrium shifts towards left
2 Equilibrium shifts towards right
3 Concentration of \(\mathrm{H}_{2}\) increases
4 The equilibrium is not affected
Explanation:
Due to the decrease in concentration of \(\mathrm {\mathrm{NH}_{3}}\) as it reacts with \(\mathrm {\mathrm{HCl}}\).
CHXI07:EQUILIBRIUM
314800
In which of the following reactions, an increase in the volume of the container will favour the formation of products?
If volume increases pressure decreases, reaction proceed in which direction where number of gases mole increases. \(\rm { 2 N O_{(2)}(g) \rightleftharpoons 2 N O(g)+O_{2}(g) \\ \Delta n_{g}=(2+1)-2=1}\)
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CHXI07:EQUILIBRIUM
314819
An inert gas is added to a dissociation reaction at equilibrium at constant pressure. The effect on the equilibrium is
1 More of the reactants will be formed
2 More of the products will be formed
3 Less of the products will be formed
4 Equilibrium remains unaffected
Explanation:
Addition of inert gas at constant pressure shifts the equilibrium towards larger number of moles and dissociation always produces larger number of moles of product.
Low pressure favours high moles side. \(\mathrm{PCl}_{5(\mathrm{~g})} \rightleftharpoons \mathrm{PCl}_{3}(\mathrm{~g})+\mathrm{Cl}_{2(\mathrm{~g})}\) Here, \(\Delta \mathrm{n}_{\mathrm{g}}=\mathrm{n}_{\mathrm{p}}-\mathrm{n}_{\mathrm{R}}=2-1=1\). It is favored by low pressure.
CHXI07:EQUILIBRIUM
314821
Which reaction is not affected by change in pressure?
The reaction in which number of gaseous products \(\left( {{{\rm{n}}_{\rm{p}}}} \right)\) is equal to number of gaseous reactants, is not affected by change in pressure. For reaction, \(\mathrm{H}_{2}+\mathrm{I}_{2} \rightleftharpoons 2 \mathrm{HI}\) Number of gaseous products \(=2\) Number of gaseous reactants \(=2\) Hence, it is not affected by change in pressure.
CHXI07:EQUILIBRIUM
314799
\({{\text{N}}_{{\text{2(g)}}}}{\text{ + 3}}{{\text{H}}_{{\text{2(g)}}}} \rightleftharpoons {\text{2N}}{{\text{H}}_{{\text{3(g)}}}}\). If some \(\mathrm{HCl}\) gas is passed into the reaction mixture at the equilibrium of this reaction,
1 Equilibrium shifts towards left
2 Equilibrium shifts towards right
3 Concentration of \(\mathrm{H}_{2}\) increases
4 The equilibrium is not affected
Explanation:
Due to the decrease in concentration of \(\mathrm {\mathrm{NH}_{3}}\) as it reacts with \(\mathrm {\mathrm{HCl}}\).
CHXI07:EQUILIBRIUM
314800
In which of the following reactions, an increase in the volume of the container will favour the formation of products?
If volume increases pressure decreases, reaction proceed in which direction where number of gases mole increases. \(\rm { 2 N O_{(2)}(g) \rightleftharpoons 2 N O(g)+O_{2}(g) \\ \Delta n_{g}=(2+1)-2=1}\)
314819
An inert gas is added to a dissociation reaction at equilibrium at constant pressure. The effect on the equilibrium is
1 More of the reactants will be formed
2 More of the products will be formed
3 Less of the products will be formed
4 Equilibrium remains unaffected
Explanation:
Addition of inert gas at constant pressure shifts the equilibrium towards larger number of moles and dissociation always produces larger number of moles of product.
Low pressure favours high moles side. \(\mathrm{PCl}_{5(\mathrm{~g})} \rightleftharpoons \mathrm{PCl}_{3}(\mathrm{~g})+\mathrm{Cl}_{2(\mathrm{~g})}\) Here, \(\Delta \mathrm{n}_{\mathrm{g}}=\mathrm{n}_{\mathrm{p}}-\mathrm{n}_{\mathrm{R}}=2-1=1\). It is favored by low pressure.
CHXI07:EQUILIBRIUM
314821
Which reaction is not affected by change in pressure?
The reaction in which number of gaseous products \(\left( {{{\rm{n}}_{\rm{p}}}} \right)\) is equal to number of gaseous reactants, is not affected by change in pressure. For reaction, \(\mathrm{H}_{2}+\mathrm{I}_{2} \rightleftharpoons 2 \mathrm{HI}\) Number of gaseous products \(=2\) Number of gaseous reactants \(=2\) Hence, it is not affected by change in pressure.
CHXI07:EQUILIBRIUM
314799
\({{\text{N}}_{{\text{2(g)}}}}{\text{ + 3}}{{\text{H}}_{{\text{2(g)}}}} \rightleftharpoons {\text{2N}}{{\text{H}}_{{\text{3(g)}}}}\). If some \(\mathrm{HCl}\) gas is passed into the reaction mixture at the equilibrium of this reaction,
1 Equilibrium shifts towards left
2 Equilibrium shifts towards right
3 Concentration of \(\mathrm{H}_{2}\) increases
4 The equilibrium is not affected
Explanation:
Due to the decrease in concentration of \(\mathrm {\mathrm{NH}_{3}}\) as it reacts with \(\mathrm {\mathrm{HCl}}\).
CHXI07:EQUILIBRIUM
314800
In which of the following reactions, an increase in the volume of the container will favour the formation of products?
If volume increases pressure decreases, reaction proceed in which direction where number of gases mole increases. \(\rm { 2 N O_{(2)}(g) \rightleftharpoons 2 N O(g)+O_{2}(g) \\ \Delta n_{g}=(2+1)-2=1}\)