NEET Test Series from KOTA - 10 Papers In MS WORD
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CHXI06:THERMODYNAMICS
369313
A system does \(394 \mathrm{~J}\) of work on surrounding by absorbing \(701 \mathrm{~J}\) heat. What is the change in internal energy of the system?
1 \(547 \mathrm{~J}\)
2 \(1095 \mathrm{~J}\)
3 \(307 \mathrm{~J}\)
4 \(394 \mathrm{~J}\)
Explanation:
\(\mathrm{W}=-394 \mathrm{~J}(\) work done by the system), \(\mathrm{Q}=701 \mathrm{~J}\) (heat absorbed) According to first law of thermodynamics \(\Delta \mathrm{U}=\mathrm{Q}+\mathrm{W}\) \(=701-394=307 \mathrm{~J}\)
MHTCET - 2021
CHXI06:THERMODYNAMICS
369314
Assertion : First law of thermodynamics is applicable to an electric fan or a heater. Reason : In an electric fan, the electrical energy is converted into chemical work that moves the blades. In a heater, electrical energy is converted into heat energy.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Conceptual Question
CHXI06:THERMODYNAMICS
369315
Assertion : For an isothermal reversible process, \(\mathrm{q}=-\mathrm{w}\) i.e.,work done by the system equals the heat absorbed by the system. Reason : Enthalpy change \((\Delta \mathrm{H})\) is not zero for isothermal process.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
In an isothermal process, there is no change in the internal energy \((\mathrm{U})\) as it is a function of temperature. Therefore, \(\Delta \mathrm{U}\) is zero. According to the first law of thermodynamics, \(\mathrm{q}+\mathrm{w}=\Delta \mathrm{U}\), this implies that if \(\Delta \mathrm{U}\) is \(0, \mathrm{q}+\mathrm{w}\) \(=0\). Therefore, when \(\left( {\Delta {\text{U}} = 0} \right), - {\text{w}} = {\text{q}}\). Thus work done by the system is equal to the heat absorbed by the system. Thus, option (3) is correct.
CHXI06:THERMODYNAMICS
369316
A system absorbs \(\mathrm{10 \mathrm{~kJ}}\) of heat and does \(\mathrm{4 \mathrm{~kJ}}\) of work. The internal energy of the system
1 Decreases by \(\mathrm{6 \mathrm{~kJ}}\)
2 Increases by \(\mathrm{6 \mathrm{~kJ}}\)
3 Decreases by \(\mathrm{14 \mathrm{~kJ}}\)
4 Increases by \(\mathrm{14 \mathrm{~kJ}}\)
Explanation:
\(\mathrm{q=+10 k J, w=-4 k J}\) \(\mathrm{\Delta U=q+w=10-4=6 \mathrm{~kJ}}\)
369313
A system does \(394 \mathrm{~J}\) of work on surrounding by absorbing \(701 \mathrm{~J}\) heat. What is the change in internal energy of the system?
1 \(547 \mathrm{~J}\)
2 \(1095 \mathrm{~J}\)
3 \(307 \mathrm{~J}\)
4 \(394 \mathrm{~J}\)
Explanation:
\(\mathrm{W}=-394 \mathrm{~J}(\) work done by the system), \(\mathrm{Q}=701 \mathrm{~J}\) (heat absorbed) According to first law of thermodynamics \(\Delta \mathrm{U}=\mathrm{Q}+\mathrm{W}\) \(=701-394=307 \mathrm{~J}\)
MHTCET - 2021
CHXI06:THERMODYNAMICS
369314
Assertion : First law of thermodynamics is applicable to an electric fan or a heater. Reason : In an electric fan, the electrical energy is converted into chemical work that moves the blades. In a heater, electrical energy is converted into heat energy.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Conceptual Question
CHXI06:THERMODYNAMICS
369315
Assertion : For an isothermal reversible process, \(\mathrm{q}=-\mathrm{w}\) i.e.,work done by the system equals the heat absorbed by the system. Reason : Enthalpy change \((\Delta \mathrm{H})\) is not zero for isothermal process.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
In an isothermal process, there is no change in the internal energy \((\mathrm{U})\) as it is a function of temperature. Therefore, \(\Delta \mathrm{U}\) is zero. According to the first law of thermodynamics, \(\mathrm{q}+\mathrm{w}=\Delta \mathrm{U}\), this implies that if \(\Delta \mathrm{U}\) is \(0, \mathrm{q}+\mathrm{w}\) \(=0\). Therefore, when \(\left( {\Delta {\text{U}} = 0} \right), - {\text{w}} = {\text{q}}\). Thus work done by the system is equal to the heat absorbed by the system. Thus, option (3) is correct.
CHXI06:THERMODYNAMICS
369316
A system absorbs \(\mathrm{10 \mathrm{~kJ}}\) of heat and does \(\mathrm{4 \mathrm{~kJ}}\) of work. The internal energy of the system
1 Decreases by \(\mathrm{6 \mathrm{~kJ}}\)
2 Increases by \(\mathrm{6 \mathrm{~kJ}}\)
3 Decreases by \(\mathrm{14 \mathrm{~kJ}}\)
4 Increases by \(\mathrm{14 \mathrm{~kJ}}\)
Explanation:
\(\mathrm{q=+10 k J, w=-4 k J}\) \(\mathrm{\Delta U=q+w=10-4=6 \mathrm{~kJ}}\)
369313
A system does \(394 \mathrm{~J}\) of work on surrounding by absorbing \(701 \mathrm{~J}\) heat. What is the change in internal energy of the system?
1 \(547 \mathrm{~J}\)
2 \(1095 \mathrm{~J}\)
3 \(307 \mathrm{~J}\)
4 \(394 \mathrm{~J}\)
Explanation:
\(\mathrm{W}=-394 \mathrm{~J}(\) work done by the system), \(\mathrm{Q}=701 \mathrm{~J}\) (heat absorbed) According to first law of thermodynamics \(\Delta \mathrm{U}=\mathrm{Q}+\mathrm{W}\) \(=701-394=307 \mathrm{~J}\)
MHTCET - 2021
CHXI06:THERMODYNAMICS
369314
Assertion : First law of thermodynamics is applicable to an electric fan or a heater. Reason : In an electric fan, the electrical energy is converted into chemical work that moves the blades. In a heater, electrical energy is converted into heat energy.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Conceptual Question
CHXI06:THERMODYNAMICS
369315
Assertion : For an isothermal reversible process, \(\mathrm{q}=-\mathrm{w}\) i.e.,work done by the system equals the heat absorbed by the system. Reason : Enthalpy change \((\Delta \mathrm{H})\) is not zero for isothermal process.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
In an isothermal process, there is no change in the internal energy \((\mathrm{U})\) as it is a function of temperature. Therefore, \(\Delta \mathrm{U}\) is zero. According to the first law of thermodynamics, \(\mathrm{q}+\mathrm{w}=\Delta \mathrm{U}\), this implies that if \(\Delta \mathrm{U}\) is \(0, \mathrm{q}+\mathrm{w}\) \(=0\). Therefore, when \(\left( {\Delta {\text{U}} = 0} \right), - {\text{w}} = {\text{q}}\). Thus work done by the system is equal to the heat absorbed by the system. Thus, option (3) is correct.
CHXI06:THERMODYNAMICS
369316
A system absorbs \(\mathrm{10 \mathrm{~kJ}}\) of heat and does \(\mathrm{4 \mathrm{~kJ}}\) of work. The internal energy of the system
1 Decreases by \(\mathrm{6 \mathrm{~kJ}}\)
2 Increases by \(\mathrm{6 \mathrm{~kJ}}\)
3 Decreases by \(\mathrm{14 \mathrm{~kJ}}\)
4 Increases by \(\mathrm{14 \mathrm{~kJ}}\)
Explanation:
\(\mathrm{q=+10 k J, w=-4 k J}\) \(\mathrm{\Delta U=q+w=10-4=6 \mathrm{~kJ}}\)
NEET Test Series from KOTA - 10 Papers In MS WORD
WhatsApp Here
CHXI06:THERMODYNAMICS
369313
A system does \(394 \mathrm{~J}\) of work on surrounding by absorbing \(701 \mathrm{~J}\) heat. What is the change in internal energy of the system?
1 \(547 \mathrm{~J}\)
2 \(1095 \mathrm{~J}\)
3 \(307 \mathrm{~J}\)
4 \(394 \mathrm{~J}\)
Explanation:
\(\mathrm{W}=-394 \mathrm{~J}(\) work done by the system), \(\mathrm{Q}=701 \mathrm{~J}\) (heat absorbed) According to first law of thermodynamics \(\Delta \mathrm{U}=\mathrm{Q}+\mathrm{W}\) \(=701-394=307 \mathrm{~J}\)
MHTCET - 2021
CHXI06:THERMODYNAMICS
369314
Assertion : First law of thermodynamics is applicable to an electric fan or a heater. Reason : In an electric fan, the electrical energy is converted into chemical work that moves the blades. In a heater, electrical energy is converted into heat energy.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but reason is correct.
Explanation:
Conceptual Question
CHXI06:THERMODYNAMICS
369315
Assertion : For an isothermal reversible process, \(\mathrm{q}=-\mathrm{w}\) i.e.,work done by the system equals the heat absorbed by the system. Reason : Enthalpy change \((\Delta \mathrm{H})\) is not zero for isothermal process.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
In an isothermal process, there is no change in the internal energy \((\mathrm{U})\) as it is a function of temperature. Therefore, \(\Delta \mathrm{U}\) is zero. According to the first law of thermodynamics, \(\mathrm{q}+\mathrm{w}=\Delta \mathrm{U}\), this implies that if \(\Delta \mathrm{U}\) is \(0, \mathrm{q}+\mathrm{w}\) \(=0\). Therefore, when \(\left( {\Delta {\text{U}} = 0} \right), - {\text{w}} = {\text{q}}\). Thus work done by the system is equal to the heat absorbed by the system. Thus, option (3) is correct.
CHXI06:THERMODYNAMICS
369316
A system absorbs \(\mathrm{10 \mathrm{~kJ}}\) of heat and does \(\mathrm{4 \mathrm{~kJ}}\) of work. The internal energy of the system
1 Decreases by \(\mathrm{6 \mathrm{~kJ}}\)
2 Increases by \(\mathrm{6 \mathrm{~kJ}}\)
3 Decreases by \(\mathrm{14 \mathrm{~kJ}}\)
4 Increases by \(\mathrm{14 \mathrm{~kJ}}\)
Explanation:
\(\mathrm{q=+10 k J, w=-4 k J}\) \(\mathrm{\Delta U=q+w=10-4=6 \mathrm{~kJ}}\)