313891
Assertion : \(\mathrm{FeCl}_{3}\) is more covalent than \(\mathrm{FeCl}_{2}\). Reason : Greater the charge on the cation, greater is the covalent character.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
According to Fajan's rule, as the cation charge increases covalent character increases. So the option (1) is correct.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313892
Which contains both polar and non-polar bonds?
1 \({\rm{N}}{{\rm{H}}_{\rm{4}}}{\rm{Cl}}\)
2 \({\rm{HCN}}\)
3 \({{\rm{H}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}}\)
4 \({\rm{C}}{{\rm{H}}_{\rm{4}}}\)
Explanation:
In \({{\rm{H}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}}\) polar bond is O – H and non-polar bond is O – O (peroxy linkage)
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313893
Choose the polar molecule from the following :
\({\rm{C}}{{\rm{O}}_{\rm{2}}}{\rm{,CC}}{{\rm{l}}_{\rm{4}}}{\rm{,}}{{\rm{H}}_{\rm{2}}}{\rm{C = C}}{{\rm{H}}_{\rm{2}}}\) are symmetrical molecules with zero dipole moment. \({\mathrm{\mathrm{CHCl}_{3}}}\) is a molecule with a net dipole moment. So, \({\mathrm{\mathrm{CHCl}_{3}}}\) is a polar molecule. So, the correct option is (3).
JEE Main - 2024
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313894
Choose the polar molecule from the following :
1 \(\mathrm{CCl}_{4}\)
2 \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}_{2}\)
3 \(\mathrm{CHCl}_{3}\)
4 \(\mathrm{CO}_{2}\)
Explanation:
\(\mathrm{CHCl}_{3}\) is having permanent dipole moment, therefore it is polar molecule whereas all other given molecules have zero dipole moment .
313891
Assertion : \(\mathrm{FeCl}_{3}\) is more covalent than \(\mathrm{FeCl}_{2}\). Reason : Greater the charge on the cation, greater is the covalent character.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
According to Fajan's rule, as the cation charge increases covalent character increases. So the option (1) is correct.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313892
Which contains both polar and non-polar bonds?
1 \({\rm{N}}{{\rm{H}}_{\rm{4}}}{\rm{Cl}}\)
2 \({\rm{HCN}}\)
3 \({{\rm{H}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}}\)
4 \({\rm{C}}{{\rm{H}}_{\rm{4}}}\)
Explanation:
In \({{\rm{H}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}}\) polar bond is O – H and non-polar bond is O – O (peroxy linkage)
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313893
Choose the polar molecule from the following :
\({\rm{C}}{{\rm{O}}_{\rm{2}}}{\rm{,CC}}{{\rm{l}}_{\rm{4}}}{\rm{,}}{{\rm{H}}_{\rm{2}}}{\rm{C = C}}{{\rm{H}}_{\rm{2}}}\) are symmetrical molecules with zero dipole moment. \({\mathrm{\mathrm{CHCl}_{3}}}\) is a molecule with a net dipole moment. So, \({\mathrm{\mathrm{CHCl}_{3}}}\) is a polar molecule. So, the correct option is (3).
JEE Main - 2024
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313894
Choose the polar molecule from the following :
1 \(\mathrm{CCl}_{4}\)
2 \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}_{2}\)
3 \(\mathrm{CHCl}_{3}\)
4 \(\mathrm{CO}_{2}\)
Explanation:
\(\mathrm{CHCl}_{3}\) is having permanent dipole moment, therefore it is polar molecule whereas all other given molecules have zero dipole moment .
313891
Assertion : \(\mathrm{FeCl}_{3}\) is more covalent than \(\mathrm{FeCl}_{2}\). Reason : Greater the charge on the cation, greater is the covalent character.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
According to Fajan's rule, as the cation charge increases covalent character increases. So the option (1) is correct.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313892
Which contains both polar and non-polar bonds?
1 \({\rm{N}}{{\rm{H}}_{\rm{4}}}{\rm{Cl}}\)
2 \({\rm{HCN}}\)
3 \({{\rm{H}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}}\)
4 \({\rm{C}}{{\rm{H}}_{\rm{4}}}\)
Explanation:
In \({{\rm{H}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}}\) polar bond is O – H and non-polar bond is O – O (peroxy linkage)
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313893
Choose the polar molecule from the following :
\({\rm{C}}{{\rm{O}}_{\rm{2}}}{\rm{,CC}}{{\rm{l}}_{\rm{4}}}{\rm{,}}{{\rm{H}}_{\rm{2}}}{\rm{C = C}}{{\rm{H}}_{\rm{2}}}\) are symmetrical molecules with zero dipole moment. \({\mathrm{\mathrm{CHCl}_{3}}}\) is a molecule with a net dipole moment. So, \({\mathrm{\mathrm{CHCl}_{3}}}\) is a polar molecule. So, the correct option is (3).
JEE Main - 2024
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313894
Choose the polar molecule from the following :
1 \(\mathrm{CCl}_{4}\)
2 \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}_{2}\)
3 \(\mathrm{CHCl}_{3}\)
4 \(\mathrm{CO}_{2}\)
Explanation:
\(\mathrm{CHCl}_{3}\) is having permanent dipole moment, therefore it is polar molecule whereas all other given molecules have zero dipole moment .
313891
Assertion : \(\mathrm{FeCl}_{3}\) is more covalent than \(\mathrm{FeCl}_{2}\). Reason : Greater the charge on the cation, greater is the covalent character.
1 Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
2 Both Assertion and Reason are correct but Reason is not the correct explanation of the Assertion.
3 Assertion is correct but Reason is incorrect.
4 Assertion is incorrect but Reason is correct.
Explanation:
According to Fajan's rule, as the cation charge increases covalent character increases. So the option (1) is correct.
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313892
Which contains both polar and non-polar bonds?
1 \({\rm{N}}{{\rm{H}}_{\rm{4}}}{\rm{Cl}}\)
2 \({\rm{HCN}}\)
3 \({{\rm{H}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}}\)
4 \({\rm{C}}{{\rm{H}}_{\rm{4}}}\)
Explanation:
In \({{\rm{H}}_{\rm{2}}}{{\rm{O}}_{\rm{2}}}\) polar bond is O – H and non-polar bond is O – O (peroxy linkage)
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313893
Choose the polar molecule from the following :
\({\rm{C}}{{\rm{O}}_{\rm{2}}}{\rm{,CC}}{{\rm{l}}_{\rm{4}}}{\rm{,}}{{\rm{H}}_{\rm{2}}}{\rm{C = C}}{{\rm{H}}_{\rm{2}}}\) are symmetrical molecules with zero dipole moment. \({\mathrm{\mathrm{CHCl}_{3}}}\) is a molecule with a net dipole moment. So, \({\mathrm{\mathrm{CHCl}_{3}}}\) is a polar molecule. So, the correct option is (3).
JEE Main - 2024
CHXI04:CHEMICAL BONDING AND MOLECULAR STRUCTURE
313894
Choose the polar molecule from the following :
1 \(\mathrm{CCl}_{4}\)
2 \(\mathrm{H}_{2} \mathrm{C}=\mathrm{CH}_{2}\)
3 \(\mathrm{CHCl}_{3}\)
4 \(\mathrm{CO}_{2}\)
Explanation:
\(\mathrm{CHCl}_{3}\) is having permanent dipole moment, therefore it is polar molecule whereas all other given molecules have zero dipole moment .
