Explanation:
Hydrolysis of sodium acetate is given by
\(\mathop {{\rm{C}}{{\rm{H}}_{\rm{3}}}{\rm{COONa}}}\limits_{{\rm{Sodium}}\,{\rm{Acetate}}{\mkern 1mu} } {\mkern 1mu} {\rm{ + }}{{\rm{H}}_2}{\mkern 1mu} {\rm{O}}\)\( \rightleftharpoons \)
\(\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\mathop {{\text{C}}{{\text{H}}_{\text{3}}}{\text{COOH + }}{\mkern 1mu} {\mkern 1mu} }\limits_{{\text{Acetic acid}}} \mathop {{\text{NaOH}}{\mkern 1mu} {\mkern 1mu} }\limits_{{\text{Sodium}}{\mkern 1mu} \,{\text{hydroxide}}} \)
Sodium acetate gives weak acid and strong base on hydrolysis. Therefore, the aqueous solution of sodium acetate will be basic in nature.